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12:00 PM
wat
 
There's a weird limit of quantum gravity
 
@0celouvskyopoulo7 Not much that I'd remember
 
The Schrödinger-Newton equation
$$i\hbar \partial_t \Psi = -\hbar^2 \frac{\Delta \Psi}{2m} - Gm^2 \int d^3x' \frac{\rho}{|x - x'|} \Psi $$
"In quantum equilibrium, the theories reproduce the predictions of the regularized quantum theory."
what about not at equilibrium D:
 
12:17 PM
@AlbertEinstein hi
 
user228700
@Kenshin: Yo :-P
 
hello @Kaumudi.H
how r u
 
user228700
@Kenshin I'm good :-) What about you? How was ur trip?
 
@yashas, how do we find the temperature of vacuum?
 
vacuum isn't really vacuum
there are atoms partying in so-called empty space
 
12:22 PM
@Yashas, [K.E]_av=1/2mc^2
 
o0
where did u get that?
 
I got somewhere in the text that, [K.E]_av=3/2 KT=1\2 mc^2
@yashas
 
did u take photons as the particles dancing through space?
photons don't have temperature
 
@AlbertEinstein What do you mean by "vacuum"?
 
I mean, in the way you are describing, photons do not have temperature
however, bodies with non-zero temperature emit radiation and we can get its temperature by looking at its spectrum
 
12:24 PM
Also, please define your notation - don't expect us to guess what e.g. "K.E._av" means (I can guess the KE part but not the av)
 
Actually my lecturer said that vacuum has temperature and it doesn't have as well
 
@ACuriousMind I think he meant average
 
K.E=kinetic energy

av=average
 
average kinetic energy of a molecule = f/2 kt
I don't know where he got the $c$ from
 
@yashas, c=mean square velocity
 
12:26 PM
.
I took $c$ as the speed of light lol
 
Yeah, soo...what are these formulas you're writing down supposed to be for? Kinetic energy of what, velocity of what?
Please try to write full sentences that communicate your thought process, not just equations where we have to guess what they're supposed to mean. Communication is often much more important than merely writing down a formula.
 
@ACuriousMind, i just wanted to.know if vacuum temperature or not
 
If there are no particles, then there can't be temperature?
 
@ACuriousMind It means "10% of alien mugwumps in interzone are green and made of jelly". Acronyms kids come up with nowadays, y'know.
 
@AlbertEinstein Well, what is "vacuum" for you? The almost-void filled with dust in outer space? The total absence of any particles? The cosmic microwave background?
 
12:29 PM
@ACuriousMind, vacuum is a completely empty space
 
@AlbertEinstein That doesn't have any temperature - there's nothing in it, while temperature clearly is a property of something by definition.
 
Holy crap
Turmeric tea is like paint
 
Never knew that turmeric tea even existed.
 
@Yashas It stains like crazy
Holy cow
 
It has anti-biotic properties :P
 
12:33 PM
@ACuriousMind, then when energy carrying radiations pass through vacuum, don't it get some energy and temperature?
 
well the vacuum is just the vacuum state $\vert 0 \rangle$
which is a pure state
hence it has the perfectly defined temperature of $0K$
 
@AlbertEinstein Well, when there's radiation, it's not vacuum anymore.
Then there's radiation in it, and you can assign a temperature to such a "photon gas".
 
o0
@ACuriousMind So if a source at temperature T emits photons, then the surrounding space is said to be at temperature T?
 
@Yashas Pretty much, yes. Although how useful that notion is of course depends on what you're trying to do
 
you can just define the temperature the same way
the average energy
or just via the thermodynamical definition
 
12:38 PM
The temperature of the vacuum is 3K
@Yashas Yes, why not?
 
We're boiling dude
 
$$T = \frac{\partial E}{\partial S}$$
 
@0celo I constructed bi-invariant metric on compact connected Lie groups yesterday.
 
@0celouvskyopoulo7 The temperature is T everywhere then unless you add or remove particles?
the photons would keep spreading out in all directions from the source
so the temperature is T everywhere?
 
$\partial_t T=-\kappa\nabla^2T$
 
12:40 PM
@BalarkaSen Good!
 
yeah the trip was fantastic @Kaumudi.H
r u done with exams now?
 
they're never going to be done with exams
eternity would pass and the JEE would still be 1 month ahead
 
I was telling people in my lab about JEE...they were horrified and you have their condolences.
 
@Yashas Well, real radiation gets stopped by walls and stuff but if you have a universe with a single source that magically maintains its temperature while having radiated for an infinitely long time, then yes, everywhere is the same temperature :P
 
user228700
@Kenshin Nice! :-)
 
user228700
12:42 PM
No man, I have two more to go.
 
I though Cowsmoothie wasn't taking JEE Advanced.
 
user228700
@0celouvskyopoulo7 And who told u that?
 
user228700
@0celouvskyopoulo7 x'D Nice.
 
user228700
@0celouvskyopoulo7 When?
 
12:44 PM
Apr 27 at 12:12, by Yashas
@Kaumudi.H So you are not registering for JEE Advanced? You can get your parents check your rank and register for you :/
 
user228700
@0celouvskyopoulo7 Well :-|
 
I'm not sure why Bohmian QFT is non-local
the equation of motion of the pilot wave is just a functional version of Klein Gordon
 
@Slereah why don't you stick to GR?
 
i read that as bohemian qft
 
user228700
@0celo: There's another exam anyway. I'm writing that one and that will be the last one I write.
 
12:47 PM
Is it the old "the KG propagator is non zero outside the light cone"?
@0celouvskyopoulo7 I can do many things
 
@Kaumudi.H So I was right about the Advanced?
 
@BalarkaSen Well, there is bohemian gravity...
 
user228700
@0celouvskyopoulo7 Well, yeah.
 
Good.
Never try to bamboozle me again.
 
user228700
Lol, sure.
 
12:48 PM
Glad that you're out of the JEE business
@ACuriousMind The hell is that man
 
user228700
@BalarkaSen Not entirely. The other exam is also a competitive exam.
 
@BalarkaSen It's...a song?
 
yeah but it's not death
 
@Kaumudi.H Are you writing BITSAT on 21st?
 
JEE is death
 
user228700
12:49 PM
Quite competitive at that.
 
@ACuriousMind Why do you know that?
 
user228700
@Yashas No, not on 21st.
 
@0celouvskyopoulo7 Know what?
 
@Kaumudi.H If you top your boards, you can get a direct ticket to BITS.
 
user228700
@BalarkaSen Sometimes, yeah :-/
 
user228700
12:50 PM
@Yashas Dude, I'm a dropper like you.
 
@Kaumudi.H I rewrote all my exams :D
 
@ACuriousMind THis song
 
user228700
I already know my board marks and no, I wasn't 1st in India.
 
user228700
@Yashas Oh, wow, nice! :-)
 
aw
 
user228700
12:51 PM
@Yashas Wow, are u hoping to top?!
 
I am in Open School (homeschooled) and my board consists of students who have failed their high exams 123123 times and those who top JEE.
 
@0celouvskyopoulo7 Uhhhh...because it was quite popular on my social media feeds when it came out? I know a lot of nerds :P
 
and it sucks
people getting 100 in everything
even if I write my math exam 123123 times, I'll make some stupid mistake
 
user228700
Ah, I see...
 
It's hard to be a god, yes.
 
12:52 PM
Who was 1st?
 
user228700
@BalarkaSen Indeed.
 
Is the person who's first some ultra nerd who studies 24/7 or some guy who just does it
 
@0celouvskyopoulo7 ultra nerd
 
user228700
@0celouvskyopoulo7 A girl called Sukriti Gupta topped my board last year, when I wrote it.
 
Even Nobel prize winners cannot get 100/100 in Indian high school exams lol
questions are bad
 
user228700
12:53 PM
99.4%; that was her percentage.
 
Girls always do well in boards
but they do horrible in competitive exams
 
@Yashas Why should they?
 
now the government has introduced 20% reservation for girls in IITs
@0celouvskyopoulo7 That wasn't my point lol
 
I don't see why a Nobel Prize winner should be able to remember organic chemsitry, if they ever had it at all
The indian education system is so strange
 
it's shit man
 
12:55 PM
Let me give an example
 
user228700
@BalarkaSen Again, indeed.
 
The physics textbook has a derivation for finding the max speed of a car on a banked road which considers friction on the road.
There is an example problem where it asks us to find the max speed for minimum wear and tear.
You are expected to plug in coefficient of friction as zero to get the answer.
Here is what I did:
I don't remember formulas. I did the entire derivation assuming that there is no friction.
Got the correct answer
got 1 mark out of 6
because that isn't in the textbook -_______-
 
#getrekd
 
have to derive with friction then substitute f = 0
 
I can't remember any formulas
I don't know the quadratic formula
(that's a lie, I memorized it yesterday for my quantum mechanics final)
I always get the sign of $4ac-b^2$ wrong
or is it $b^2-4ac$?
 
1:00 PM
just derive it
 
@BalarkaSen I don't know how to prove things
 
ah, then you're rekd
 
duh, use dimensional analysis
 
@AccidentalFourierTransform what if there was a constant?
 
1:02 PM
then you take the other derivative
 
?
 
@0celouvskyopoulo7 I only remember the formula for $a=1$, and I also only remember that one because the memory of my math teacher shouting Halbieren, Quadrieren, Negieren dozens of times a day is burnt into my brain forever.
 
I can never remember the trigonometric identities
 
@ACuriousMind See...I never learned the quadratic formula in math class.
 
derive it always ever
 
1:02 PM
I had 4s in math in Germany, maybe we learned it there
In America I got put into stupid people class and we didn't get to it
Then in the next class I was assumed to know it
 
The worst high school math is trig. You have to memorize some identities or keep them at the back of the head or you don't get lightbulbs while solving problems
 
Find the length of the curve: x=10cos^3t, y=10sin^3t :::t€(0,π/2)
 
@BalarkaSen We were given a formula sheet for trig
Still had to memorize the unit circle
@AlbertEinstein No.
 
@AlbertEinstein $\int_a^b \sqrt{\left(\frac{dx}{dt}\right)^2 + \left(\frac{dy}{dt}\right)^2}$
 
38 mins ago, by ACuriousMind
Please try to write full sentences that communicate your thought process, not just equations where we have to guess what they're supposed to mean. Communication is often much more important than merely writing down a formula.
 
lol
 
What on earth is ":::t€(0,n/2)" supposed to mean? Did you just copy-paste that from somewhere and not even bother to look at what it had pasted before posting it?
 
@ACuriousMind I think he meant $t$ belongs to range (0, n/2)
 
@Yashas Why are you doing his googling for him? :P
 
I think the euro is supposed to be $\in$
 
1:08 PM
@Yashas I know what he "meant". I'm exasperated at the lack of effort that went into that message after I asked him to try to communicate better.
 
if Le Pen wins slereah wont be able to use $\in$ ever again
 
@ACuriousMind I wanted to send a proof for that equation but looks like the link I sent does not have it :P
 
@AccidentalFourierTransform lol
 
@BalarkaSen Did you do 2.6 in do Carmo?
 
also, n probably means $\pi$
 
1:09 PM
@Slereah is le pen gonna win?
It's a pi on my screen.
 
no, Merkel is gonna win
 
@0celouvskyopoulo7 prolly not
 
@ACuriousMind Most Indian high school students don't bother to find out why something works.
 
Reminder that the Be Nice policy also applies to people not present.
 
yes, to people
not to demons
 
1:10 PM
Demons are people too
 
most high school proofs of that integral being the length is not quite rigorous either
demons are great. I love cenobites
 
#DemonsLivesMatter
 
@BalarkaSen I was waiting for that :P
 
@0celo 2.6? Let's see
 
1:12 PM
local isometry not being a symmetric relation?
that's pretty much obvious. take an appropriate riemannian covering map
oops no that's 1.6
 
@AccidentalFourierTransform ?
 
@0celo Covariant derivative along the tangent field of a curve is same as usual derivative? That's obvious too. Am I looking at the wrong problem?
@ACuriousMind Really fantastic creatures though.
 
I swear, if this is a setup for some ASCII testicles again...
 
1:17 PM
ASCII what?
am I supposed to know what you're referring to?
 
$\omega$ isn't ASCII
It's unicode
 
22 hours ago, by AccidentalFourierTransform
user image
 
@BalarkaSen Only if you obsessively read this chat's transcript :P
 
@AccidentalFourierTransform What's <|>?
 
@Slereah true enough
 
1:18 PM
an ASCII penis
 
.
 
[Philosophy dump]
Given a subjective experience felt by a person A. A have described the experience in sufficient detail that B,C,D,E etc. is able to cause A to relive the experience when B,C,D,E etc. does things and show it to A. But then, if a subjective experience of one individual is able to be replicated by other people on the same person, is it still subjective?
 
@AccidentalFourierTransform Sometimes, I don't know whether to laugh or to sigh heavily at your antics :P
 
noice
im so proud right now
 
@Secret You know how to cause other people pain - hit them. Does that imply you have any idea of their experience of that pain?
 
1:24 PM
probably not... even though I can replicate the very specific scenario such that they always felt that highly subejctive pain they claimed, I won't be any closer to know what exactly that specific pain felt like
 
The only way to fully communicate the sensory experience of pain is to make a good aim right up to the other person's ...
 
@yashas what is the meaning of thermodynamic system?
 
That's a hard question lol
 
1:28 PM
I'm voting to close that comment as off topic because it shows insufficient prior research.
2
 
too hard :P
 
@yashas why?
 
anything can be a thermodynamic system as far as I know
Wiki says "A thermodynamic system is the material and radiative content of a macroscopic volume in space, that can be adequately described by thermodynamic state variables such as temperature, entropy, internal energy and pressure."
 
Zeroth law of thermodynamic- it states that if two thermodynamic systems are each in... so what is thermodynamic systems here? @yashas
 
That question is too hard to answer.
I lose marks because of these kind of questions.
 
1:31 PM
@yashas, wiki definition is quite complex.
 
Thermodynamics is a branch of physics that studies the movement of heat between different objects. Thermodynamics also studies the change in pressure and volume of objects. A branch of math called statistics is often used in thermodynamics to look at the motion of particles. Thermodynamics is useful because it helps us understand how the world of the very small atoms connects to the large scale world we see everyday. Thermodynamics also has two main branches called classical thermodynamics and statistical thermodynamics. An important idea in thermodynamics is that of a thermodynamic system. An...
 
@AlbertEinstein The system can be anything
You can take two cylinders with two different gases
or you could take two animals
 
> In thermodynamics, a thermodynamic system is defined as that part of the universe that is under consideration. A real or imaginary boundary separates the system from the rest of the universe, which is referred to as the environment or surroundings.
A useful classification of thermodynamic systems is based on the nature of the boundary and the quantities flowing through it, such as matter, energy, work, heat, and entropy. A system can be anything, for example a cylinder, a solution in a test tube, a living organism, or a planet, etc.
 
There is a difference between "too hard" and "too silly".
 
so, periods and commas inside the quotation marks or not?
bear in my that I hold strong opinions about that
and depending on your answer, I may never talk to you again
 
1:38 PM
commas inside, periods outside
I guess I use periods inside too sometime
 
looks like there's an international conspiracy at work here
I point out the crimes of a demon and get banne
very suspicious
 
Balarka is silenced for me now
 
@BalarkaSen I meant 1.6, do you have an explicit example though?
 
whatever man
 
I don't remember how he defined locally isometric
It it means local diffeomorphism with $df_p$ an isometry everywhere, then yes
A covering works
 
1:42 PM
What else can be the definition?
 
@BalarkaSen Each $p\in M$ has a neighborhood isometric to some open set of $N$
They're inequalivalent
 
Think of a plane and a sphere which is very flat on the top
every point in the plane has a nbhd isometric to the flat bit of the sphere
 
Yes, that's the usual example.
Amazing you came up with it
 
@yashas, what is absolute zero temperature?
 
:|
Absolute zero is the lower limit of the thermodynamic temperature scale, a state at which the enthalpy and entropy of a cooled ideal gas reaches its minimum value, taken as 0. The theoretical temperature is determined by extrapolating the ideal gas law; by international agreement, absolute zero is taken as −273.15° on the Celsius scale (International System of Units), which equates to −459.67° on the Fahrenheit scale (United States customary units or Imperial units). The corresponding Kelvin and Rankine temperature scales set their zero points at absolute zero by definition. It is commonly thought...
 
1:45 PM
I think this came up in some discussion of mine with Ted's. I don't really come up with any example I say
 
@yashas, I already read that. There are some words which I don't understand (thermodynamic temperature, enthalpy, entropy, cooled ideal gas.)
 
if the word is blue, you can click on it
 
@BalarkaSen I would like to read Federer but it's 600 pages. Insanity!
The co-area formula has showed up recently and I'd like to understand it
 
@AlbertEinstein Which word is bothering you?
 
1:50 PM
It's called Federer's tomb
you could die in it's pages
 
@BalarkaSen Hmm?
Who said that
 
@yashas, I listed in brackets.
 
@ACuriousMind My physics professor is german
 
@AlbertEinstein Let us start one by one. Choose one.
I have to learn these definitions too
 
I'm tempted to misspell Bremsstrahlung on the test
 
1:52 PM
@0celo I don't remember
 
@BalarkaSen I think co-area is something most people take as a black box
 
@yashas, Ok at first, thermodynamic temperature scale
 
also remember to call X-rays Röntgen rays
 
No one wants to deal with approximate tangent vectors, Hausdorff measure, and all that
@Slereah That's what they're called in germany
 
@0celouvskyopoulo7 That would be an instant fail on my test :P
 
1:55 PM
dunno coarea
 
Thermodynamic temperature is the absolute measure of temperature and is one of the principal parameters of thermodynamics. Thermodynamic temperature is defined by the third law of thermodynamics in which the theoretically lowest temperature is the null or zero point. At this point, absolute zero, the particle constituents of matter have minimal motion and can become no colder. In the quantum-mechanical description, matter at absolute zero is in its ground state, which is its state of lowest energy. Thermodynamic temperature is often also called absolute temperature, for two reasons: one, proposed...
first paragraph
 
@BalarkaSen $$\int h|\nabla f|\, dv=\int_0^\infty dt\int_{[f=t]}h \, dA_t$$
for smooth functions $f$ it's not that bad
 
> Well darling let me see how to formulate my question easier.
 
It's true for Lipschitz functions, but then the $dA_t$ becomes a nightmare to construct
 
1:59 PM
[Weird question] Find me the prettiest nontrivial path integral expression (NB pretty =/= simple, pretty = actually have some kind of symmetry in it)
 

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