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user116211
8:03 AM
Hey @JohnRennie, you wrote in your answer:
 
user116211
> since this probability is just the charge density that means the charge density varies smoothly throughout the atom.
 
user116211
What do you mean by smooth charge density?
 
how can you have an accelerating motion with constant magnitude of speed. :(
 
user116211
@ManolisLyviakis its unit vector must be changing.
 
change of directio resulting in an accelerating motion doesnt come intuitively to me
say i have acceleration=C (constant) if i integrate that what do i get?
 
user116211
8:11 AM
@ManolisLyviakis $$\dot{ \mathbf v} = \dot v~\mathbf e_{\theta} + v~\dot{\mathbf e_{\theta}}$$; simple application of chain rule.
 
user116211
@JohnRennie, Feynman in his last lectures mentioned:
 
user116211
> The wave function $\psi(\mathbf r)$ for an electron in an atom does not, then, describe a smeared-out electron with a smooth charge density. The electron is either here, or there, or somewhere else, but wherever it is, it is a point charge.
 
Well yes
That's non relavistic QM for you
The measurement is of a point particle
 
user116211
Although I'm dubious of what he wanted to mean by point
 
doesn't work for QFT, tho
 
user116211
8:14 AM
@Slereah Of-course, he was giving lectures in non-relativistic realm QM.
 
It means that when you consider a non-relativistic electron, you can consider an arbitrarily small volume in which the probability of presence of the electron is 1
 
what is the derivative of a unit vector
 
user116211
@Slereah oh.
 
user116211
@ManolisLyviakis $$\dot{\mathbf e_{\theta}} = -\mathbf e_r$$
 
The wavefunction just describes the probability of finding it somewhere
But one measured, it is exactly located somewhere
 
8:16 AM
O_o how did you come up with that
 
user116211
@Slereah: Feynman was just telling where Schroedinger mistook in interpreting the probability density $P$ as charge density and probability current density $\bf J$ as electric current density.
 
user116211
@Slereah yep.
 
velocity $v=υ_xi+υ_yj$ in 2d where i,j unit vectors
 
user116211
@ManolisLyviakis Polar coordinates; covered in every introductory mechanics book and calc 1 course.
 
then the derivative of v is the derivatives of υ_χ u_y am i wrong?
 
8:35 AM
@MAFIA36790 bit mean considering he invented quantum mecanis basically
Can't have everything right on the first go
 
8:49 AM
There's quite a lack of pre-QM explanations of the atom structure, I feel
The only one I can remember is ring-shaped electrons
 
user116211
@Slereah You mean the Bohr dude's model?
 
Well then Rutherford experiment was in like 1910
And QM was around the mid 20's
There was 15 years without an adequate model for the atomic structure
History of physis texts rarely mention models of that era
 
user116211
@Slereah ah! a good question for HSM
 
Probably
Let's ask
 
user116211
@Slereah what happened in those years? Any discovery?
 
user116211
8:56 AM
Before de Broglie?
 
user116211
@Slereah okayish, let you give me the opportunity ;P
 
There's always discoveries
0
Q: Atomic models in the 1910's and early 1920's

SlereahThe Rutherford model that invalidated the plum pudding model occured in 1909, while the first model for quantum mechanics was around 1924, leaving a period of 15 years without an adequate model for the atom, as the Rutherford planetary model did not work out due to the emission of radiations. Tha...

There we go
 
user116211
@Slereah Hmm, there is actually no mention, no discussions on that in any book ;\
 
9:25 AM
@MAFIA36790 and you believe Feynman over me???
@MAFIA36790: you realise I now deliberately leave out the \mathrm just to annoy you :-)
 
user116211
@JohnRennie huh? hmm.
 
user116211
@JohnRennie Well, there were two d in your post; so I used \mathrm to distinguish the operator and yeh, I'm \mathrm monster ;)))
 
Re Feynman's comment: I think this is largely a matter of terminology. In principle there exists position eigenfunctions for a particle, and in principle you can construct the wavefunction of an electron in an atom froma superposition of these position eigenfunctions.
But so what? I could just as well start from momentum eigenfunctions in which the particle is completely delocalised and build up the wavefunction from those.
 
Well yes, but if you measure the position you collapse it into a position eigenvector :p
 
@Slereah if you measure the position precisely you can collapse it into a position eigenstate, but that requires an infinite energy to do. In practice you collapse the particle into superposition of eigenstates with a lower uncertainty.
 
9:38 AM
Yes but we're talking theory ere
Let's go nuts
 
10:27 AM
[After more than 3 weeks of corrections from self analysis]
Now the question is then, what do those antidiagonal (and their equivalents in other basis) of the density matrices physically mean, if they are not part of the partial traces of the subsystems?
Begin with the following partially entangled state
\begin{align}
\lvert@\rangle=\sqrt{\frac{1}{3}}\lvert ud\rangle-\sqrt{\frac{2}{3}}\lvert du\rangle
\end{align}
, and using the convention $\lvert u\rangle$ and $\lvert d\rangle$ for spin up and spin down states respectively. Spin right and spin left states are labelled $\lvert r\rangle$ and $\lvert l\rangle$ respectively and given by.
\begin{align}
\lvert r\rangle=\sqrt{\frac{1}{2}}\lvert u\rangle+\sqrt{\frac{1}{2}}\lvert d\rangle\\
\lvert l\rangle=\sqrt{\frac{1}{2}}\lvert u\rangle-\sqrt{\frac{1}{2}}\lvert d\rangle
 
Hi everybody.
 
(Background: 2 days ago, a calculation error result in deriving the wrong conclusion that $\dot{\rho}_A$ and $\dot{\rho}_B$ nonzero, which would have implied that Alice and Bob can encode information by assigning classical bits as follows:

1. Begin by making 100 replicates of the state $\lvert @\rangle$
2. Distribute one pair of the 100 replicates to Alice and Bob.
3. Alice and Bob go on their separate ways in at least 1 light year away
4. Alice and Bob then measure (in their ow pace) all 100 replicates. This should return a sequence of ups and downs on their paper with ratios of 1:2 for A
@DanielSank How to prove using no communication theorem that any conceivable time derivative of the density matrix of a two level two particle composite system does not have nonzero elements in all entries marked by *
i.e. if we have (under the standard basis $\lvert 00\rangle$,$\lvert 10\rangle$,$\lvert 11\rangle$ and $\lvert 01 \rangle$)
\begin{align} \dot{\rho}= \begin{pmatrix} * & * & * & \\ * & * & & * \\ * & & * & *\\ & * & * & * \end{pmatrix} \end{align}
Then how to use no communication theorem to show that all * must be zero?
 
10:48 AM
What is the "no communication theorem"?
I've been in superconducting information for almost ten years and I've never heard of it :P
 
@DanielSank
https://en.wikipedia.org/wiki/No-communication_theorem

It's the no go theorem that an entangled state cannot be used to transmit information superluminally between two parties because if the parties measure their system in isolation, they cannot determien whether the measurement is obtained from them measuring it, or because the entangled state have already projected into an eigenstate caused by the other party measuring it

I think Susskind in p. 223-226 give something similar in that he showed how the density matrices of Alice are unchanged by a unitary evolution in Bob's sub
 
@Secret I'm confused about your basis.
 
user116211
Hey @DanielSank o//
 
user116211
okay, I'm not a LaTeX guy; that's why I'm asking:
 
@Secret Well how do you know they should be zero?
@MAFIA36790 \o
 
user116211
11:03 AM
I've seen many using \begin{align*} \end{align*} and also some people using \begin{align} \end{align}; what's the difference between the two?
 
Plz stop using @ as a symbol
 
@Secret the basis ordering you've chosen seems weird to me as it is not the kronecker product of two copies of the same single particle basis.
 
user116211
@Slereah oh, man ;(
 
user116211
Although I've used the later and frankly speaking both render the same output at least in PSE.
 
@Danielsank For a bloch sphere, it has two base states $\lvert 1\rangle$ and $\lvert 0 \rangle$ corresponds to spin up and down. Therefore, for a two qubit system, the basis vectors of the composite system are given by tensor products thus giving 00 01 10 11 (in this order)

If they (or at least the 8 entries that will be partially traced to give Alice's density matrix when the hamitonian has terms dependent on what bob did to his subsystem (or vise versa for Alice)) are nonzero, then the density matrix of the other party will have a time dependence and the encoding of classical bits via a
 
11:12 AM
@Secret Yeah ok, that's not the order you wrote above.
 
@DanielSank Sorry typo. Clarification: The basis used for the big calculation above is (in this order) is (in susskind's noration) uu ud du dd which in conventional notation 11 10 01 00
 
Yeah ok.
@Secret did you try writing everything out explicitly?
 
11:30 AM
I think so, for example, the aforementioned partially entangled state, its coordinate vector in this basis is $(0 \sqrt{\frac{1}{3}} -\sqrt{\frac{2}{3}} 0)$
 
Uh, ok but your goal is to see what happens if you have dynamics on one particle... right?
Act a Hamiltonian on one particle and see which terms in the density matrix change.
My guess is you could do that reasonably easily using index notation.
 
Do I act the hamitonian on the density matrix like how we usually do for state vectors, or do we need to wrote it as something like $H\rho H$?
 
Well there are a few ways you can go about this.
The equation of motion for a density matrix is easy to compute.
You have $i \partial_t \Psi = H \Psi$.
(turning on mathjax, one moment)
So then
$\partial_t \rho = \partial_t (|\Psi\rangle \langle \Psi |)$
$=\partial_t | \Psi \rangle \langle \Psi | + |\Psi \rangle \partial_t \langle \Psi |$
=$-iH |\Psi\rangle \langle \Psi | + i |\Psi \rangle \langle \Psi | H $
$= -i [H, \rho]$
I'm on a bad internet connection. Sorry for delays.
Anyway, that's the equation of motion for the density matrix.
So now just use index notation to keep track of everything and see if you can prove your desired result.
FWIW if you have a propagator $U$ for the state taking $\Psi \rightarrow U \Psi$, the equivalent expression for the density matrix is $\rho \rightarrow U \rho U^\dagger$.
 
user116211
12:24 PM
3
A: About time and time dilation

Luboš Motl We are only allowed to add quantities with the same units. Time and distance can't be added just like apples and oranges shouldn't be mixed. To add them, one must first convert them to quantities of the same unit, and a speed is needed. The speed of light in the vacuum $c$ is the right speed th...

 
user116211
Was it necessary to write this:
 
user116211
> Your question is equivalent to a question "how do mathematicians dare to say that 2+2=4 if 2+2=37 is equally good if not better", and so on. Well, the alternative is not better. It's demonstrably rubbish.
 
user116211
I like his metaphors ;)
 
@yuggib what
 
Jim
@MAFIA36790 37 is bigger than 4, bigger is always better, therefore 2+2=37 is better than 2+2=4
 
12:35 PM
Guys
What's a good GR approximation for an object
Like just a hunk of metal
Perfect fluid?
 
user116211
@Jim ;D
 
Jim
@Slereah nothing. That is a standard GR approximation for a random hunk of metal
 
Not a v. good approximation
 
Jim
depends on context
 
Perfect fluid is probably better I'd say
But I'm wondering if there is better
 
Jim
12:37 PM
what are you using this approximation for?
 
Like some state equation that is approximately correct for solid objects
Computing the metric generated by metal plates
 
Jim
how big is the metal plate
 
Either I use the Polyakov ation and pretend they are 2D or I try to do something a bit more realistic
Not sure yet
 
Jim
bigger than a breadbox?
 
Either infinitely thin or with a small thickness, and either infinitely large or with boundaries
Depends on what is solvable
 
12:39 PM
@ACuriousMind I'm still super confused by the Lie group thing...
 
Jim
@Slereah so it is potentially anything at all except nonexistent?
 
why does $\mu$ analytic near $e$ mean $\mu$ is analytic everywhere
 
Well they're not called LIE for nothing
 
I know that $G$ is generated by any neighborhood of $e$
 
@Jim Ideally with thickness and boundaries, but I'm not sure this will pan out
The size is like
Apparatus size
So bigger than a breadbox, probably
 
Jim
12:41 PM
smaller than a building?
 
yes
 
Jim
then a good approximation in GR is nothing
 
Perfect fluid it is
 
Jim
the effect that it will have on the metric is negligible
 
I am currently not too worried about measurements
More about effects
 
12:43 PM
> To sum it up, my question is: Mathematical techniques used to describe physical phenomena are not necessarily specifically invented for physics and do not necessarily have any meaningful physical interpretation. How come these techniques are able to produce correct (can be verified by experiment) results?
Oh god
 
I guess a broader question is
What's the state equation for a metal object
What are the pressures in it
Can I assume 0 pressure
Or would that be a bit much
 
Jim
good question, but now you're outside the scope of GR
 
I guess let's start with infinite plates
 
Jim
infinite plates are a different story
 
I don't like abandonning all Killing vectors in one go :p
Hm, I forget the metric for 2 Killing vectors $x, y$, and I am far away from Stephani
Woe is me
Infinite plates I'm guessing is similarish to Domain wall metric
Apparently static with plane symmetry is $$ds^2 = -f^2(x) dt^2 + \frac{1}{f^2(x)} dx^2 + g²(x) (dy^2 + dz^2)$$
 
Jim
1:12 PM
yeah, plane symmetry is definitely a good idea
frankly, with such a large metal sheet, you may find that aphysical effects develop in your metric, which corresponds to the notion that one should not be able to have an infinite sheet of metal in our universe. Also, don't forget to make it an FRW metric because an infinite sheet affects the cosmological scale
 
There's even an exact solution for plane symmetric static spacetimes
Although not closed form
 
Jim
someone is arguing with me that "point" has no definition in geometry
 
Tho I can throw FRW in the trash, really
 
Jim
my answer to them? link to google search
 
Since the point is to then find the solution wit boundary terms :p
Not to have an actual infinite plate
I'm doing a metal plate not domain walls
Maybe I will even do me a lazy thing and use a Gaussian for the plate energy distribution
I don't want to use mollified Heaviside funtions, those are a bother
 
Jim
1:21 PM
is this a hobby thing or are you doing it for actual research?
 
More of a hobby
I ain't getting paid for this
Maybe I should start with a Polyakov thing, tho
Easier to start
 
Jim
I'm sure it has been done. But if you do end up creating a metric for spacetime with a metal sheet of arbitrary dimensions, you'll see that as the dimensions get closer to the scale of a breadbox, the difference between your metric and one without the object rapidly falls to zero
 
Well obviously
But I'm more interested in the form than the scale of the measurement
Plus
There isn't just a metal plate!
There is dynamic Casimir effect involved
I'm guessing if I want to do plates, a round plate probably is better than a square one
Round one is gonna be all Bessel functions
Not a fucking clue what kind of function a square has
 
@Jim lolwut
 
Like what is even the classical gravitational field of a cube
Thank you internet
 
1:33 PM
@Jim link?
@Slereah LINK TO ABSTRACT
 
That's not GR @Slereah
 
> James M. Chappell,∗ Azhar Iqbal, and Derek Abbott
School of Electrical and Electronic Engineering,
University of Adelaide, South Australia 5005, Australia
 
> Principle of superposition
Ain't nobody got time for Newtonian physics
 
Why are electrical engineering students writing that paper anyway
 
$$V(x,y,z) = -G\rho \sum_j [\sum_i (\frac{xyz}{x_i} \ln (x_i + r) - \frac{x_i^2}{2}\arctan(\frac{xyz}{x_i^2 r})) )]^{L-x_j}_{x_j = -L-x_i}$$
Gross
Thinking about it, maybe I should also start my thing in linear GR
Might be prudent
Plus realistic at this scale
And I'm sure the solution of the wave equation for a cylinder exists in EM
(BESSEL)
 
1:45 PM
@Slereah that's not even GR...
 
Well let me tell you what GR will look like with 0 Killing vectors
A mess
 
no conserved quantities!
 
At least linear GR will be all linear, baby
 
user116211
Wow, a post is making reference of Vixra paper ;)
 
Does it reference the papers written by Jesus
 
user116211
1:47 PM
;D
 
user116211
0
Q: Feynman path integral interpretation of the Aharonov Bohm effect

JuanI have recently been reading about the interpretation of the Aharonov Bohm effect via Feynman's path integral (see vixra.org/pdf/1403.0950v1.pdf). I do not know whether I am missing something, but I do not understand why when evaluating the action they have to take into account the potential even...

 
@Slereah what
 
Jim
Definition: A "point" in geometry is a location. It has no width, length, or depth. It has no volume; only coordinates of the location. Now, please prove to me there is no time dilation. — Jim 1 hour ago
 
what
Oh no
This paper on the dynamical Casimir effect is in French
BUT WAIT
Well, a thesis, technically
I don't think a lot of physics papers are still in French
It's pretty rare to find papers that aren't in english, french, german or russian
I've seen a handful of chinese and japanese papers, but that's about the extent of it
 
2:09 PM
That does not help to work out the answer! Stop trying to find duplicates but start to actually help! — Kristens Taurins 3 hours ago
Comments I could have left (© dmckee 2016):

Hi Kristens.

Being British I tend to be somewhat reserved, so I tend not to tell people when I think they are being a feckless, idle parasite more interested in getting other people to do their work than in showing any effort for themselves.

In these circumstances I might point to a question that I think is a duplicate partly because it is a duplicate, but also as a hint that if the OP was willing to get off their arse and do some work the linked question would be a good place to start.
 
user116211
May 30 at 13:49, by ACuriousMind
@0celo7 I have been told that reading French papers without speaking actual French is a skill a mathematician has to acquire
 
Stiff upper lip and all that
 
user116211
It applies to physics too ;]
 
Tell me @JohnRennie
Do you know Lily the Pink
 
2:20 PM
The very same, yes
Though that is not the correct version
 
@Jim good lord
 
Hi all
 
Hello
 
John Doe?
We have had bad experiences with other Johns in the past.
 
Especially John D's
 
2:27 PM
@Ocelo7 Not so much Mr Doe as unknown name...
 
user116211
@0celo7 John Doe is the dummy user of SE's tour.
 
user116211
@Slereah Hmm.
 
@MAFIA36790 Really? Think I skipped the tour...
 
It's quite unfortunate that GR history usually only teaches about the usual stuff from te early 20th century when curved cosmological models have existed since the 19th century
 
user116211
 
2:32 PM
0
Q: Why does math work for describing and solving physics problems?

NikMy question is a general one. But to explain what it is asking let's first a look at "solving" of an electrical circuit using Kirchhoff's laws as an example. (And this example takes a considerable amount of the question's real-estate but please keep in mind it is only an example to base the act...

Too broad? Off-topic?
 
user116211
@Qmechanic I would definitely say it's off topic.
 
Off topic
I say flog 'em
 
2:42 PM
Just got an email from a prof with an emoticon
 
user116211
@0celo7 Do profs do such that?
 
@MAFIA36790 Hmm?
 
@Emilio Pisanty : Thanks for the bounty on this meta.SE question.
 
3:06 PM
hey @0celo7 can u answer a quick question for me. it's a question in the lab manual. Describe the situation in which the object submerged and the fluid have the same density
I know buoyancy is independent of densities, it is due to a pressure difference in the fluid
So the buoyant force still occurs in this example. Would it be the case that the buoyant force is equivalent to the weight of the object?
 
@Qmechanic No worries. I'm still at a complete loss as to why this isn't implemented.
 
@0celo7 you have until 3pm tomorrow to answer me. thx
 
@EmilioPisanty : Me too.
 
3:22 PM
@Jim It doesn't.
At least, not in Euclidean geometry.
That's why such a framework is an example of a "synthetic" framework - you write down a bunch of axioms about an undefined thing and do math with them.
@Jim Yes, and that definition is only an intuitionistic definition in Euclidean geometry as you don't define "width", "length", "depth", "volume" or even "location" before defining what a point is.
 
Anyone here with a solid grounding in stats?
 
user116211
@KyleOman Cross Validated Chat room? Nevertheless, welcome :)
 
user116211
Title of the Day:
 
user116211
0
Q: Mag.-flux build up...hate it

Jbb"An old bell ringer". After a few minutes of running, the steel pole of transformer, slowely becomes magnitized. Are there any unique metals that would prevent the mag.-flux build up, in the steel transformer?

 
yeah I popped in on crossvalidated too, looks quieter there though ;)
 
user116211
3:31 PM
@KyleOman You can leave message there; but they are generally quieter at this time ;/
 
and I'm mulling over something trivially simple, where I think I know the answer, but it's for a journal article so I need to be sure :/
 
@BalarkaSen I doubt there is anything "intuitionistic" about that definition
 
@yuggib I meant intuitive, oops.
 
@BalarkaSen ;-P
 
Did Italy qualify? @yuggib
 
3:42 PM
freudian slip?
 
I guess so.
 
@skillpatrol no... T__T
 
with awful refereeing
lost in overtime to croatia
 
The refs can ruin any game.
 
3:44 PM
yeah, but it is not worth to complain to much
 
true
 
still, we ended up with like 4 people with 4 fouls, and 3 or 4 fouled out
they did not have a single fouled out
(in fiba you're fouled out with 5)
 
wow it was a close game regardless..
AND italy lost to germany in eufa QF 1-1 to germany D:
2 close games in 2 different sports
 
it happens
but in basketball we were a good team, in football...not so much ;-P
 
user116211
Please don't talk about EURO ;((
 
3:47 PM
@yuggib You're a mathematician, right?
 
user116211
@BalarkaSen Mathematical Physicist
 
@BalarkaSen I have a Ph.D. in mathematics
 
user116211
;)
 
and a master in physics
 
@yuggib Ah. What do you work on?
 
user116211
3:48 PM
@BalarkaSen Would you come tomorrow and save these questions?
 
I work on mathematical physics/analysis of PDEs mostly
 
@MAFIA36790 Huh?
Ah, I see.
 
user116211
Tomorrow is AMA.
 
I don't know what that means.
 
user116211
@yuggib would be our guest.
 
user116211
3:49 PM
15
Q: Ask Me Anything 12th July: guest's introduction and questions

yuggibI will be the next AMA guest. So here it is a brief introduction of myself, and you can suggest some topic/questions that can be discussed during the session. Academic Background. I obtained a master degree in theoretical physics almost ten years ago, working on the regularization of path integr...

 
user116211
and links therein.
 
@0celo7 so, are you convinced you should read Jech's book?
 
@yuggib no, why on Earth would I do that
will it help me understand geometry and topology
 
@MAFIA36790 Curios event.
 
@0celo7 topology, maybe yes ;-P
 
3:56 PM
@Slereah yes, though admitting you know the song is instant uncool points. That doesn't affect me since as a Hawkwind and Pink Floyd fan I am uncool beyond any hope of redemption - at least, that's what my 14 year old niece tells me.
 
@JohnRennie I don't even know what Hawkwind is.
And your niece sounds mean.
 
@0celo7 it will help you find models where things behave much bizarrely better
 
@yuggib Not very interesting
 
@0celo7 how could you say if you do not know?
 
I'm mainly interested in topological Hausdorff spaces with a countable base, which are also locally homeomorphic to Rn
 
3:58 PM
@0celo7 She's 14 and female. of course she's mean!
 
Kids these days :-)
 
@0celo7 aka smooth manifolds
 
@yuggib Just topological manifolds.
 
@yuggib topological manifolds
 
Smoothness requires more structure.
 
3:59 PM
I see
I don't really care about manifolds
 
@yuggib maybe you should read a geometry book
 
especially finite dimensional ones
 

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