@BalarkaSen saw that in a fun doc recently that has a lot on notch, recommend it, bet youll like it. have you ever tried minecraft? imdb.com/title/tt2087878
@ACuriousMind "I wouldn't ask MO about this specific issue either. ... In general, it is a very bad idea to advertise to the world (or even to your colleagues) what you're thinking about. You should really try to exhaust every possibility of settling questions on your own (or with people at your department) before asking the internet or people elsewhere. It's a competitive profession, and good questions are few and far between."
@JohnDuffield (have cyberstalked tracked him some...) he has an SE acct & some posts on Physics, now maybe inactive, look up the one where he complains nobody takes him seriously, its my favorite :P
@0celo7 Well, then I don't see an immediate problem. After the thesis is done you can still consider going against your advisor's advice and asking the author directly.
@0celo7 If you want to be "competitive" and you find a counterexample, you could also try to publish the counterexample. Although I personally would very much dislike doing that without asking the author first.
@0celo7 are you joking? only 1 of the most important math concepts from 20th century dude, strongly running into 21st :P vzn1.wordpress.com/2016/01/22/…
@0celo7 Oh, so you can be the young upstart who found an error of Yau...or the young upstart who thought he found an error but overlooked something and embarrased himself by publishing it - and that's precisely why I'd ask the author first, but maybe make sure somehow to establish that it was you who found the counterexample first.
@ACuriousMind My advisor sent me a list of counterexamples to try -- none of them are actually counterexamples. We've basically exhausted all of the "standard" manifolds. So maybe there's not an error with the conclusion, but the proof is definitely shady. This is why I think I should ask on MO. The paper has a billion citations so someone has probably thought about it in some detail -- I can't be the first.
@vzn : I found 't Hooft's his answer to [Does any particle ever reach any singularity inside the black hole?] "Look at what happens in a space-time diagram. At the spacetime point where your astronaut passes the horizon... the observer just continues on, and in a finite amount of time, very quickly unless the black hole were more than millions of times heavier than the sun, he is killed by the central singularity..."
"In a black hole with high angular momentum (Kerr black hole), the singularity takes the form of a ring along the equator, and the astronaut might try to sail past it safely, and he would be able to enter into a strange new universe where he may or may not leave a negative mass black hole behind him..."
@0celo7 Oh, I think "doing surgery on a $p$-sphere" just means doing the surgery where you cut out $S^p \times D^{\dim(M)-p}$. Or is the question what surgery is?
Who wants to talk about my book sitting on my table? It's The Principle of Relativity by Albert Einstein. Apparently it's accelerating upwards at 9.8m/s². Funny, I don't seem to be able to see any change of velocity there.
@Pieter are you here? I'm wondering about the difference between a perfect conductor and a superconductor. I know the latter can expell an already present B field inside it, while the former can't. is that the only difference (ignoring phase transition) ?
@no_choice99 A perfect conductor is an idealization of a real classical conductor, while a superconductor is not an idealization, and not really a classical conductor.
@no_choice99 Depends on how you define "difference". For instance, clearly a "perfect conductor" still has ordinary electrons moving through it while a superconductor has Cooper pairs.
But of course that's not something one could directly mesure
from hyperphysics.phy-astr.gsu.edu/hbase/Solids/meis.html#c1 , I'm unable to show "If there were no change in the applied magnetic field, there would be no generated voltage (Faraday's law) to drive currents, even in a perfect conductor. " I start with dB/dt =0 and this is equal to the curl of E. or curl of -grad(V) =0 . im not able to see that V = 0 like it's stated
@ACuriousMind One can see that there are Cooper pairs by doing Andreev reflection. And one can measure the superconducting gap, which is a measure of the pairing energy.
@0celo7 Well, it's true in $\mathbb{R}^n$ and I don't see a global obstruction to gluing the local hypersurfaces you get in balls around points on the subfold.
> In his meditations on the topology of Borromean knots, and in particular throughout his seminar of 1974–1975, the French psychoanalyst Jacques Lacan exposes the interrelation between the Symbolic, the Imaginary, and the Real in terms of link-topology
@vzn : it's similar to what a lot of physicists would describe. But it came out of what you might call Misner-Thorne-Wheeler general relativity, which exhibits some marked differences from what you might call Einstein's relativity. When you stick to the latter, you get a very different picture of what happens to the infalling observer.
Mathematicians are like theologians: we regard existence as the prime attribute of what we study. But unlike theologians, we need not always rely upon faith alone.
@JohnDuffield ok. think somebody should just write all this up (maybe you!) as "different interpretations" much like in QM. which btw there are some very excellent papers out now surveying that. & btw think "what really happens™" is probably as unanswerable as it is "currently" with QM...
@BernardoMeurer I have to say that I find the idea of the graph of semi-signifieds interesting, but can't discern the reason all the other philosophy is there :P
@vzn : no, it's much more than two different interpretations. You end up with very different predictions about what happens when it comes to black holes and the like.
@BernardoMeurer I actually don't, there is no "general education" requirement here, so I never had to take a university course on anything besides math and physics.
@JohnDuffield the point is that even mainstream physicists have ideas with different nuance and theres no airtight consensus on certain topics. its the scientific equivalent of the zen question, what is the sound of one hand clapping? what happens when an astronaut falls into a black hole?
@BernardoMeurer What if they were delighted by the ambiguity of their statement, not fully intending any particular meaning?
And why is what they meant privileged over what others understand?
you could have a graph of all possible signifieds, without the "intended" signified being special at all. Right now it looks as if the graph terminates at the correct signified for some reason
@vzn : What happens when an astronaut falls into a black hole? He doesn't even make it to the event horizon. It's like Winterberg said. Winterberg was the guy who came up with the idea for GPS, he's no joker. The astronaut is destroyed and turns into a gamma-ray burst. I am confident that Winterberg is right, and 't Hooft is not.
@JohnDuffield lol if humans want to destroy themselves in space all they have to do is get sucked out of the airlock just like what happened to the traitorous spy in the last gerard butler movie last summer geostorm :P imdb.com/title/tt1981128
@vzn : the point is that light curves because the speed of light is spatially variable. That's what Einstein said. That's why optical clocks go slower when they're lower. That's why your pencil falls down. And when you drop it into a black hole, it falls faster and faster and faster, through space where the speed of light is getting slower and slower and slower. Something has got to give.
@BernardoMeurer But in such cases, it's hard to see how anyone trying to understand a statement is supposed to ever generate that signified in the graph to begin with. Do all statements always have "all possible" (whatever that means) signifieds in their graphs?
@JohnDuffield let me try to cook up an analogy. think some of the terminology problems are related to this. imagine a fluid with varying density regions. now someone is trying to "describe" those density variations. now is the observer himself inside or outside the fluid? you seem to have an outside of fluid pov. but maybe physics is still using an inside of fluid pov descr. but maybe theres not much difference mathematically as ACM once pointed out in comment (cf earlier)...
@ACuriousMind Well, yes, for any statement you make, someone (omniscient) could produce a graph with all the possible signifieds. You might only be able to produce those which your contextual knowledge allow
And even the originator (of the sentence) might not be able to construct his true signified, maybe he doesn't know it consciently
@BernardoMeurer Well, I mean, won't the omniscient version simply include all signifieds. I.e. the omniscient graph always has the same nodes and they just differ in their connection? The interesting part here is the construction of the graph more than finding a way through it, imo.
So maybe I tell Ryan I love him, and I think the master signified of that is a true feeling, but in reality i subconsciently just want his money or w/e
But yes, currently my main problem with saying that "understanding" is finding the route through that graph is where the graph comes from in the first place.
@vzn : my pov is that the photon is a soliton wave in space, we can make an electron and a positron out of photons in gamma-gamma pair production, and we have hard scientific evidence of the wave nature of matter. So the electron is a wave in space, and the observer is more of the same. The difference is that people like 't Hooft think you can dive into a black hole and emerge in some parallel universe. Whilst I think there's a BOOM and you're just a gamma-ray burst.
@JohnDuffield we may have similar picture/ pov, but havent thought about black holes that much except like a highest-possible-density area in a space fluid, maybe something like what youre sketching out (where "speed" is inversely related to density). it appears to me photons are like solitons but are spherical and expanding, not spatially localized like solitons. (have been talking about solitons in here/ elsewhere for ages, still not much reaction so far...)
@BernardoMeurer Although I approve of the usage of "virtual" likening it to Feynman diagrams - where do these intermediate signifieds come from? How do you determine how far they are from the originator's actual imtermediate signifieds?
@vzn : IMHO a photon isn't spherical and expanding. And it isn't spatially localized either. IMHO the best analogy for a photon is a seismic S-wave. But whatever you think of it, it has a wave nature, so do buckyballs, and so do you.
1. I don't know, I've been thinking about it. I think the virtual signifieds come from the originator's thought process in the production of the sentence, but I haven't been able to formalize it yet. So, right now, they come from the originator's thinking that generates s
@JohnDuffield yes exactly. p-waves/ s-waves are a form of matter "polarization"... its so bizarre that there seems to be no physicists describing the analogy! re photons, think you will have to revise that. (have a fairly simple experiment in mind.)
2. I don't know how to do it properly yet. Right now I'm modeling it as a boolean distance, where there's a cost of 1 if the virtual signified is not the originator's and 0 otherwise
I'm just thinking that generating the tree on the part of someone trying to understand the sentence seems even harder than finding the correct path through it, i.e. "most" of the effort of understanding in your model would be in that generation.
@vzn : IMHO this physicsFAQ article is worth a read. Note the general relativity section. The speed of light at the ceiling is greater than the speed of light at the floor. So the ascending photon speeds up. In a very strong gravitational field, it speeds up more.
@JohnDuffield nice article but could use more eqns & diagrams. a key idea is that "reference frames" are similar to coordinate systems. etc and the whole theory is about 3d linear/ nonlinear translations etc... actually have found a very nice analogy that others have missed. speed of sound in gases
@vzn : Compare and contrast with what some highly-regarded authors say: "We may think of C as being in such a strong gravitational field that even the ‘outgoing’ light rays from it are dragged back". In a very strong gravitational field the ascending light beam speeds up more. It doesn't get dragged back.
@ACuriousMind I guess an interesting point too is that even if you're capable of constructing a graph with all the virtual signifieds needed for understanding the originator, doing so is still extremely hard
@vzn "etc."? What is this et cetera that no one but you and JohnDuffield have access to? Stop weaseling around and write down a single equation substantiating any of the claims you made.
@vzn : the crucial point is that a black hole is a place where the speed of the wave is zero. Einstein thought a black hole could therefore never form, but he forgot about hailstones. They form from the inside out. That's what Winterberg said about black holes. You're a water molecule, and you can't pass through the surface of the hailstone. But you can alight upon the surface and get buried by other water molecules. So the surface can pass though you.
@JohnDuffield am not familiar with einsteins ideas on black holes but its not surprising they need revision lol ... anyway think avoiding ref to speed (which is intra-fluid) and thinking more about density (extra fluid) may actually be helpful.
@0celo7 did you look at wikipedia? have you ever seen a typewriter? or ticker tape? they existed when Turing came up with the idea & think probably nearly inspired it... en.wikipedia.org/wiki/Turing_machine
@WilliamBulmer : the way the electromagnetic stress tensor resembles the continuum-mechanics Cauchy stress tensor. And the way the expression for the speed of a shear wave in a solid c = √(G/ρ) resembles c = 1/√(ε0μ0). The reciprocal is there because permittivity is a "how-easy" measure rather than a "how-hard" measure.
We all know that, for a test particle (classical) in a gravitational field, the motion is only determined by the geodesic lines
Actually, that isn't quite right. The geodesic lines don't actually exist in any objective sense. They're abstract things that are used to model particle motion, but's ...
@SirCumference It is...both. Just like a matrix can be seen both as a linear transformation and a "vector of vectors", so a tensor is both a kind of linear map and a "vector of vectors of .... vectors"
For instance, you can say that a 4-tensor consisting of components $T^{abcd}$ is a vector of vectors of vectors of vectors by parsing it like $(((T^a)^b)^c)^d$, and also that it is a (multi-)linear map in four arguments by interpreting it as the map $V\times V\times V\times V\to \mathbb{R}, (v,w,x,y)\mapsto T^{abcd}v_a w_b x_c y_d$.