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15:00
Unless someone with specific experience tells you otherwise, you're most likely to be better served by putting the focal plane at the middle of the crystal
I don't know if any of this points towards anything useful in analyzing our cognitive reasoning or just a fancy theoretical observation
But in general understanding the topology of a given set of data points is a classic problem
(There are applications in machine learning; one of the simplest thing is thumbprint recognition)
Anonymous
I have heard about the applications in machine learning
Anonymous
also data analysis
@EmilioPisanty i just mean taking the original laser beam and collimating - i'm not doing it after the crystals or anything.
or by re-collimating do you mean something else?
vzn
vzn
@heather there are a lot of cheap laser pointers out now, can even buy em in toy stores. used a few myself once in experiment. they come with lenses. wonder if any might work with BBO. not sure what wavelengths they are but thats the main question. ps did you see my writeup of undergrad bell experiments? has 2 parts/ supply lists. vzn1.wordpress.com/2017/09/08/…
15:09
@vzn yeah, I found a ~$40 one on digikey that is the appropriate wavelength/power/etc
vzn
vzn
@heather right, saw that, looks cool, but without lens, complicating it, therefore suggest at least looking into whether "off the shelf" laser pointers could possibly work with BBO... lasers tend to be made out of a "few" different sources...
sure.
vzn
vzn
its up to you if you want to learn/ add optics for fun, its certainly worthwhile, but for me think it could be some complication & maybe simplification is possible...
@BalarkaSen did you see this?
thoug the sax is misssing
15:13
reminds me of granday's darude sandstorm remix :P
gta5 is such a big meme
well, i can tell you i'm already reading some about optics just to figure out what i'm doing.
grandayy is awesome
i can't say i'm studying it very methodically though.
his soviet anthems....
are really patriotic
vzn
vzn
15:15
@heather where did you get the 405nm req from?
i think grandayy is a french guy
since you mentioned it, it does seem like it
the cartoon mascot looks very french
@vzn 405 nm both seems to be fairly commonly used in spdc experiments and it's a common laser diode wavelength, meaning it will be cheaper. i think there were some other things that contributed to the choice, but i can't remember them from off the top of my head.
vzn
vzn
this wikipedia article on BBO seems to indicate the birefringence starts at ~409.6nm? is that right? en.m.wikipedia.org/wiki/Barium_borate
> Barium borate has strong negative uniaxial birefringence and can be phase-matched for type I (ooe) second-harmonic generation from 409.6 to 3500 nm.
speaking of USSR memes, you know the hard bass meme, surely? @Prathyush
15:19
why has this chat become meme central
just curious
@BalarkaSen do you meme up the math chat?
no but a bunch of the math guys, including meme, have a discord server which is pretty much literally memes
including me lol
Freud on the loose there
sigh
ok
vzn
vzn
@heather interesting, 405nm is "blue ray"/ violet laser pointer became available in ~2010. note a wide variety of wavelengths are available now. en.wikipedia.org/wiki/Laser_pointer
@vzn not sure - i'll have to look at it
What will happen to an object moving straight up at less than escape speed?
15:33
it wont escape
thats what i thought but i thought it would also
deaccelerate
yes
the object wont be able to escape and start going in the other direction
absolutely
but if moving at more than escape speed
then it'll just escape?
15:35
yes
does anyone want to play chess
just click the link
@vzn the paper i posted above seems to be an experiment using 405nm light with BBO crystals for type I spdc
see for example fig 1b, pg 5
ah @vzn i think i figured out the difference.
> Barium borate has strong negative uniaxial birefringence and can be phase-matched for type I (ooe) second-harmonic generation from 409.6 to 3500 nm
(bolding mine)
second-harmonic generation and spdc are two different processes.
so i think i'm good with a 405 nm laser.
vzn
vzn
@heather some very nice/ high finesse optimization/ finetuning/ efficiency work but find it hard to follow, all the terminology without much diagrams. they are excited about BiBO.
i have to go for now
vzn
vzn
> Nevertheless, while biaxial crystals such as BiBO may appear to be a better source material, their lack of the rotational symmetry present in traditionally used uniaxial crystals can significantly complicate the compensation techniques presented here...
@heather not an expert on this but iiuc the 1st harmonic & 2nd harmonic are simply referring to the 2 outgoing rays, ie the birefringence.
15:52
2
Q: Problems with tag notes

TheEnvironmentalistOn the physics tags page, the tags mathematical-physics and mathematics are described as "Just because your question involves math!..." whereas on the actual pages for the tags, the descriptions of both begin, "DO NOT USE THIS TAG just because your question involves math!" I would have to ass...

By what factor would a person’s weight be increased if Earth had 10 times its present mass, but the same volume?
@Brogrammer you should be able to answer that. What is the equation for the gravitational force? Hint: Newton's law of gravity
F=gm1m2/r^2
i meant big G
Correct!
why is the volume mentioned tho
anyways
15:57
If the volume stays the same that must mean the radius of the Earth stays the same ...
o
so is it 10 times as much then
@Brogrammer Yes. It is as simple as that.
i wasnt sure if that was a trick question
but apparently its that simple
vzn
vzn
@ACuriousMind ok afraid of that. confused because wikipedia article mentioned birefringence/ 2nd harmonic generation in same sentence :| ... so (n00b question) in SPDC are both signal/ idler photons same wavelength?
16:03
In 1996, astronomers discovered an icy object beyond Pluto that was given the
Designation 1996 TL 66. It has a semimajor axis of 84 AU. What is its orbital period according to Kepler’s third law?
kepler's third law ik says
the square of a planet orbital period is directly proportional to the cube of the average distance of the planet from the sun. Based on the rule, we can say the orbital period
well idk what 84 au is
and how i can apply to the formula
but it says semimajor axis
so im assuming thats the radius
vzn
vzn
(seems like wikipedia could be more clear on that) en.wikipedia.org/wiki/Spontaneous_parametric_down-conversion#
@JohnRennie can you recommend good value/money PC speakers?
It depends what you want. On my desk computer I use a TV soundbar and that works really well. On my living room computer I have proper hifi speakers going through a proper hifi amp and that's on another level again.
Is it just for gaming and listening to YouTube videos?
can someone tell me if my answer is correct
i got around 756 years
for the orbital period
@JohnRennie yeah
my monitor's built in speakers can't beat the jet engines on my 1080
16:17
How much do you want to spend?
ideally nothing
can I be one of your charity cases?
jk, idk how much these things cost
Sid
Sid
Why don't you simply plug in ear phones to your computer and listen?
@Sid It's nicer using speakers
@Sid don't want to mess up my hair
Sid
Sid
16:21
Maybe, it's just me but I feel earphones are clearer. Speakers tend to become disturbances for others..
And someone stole my earbuds
@JohnRennie do I have enough room? gyazo.com/6e865b0e1ebab4432fc0ac3f052c3f41
I like to put my keyboard up under the good monitor when writing on paper
So I can't have anything else there
It would be a bit tight for space. I don't think the soundbar I linked would fit.
I can't really advise you as I don't know much about PC sound.
I would just Google PC speaker reviews and buy whatever has got a reasonable review.
16:59
@BalarkaSen The one in which russians stomp to the badass song? Why wouldn't i have heard of it:P
^@BalarkaSen what do you think of this?
17:26
@JohnRennie my pagefile usage was 26GB
I don't know what that means but it can't be anything good
17:59
Hey guys I have a silly question about a passage i don't understand, can someone help me with it? I have this

$(exp \{ -i \omega_{\mu \nu} \Sigma^{\mu, \nu}\} )^{\dagger} = exp \{ +i \omega_{\mu \nu} (\Sigma^{\mu, \nu}) ^{\dagger} \} $

while, since $\omega_{\mu \nu}$ is a real and antisymmetric object I think it should be
$(exp \{ -i \omega_{\mu \nu} \Sigma^{\mu, \nu} \})^{\dagger} = exp \{ +i (\Sigma^{\mu, \nu}) ^{\dagger} (\omega_{\mu \nu})^{\dagger} \} = exp \{ +i (\Sigma^{\mu, \nu}) ^{\dagger} (\omega_{\nu \mu}) \}) = exp \{ -i (\Sigma^{\mu, \nu})^{\dagger} \omega_{\mu \nu} \})$
I posted here cause I thought it wasn't good to open a question in the main site about this computation
aren't the $\omega_{\mu\nu}$s just numbers?
so why would you $\dagger$ them
but the whole thing is a matrix
$\Sigma^{\mu\nu}$ are matrices
so $(\omega_{\mu\nu}\Sigma^{\mu\nu})^\dagger=\omega_{\mu\nu}(\Sigma^{\mu\nu} )^\dagger $
18:02
ok, for each value of the indexes Sigma is a matrix
oh come on mathjax
@Runlikehell yeah, so?
just look what I wrote
$\omega_{\mu\nu}\Sigma^{\mu\nu}$ is a linear combination of matrices, so you dagger the matrices
yeah I considered the $\omega$ as matrices, you pointed it out they were just numbers , thanks. God I lost like 20 minutes on that and other 10 minutes to ask the question here in latex...
But thanks, at least I understood my mistake
18:18
> Using the chain rule is like peeling an onion: you have to deal with each layer at a time, and if it is too big you start crying.
- Anonymous professor, as per 3Blue1Brown's video on the chain rule
Sid
Sid
@heather that is....one of the best things ever said of the chain rule...
@heather I don't like this analogy. You just deal with each layer at a time, but it doesn't really make you cry. He's just trying to give an analogy when none is needed, lol.
@Jasper not really an analogy; more of a joke quote =) 3blue1brown includes a quote at the beginning of most of his videos.
18:43
@Balarka oh please no. But I'll watch it because you shared it
0
Q: What if what we observe through telescopes is phase space

bvsnRather than real space as we know it, what if what we observe in space is actually the phase space and not the underlying actual action?

Huh?
@LeakyNun is it not?
@Abcd watch the video lol
OK
19:00
22
Q: Redshifting of Light and the expansion of the universe

QEntanglementSo I have learned in class that light can get red-shifted as it travels through space. As I understand it, space itself expands and stretches out the wavelength of the light. This results in the light having a lower frequency which equates to lowering its energy. My question is, where does the e...

@JohnRennie nice
@LeakyNun You study physics too?
@Abcd I don't
@LeakyNun Which subjects do you study? Only maths?
@Abcd right
19:10
@LeakyNun But you know programming also if I am not wrong.
doesn't mean I study it in uni
Ohkay.
 
2 hours later…
vzn
vzn
21:01
↑ o_O possible achilles heel?
21:40
@ACuriousMind if I had to attribute a name to the sheafy de Rham theorem, whose would it be?
::does a dance:: yes, yes, yes!
it'll still need tons more work, but i've got a terribly written program that can handle multiple qubits in some cases
and i am happy.
21:57
@heather ::chuckles:: The 'it's kinda working' dance is even more excited than the 'it finally compiles' dance.
A program to handle qubits? Can I inquire how / why / anything about it tbh, sounds interesting. Can you compile it without a Quantum Computer?
@Phase yeah, you can compile it without a quantum computer (if you couldn't I'd be screwed ;)
^code for project
one moment, let me push the code i've got to the repo
Oh
So its like cnot gates etc?
erm...not cnot gates yet
just single qubit gates
but they work on multiple qubits =P
i know, it's kind of stupid right now.
i just pushed the new code.
@dmckee yeah =)
I haven't really looked into Quantum Computing much but wouldnt you need to take the tensor product of two operators if you're operating on two states at once?
22:03
if anyone feels like taking a look at my question on SO, i'd appreciate it - stackoverflow.com/questions/46269261/…
@Phase basically, yeah
and i did
Oh nice, haven't looked through just checking if my very mundane knowledge is even right
you use the kronecker product
so if i wanted to apply the hadamard gate to the first qubit of two, i'd do $I\otimes H$
oh, whoops
no, $H\otimes I$
if i wanted to apply the hadamard gate to the second qubit of two, i'd do $I\otimes H$.
and if to both, $H \otimes H$
Although tbh idk what a Hadamard gate is RIP
$H =\frac{1}{\sqrt{2}} \begin{bmatrix}1&1\\1&-1\end{bmatrix}$
@JohnRennie is it wise to run GPU benchmarks to heat up the PC and turn it into a foot warmer?
22:49
@heather Too much code ;-) When I have something like that where I can't identify where the error is coming from, I'll aggressively trim out parts of the program (starting with those least likely to be related) until I narrow it down to a small chunk that reproduces the error.
@DavidZ heh, yeah. thankfully someone was able to point out it was a persnickety float vs int thing.
weirdest thing was that it came up only when i scaled up, even though it was part of a function that had been there all along...
Yeah, I guess it might be related to some Numpy optimization or something...
Is a direct sum just like a geometric inverse of a projection?
23:40
@BernardoMeurer turning my desktop into a potato:
23:53
@0ßelö7 Wow, you have so many computers!
He managed to install proprietary malware into Linux
@BernardoMeurer Is it always a good idea to turn on GPU acceleration in your browser or other apps?
@Jasper Generally yes

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