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5:01 PM
Hello! Can anybody explain how the second last equation converted to the last equation. Which trigonometric equation did they use . Thank you!!!
 
@Mesentery $\tan = \cos / \sin$
Err
$\sin / \cos$
 
cot=cos/sin tho
iirc
 
True
Hm
Might be a typo
Would make more sense with $\cos$
But then...
Where does $\pi / n$ come from
 
from the front of the equation
 
well it's $/ pi/n$ which is $n/pi$ which comes earlier.
 
5:14 PM
yeah but it's $n^2 / \pi^2$
Not its inverse
Oh, I didn't see the division
So yeah it may just be $\cos$?
 
horrible typesetting!
 
it is a bit crass to put a division in a fraction
 
cos would make sense but isn't there an extra pi/n cause it's squared
that doesn't really fit in?
 
No, there's two $n$'s in the other formula
so it's all good
and two pi's
 
ahh yeah my bad
 
5:16 PM
If I were you I'd check the same problem on some other site or book, just in case
or check erratas of that book for typos
 
I don't know anything about the topic but to me it seems like a weird simplification - if a simplification at all...
Then again that's sometimes a physics thing to do innit
 
Well.... Thanks @Slereah and @CooperCape. Let me try my luck in math.SE
 
(I feel like I didn't add much but good luck :) )
 
Anonymous
@Mesentery There's really not much to this :P Just check for $n\to\infty$. If you get the magnetic field at $0$, then the book has a typo.
 
Anonymous
Glancing at the last line, that seems to be the case
 
Anonymous
5:24 PM
Also in the second last line there is a $\sin$, but in the last line there is a $\sin^2$
 
Anonymous
The $\tan$ remaining unchanged
 
@Slereah I don't understand your affine gravity question anyhow
 
@Blue Yeah it seems to imply that $\sin=\sin^2$
 
do u not
 
I don't know what affine gravity is
 
5:25 PM
Affine gravity is GR with a general connection
 
but...why?
 
why not
The connection is like
 
@Slereah Anyhow it's a well known result that geodesics are length minimizing only for the Levi-Civita connection
 
$$\Gamma _{\mu \nu \alpha }=\{{\mu \nu \alpha }\}+S_{\mu \nu \alpha }+{\frac {1}{2}}C_{\mu \nu \alpha } $$
 
in fact, if another connection has the same geodesics, it's projectively related
 
5:27 PM
Yes, but in this case
How do point particles move
 
you need to ask yourself why the Nambu-Goto action should still be the action
 
Along geodesics, or along the critical point of the Nambu-Goto action
Yes, but
In this case
What's the proper action to use
 
well, that's the question, but it wasn't clear to me that's what you're asking
I don't know enough (anything) about affine gravity, so I can't give an answer
 
Although...
 
it doesn't seem clear to me that there would even be a "right" answer because this isn't actual physics
 
5:29 PM
Does the non-metricity part of the connection have a symmetric part
 
@Slereah I've gotta go, but just remember that if you vary the NG action, regardless of what connection you "think" you have, the critical points will be geodesics with respect to the unique Levi-Civita connection associated to the metric.
 
I'm not sure
I know!
That is the issue
It's not like Nambu-Goto even depends on the connection
 
So why would the other connection matter at all? Are you asking what action you need such that the critical points are geodesics of it?
@Slereah It (the NG action) depends on the metric, and the LC connection depends only on the metric.
 
Either that or if there's a motivation for point particles to not follow geodesics in such a theory
Basically what is the proper action to use in affine gravity
 
Why should point particles follow geodesics in GR? Equivalence principle?
@Slereah you need to reformulate your question and ask that, then.
 
5:32 PM
Maybe!
Also if you add a term that depends on the connection in the action, the backreaction will change
and that may be an issue too
Point particles may not generate Schwarzschild solutions
(or the ultraboost garbage solution for null curves)
Hm, I wonder what's the metric generated by a spacelike curve with NG
 
@Slereah what
 
Point particles follow geodesics because GR is special relativity locally
 
@0celo7 The NG action as a source terms gives the Schwarschild metric
@bolbteppa Is that true for a non-metric connection, though
I guess that may be an issue with the equivalence principle
there's that weird thing where particle rest mass can change if the connection isn't metric
 
What does that mean, you have spacetime and you have a worldline, the action is the extremal of the arc length
 
@bolbteppa But if the connection isn't metric, the extremal of the arc length isn't a geodesic
 
@Slereah What is your motivation for affine gravity? You're throwing away the EP (else you'd get GR), so what is the actual guiding principle?
 
How do people set up special relativity without being able to set up arc length
 
@0celo7 I'm not sure
 
Anonymous
@Mesentery What ?
 
I should look up some paper on affine gravity
See if there's a motivation behind it
other than "let's try to make the connection general"
 
5:38 PM
I guess this is a motivation to try to read Kobayashi to see if SR can be set up with this stuff
 
I'm guessing the answer is "maybe if we squeeze hard enough we'll get quantum gravity out of it"
it's the motivation of a lot of weird GR alternatives
 
@blue that's what they said in math.SE although I didn't understand any of it. So maybe the book is right
 
You should probably set up weird SR first so that weird GR can reduce to it
 
"Metric-affine gravitation theory straightforwardly comes from gauge gravitation theory where a general linear connection plays the role of a gauge field."
I guess that's probably the motivation
 
@Mesentery there is likely a typo in the second equation, it has one more factor of $\sin(\pi/n)$ than the bottom one
 
5:42 PM
Let's investigate
"The vain effort so far to quantize gravity is, perhaps, the strongest piece of evidence for going beyond a geometry which is dominated by the classical distance concept"
I KNEW IT
 
@Mesentery other than that, it's just the trivial identity $\displaystyle \tan(x)\equiv \frac{1}{\cot(x)}$, which comes directly from the definitions of tan and cot
 
Let's squeeze that manifold for all the quantum
That paper seems a bit weird
 
@EmilioPisanty Ah! Thanks! Got it. You mean that there is one sin pi/n more in the last equation. Or maybe it should be cos pi/n instead of cot pi/n
 
@Mesentery precisely. as to how you might fix it - there's an infinite number of options, all of which depend on the context.
@hbar QFTers
0
Q: What is a gauge field exactly w.r.t. a gauge theory (QFT)

user176549It is not really clear to me, what the term "gauge field" really encompasses. To illustrate this with an example, consider QED: I'm familiar with the canonical quantisation of the QED Lagrangian (Lorentz + Gupta-Bleuler formalism). I also know about the Gauge symmetry $A_\mu \rightarrow \ A_\mu+\...

duplicate?
@ACuriousMind @Qmechanic
 
5:58 PM
What the hell is this symbol
For the connection
Is it a Jesus fish
 
@Slereah the $(\!\!)$ thing?
definitely nonstandard
 
yes
 
not a Jesus fish though
vertical, symmetric
it made it to the journal version, though, surprisingly enough
I agree that it's ridiculous
to quote Michael Berry,
> To emphasize the importance of notation, Robert Dingle in his graduate lectures in theoretical physics at the University of St. Andrews in Scotland would occasionally replace the letters representing variables by nameless invented squiggles, thereby inducing instant incomprehensibility.
 
he should use emojis
 
> Extending this one level higher, to the names of functions, just imagine how much confusion the physicist John Doe would cause if he insisted on replacing $\sin x$ by $\mathrm{doe}(x)$, even with a definition helpfully provided at the start of each paper.
I've been tempted to do this ever since
 
6:05 PM
$\mathfrak{Pisanty}(x)$
 
@Slereah oh, hell, no
 
$x(x)$
 
Fraktur can go burn in Hell
what's with that B-like $\mathfrak P$?
also, on that note
c'mon, Physics Today
what do we pay you for
you've typeset the $x$ in $\mathrm{doe}(x)$ correctly
was $\sin x$ so hard?
 
6:28 PM
"Additionally, one can easily argue that within a metric-affine setting the Einstein–Hilbert form of the action is not necessarily well motivated anyway: under the assumption that the connection is the Christoffel symbol of the metric, the Einstein–Hilbert action is indeed the unique diffeomorphism invariant action which leads to second order field equations (modulo topological terms and total divergences).
However, this is not the case if the connection is allowed to be independent and it is not assumed to be symmetric: in this case there are other invariants one should in principle includ
 
@EmilioPisanty dat typesetting doe
as the hip kids say nowadays
 
is that a hip kid
 
dat doe doe
 
 
6:39 PM
dat doe doe doe
 
No, this is a hip kid
 
totally worth the time
 
doe of x?
 
hmmmm
$$\LARGE 🦌(x)?$$
2
huh, not on this font, it seems
my phone does display it, though
but it's a deer, not a doe
 
:o
lotta fake does in 2018
 
6:48 PM
I prefer $$\large{\hat ☎^{-1}}$$
 
ringring
 
Hm, seems the telephone doesn't scale
 
$$\large{☎️^{+---}}$$
puts down headset harshly
 
@Slereah Christian Geometry.
 
$$\large{\textcolor{blue}{{{{}^o}^o}^o🐋}}$$
those were supposed to be water bubbles
 
6:53 PM
beautiful
 
shit
i should have just used color
:'(
 
@Slereah ugh what’s the chance people remember the definition of the Hodge star
 
$$\large{\color{cyan}{{{{}^o}^o}^o🐋}}$$
2
 
I'm not 100% sure I remember it off the top
 
@ooolb beautiful
10/10
 
6:54 PM
thanks
 
Except for "apply a big old Levi-civita tensor to it"
bc I'm a physicist
 
@Slereah that’s basically it.
 
Well I know how much you hate coordinates :p
Ah, there it is
$\alpha \wedge (\star \beta) = \langle \alpha, \beta \rangle \omega$
 
Hmm, does the Hodge star require an orientation?
 
$$\large{{}^{🐟}🐋}$$
the whale is eating a fishy
or about to
gtg bye guys
 
7:00 PM
@0celo7 it requires a volume form
so yes
volume form induces orientation
 
@ooolb cyan doesn't read very well
$$\Huge{\color{blue}{{{{}^o}^o}^o🐋}}$$
 
$$\Huge{\color{blue}{{{{}^o}^o}^o🐋}}$$
those look pretty similar in size
$${}^{\tiny{🐋}} 🍽️ \Huge{🐟}$$
hmmmm
 
@0celo7 How else do you get the big levi civitta
 
7:50 PM
@Slereah write the symbols and pray no one is paying too much attention
(I’m learning the physicist tricks)
 
I guess you can do the hodge star up to a sign if it's not orientable
Is there a generalization of line elements for tensors
Where you identify $T$ and $-T$
 
8:13 PM
@Slereah have you found something on affine grav
@ACuriousMind what's the name for something satisfying $a^2=1$?
not idempotent
 
@0celo7 found this : xxx.lanl.gov/pdf/1008.0171v3
 
9:18 PM
Hi, everybody.
 
ola
 
@Slereah and what is the conclusion?
 
Why does a point particle break boost and translation invariance?
 
9:34 PM
when the structure constants of a Lie algebra become nonconstants, what harm will be arisen?
 
9:45 PM
@Slereah what's the significance of the DEC?
 
@0celo7 To not have stupid matter propagation
There's the whole theorem on how DEC matter's influence doesn't leave the light cone or something
 
hmm, right
isn't that in straumann
 
@apt45 Here's how it breaks translation invariance : if you move away from the particle, the particle is at a different distance now
@0celo7 It's in HE at least
 
@Slereah So, why do we care about Lorentz invariance? Is just the vacuum Lorentz invariant? I am a bit confused
 
what
Yes, only the vacuum is Lorentz invariant
It's the definition of the vacuum
QFT isn't Lorentz invariant, it's Lorentz covariant
The laws are Lorentz invariant, but initial conditions may not be
 
9:50 PM
3.10 in Straumann
 
so, given a state $|\psi\rangle$ and a symmetry, this state transforms in a given representation of the symmetry. If I have a point particle state in $x^\mu$, let's say $|\psi(x)\rangle$, we said this breaks boosts (and then Lorentz). But, we know this states transforms accordingly to Lorentz, doesn't?
 
yes
Well, to be precise
 
ugh, the horror
 
There's a unitary representation of the Lorentz group that acts on the state
 
But we said lorentz is explicitly broken;
 
9:55 PM
trying to do GR without coordinates
$T^\mu{}_\nu \xi^\nu$ becomes $T(\cdot,\xi)^\sharp$
 
The state isn't Lorentz invariant, yeah
On the other hand, momentum eigenvectors do have a symmetry group
Called the little group
Which is interesting to know about
 
@Slereah where's the list of energy conditions
I know you have one
 
yes, I know
 
wtf?
 
@0celo7 There's a bunch of papers about them
I think Visser has one
How many do you need
 
9:57 PM
I know I will be grilled on what DEC means
it's kind of a strange thing to demand
I wonder if something weaker gives me what I want
 
The DEC implies like
Almost every other energy condition
It's a pretty strong one
Except the SEC and the SDEC
(Without going into the weird energy conditions, at least)
@0celo7 the hell kind of bundle is $VY$ for a manifold $Y$
 
vertical subbundle of the tangent bundle, most likely
 
Oh yeah
 
er
of the double tangent bundle
geometry is too hard
 
that it is
Let's just go into sociology
 
10:17 PM
@Slereah I can't even remember how to define Lorentzian metrics
what the hell is a signature
 
Eigenvalues of the metric?
 
the signature of $g_{\mu\nu}(p)$ is num(pos evs) - num(neg evs)?
 
yeah that's usually how it's defined
 
I'm expecting at least two people to not know this stuff
most should though
 
Hamiltonian is apparently applying the ~Legendre morphism~ to the Lagrangian density
$$\hat L : J^1 Y \to \bigwedge^n T^*X \otimes_Y TX \otimes_Y V^* Y$$
 
10:21 PM
lol
so Christo Doulou only does nonconstrained stuff, which is...strange considering GR and EM are both constrained
 
$$H = p^\lambda_i dy^i \wedge \omega_\lambda - p_i^\lambda \Gamma^i_\lambda \omega - \mathcal H_\Gamma \omega$$
What
 
what's that supposed to be
 
The Hamiltonian
First terp is $\pi \dot \phi$ I suppose
Also he never seems to talk about like a foliation or anything, which is weird
 
what is $\omega$
@Slereah what are you reading
 
10:28 PM
oh, field theory of sections
this is in Christo
I think it's slightly more palatable
 
I guess I'll download Christo
Question is, where the hell does the foliation come in
 
"Given a Lagarngian density"
 
What happens if you look at a Hamiltonian on some non-globally hyperbolic manifold
 
spell check?
@Slereah that's an evil question
 
I'm not even 100% sure if there's a time involved at all in this formulation
For all I know you could do it on any manifold
 
10:31 PM
this is how Christo does things then
honestly I find this stuff very hard to read
maybe someone who lives and breathes bundles can parse it easier
 
I'm already not even sure what the velocity space is and I'm on page 1
 
@Slereah if you look on there seems to be way more details
I think the first bit is the goal of the lectures, it seems more sane later on
 
Is it just the space of $n \times m$ matrices from the tangent space of $M$ to $N$?
Also what does that correspond to
 
I'm familiar with the velocity space being Hom(TM,TN), but this is for bundles which I don't know about yet
oh are you talking about Christo?
 
yes
What does that correspond to for like
 
10:35 PM
an element of $\mathcal V$ is indeed a linear operator $T_pM\to T_qN$
 
One particle Lagrangian
 
ugh
so for a point particle you have $M=\Bbb R$ and $N=\Bbb R^3$
 
Why $\Bbb R$?
 
because you're looking at a theory of maps $u:M\to N$
 
isn't the configuration space the position and velocity
Oh
So time and position
 
10:37 PM
for instance
 
So the velocity is just maps... $\Bbb R \to \Bbb R^3$?
which I guess is $\dot x(t)$
 
well there's of course the meme that $T_x\Bbb R=\Bbb R$
 
Is it not
 
it is
 
Phew
So far so good
 
10:39 PM
so $\dot x(t)$ is really a differential operator at $t$
but it can just as easily be represented by a number
this choice is not canonical and thinking about it gives me a headache
 
I guess for field theory it's gonna be $\mathcal M$ and $J^1 Y$
 
no, the formalism for sections of fibrations is different
 
then what's all this garbage for
 
oh also I think Christo only does vector bundles which might be easier
 
Isn't there already a perfectly fine tangent bundle fort that
 
10:42 PM
@Slereah fluid mechanics is not a bundle thing
 
Damn fluids
 
damn GR too
 
The problem with Legendre bundles is that only math people seem to do it
And as they are insane they don't seem to think time is important for Hamiltonian mechanics
 
I think this is the part of math that only physicists do, actually.
What use would it have in mathematics?
 
Who knows
Does any math have any use
Also is GR on $J^1 Y$ or $J^2 Y$
It has second derivatives
Should be like $J^2 O\mathcal M$
jom jom jom
 
10:51 PM
I don't knoooow
 
Except the configuration space isn't that because of the constraints and help why is physics so bad
 
don't worry buddy I'm struggling too
I want to go back to math but I have this blasted physics talk
this is what I get for telling people I know physics
 
Wouldn't $J^1 T^1_1 \mathcal M$ be the weird 56 dimensional bundle of what's his name
or close to it, anyway
 
not so fast
 
Hm, this paper says that matter fields are of the form $(P \times V) / G$
 
10:57 PM
you want the subbundle of the symmetric 2-bundle of Lorentz metrics
@Slereah associated bundle?
 
yeah
And the gauge fields are $J^1P/G$
Why does the gauge field have the jets but not the matter field
 
ask ACM
 
@ACuriousMind halp
 
actually I bet Qmechanic would know
 

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