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12:04 AM
I just got destroyed
Holy shit that was a hard test
 
@0celo7 He probably scaled it
 
@0celo7, in what?
 
Grad QM
Two people finished
Out of 40
 
@0celo7 Grad?
 
Graduate level
@SirCumference sexist
 
12:11 AM
@0celo7 ...
 
wow, that sounds hard
thank goodness middle school tests are a tad easier =P
 
@0celo7 Help me with chem plz
 
Can someone help with the above question?
47 mins ago, by heather
I have the problem "What is the principal value of arctan(2.6)?" and I have no clue how to begin.
 
@heather Like a psychopath, let's go by parts
Do you know what $\tan(x)$ is?
 
Yeah, it's the sin(x)/cos(x) or the y/x (or maybe I flipped the order on those?)
 
12:15 AM
I'll call you from the car ok
 
no, that's correct
 
oh, okay
good, I remembered right =)
 
@0celo7 Yes, okay
 
How long are you going to be awake?
I have to do homework due at midnight. Reb is driving us to AL
 
@0celo7 Not much longer
just call me dood
 
12:25 AM
@BernardMeurer, so then how would you get from $\tan(x)$ to $\arctan(x)$?
 
@heather do you know what the arctan does?
@heather Sorry for my intermittent and subpar help, studying right now makes it hard to multitask
plus the flu
 
@BernardMeurer, oh, man, you have the flu? Hope that gets better soon! And homework, too? Wow, I'm sorry. But anyway, arctan is the inverse of tan, I know that, but I'm not quite sure what that means in this context. I know that normally inverse is 1 over whatever number, or if it is a fraction, flipping the numerator and denominator (which is basically the same thing, because any whole number can be written as a fraction).
 
@heather I have an important Chemistry exam tomorrow morning :)
I hate chemistry fyi
 
@BernardMeurer, right, because you're a computer science major (right?)
 
@heather Computer Engineering
 
12:30 AM
Good luck! (and sorry, because it's terrible to study for something you don't even like, and double sorry, because I mixed up your major)
=)
 
I feel like I should have gone for CS now that I look back though
Anyway, I digress
(@heather Don't worry ;))
 
@BernardMeurer she won't let me
 
@ACuriousMind > There's no continuous set of generalized position operators - not ever a position operator at all - and hence no "wavefunction".
This is a nice way of wording my long-time hate for the wavefunction approach
 
12:50 AM
@EmilioPisanty, that last picture is just a trivial modification of this one, duh!
 
@DanielSank Mixes up my majors all the time and I still love him
 
@SirCumference The reality is that, for many (most?) professionals, taking seriously the opinions of those that disagree with you is, in fact, a pretence. That is, don't take take seriously those that claim to take your opposing opinion seriously.
 
$\arctan$, anyone?
If anyone is interested in a trig discussion.
=)
 
@heather go to math chat room
 
1:06 AM
@Ramanujan, okay, thank you
 
1:47 AM
@BernardMeurer wut?
 
rob
2:14 AM
Evening, all
 
user228700
Morning :-)
 
rob
A round world is a strange thing
 
Rob
Can I ask you a question?
 
2:29 AM
Don't ask to ask
 
rob
@SirCumference Only one, and that was it.
 
@rob :(
 
rob
From here on, statements only.
"I wish you would tell me about X"
 
I wish you would tell me if the following is correct or not: At some time t, is the scale factor just the ratio between the proper distance of an object from us at time t and its distance now.
 
rob
I dunno. Cosmology isn't my strong suit.
 
2:30 AM
All right, thanks
btw @0celo7 can I ask you something?
 
rob
2 mins ago, by 0celo7
Don't ask to ask
 
Fine
@0celo7 I wish to ask you a question
 
user218912
request an answer to your question.
 
user218912
or, demand it?
 
@obe You oughta post more answers here
I'm serious, join the > 200 rep club
 
user116211
3:19 AM
Won't say one of the best answers; but not that bad also:
 
user116211
2
A: What are the goals of this site?

Cursed1701I am an A level physics student, and whilst I see people using this as a homework site, there are students like me who use this site to expand knowledge through asking questions and viewing others' questions. Therefore, I think the goal of this site is to teach through community knowledge, to gr...

 
rob
3:33 AM
@MAFIA36790 Yeah, that's not bad.
 
user116211
3:44 AM
Hmm...
 
user116211
3
A: What are the goals of this site?

Cursed1701I am an A level physics student, and whilst I see people using this as a homework site, there are students like me who use this site to expand knowledge through asking questions and viewing others' questions. Therefore, I think the goal of this site is to teach through community knowledge, to gr...

 
user116211
Poor lad :(
 
user116211
AARRRGGGG!!
 
user116211
Timeout :(
 
user116211
I meant this:
 
user116211
3:49 AM
163
Q: Previous company name is ISIS, how to list on CV?

KogeshoThe previous company I worked at for 6 months is named ISIS. It was founded way before the terrorist organization of course, and now it is a bad coincidence that I list ISIS as work experience on my CV. I am afraid of this name affecting my future job applications as the name ISIS is associated ...

 
although interestingly I'm off from LIGO's claimed event timing by 15 seoncds
despite using their recommended library to parse their time data
\o/
Although it's possible I missed something else there :P
 
rob
4:06 AM
@GPhys That's potentially interesting, since the Fermi telescope detected a possible faint one-second transient in coincidence with the 2015-09 event. Most likely outcome, as you say, is that you missed something.
 
0
Q: I don't understand what is "unclear" with my question

Misuser I have a question about my Physics Stack Exchange post: Possible reactionless drive My question is [on hold] as "unclear what asking". From my analysis the system should work and start to move after photons injection on trajectory and my question is if someone find an error in my reasoning a...

 
user116211
@PhysicsMeta WoW! That's good.
 
user116211
A newbie is airing his grievance in Meta!!
 
user116211
Without any ranting in the main page ;)
 
user116211
This made my day \o/
 
user116211
4:32 AM
0
Q: Kinetic energy storage via superconducting loops aka LHC but with much more massive projectiles

hrmwhataboutHi I have an idea floating around i've always wondered about.. Would it be possible to use the particle fountain concept to store kinetic energy? ie. use magnetically suspended ..uh physical magnets i guess, rather than beams... like a circular gauss rifle? I would suppose that this idea would be...

 
user116211
Mainstream? A legit query?
 
rob
@MAFIA36790 Vote up, then.
 
user116211
Morning @JohnRennie.
 
user116211
@rob sure.
 
rob
@MAFIA36790 Also thanks for fixing the tags there.
 
4:36 AM
Morning!
 
user116211
No need to thank. That's my responsibility as a responsible user and editor here :)
 
@SirCumference Yes, provided both objects are comoving i.e. stationary in comoving coordinates.
 
@JohnRennie Ah, awesome
 
@BernardMeurer dude
 
rob
@MAFIA36790 My feeling is that the user means well.
 
user116211
4:40 AM
Hey hey @0celo7.
 
user116211
@rob okay.
 
And since the scale factor can be thought as position, then the second derivative would be acceleration. And since the second derivative is positive, we'd get an accelerating universe?
 
user228700
Hello everyone :-)
 
Morning :-)
 
user228700
I've a quick...math question regarding linear programming.
 
4:47 AM
@SirCumference Yes. If you're interested I answered a question along those lines. If you want I can have a search for it.
 
@JohnRennie Sure
 
@Kaumudi you can ask, but it's a looooooooong time since I did any linear programming.
 
user228700
 
user228700
(The last question)
 
user228700
@JohnRennie That's OK, I don't have any problem with the mathematical aspect of the problem.
 
user228700
4:49 AM
I just don't understand what the question is asking me to do.
 
user228700
I mean, I don't even have enough of an idea to tell u what I think the question means.
 
@Kaumudi Well you have a function $z$ that is a function of $x$ and $y$, and you're asked to find the value of $x$ and $y$ that minimises $z$. OK so far?
 
What is a-goin' on here?
 
user228700
Well, yes. Hang on, I think I have some idea. Will u till me if I've got it right?
 
OK ...
 
user228700
4:55 AM
So I need to produce those many clothes and I've employed two tailors. I need to pay them Rs. 150 and Rs. 200 for every day they work for me. I need tailor A to work for $x$ days and tailor B to work for $y$ days, so that at the end, I have at least 60 shirts and 32 pairs of pants with me. And I need to minimize the amount I spend, ie. $150x+200y$.
 
user228700
Does this describe the situation correctly..?
 
user228700
@DanielSank Linear Programming!
 
user228700
..?
 
Ah, I was looking at the wrong problem. Hang on, let me reread it ...
 
user228700
Oh! OK :-P
 
user116211
5:00 AM
@Kaumudi Sounds okay.
 
user116211
Now make the constraints.
 
@Kaumudi yes, minisise $z = 150x+200y$ subject to the constraints $6x+10y\ge 60$ and $4x+4y\ge 32$
 
user228700
I've made them. I'm not going to draw the graph and everything-gonna leave it at that.
 
user116211
Also $x, y\gt 0\,.$
 
user228700
Is it just me, or could the question be worded better..?
 
5:02 AM
@Kaumudi I should know what that means.
 
user116211
The question sounds okay.
 
user116211
@DanielSank o/
 
@MAFIA36790 True :-)
 
Oh, constrained maximization.
@MAFIA36790 \o
 
user228700
Huh. It took me awhile to understand the question properly. I feel that it could've been worded better :/
 
user228700
5:03 AM
@DanielSank Yeah :-)
 
@Kaumudi it seems clear to me ...
 
user228700
It wasn't immediately clear to me that I'm the one employing the tailors...
 
user228700
Anyway, thanks, guys :-)
 
@SirCumference I think I was remembering this, which is only slightly related:
4
A: Accelerating expansion of the universe: so?

John RennieThe Hubble constant is defined by: $$ H = \frac{\dot{a}}{a} \tag{1} $$ where $a(t)$ is the scale factor as you describe. Acceleration means $\dot{a}$ is increasing, but then of course $a$ is also increasing so how $H$ behaves with time depends on which of the two increases faster. We can calcul...

 
@JohnRennie Thanks though
 
A big chunk of quantum computing is about maximization problems.
@heather know when you're in socal yet?
 
user228700
Not to alarm anyone, but I've started to design my schedule for the day depending on who comes online at what time :-P @JohnRennie: After 10 AM here, (which is mostly when u come) I study Physical Chemistry/Physics :-P
 
@Kaumudi Sounds reasonable.
 
:-) Your time is 5:30 ahead of GMT? So 10:42 right now?
 
user228700
10:45 AM :-)
 
user116211
5:22 AM
@MetaEd?
 
user116211
Anyone flagged again?
 
user116211
Hmm ;/
 
@MAFIA36790 Just routine. Nothing to see here.
 
user116211
ohh ::sigh::
 
What happened last night? A quick glance through the log suggests something kicked off yesterday evening.
 
user116211
5:34 AM
@JohnRennie Huh; the flag stuff; you know.
 
Flag stuff?
 
user228700
5:48 AM
Does anybody know a formula for bond order that does not involve MO (molecular orbital) theory?
 
user228700
Almost literally no one is online at the CSE Chat, so I'm asking here: I'm learning about the 3 center, 2 e- bond in molecules such as $B_2H_6$.
 
user228700
 
@SirCumference gravitational waves travel at the speed of light, but light doesn't always travel at the speed of light! In GR the speed of light is always locally $c$ i.e. if you measure the speed of light at your location you will get the result $c$. However at locations distant from you it can be greater or less than $c$.
 
user228700
Few things to notice: The bond lengths of the normal, terminal bonds with hydrogen are shorter than the bridging bonds.
 
user228700
Secondly, the angle are larger for the terminal bonds when compared to those of the bridging bonds.
 
user228700
6:00 AM
I'm thinking, the bridging bonds are weaker, hence they are longer? And OK, as a consequence of them being longer, the angles are smaller?
 
user228700
And thirdly, I dunno how important this might be, but I'm unable to make sense of why the B-H-B bonds are smaller than the H-B-H.
 
user228700
So, yeah, am I correct? And what about the last point?
 
user228700
(I hope I don't get banned for asking questions relating to Chemistry here, like all the time :-P)
 
@Kaumudi Bearing in mind I never knew much about inorganic chemistry and have forgotten most of what I knew ...
 
user228700
Sure, do go on...
 
6:06 AM
Suppose you start with borane, which is planar, then form a dimer by hydrogen bonding between two of the BH bonds.
You'd end up with something like the structure you posted but with very long bonds between the two BH3 molecules.
 
user228700
Uhh, I'm a little wary of using the term hydrogen bonding, but OK...
 
Now mix in a bit of resonance, which will make the dimer bonds stronger and more symmetrical.
And you'd get something like the structure you posted.
 
user228700
Erm, OK...
 
The terminal HBH bonds are roughly the same as in borane and have roughly the bond angle as in borane. They're just a bit distorted.
 
user228700
Right...
 
6:09 AM
Meanwhile the bonds forming the dimer are still weak and long because they're kind of intermediate between a full bond and a hydrogen bond.
 
user228700
Uh huh...
 
I think that's the best I can do in an arm waving kind of way.
 
user228700
Okay, thank you :-)
 
hi everyone?
I mean ! :P
 
user228700
Hi :-) (:-P)
 
user228700
6:49 AM
@JohnRennie The problem is:
 
Yes ...
 
user228700
 
user228700
So, that's why I said:
 
user228700
46 mins ago, by Kaumudi
Uhh, I'm a little wary of using the term hydrogen bonding, but OK...
 
user228700
Anyway, never mind just now...I'll ask DHMO/Orthocresol when they arrive. They know a lot of inorganic chemistry :-D
 
6:56 AM
I concede that the B-H bond is not very polar because the difference in electronegativities isn't very great.
 
@JohnRennie Elaborate?
 
My point was that if you start with two planer BH3 molecules you can imagine gradually increasing the strength of the interaction between them. And as you do the originally planar BH3 moles get distorted into pyramids and the bonds between then get shorter.
 
user228700
@JohnRennie Hm, OK...
 
@SirCumference I've answered loads of questions on this subject. Let me see if I can find a suitable answer ...
 
user228700
@JohnRennie Yeah...my textbook (not reliable, but still) says that hydrogen bonding tends to happen in/among those molecules which have the atoms F/O/N.
 
user116211
6:59 AM
Maybe I say it as imaginary particles , that would be better. — Lincoln 14 mins ago
 
user116211
WTH is that O.o
 
@Kaumudi that's a reasonable statement. Only the more electronegative atoms will produce a big polarisation of the X-H bond.
@MAFIA36790 complete gibberish :-)
 
user228700
Hm, OK...
 
user116211
@JohnRennie yeh, I guess so.
 
9
Q: Speed of light in a gravitational field?

user28936How do I solve the speed of light in gravitational field? Should I just add gravitational acceleration in speed of light? $$c'=c_0+g(r)t~?$$

 
user228700
7:01 AM
Sigh. There's still nobody at the CSE chat. Better do something else now...
 
user228700
@JohnRennie: Conservation of Momentum again :/ Do u mind..?
 
user228700
(Quick question)
 
user228700
So we can conserve momentum only when there are no external forces, yes?
 
user228700
(Sorry. Just being thorough :-P)
 
7:06 AM
Yes
 
user228700
My number one confusion is when something's at rest and has zero momentum but then I exert some force and now it does have momentum >.<
 
user228700
Oh, wait.
 
user228700
Whatever that exertnal force-exerting object is, I include that in my system and now I conserve momentum, yeah?
 
user228700
Omg, we've been through this so many times. Idk why I still haven't understood it aaah! >.<
 
Yes, exactly. When you push the object it moves in one direction and you move in the opposite direction. Overall the momentum is conserved.
 
user116211
7:09 AM
Hey @Bernard!! What about the test?
 
user228700
I feel like my brain has this thing where it just cannot understand this principle. Not even if it tries for 2.5 years.
 
user228700
@MAFIA36790: Resnick and Halliday any good for conservation of momentum?
 
user116211
@Kaumudi You are saying it right; but still you claim you don't understand; weird for me, at least.
 
user228700
Yeah, it is weird :/
 
user116211
@Kaumudi Well, any book does explicitly make it clear.
 
user228700
7:12 AM
I do understand... and then, while doing problems, my brain is like "Hey hey! The hell is this?!"
 
user116211
I think you know the principle; it's just you get confused applying it.
 
user116211
For that, I would say do more problems.
 
user228700
OK, I'm clearly exaggerating, but yeah, OK, I'll do some more problems now...
 
user116211
WoW! Herstein asks to prove Cantor's Theorem in his problems ;P
 
user228700
@DanielSank: Turns out, the two blocks can move together, the spring touching both blocks:
 
user228700
7:18 AM
 
user228700
 
user228700
(@MAFIA36790: Isn't this what u meant BTW?)
 
user228700
@DanielSank: I feel like the same principle should apply, even when the front block is initially at rest.
 
user116211
@Kaumudi Well, that was the explanation; but I was talking about a problem you would see quite related to yours in the examples after the chapter.
 
user228700
@MAFIA36790 Oh, OK...
 
7:21 AM
@SirCumference: since you edited my answer I take it you've read it and it makes sense :-)
I thought only @MAFIA36790 was allowed to correct my $d$s to $\mathrm d$s :-)
 
user116211
@JohnRennie I did; check.
 
Oh yes, SC edited some of them and you corrected the rest :-)
 
user116211
Huh!
 
user116211
Hmm; it has been over five days I haven't touched Lanczos :(
 
user116211
I must read it today or all I'd forget the things I've learnt ;/
 
7:32 AM
@Kaumudi Yeah, that's ok as long as the spring is at its natural extent.
 
user116211
0
Q: Fate of an object in between two rotating black holes

Naveen BalajiMy question comprises of three parts: First part : What would happen to an object if it is present in between(let's say at the exact centre) two black holes(exactly identical),rotating in opposite directions? Second part : What would happen to the object when the black holes(same conditions as...

 
user116211
Too many questions in a single post?
 
Yeah, I'd say so
 
7:57 AM
@MAFIA36790 Also vague.
"What would happen if..." questions are not particularly good.
 
user228700
@DanielSank Huh. Something I still don't understand is how the compression keeps increasing :/
 
user228700
This would mean that the net force acting on the spring is in the forward direction, but this force is decreasing, no..?
 
user228700
OK, as long as this force is greater than the tension developed in the spring, I guess it would keep on getting compressed, and then at max. compression, the tension in the spring would cancel this force. Is this correct..?
 
user228700
I dunno why, but I myself am not so convinced by this :/
 
user228700
8:12 AM
Maybe I should think about it in terms of the difference in velocities of the two blocks connected to the ends of the spring..?
 
user228700
Can someone please help me to understand this?
 
user228700
🙏
 
user116211
What is the problem?
 
user228700
The same...
 
user228700
Hang on, I'm watching a small video about this (I think :/) I'll check if I understand...
 
user116211
8:29 AM
0
Q: Understanding the Susceptibility Tensor

VIPWhen an electric field passes through a dielectric medium, it causes polarization for the medium, and we define the electric susceptibility $\chi_e$ at some point in the dielectric as:$$\vec{P}=\varepsilon_0.\chi_e.\vec{E}$$Where $\vec{P}$ is the electric dipole moment per unit volume and $\vec{E...

 
user116211
Depends on the property of the substance concerned?
 
@Kaumudi this all becomes ridiculously simple if you work in the centre of mass frame ...
 
user116211
Hello @VIP; welcome to The h Bar.
 
user116211
0
Q: Time Domain Reflectometer

AmmyHow can I analyze the data time domain reflectometer measurement from this picture?

 
user116211
Homework?
 
8:38 AM
Doesn't look like it
Unclear, I'd say. What sort of analysis do they want to do?
 
user116211
okay.
 
VIP
8:59 AM
@MAFIA36790 Thanks, the question above is mine.
 
user116211
I know :)
 
VIP
What do people do here ?
 
user116211
We talk maths, physics, current affairs, video games, shows - everything here.
 
user116211
@VIP Most important thing?
 
user116211
We help each other here ;)
 
VIP
9:06 AM
cool
 
user228700
@JohnRennie Tell me, Sir. How to work in that frame?
 
user228700
Aw man, did u leave? I fell asleep and took a nap for 'bout 30 mins :/
 
user228700
@MAFIA36790 U put Maths before Physics. Nice :-P
 
user116211
@Kaumudi The weather is humid here; and AC is not working; it's Saturday; the service is closed now :( I can't even think of a nap ;/
 
user228700
9:22 AM
@MAFIA36790 It's not humid here, which helps. Still, it is relatively very warm. Too warm, some feel. Not me! :-P
 
user228700
@JohnRennie: If u don't feel like killing me for being so dumb, I hope u'll teach me how to work in that frame whenever u are free. My textbook never works in that frame!
 
user228700
9:50 AM
@MAFIA36790: Are u busy? I've a quick question...
 
user116211
Ask; will respond if it is needed.
 
@Kaumudi hi, I'm back if you you still want to know how to use the centre of mass frame ...
 
user228700
OK. When a bullet is fired from the barrel of a gun, if the bullet+gun system is considered, the net momentum must remain the same, before and after the trigger is pulled, since no external forces acts on the system. So, as the bullet moves in one direction, the gun recoils in the opposite direction, hence conserving the momentum of the system. The explosion of the gunpowder causes the bullet to propel forward. Which force causes the gun to recoil?
 
user228700
@JohnRennie Yes, yes!
 
OK let's go back to your blocks problem but ignore the spring for now so we just have the two blocks. Give me moment to draw a diagram ...
 

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