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11:00 AM
@Kaumudi.H Countryside is obviously more peaceful and away from the hustle bustle :)
 
Also cheaper
And all the scrumpy you can drink
 
@Kaumudi.H I do live in town, well on the outskirts of town, but Chester is a small city.
 
user228700
> Small city
 
user228700
OK...
 
In fact it is 1% of the population of Chennai (according to Wikipedia)
 
user228700
11:03 AM
Wow, that sounds nice, actually.
 
user228700
I love this city but I'm getting a bit tired of it--I've lived here for 18 years now.
 
I've lived in Chester since 1986 and I think I like it best of all the places I've lived in the UK.
 
user228700
1986?!
 
user228700
Holy cow, that's 31 years!!
 
21?
 
user228700
11:06 AM
Typos galore!
 
:-)
 
user228700
Holy crap, that is such a long time.
 
user228700
I'm Googling "Chester" and it seems that u guys have very tall buildings!
 
user228700
Or am I looking at the same building from different angles? :-|
 
user228700
Yep, that's the same building.
 
user228700
11:08 AM
Have u decided on lunch yet, BTW?
 
@Kaumudi.H I actually don't feel very hungry. I'm thinking I might just have the risotto then make a special effort for the weekend.
 
user228700
Oh, OK :-)
 
@Kaumudi.H I think the tallest building is Chester Cathedral.
 
user228700
 
user228700
11:10 AM
^ This building kept coming up.
 
user228700
@Slereah "Come and look at both of our buildings" x'D
 
@Kaumudi.H Looks more of private house rather than a shopping center as written at the front :-P
 
Those are only four stories. They aren't high by modern standards. The cathedral tower is 40m high - again not that high.
 
user228700
So many pretty places.
 
user228700
Most of Chennai looks like...how to put it mildly-- shit.
 
11:14 AM
@JohnRennie In Chester are most of the buildings shaped like the one in K's picture? Are there cottages or skyscrapers ?
The architecture seems to be quite different from London
 
user228700
At least we have the Marina Beach...which also looks like shit but:
 
user228700
> With a length of 13 km, including a 6 km promenade, the Marina is considered the world's second longest urban beach
 
@anonymous those buildings are about 500 years old. Chester dates from Roman times, and we still have some of the Roman buildings left though they are mostly just ruins now.
 
user228700
 
The buildings in the picture are typical of the centre of Chester. They are known as The Rows. They are half timbered buildings.
 
user228700
11:17 AM
@JohnRennie Ah, that's why they kept popping up so much.
 
@Kaumudi.H Chester is near the coast, but there aren't any beaches - just mud flats!
 
@Kaumudi.H wtf ! SO MANY PEOPLE!!!! Is that during a festival or something?
 
user228700
As of today (or yesterday perhaps, I'm not sure), I've been a member of SE for one full year.
 
user228700
@anonymous Perhaps, I'm not too sure.
 
I've some questions about action of certain drugs. Should I ask on Chem SE or Biology SE ? :/
 
11:25 AM
If it's physiology then I'd ask on the Biology SE
If you just want to get high then ask on Life Hack SE :-)
 
@anonymous what's your question
@Kaumudi.H happy birthday
 
user228700
Dude, it's not my birthday x'D
 
yeah your SE birthday
 
user228700
Ohh. Um, thanks (?) :-P
 
@Kenshin Why is Zantac better than Tegamet/Cimetidine in preventing histamine action ?
Zantac is ranitidine by composition
 
11:28 AM
define better
 
@Kenshin When Zantac was discovered Tegamet lost its popularity...so something must have been better about Zantac
 
oh k
good quesiton
the answer might not be pharmaeeutical maybe it could be economical
@anonymous here is the answer: Ranitidine was found to have a far-improved tolerability profile (i.e. fewer adverse drug reactions), longer-lasting action, and 10 times the activity of cimetidine. Ranitidine has 10% of the affinity that cimetidine has to CYP450, so it causes fewer side effects, but other H2 blockers famotidine and nizatidine have no CYP450 significant interactions.
 
@Kenshin Thanks. Source please! BTW why does cimetidine have more affinity than ranitidine ? Can it be explained using the chemical structure?
(Ranitidine)
 
do you mean affinity for CYP450?
 
@Kenshin yes
(cimetidine)
 
11:35 AM
I dunno that's too detailed for me
 
Oh its okay. Can you give me the source of your info ?
Thanks anyway :)
 
@anonymous
Ranitidine, sold under the trade name Zantac among others, is a medication that decreases stomach acid production. It is commonly used in treatment of peptic ulcer disease, gastroesophageal reflux disease, and Zollinger–Ellison syndrome. There is also tentative evidence of benefit for hives. It can be taken by mouth, by injection into a muscle, or into a vein. Common side effects include headaches and pain or burning if given by injection. Serious side effects may include liver problems, a slow heart rate, pneumonia, and the potential of masking stomach cancer. It is also linked to an increased...
scroll down to the "History" section
paragraph 2 is what i copied but paragraph 1 is also interesting
 
@Kenshin Great. I will read it . Thanks :) Bye
 
@Kaumudi.H I am now
Just woke up
 
12:18 PM
@SirCumference LOW ENERGY
@Slereah I tihnk I'll be getting that wave equation book
@ACuriousMind Why is geometric quantization so bad? Hall says you can't even quantize the usual kinetic energy in general.
Why does anyone bother with it?
 
@0celo7 Coffee!
 
12:33 PM
@SirCumference I'm about to head to work and get me some coffee
 
Huh, you have a job?
 
Yes, I think pretty much everyone knows I do.
 
Where you work?
 
I'm a research assistant.
 
I'm a bit jelly
 
12:36 PM
Do you not want to know what I do?
 
I'm guessing nuclear physics?
 
user228700
1:00 PM
Is Starbucks affordable for the middle class in the U.S?
 
user228700
400 rupees for one cup of coffee and a pastry--I could have a grand lunch with that much money!
 
@Kaumudi.H That's overpaying. I think it usually costs $3 for that in the US, though that number is just off the top of my head.
Still, I wouldn't pay 400 rupees ($6)
 
user228700
$3 for coffee and a pastry?
 
@Kaumudi.H Can't really tell off the top of my head, but that's what I'd guess
 
user228700
When I "grow up", I want to be the person who photographs food from restaurants and cafes for other companies.
 
user228700
1:05 PM
From what I find on Zomato, a person named Gaaya has bought every item on the menu to provide photographs.
 
user228700
@SirCumference That's so much more affordable, wtf! Here, one brownie costs north of 110 rupees.
 
@Kaumudi.H You'd think the people at Starbucks would think that's sketchy
@Kaumudi.H Again, I'm making those numbers up, but that's what I'd guess
 
user228700
@SirCumference What, why?
 
@Kaumudi.H That, or the person has a binge eating disorder
 
user228700
@SirCumference Nah, the (most) people of Chennai are warm and non-judgemental.
 
1:09 PM
@Kaumudi.H That's quite a contrast. Here in New York people will punch you in the face if you look at them in the street (exaggeration)
 
user228700
U live in NY?!
 
@Kaumudi.H Yeah?
 
user228700
That is quite a contrast to Chennai.
 
Certainly :)
 
user228700
I watched this video:
 
@Kaumudi.H That makes NY look nicer than it feels, imo
 
user228700
> Nicer than it feels
 
user228700
Hmm, OK...
 
In fact, I don't remember the last time I saw sunlight like in that video
It's usually overcast
 
user228700
Ohh, OK...
 
1:16 PM
@Kaumudi.H Huh, I actually didn't know we had that much public art
 
user228700
Hehe, OK...
 
user228700
So many movies and T.V shows are based/set in NY!
 
user228700
Just look at this:
 
user228700
In the history of motion pictures in the United States, many films have been set in New York City, or a fictionalized version thereof. The following is a list of some of the more memorable films set in New York City, sorted by the year the film was released. == Prior to 1910 == What Happened on Twenty-third Street, New York City (1901) The Thieving Hand (1908) Bolletje lulkoek (1909) == 1910s == Fatty at Coney Island (1911) Regeneration (1915) Lights of New York (1916) Coney Island (1917) The Delicious Little Devil (1919) == 1920s == Manhandled (1924) Subway Sadie (1926) East Side, We...
 
@SirCumference No, I work for a psychology prof I had freshman year
we work on pain responses in small animals
 
1:21 PM
@0celo7 Oh, wow
Oh crap
I can't believe I fell for that...
 
At least you're learning
back in the day I could have kept up the ruse for a week
 
I work in solid state physics
 
Oh, that's neat
 
@SirCumference So, I've been thinking about learning some cosmology
When I'm done with my current reading I don't really have anything planned
 
1:23 PM
What animal models you guys are using?
What subfield in solid state?
 
@0celo7 You should, it's really neat
 
@Secret Mice, but we want to use children
Apparently it's very difficult to do human testing
 
Especially some nonstandard cosmologies like the Big Rip. Those are the most interesting parts imo
 
there's regulations and there needs to be a state inspector, etc.
it's very expensive
 
Human testing is part of bioethics, one has to gain all sort of permit in order to research on that as well clinical trials
....Uh why the eerie silence....?
 
1:49 PM
> Of a symplectic Lie $n$-algebroid

??
@BalarkaSen @ACuriousMind Lol even n Lab doesn't understand this shit
 
2:11 PM
The following google search is inspired from reading the ACS report on the renewable energy sector from 2016 onwards
In a sense, it kinda make sense as when an entangled state changes, all the subsystems's wavefunctions has to change in lockstep, thus minimising the number of steps needed to flip those states
The following acuriousmind either already aware or might be interesting to him:
1
Q: The Stone von Neumann theorem without exponentials?

MattaConsider $\hat{r} = (\hat{x}_1,\hat{p}_1,\ldots \hat{x}_n,\hat{p}_n)^\intercal$ with commutation relation \begin{equation} [\hat{r},\hat{r}^\intercal] = i\Omega. \end{equation} I want a simple statement like: Any two irreducible representations of the canonical commutation relations are unit...

 
Does anyone here know the answer to this (apparently silly) question of mine : physics.stackexchange.com/questions/310851/…
0
Q: Leading/Lagging terminology for sinusoidal waves

anonymousWhat is the method to identify which wave is leading and which wave is lagging from their equations? For example the two waves are $A\sin(wt+\pi/6)$ and the other is $A\sin(wt+2\pi)=A\sin(wt)$ (by trigonometric relations). So is the second wave leading in phase or lagging in phase compared to t...

 
@anonymous At time $t = 0$, the first wave is at $A\sin(\pi/6) = A/2$ and the second is at $0$. So the first is obviously leading, right?
Note that a phase difference of $2\pi$ is the same as a phase difference of $0$. The "position" of the two waves are the same.
 
@BalarkaSen Well, is that the way to define "leading" ? At t=0, the one which has greater magnitude will be called "leading" ?
I haven't found this definition in any book
Actually none of my books bothered to discuss it :P
Can you give me the source of your definition ?
@BalarkaSen I agree with the phase difference part :)
 
I don't have a definition, I just said out loud the most obvious thing I'd imagine is meant.
 
2:26 PM
@BalarkaSen If I have some vector space $V$, can I find another vector space $W$ with $V=W\otimes W$?
 
Maybe someone can tell you the actual convention. Geometrically I think that should exactly be it.
@0celo7 No; think of a vector space with prime, or even squarefree dimension. Like $\Bbb R^2$.
Dimension is multiplicative under tensor.
 
@BalarkaSen Exactly.
Wonder what I'm missing here
I'm supposed to take the square root of an $n$-vector bundle
 
That's only well-defined for line bundles, not? Otherwise, even if you can write it as a tensor product, it'll be of a different dimension.
 
Oh, it's a line bundle because the elements are $n$-forms
 
Cool, then you're safe and sound.
 
2:30 PM
@BalarkaSen Umm, suppose one wave A is $A\sin(wt+\pi+\pi/6)$ and the other wave B is $A\sin(wt)$. At $t=0$ the first wave is $A\sin(7\pi/6)<0$ while the other is just $0$. So by your definition $A\sin(wt)$ is leading $A\sin(wt+7\pi/6)$ ?
 
Yeah.
If you graph it, you'll see that would match the geometric intuition.
 
@BalarkaSen So since my fiber is $\Bbb C$, I just use $\Bbb C\cong \Bbb C\otimes_\Bbb R \Bbb C$?
 
C \otimes_R C is not C!! C \otimes_C C is.
 
@BalarkaSen That does seem like an easy to follow convention. Anyway, I am waiting for some more people to comment on the question. Thank you anyway!
 
@anonymous Right, better to check it through someone who actually knows their physics.
 
2:32 PM
@BalarkaSen I'm confusing myself.
My bundle is real
so it's $\Bbb R\cong\Bbb R\otimes_\Bbb R\Bbb R$
 
Righto.
 
Geometric quantization has too many definitions!
real bundles, complex bundles, Lagrangian submanifolds, Kahler forms, holonomies, polarizations, more bundles
everything flying around
For something that can't even make sense of $\frac{1}{2}mv^2$ in general!
@BalarkaSen so what is $\Bbb C\otimes_\Bbb R\Bbb C$?
 
C, as an R-vector space, is R^2. So it's isom to R^(2*2) = R^4.
 
ah, yes
 
@BalarkaSen I was considering learning about symmetric spaces, or cats, but then there's this
 
You should do what makes you happy.
 
I don't know what would make me happy
 
Well definitely figure that out
 
3:20 PM
@BalarkaSen Do you do know about Young's double slit experiment ? I had a question on YDSE and JR is missing today :P
 
@anonymous I know a little, but not much. What's the question?
 
In Young's Double slit experiment, if we use white light then what color will form closest to the central bright fringe? Most books say that the answer is violet as it has the shortest wavelength and will have constructive interference nearer to the center when path difference is $\lambda_v$. However, I feel the answer should be red as violet light will have destructive interference at $\lambda_v/2$ leaving behind the red end of the spectrum.
@BalarkaSen
This video contradicts with my answer though: youtube.com/watch?v=GEqwRBjHdwc
 
That's an interesting question.
 
Yeah, its been bugging me for quite some time
 
@Slereah I am beginning Wald
 
3:34 PM
@anonymous I am not sure I understand your argument though. Violet does have destructive interference at $\lambda/2$, so that bit of the band should be red. But why do you think it would influence the central band?
I have admittedly never thought about what happens to the double slit experiment if ones works with lights composed of multiple wavelengths.
 
@BalarkaSen "But why do you think it would influence the central band?"...I never said anything about central band. Look at the video I linked. They are showing the blue/violet color appears nearest to the central bright. But I feel the first tinge of color (nearest to central bright fringe) should be reddish rather than bluish (due to destructive interference of violet)...
 
how can you even compete with this typesetting
 
Ahh, I see, @anonymous. Well, I have no idea.
@0celo7 I think it's great
 
@BalarkaSen I guess I'll wait for JR :).
 
@BalarkaSen you have issues
 
3:39 PM
so do you
 
you like the Milnor typeset too I bet
 
it's my favorite
 
@JohnRennie When you return please do have a look at this question: chat.stackexchange.com/transcript/message/35324052#35324052
11 mins ago, by anonymous
In Young's Double slit experiment, if we use white light then what color will form closest to the central bright fringe? Most books say that the answer is violet as it has the shortest wavelength and will have constructive interference nearer to the center when path difference is $\lambda_v$. However, I feel the answer should be red as violet light will have destructive interference at $\lambda_v/2$ leaving behind the red end of the spectrum.
3 mins ago, by anonymous
@BalarkaSen "But why do you think it would influence the central band?"...I never said anything about central band. Look at the video I linked. They are showing the blue/violet color appears nearest to the central bright. But I feel the first tinge of color (nearest to central bright fringe) should be reddish rather than bluish (due to destructive interference of violet)...
 
@BalarkaSen I bet you like Spivak's font too
if your favorite font isn't computer modern, I'm not sure there's anything to be said
it's just a sad state of affairs
 
I haven't seen Spivak's font.
My favorite font is Courier New.
 
3:42 PM
It might be the same as Milnor, I'm not sure
I don't have the books here
 
Yeah, that's great. Typewriter fonts.
 
Why on Earth would that be appealing?
@Slereah Wald doesn't care about domains of operators. Low energy!
Never mind, he does.
 
4:12 PM
guys I'm finding out the relantionship between resonance frequency and height of the building. So I devised the eqaution F = k x H which than goes to log⁡(F)=xlog(H)+log⁡(k) and to F=k ×H^x. I found out x(gradient) to be -1.998
my question is does the gradient get affected by the material of the building?
 
@Wdoctor123 have you tried with different materials ?
 
I don't have the time
now
I was just wondering because my friends got different results
 
It should be affected by the material
Isn't that obvious ?
 
It is quite logical yes
but just wanted to know for sure
 
I don't know the exact equation but logically the material should play a role
May I know why you are doing this experiment? Is it a project ?
 
4:19 PM
0
Q: Ampere's Law Confusion

Alpha RomeoI had this question recently in a test. Different methods are yielding different answers. Can someone point out the mistake? We are given 4 infinite wires carrying current out of the plane as shown. Find $$\int_{-\infty}^{+\infty} \vec{B}\cdot\,\mathrm d\vec{x} ,$$ (along x axis) My logic f...

Plz take a look, i have exam next week
 
@AlphaRomeo What does u vector stand for in the last few lines ?
 
it's a project
 
@AlphaRomeo $\bar u (-3)$
@Wdoctor123 Oh. I see.
 
ye
so you study physics at university?
 
@Wdoctor123 I'm in school..
@Ramanujan eh ?
 
4:29 PM
@anonymous I thought you were accessing chat being in school right now :P
 
oh i confused with last person who helped me
XD
 
@Ramanujan haha, no! i'd be kicked out :P
 
@Wdoctor123: as a rough guide the resonant frequency will be proportional to the square root of the stiffness of your building, and inversely proportional to the mass of your building.
So both the material the building is made from and the style of construction will affect the resonant frequency.
 
resonance frequency is also inversely proporptional to height
well that's what i found out during my experiment
 
3
A: why do tall buildings have low resonant frequencies?

tmwilson26In order to excite a resonance in something, you need to produce oscillations that add coherently, or in phase. This means that when you vibrate on object, you will want the reflections of the vibration to add with the new vibrations that are coming in. These reflections will take time to get f...

 
4:33 PM
Increasing the height will decrease the stiffness i.e. it takes less force to deflect the top of a tall building than to deflect a short building.
 
0
Q: How orbitals exist in atom?

Lz4We know that there are 5 different kind of orbitals and we also know that these are regions of maximum probability where an electron can be. Orbitals are plotted on XYZ plane. So here my doubt lies, we show each orbital individually for the sake of understanding but how we visualize these for an...

^ interesting mix of misconceptions
 
@JohnRennie Did you have a look at my previous question about YDSE directed at you ? :) (I pinged you when you were offline)
 
vzn
@Emilio question/ wondering, not sure where to look, have you heard of laser experiments with "very long wavelengths"... what are the longest used?
 
I had a quick look and offhand I don't know how the fringe would look. Since the red intentity decreases more slowly as you move from the centre I'd guess the central fringe will get redder as you move away from its centre.
Is that what you are asking?
The first (non-central) fringe will be violet on the inside and red on the outside.
 
@JohnRennie Why should that be ? Doesn't the destructive interference of violet occur at $\lambda_v/2$ (leaving behind the red end of the spectrum) whereas the constructive interference of violet occur at $\lambda_v$ ? I feel the first non central fringe should start with red on the inside and end with red on the outside and peaking towards violet at the center of it.
 
4:45 PM
Have you tried graphing the red and violet intensity on the same graph?
 
@JohnRennie No. How do I know the intensity ?
And how does it play a role?
I found this ^ on the net
Not very clear
 
From memory it's: $$ I = I_0 \cos^2 \left(\frac{\pi d \sin\theta}{\lambda} \right) $$
So fire up your spreadsheet and plot the intensity as a function of $\theta$ for $\lambda=40$nm (violet) and $\lambda=70$nm (red).
 
@rob I'd be interested to discuss this.
My guess is that the most important issue of all those mentioned in the article is the general discomfort with mathematics.
 
Plot them on the same graph so you can see how the intensities of the two colours compare.
 
Red always seems to have greater intensity
I took $I_o=1 unit$
and $d=10 units$
 

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