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21:00
@KyleKanos seems kind of useless then :/
"I had a Wii"
No way
Homebrew +infinity
I've got a SNES EMU on there, so I can play any awesome game I want
(e.g., LoZ:LttP, FF 4,5 & 6, MMX, ...)
@KyleKanos "something"?
@ACuriousMind I think it's a piece to a board game, but not sure since it's still in there
Ah, and you can't get it out?
Correct
Sorta
I've not really tried
I need something long and thin, and I don't have any tools that could work
21:03
No Idea how heavy this thing is, but...plastic straw?
(I also don't know how broad the Wii slit is)
Hmm. A straw might work.
I'll have to procure one. I think the midwife gave my wife one
Unsuccessful
The procurement or the removal of the alleged board game piece?
The removal
Is the straw too soft or not the right shape?
@acuriousmind have you ever taken a fluid-mechanics class/know much about the navier-stokes equations?
21:19
@ACuriousMind Too soft, it seems
@ACuriousMind Yo
How do those anti-static "guns" work?
It seems too good to be true
@Obliv I know nothing about hydrodynamics
@BernardMeurer I have never heard of them
@ACuriousMind Supposedly you just point them at whatever you want to decharge
and you press the trigger
and God himself, comes from the sky and takes the static with him to heaven
@Secret, they are currently lower level questions, but we welcome questions of any level, and we would welcome that question, especially if they added more of their own work.
@BernardMeurer Quick googling tells me that there appears to be a piezo-electric cyrstal inside that is struck by a hammer when you press the trigger, which then releases charges that supposedly neutralize the static charge on the surface. No idea how well that works in practice
21:32
@DanielSank, good news: I've made it through derivatives and integrals unscathed. I need to do a little more practice with them, and some work with limits, but otherwise I think I've got basic calculus down fairly well. I'm going to try multivariable calculus next - I found a nice series of YouTube videos on it.
@ACuriousMind I've heard it works, but I don't trust Audiophiles
An anti-static gun seemed like crackpottery
would anyone mind giving an example of a derivative/integral problem that might be used in classical mechanics so I can try my hand at it?
@heather Can it be the mechanics of my poor grades? :P
@BernardMeurer, they can't be that bad =P
@heather They're cancer. I have 10/20 in chemistry :P
And God only knows what I'll get in Analysis
21:35
@BernardMeurer, ooh, I'm sorry about the chemistry grade. You'll be fine in analysis though, I'm sure!
@heather find the work required to pull up a 25m rope with linear mass density 1 kg/m with a 25kg sandbag attached to the bottom that leaks at a rate of 1kg/s
I remember something like that in my old single var calc txtbook
I gotta change majors
CEng is just utter bullshit
oh, boy, okay I'll give it a whirl @Obliv, thanks for the problem
np gl
@heather you learned calculus in one day?
4
21:38
@DanielSank, there was a really good YouTube video series I found that taught it
it explained it pretty clearly
@heather sure. Solve for the position versus time of a mass on a spring with initial position 0 and initial velocity $v$.
I'm 3 months into Calc and I haven't learned a thing yet
@KyleKanos don't care. I might try netplay at some point.
@heather Ryan says "Heather is basically Feynman"
@BernardMeurer, 1. no way am I Feynman =P 2. sorry, who's Ryan?
21:40
@heather @0celo7 is Ryan
@BernardMeurer, oh, I see
@0celo7, thank you =)
I forgot some information for that problem @heather lol, you pull the bag up at 2 m/s
@Obliv, okay, thanks =)
$$||f^\epsilon||_\infty=\operatorname{ess}\sup_{x\in\Bbb R^n}|f^\epsilon( x)|=\operatorname{ess}\sup_{x\in\Bbb R^n}|\int_{\Bbb R^n}\eta^\epsilon(x-y)f(y)dy|\le \operatorname{ess}\sup_{x\in\Bbb R^n}||f||_\infty\int|\eta^\epsilon(x-y) |dy=||f||_\infty$$
if you didn't have that information i think you could just wait until the sandbag emptied then pull it up lol
21:41
@ACuriousMind Is that right
@DanielSank you should try 'faster melee' it's a different type/version of dolphin netplay that apparently has less input lag than a crt.
just have to join the discord and download the latest version I think.
@obe I mustache you a question
user218912
lol
@DanielSank Still haven't tried netplay
@obe But I'm shaving it for later
21:44
On anything for the Wii
I know I'm doing something wrong here and I haven't even gotten to the actual calculus yet...
Work = Force $\times$ Displacement
and Force = mass $\times$ acceleration
and Displacement = $v_0t+ \frac{1}{2}at^2$
@heather I don't think it's possible to learn calc in a day
user218912
I learned calc in ~3 days.
@obe Oh shut up
and I know that the initial velocity is 2 m/s
user218912
21:47
@BernardMeurer I did, basic calc.
and that there is no acceleration, right, because it is moving at a constant rate
@BernardMeurer Ahaha
@SirCumference, why not?
@heather Have you learned all the derivative rules?
Woot...answered my first question in 7 months!
21:47
@heather What is $\int_0^L sin(n\pi x/L)sin(m\pi x/L) dx$, where $n$ and $m$ are integers?
so the displacement equation turns into $d = v_0t$
From Ryan :P
@BernardMeurer God, fix that LaTeX
@BernardMeurer 0
@BernardMeurer, I'll start solving it after I figure out the other two
21:48
$\int_0^L \sin(\frac{n\pi x}{L}) \sin(\frac{m\pi x}{L}) \mathrm{d}x$
@heather the important part is that the mass varies as you are pulling it up. Also, the acceleration that you are concerned with is that of gravity. Remember, there is no work done on an object if there is no force.
@KyleKanos "Go back to high school"
@Obliv, right, I forgot about that. So there is acceleration, duh. Okay, thanks!
@heather Did you only learn power rule?
@SirCumference, I learned about the product and sum rule, or is that not what you're talking about?
21:49
And to be honest, this problem isn't very much calculus as it is physics/general problem solving.
@BernardMeurer No way man. High School sucked
@heather Basically subtracting from the exponent and bringing it down, for derivatives
@KyleKanos Meh, university sucks too
user218912
everything sucks
21:50
@SirCumference, no I didn't learn the power rule...I'll look it up.
@BernardMeurer And I'm glad to be done with that too
Let's be honest here guys, life's a bottomless pit of pain and suffering
And grad school
@heather You're better off learning it in order
And I'm very happy to be working
21:50
Don't go looking for abritrary things
@SirCumference, I don't want to wait four years to learn about what I want to learn about.
It'll make it harder to learn
@heather No, I mean learn the calc concepts in order
@heather That's good
user218912
no
user218912
order is bad
21:51
@obe Stop
@obe You're a dirty anarchist
You're not helping
@SirCumference, oh. I am trying too.
@heather So I'd hold off on whatever you don't know until you get to it
@bernard what's wrong with anarchy
21:52
@Obliv It's for kids
false argument
@BernardMeurer Silly rabbit, anarchy is for kids
Anarchy is for people who think they want no order but really just want to be in charge themselves
3
@heather Try learning maths the way I learned programming, be the guinea pig :P
@heather Pick a problem, learn the tools to solve it, solve it, repeat
@heather Did you finish algebra 2 and trig yet?
21:53
I taught myself trig
user218912
best way to learn anything is to jump into the deep end.
and most of algebra II
@heather Learn it all first
@heather And the inverse trig functions?
@heather What's the sine of 2$\pi$?
With the unit circle definitions?
21:54
@BernardMeurer 0
@kylekanos Do you think anarchy is only achievable through an external influence? I think nature just orders things by itself (at least in the context of animals, what with the DNA & biological functions)
@BernardMeurer 12
@KyleKanos Wrong, it's 12
2
@SirCumference Perfect
@BernardMeurer, 0
@heather What's with you people, 12!
2
21:55
@Obliv The thing that is, in all seriousness, wrong with anarchy is that no one has shown an example of a stable anarchy without being imbeded in a surrounding non-anarchic sociaety that provides a norm of peace and order.
user218912
it gets dark so early now
@sirC if she wants to learn some calc let her. She's going to fill the holes eventually, I'd hope, with like 4 years of hs ahead of her.
@Obliv I don't think anarchy is achievable because humans are too domesticated.
@Obliv It'll be easier if she knows algebra first
Vernor Vinge has offered some fiction portrayals of how that might work, but no one knows for sure.
21:55
Really lots of things will be easier if she learns algebra first
I'm stuck with the physics part of your problem @Obliv, I don't know how to calculate the acceleration.
In a sine you just take one leg and the hat off the $\pi$ and then the number multiplying it goes after that. So $\sin(2\pi)=12$
3
@BernardMeurer Oh god XD
@SirCumference, I'd like to think I know algebra well enough to carry on. I have most of it, if I come up against a gap, I can go back and fill it in.
@heather I'd still learn all of algebra first
user218912
21:56
most calc books will cover the algebra you need in the back.
You won't know when you come across a gap, sometimes
user218912
so just look at that
Even outside of calc, algebra can be helpful if you know its entirety
@dmckee do you mean an example in nature? Surely it's not necessary to provide a real example of anarchy when it's just a theorized way of life (or death). Doesn't mean it can't happen, does it?
You won't know what you missed if you don't finish it
21:57
if an object's mass is changing, its acceleration is changing
It'll really only help you, and a lot
@SirCumference, I do have the actual class Algebra II next year
@kylekanos Well, I think there are ways to reduce the order (global crises,natural disasters, etc) but to have no order might be impossible.
which is key to the whole equation
@Obliv We have plenty of examples, most of them either develop into tribal system or get conquered. Sometime both.
@heather The acceleration is not changing. it's always 9.8 m/s
In case anyone missed out on this gem
@Obliv As soon as you have 2 people, one will naturally become the de-facto leader
user218912
@heather that doesn't mean anything
the force is changing, though.
21:58
The basic problem is that organized humanity is more powerful than unorganized humanity.
@Obliv, oh, wait, I know what I did wrong
So unless all the organized types are willing to let you mremain unorganized you're in trouble.
okay, rewinding =)
@Obliv Didn't realize she meant gravitational acceleration
Somehow...
There are a few counterexamples, but all of them recieve the benifit of protection from a surounding organized society.
So, the fun part is trying to figure out how to get a resistance to organized attack that will work in a reasonably anarchic society.
And that's non-trivial.
22:00
@kyleK @dmckee so basically you're saying it's an incompatible way of life for people
@Obliv Correct
More like the few #@()*&%#*s among us ruin it for everybody else.
has the fundamental reason to do with a well-ordering of desires within the genetic makeup of people?
"This is why we can't have nice things..."
@heather Btw we were kidding about the whole $\sin(2Ï€) = 12$ thing...
22:02
@Obliv Honestly couldn't say. I just think people are more comfortable with rules being in place
@SirCumference, I thought so, judging by the number of stars by the statement =P
@kyleK is anarchy a system with no government, or one without order? I thought it was the latter, which is why i asked that.
user218912
why are we even talking about anarchy?
user218912
i meant no order as in don't learn stuff in order.
i.e something like the lifestyle of lions would still be non-anarchy.
user218912
22:04
and i was joking
@obe well I asked the question because it was brought up. it's nice to hear opinions from people sometimes.
@Obliv I think it colloquially is used to mean no "big" government, but it's supposed to mean no government at all
@Obliv Self organization that you can opt out of without any cost beyond not being part of the ordered activity is generally included under the notion of "anarchy".
@dmckee Woah
Serious question
How long have you been a mod?
I never noticed your blue text before...
user218912
do you ever notice anything?
22:09
Hmm okay I see then. I might be wrong, but, I think somalia was under an anarchy at some point in the near past. Never really confirmed this but this isn't a counter-example to your argument because it existed inside of a non-anarchy system, right? @dmckee
@obe no but seriously how long has he been a mod?
@SirCumference since the beginning of Physics...
@KyleKanos whoa....
@Obliv, so here's the equation I've got so far (I simplified a bit from the original):
$W = (245 \text{kg m/s} + 9.8(-t)\text{m})(\frac{11.8t\text{m}}{2})$
At least I think so
22:10
where $t$ is of course time, $W$ is work, and the text is the units
what is $m$ @heather
@Obliv, meters
and kg m/s is kilogram meters per second
@Obliv It didn't have a internationally recognized governement, but it did have half a dozen clans and strongmen. Most people had someone who could tell them what to do most of the time.
That's called "anarchy" by people who think recognized governments are special, but not by people who take the concept seriously.
And the fact that those clan leaders and strongmen appeared and took power is exactly the problem.
You need to figure out a way to not have a centralized government and still keep those people from popping up.
And that's hard.
@dmckee Question, our astro prof said that everyday matter is nearly degenerate
Is that true?
As in, almost all the fermions are near their lowest energy states
@SirCumference Well, the atoms are mostly not excited, so that's an defensible position to a certain way of thinking.
And exclusion plays a role in the structure and behavior of solids.
22:15
@dmckee Cool, because he took out a coin and said "this is degenerate"
But I wouldn't use of condone the phrase myself.
@Obliv, am I doing this really wrong, or is it alright?
@heather working through it now, but I don't think that's right (or it's in a form I can't quite recognize)
@Obliv, okay, should I post the work I did?
that would be helpful, yes.
22:16
Simply because I like to ephasize that "degenerate matter" has a different set of properties from ordinary solids.
@dmckee Simply because all the energy states from the ZPE to the Fermi energy are occupied?
I got $M_{total} = M_{sandbag} + M_{rope}$ where $M_{sandbag} = 25 - t$ and $M_{rope} = 25 - 2t$ so we have $M = 50 - 3t$ , is this what you had @heather
That leads to such a huge difference in properties, from ordinary matter?
I mean, you just said that the atoms are mostly not excited
@Obliv, oh, I didn't add in the rope's weight, darn, okay, I'll do it again
@SirCumference Because there are few accessible modes for a lot of constituent particles.
But I have to go. Take care.
22:17
@dmckee Ah, makes sense
@dmckee Bye
@obe Question
.
@heather okay let me know when you want the solution
@Obliv Please use \mathrm{d}x
It looks prettier
@Obliv, okay, thanks
@dmckee but not impossible ;) But for all practical purposes and being relevant to reality, I agree.
{\rm d}x also works
22:19
@KyleKanos Lame...
$\text{d}x , dx, \mathrm{d}x$
\mathrm is the way to go
you could just use \text{}?
@Obliv No, mathrm is for symbols
Or units
Text is for words
it's the same exact thing.
user218912
22:20
what
@Obliv No, mathrm is more mathy, can't you read it?
@SirCumference Only because it's more "standard" or something
$\text{d}x$ <--- text $\mathrm{d}x$ <----- mathrm
literally no difference.
@KyleKanos I just proved mathrm is specifically made for math
Proof: it has math in it
They do different things really. \mathrm takes arguments, \rm modifies the equation environment
22:21
@Obliv, okay, now I've got $W = (490 \text{kg m/s} - 29.4t\text{m})(\frac{11.8t\text{m}}{2})$
82
Q: Is there a preference of when to use \text and \mathrm?

yunoneI'm unsure of when it is preferable to use \text versus \mathrm, is there some unwritten rule about the use of these? For example, I saw the following code in a math post: \frac{\mathrm{lcm}(m,n)}{\mathrm{gcd}(m,n)}\quad\text{divides}\quad \frac{\mathrm{lcm}(m,n)}{|\langle x\rangle\cap\langle ...

Better detail than I can
3
Q: How to write maths symbols

LauraI have written in my work $X^{+},\,\rm{e}^{X},\,|X|^{p}$. Why is the second and third term not in italics?

I realized something else I did that may be kind of funky: I reduced it such that for all $t$ you ignore the units (I assumed $t$ was in seconds and simplified in that manner, which I probably shouldn't have done).
I keep making all these stupid mistakes. I'll rework it without the $t$ weirdness.
what is that 11.8/2 term on the right @heather
can you show me the integral?
$$\Huge \color{purple}{\LaTeX}$$
22:24
@Obliv, okay, now I know I'm doing this really wrong.
Here's what I did:
$F = ma$
$d = v_0t+\frac{1}{2}at^2$
$W = F\times d$
$m = 25 - t+25-2t$
$m = 50\text{kg} -3t$
$F = 9.8 \text{m/s}(50\text{kg}-3t)$
$d = 2 \frac{m/s}t+\frac{1}{2}9.8\text{m/s}t^2$
$W = (9.8\text{m/s}(50\text{kg} - 3t))(2\text{m/s}* t+\frac{1}{2}((9.8\text{m/s}) (t^2)))$
@heather oh my. yes, that is wrong. But, you had the right idea with W = f*d
@heather Be sure to use \times instead of *, in LaTeX
@Obliv, where did I go so wrong?
You dont' need to invoke any kinematic equations. We know the distance that you're pulling the rope. It's going up 25 meters, the rope length. That's how you have the mass of the rope as 25 - 2t (the mass during the whole trip)
right
and you're pulling it at 2 m/s
22:30
The force of gravity acts during the whole trip up, right?
sright
right
so if $W = F\times d$
(Assuming gravity is real)
and the displacement is 25 meters?
The speed at which you pull it up is irrelevant, except to determine the variable mass of the sandbag. You could pull it up at 100 m/s or 1 m/s, the work will be the same. You are familiar with this concept? @heather
@Obliv, I don't really know much of any classical physics, sorry. I didn't know that.
22:32
Well, we know the mass varies during the trip with the given relation M = 50 - 3t and at each moment in time we have a different mass and thus a varying force. If the force varies, the work will vary, in this situation. That's where the integral comes in.
so F = ma, then we know that it'd be F = (50kg - 3t)(9.8 m/s) and then it'd be that times 25m?
@heather well, that's very important to know lol. It's $W = \int F~\mathrm{d}x$ which say nothing about time, assuming a is constant.
@Obliv, I'm confused now, how did we get the integral?
Not quite, we have a varying force at each time interval that we pull it up. It gets easier to pull up as we get closer to the top. So, we must take the limit to infinity of a riemann sum of the forces at each interval. Can you picture this?
Oh you didn't know the integral definition of work D: that's very important for this problem!
@Obliv, yeah...sorry!
22:36
It's fine. Did you go over the definition of an integral by taking the limit of riemann sums when you learned calc, btw? @heather
Hello everybody
@Obliv, well, I know that the Riemann sum has to do with using rectangles of a specified width just under and just over the curve you are trying to find the area of, but beyond that, not really.
And then as the width of the rectangles approaches zero, the more and more accurate your area calculation gets.
Okay. So, let's say we had a graph of the force w.r.t time during the trip. You agree it would look like a line with y-intercept y = 50 and a slope of -3?
Yes, exactly.
I suppose so, yes
yes it would
If you took a finite amount of rectangles to sum the forces during the whole trip and multiply that by the acceleration, you agree it would lead to a close-but not completely accurate result?
22:40
yes
I have a simple question, please help: what does it mean when angular frequency is expressed in electron volts? and why is it for?
Well, that's why there is an integral. If the force was constant the whole time (suppose the bag wasn't leaking and the rope was massless), you wouldn't need an integral, but for the times when it isn't constant, it's necessary.
So now, we know the precise equation for the force, that is $F = (50-3t)(9.8)$. We just need to integrate this over some interval. Can you think of some interval?
a time interval? a second, maybe?
or, well, actually, no
we'd do it over the time it takes to pull the rope up, right?
Exactly. That equation yields the exact force at each time $t$ during the interval. We need to sum these forces during the trip to get the work done.
12.5 seconds, right? because 25m of rope, and 2m/s is the speed you are pulling at
22:43
we'd need an infinite amount of slices of time so we have something of the form $\int_a^b F~\mathrm{d}t$ where $a,b$ is the beginning and end of the trip in terms of time.
yep. you got it.
oh, so $\int^{12.5}_0 (50 - 3t)(9.8) dt$?
yes
=D okay, I'll solve that
one moment
0
Q: Would it have been possible to send a manned mission to Mars using Apollo technology?

JamieTheBastardTo clarify, I am writing a science fiction story in which a manned Mars mission in 2025 discovers a previous manned mission to Mars sent in the 1990's using modified Apollo lunar technology. Even though it is science fiction I want my story to be as scientifically accurate as possible. For exampl...

^engineering?
@ACuriousMind Is engineering not a part of physics?
22:53
@SirCumference No. One of our close reason is explicitly about a question being about constructing a solution to a particular problem using science (which is engineering) instead of about the natural science of how the world works (which is physics).
@ACuriousMind So applied physics isn't physics?
Only theoretical physics counts?
No. Experimental physics also counts. But applied physics is engineering.
@ACuriousMind Never heard someone say "Applied physics isn't physics"
Now you have.
@ACuriousMind Now I know.
22:55
It isn't though @sirc is it the case that sports (an application of setting up rules for a game) are the same thing as theorizing games?
@Obliv You gotta be more specific when you say "games"
Sports are specifically meant for exercise
Sports are physical games basically
@Obliv Nah, chess is a sport
That's mental exercise
Eh I'm not getting into this lol I do not think chess is a sport in the usual definition of the word. A mental sport, competitive game, game, sure.
@heather do your calculations with symbols instead of numbers.
23:00
@DanielSank, for your problem or Obliv's problem?
@heather any problem.
This is one of those really important habits that makes science/math a lot easier.
@DanielSank, use symbols instead of numbers...okay, I'll try it.
nobody can help????
I agree with Daniel even though I hardly ever do it myself lol
I'm doing something really wrong, I'm getting a negative number (::sighs::) I'm thinking I need more practice =)
work is not negative =P
oh, wait, I see what I did wrong
doing it again
23:17
I think the answer is around 4000 joules. Make sure you're separating the integral and performing the power rule correctly. Have to do a lab now so I leave u in the good hands of hbar @heather gl
@Obliv, thank you for the problem and help!
have a good day
okay, so given the integral $\int^{12.5}_0 (50-3t)(9.8) dt$
you can then have $\int (50 - 3(12.5))(9.8) dt - \int (50 - 3(0))(9.8)$, right?
then I need to use the product rule...
Noon Heather use the fundamental theorem of calculus pt 2
Noo** argh phone corrections.. $\int_a^b f (x) dx = F (b) - F (a)$ where F is the antiderivative of f
@heather And now I am off. Np
@Obliv, okay, thank you for all your help!
Wonder if I can hit 20k before I go back to work
That's only like 1k rep in about 10 days
@KyleKanos If I ever drop by SC will you buy me ice cream?
23:32
so confused by integration. I clearly have not got it. =/
@BernardMeurer Probably not, I'm not in SC anymore
@KyleKanos :(
I wonder if I understand differentiating as much as I thought I did...
23:51
@heather "Remember your Banach space rules"
what, we never did banach spaces =P
though there was many a mention of them =D
@heather Probably because they're fake
banach spaces aren't real?
=(
rob
rob
@heather No, but you can anagram the letters in "Banach-Tarski" to make "Banach-Tarski Banach-Tarski"
3
@KyleKanos $L^p(\Omega, \mu)$

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