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user218912
12:13 AM
@heather what's beautiful about it?
 
user218912
it's like a basic proof
 
simple is beautiful
 
user218912
yes but there is nothing special about it.
 
user218912
you do it in the most standard way.
 
12:35 AM
@bl00 wtf is enriched UC?
 
user218912
@0celo7 what?
 
user218912
what do you mean?
 
I have no clue
4% enriched UC showed up on my homework
and I have no clue what it means.
 
user218912
what homework?
 
user218912
nuclear engineering?
 
12:37 AM
yes
 
user218912
no idea, googling doesn't help either.
 
ah
Uranium Carbide.
 
user218912
that's what I thought
 
user218912
but I've never seen uranium carbide before
 
So it's UC with 4% U-235.
 
user218912
12:39 AM
so I thought it would be dumb to say that since I thought it didn't exist
 
user218912
yes
 
@bl00 it's used in experimental reactors IIRC
 
user218912
experimental reactors?
 
user218912
aren't all reactors experimental?
 
Huh?
 
user218912
12:40 AM
idk...
 
user218912
i'm so dumb
 
user218912
was evaluating this integral with time in the exponentials but it's supposed to be at t = 0.
 
Hey @0celo7, what's the diagnosis?
 
I need stronger glasses and I shouldn't waste the doctor's time like that.
 
@0celo7 You suddenly need glasses in one eye?
That's suspicious.
 
12:53 AM
I've had glasses in one eye already
But they stopped working
which was the whole point
although the prescription he wrote has corrections for both eyes
-1 R, -0.5 L
But my left eye is fine
er
fuck, I always mix up left and right
-1 L, -0.5 R
My right eye is fine
So I don't know why he wants a correction on both eyes.
 
1:15 AM
@bl00 holy shit I'm stupid
I spent the last hour deciphering this thermal utilization calculation
I was looking at the wrong cross sections.
 
user218912
lol
 
user218912
nice
 
why does the math chat get weird dudes so often
 
@BalarkaSen You mean that Inquirer dude?
i think he used to be called Twink
 
1:23 AM
he's probably severely autistic, he's been stalking Ted for a while
sad really
 
i remember that guy, but never realized this is he
 
I think it's him
Similar attitude
We get weirdos too.
One of them is banned for a year
 
i liked that dude
good trolls are always likable
 
Me too
I named my former blog after him
 
heh
there's an algebra troll i like in the math chat, i think he's syzygy now.
he's rather condescending sometimes, but his trolls were pretty solid.
 
1:28 AM
@bl00 Hmm. Possible pitfall. Do I separate the uranium from the carbide in the total number of moles of stuff in the reactor?
 
user218912
@0celo7 depends what the question is asking.
 
user218912
I remember when I used to be good at chemistry.
 
user218912
like 3.5 years ago
 
well I need relative ratios of all the stuff in there
so because I have separate cross sections for U and C I have to separate them
 
user218912
brb getting a drink
 
1:33 AM
@BalarkaSen Hey maybe you can explain what the smash product is telling me
I haven't had time to read Hatcher this week but I've been pondering it
I understand that $S^m\wedge S^n= S^{m+n}$.
 
mhm
 
So I'm trying to picture $S^1\wedge S^1=S^2$.
 
and?
 
it's not working :P
I don't understand Hatcher's comment about collapsing $X\vee Y$
I understand what it means, sure
But I can't picture it.
 
Think of a torus as a 2-cell attached to the wedge of circles, in a way so that that wedge is precisely wedge of a pair of meridian and longitude in the torus
Can you do that?
 
1:38 AM
Yikes, this cell stuff is freaky.
I'll think about it and get back to you. (Doing other things now)
I also have to think about something for ted, can't forget that
@BalarkaSen Yes, I think that works.
Definitely.
Unfold the torus to a square
 
That's it.
Now pinch off the wedge of circles (that's what quotienting means!). Your 2-cell gets attached to a point (the equivalence class of the wedge of circles inside the qt space). That's a sphere.
 
Ah ok.
So that would be like collapsing the border of the square?
 
That's it, yes.
 
Cool, thanks.
 
No problem
A word of advice: I mostly don't care for smash products, but it's useful in homotopy theory. I don't know why one would care for join of spaces. So read these constructions only if you're interested.
 
1:45 AM
@BalarkaSen Well, I think right now I'm only looking for the basics of covering spaces and fundamental group.
 
You'll find them in chapter 1
 
I want to read Wolf's book on constant curvature spaces and I want to be more familiar with that stuff because he uses it extensively.
@BalarkaSen Yeah
 
I wish I knew more geometry nowadays
 
I wish I knew algebraic topology.
I just can't seem to sit down and read it
I really enjoyed the first half of Bott & Tu but that was basically geometry.
 
@acuriousmind I figured out my issue
kind of.
 
2:00 AM
What was your issue?
 
I realized that the reflected wave in my experiment was a standing wave. So, I still don't know what happens if you stand closer or further away from the point source (I am told to believe that the amplitude of the wave varies)
@0celo7 issues with understanding how we hear sound waves w.r.t. position you are at
 
Hello again
I had to leave because I had to do some stuff and didn't think I'd be back
So, I'm confused.
A set $A$ can be a subset of itself.
And sets can have other sets as elements.
But I read somewhere that $A$ isn't always $\in A$.
Why not?
 
@heather What are the elements of $A=\{a,b\}$?
 
2:25 AM
@heather If A is the set of all silverware in my house, then A, not being silverware, is not an element of A.
 
@0celo7, it's just any set, I guess.
@AlfredCentauri, but then why can sets be sets of sets? (Sorry, convoluted, I know.)
 
@heather what
 
@0celo7, sorry, I misunderstood what you were asking. $a$ and $b$, right?
@AlfredCentauri, and why can $A$ sometimes be $\in A$ then?
 
It can't
 
What can't?
 
2:35 AM
$A\in A$
 
Huh...then why did I think it could be, I wonder? Ah, well. Misconception cleared up. Thanks!
 
user218912
well do you know why?
 
@bl00, I think so. It's like AlphaCentauri said: if you have a set, like A = {1, 2, 3}, A is not in A; to be, the set would have to be like {1, 2, 3, (1, 2, 3)} but then, if you set that equal to A, then you have to have that added in, and so on.
If that makes any sense.
 
user218912
what's the real formal reason for it though
 
@bl00 Hell if I know.
What is it?
 
user218912
2:42 AM
idk I thought you knew
 
I don't know PhD set theory.
 
hello
 
@bl00 so, explain
 
user218912
I don't know!
 
user218912
I already said idk the proof
 
2:51 AM
@bl00 Because you can't prove it.
 
user218912
why not?
 
It's an axiom.
 
user218912
oh, k
 
I should write a book.
 
user218912
but you don't have a ph.d
 
2:54 AM
no one would read it
but it would be nice to have
 
user218912
i'd read it.
 
user218912
depends what it's on though
 
No you wouldn't.
We would begin with a proof of the Steenrod theorem.
i.e. derive the necessary and sufficient conditions for Lorentzian metrics
 
user218912
you're right I wouldn't
 
what a noob.
 
user218912
2:56 AM
flagging.
 
you won't
you don't have the guts
 
user218912
only one way to find out
 
user218912
but it's not bad enough to get you banned for 30 mins.
 
user218912
so it's pointless
 
lol
as I thought
 
user218912
2:58 AM
:(
 
user218912
you need a new avatar?
 
no
 
user218912
what were you pinging me this morning for then?
 
I changed my mind.
@bl00 quiz me on QM
I have an exam tomorrow.
 
user218912
idk what your course covers
 
user218912
3:04 AM
do my qft problem set 1 for review
 
user218912
it has qm stuff
 
The exam is the first quarter of Sakurai.
 
3:25 AM
If anyone wants to know how to find the composition of two axis-angle rotation vectors, check out my question and answer here:
0
A: What is the formula for the composition of two axis-angle rotation vectors?

Keshav SrinivasanThe formula is given in this excerpt from a journal paper. It was discovered by the French mathematician Olinde Rodrigues in 1840, which was before the invention of vectors or even quaternions (which were invented before vectors). The composition of $\alpha\hat{l}$ and $\beta\hat{m}$ (where the...

 
4:14 AM
0
Q: Repeating question

ABCDNew user here. I asked this question a few days back. (first post) Relative motion-Acceleration And i did not get a satisfactory answer for the above question. so I framed my question better this time and asked again as I dont see any activity with my previous question http://physics.stackexch...

 
How swimming make us float????
 
user218912
it doesn't work for everyone, clearly. that's why people drown.
 
4:33 AM
Well think about an athlete or a normal person who knows well off swimming... so why doesn't he drown ? Any explanation? Is it buoyancy or Newton's law.... I just assumed ... if anyone knows the actual phenomenon then pls tell me ???? :-)
 
user218912
@ffahim I think it's buoyancy and conservation of momentum.
 
user116211
What did the doc say @0celo7?
 
user116211
I suppose you got a spec.
 
user116211
Maybe ;/
 
user228700
4:50 AM
@0celo7: So u don't have eye cancer or whatever. Cool.
 
user228700
5:02 AM
@JohnRennie: Morning sir :-) I read that post (regarding the collision of a ball with a wall) that u had linked yesterday, and the OP uses the phrase "momentum came from the ball". Is this a correct way to phrase it?
 
@Kaumudi remind me which question that was - have you got the link?
 
user228700
Yep:
 
Ok. I think the OP means that initially the ball was the only object with a non-zero momentum. This is true in the rest frame of the wall.
 
user228700
Ah, OK, thank you :-)
 
user116211
5:14 AM
0
Q: What is meant by "space is expanding"?

Lorry Laurence mcLarryIs it just the distance between galaxies that increases? Or is the distance increasing between the molecules in my body? Does expansion affect universal constants?

 
user116211
Lack of research efforts?
 
6:04 AM
@SirCumference none of the usual black hole metrics have a limit on the black hole mass. There is a practical limit to the size of current black holes because they've had only 13.8 billion years to grow. But there is no theoretical limit.
 
 
1 hour later…
user116211
I wonder whether they are the same person.
 
Yes, Lawrence left then rejoined. He doesn't seem fussed about merging the accounts.
 
user116211
7:22 AM
ohh.
 
user228700
@JohnRennie: Busy, sir?
 
five hours of filtering LIGO data later
 
@Kaumudi Bad timing! I have a work activity that starts at 08:30 i.e. right now. Back in 15 minutes.
 
I've.........slightly lowered the noise
:D
actually I think that's good enough, now I just have to go and find all the harmonics of the things that are obviously noise and add filters to kill those
 
@JohnRennie Hello.
 
user228700
7:31 AM
@JohnRennie Oh, that's OK, I'll wait :-)
 
user116211
@DanielSank o/
 
user228700
@GPhys I feel like u deserve a high-five for ur hard work so here: 🙋
 
@MAFIA36790 \o
 
user228700
@DanielSank: Hi :-)
 
@Kaumudi Hi.
 
user228700
7:33 AM
Hey, @DanielSank: Are you busy?
 
@Kaumudi Only a little.
Doing my Russian lessons.
What's up?
 
user228700
Oh...
 
user228700
Well, I came across this problem that I did solve but I'm a little confused about the wording, which didn't allow me to solve the question w/o taking a quick perk at the solutions first.
 
user228700
I was wondering if it was indeed improper wording or just my general dumbess...
 
Okay, where's the problem?
 
user228700
7:44 AM
This:
 
user228700
 
user116211
@DanielSank I translated online a Russian pdf file today both by Google Translate and Microsoft software.
 
user116211
The output was a mess.
 
I'm back!
 
user228700
While trying to solve the problem the first time around, I kept thinking about all the different possibilities...
 
user228700
7:46 AM
@JohnRennie Yaay! :-)
 
@Kaumudi Work in the centre of mass frame and the problem becomes straightforward.
 
user116211
@Kaumudi It is in HC Verma.
 
user116211
Or related.
 
user116211
He worked in COM Frame.
 
@JohnRennie It's a conservation of energy problem...
Am I missing something?
 
7:47 AM
That is, the frame where each block is moving towards the centre at 1m/sec
 
user228700
@DanielSank No, u're not...
 
user228700
I had to use both, conservation of energy and momentum.
 
Wait, when it says "...front block kept at rest..." does it mean that the front block is fixed in place or that it's not moving at the beginning but is free to move?
 
user228700
@MAFIA36790 Oh, really?
 
@Kaumudi switching to the COM frame implicitly uses conservation of momentum, but in the COM frame you only need conservation of energy.
 
user116211
7:49 AM
@Kaumudi yes, more or less same sort of problem has been given in the illustrated examples.
 
user228700
@DanielSank Not moving but free to move.
 
user228700
@JohnRennie When we switch to the COM's frame, what we're essentially doing is having the COM be at rest, yeah?
 
@Kaumudi Ohhhhhhh. Yeah use the COM.
@Kaumudi Yes.
 
@Kaumudi Yes.
 
user228700
Hm...
 
user228700
7:52 AM
This switching isn't making that much sense to me...
 
user228700
I guess I need to think about it some more :/
 
Hi everyone
 
user116211
Hello.
 
user228700
Hi :-)
 
user228700
Well, my original question was different...
 
user228700
7:55 AM
When I was attempting to solve this question for the first time, I was trying to list all the different possibilities...
 
@Kaumudi Ok, please ask original question. Meanwhile, when we say "switching" we just mean to express the motions of the blocks from a different reference. For example, from your current reference, your computer is not moving, but from the point of view of someone driving past you, your laptop is moving.
@Kaumudi ok...
 
user228700
Since the table is frictionless, the case in which the rear block collides with the front block and then everything comes to a stop is ruled out, correct?
 
user228700
..?
 
@Kaumudi yes because momentum wouldn't be conserved.
 
user228700
Right.
 
user228700
8:00 AM
Okay, the next possibility is that the two blocks collide, and then, they move together.
 
user228700
The last possibility is that the two blocks collide, and then the block with the spring gains more velocity and speeds away, while the other block moves slower...
 
user228700
Yeah?
 
user228700
..?
 
Perhaps, but where are you going with this?
 
user228700
My book says "Find the max. compression of the spring".
 
user228700
8:10 AM
I am to take this as "Find the max. compression of the spring", possible in all the cases taken together, yes?
 
user228700
See, the thing is, I wasn't immediately able to identify which case it was 'cause they didn't specify.
 
user228700
And then I looked at the solutions and saw that they'd taken it to be the case in which both blocks move together (w/ the same velocity, of course) after collision.
 
user228700
And that they'd done this 'cause of the "max. compression" thing.
 
user116211
@Shing, Try to make the units upright in your edits. Use \mathrm for that.
 
user228700
Do u understand what I'm getting at..?
 
8:21 AM
@Kaumudi Yes I understand why you're confused.
You've identified several possibilities for how moving objects can behave.
You've assumed from the start that you should consider all of these cases.
 
@MAFIA36790 got it, thanks for the reminder
 
@Kaumudi Note that the small block could even reverse direction.
Imagine the small block is 1 gram, and the big block is 200 kg.
The 1g block surely "bounces" off the 200kg one.
But in any case, how could the blocks move together after the collision? We have a spring there.
 
user228700
@DanielSank Exactly.
 
user228700
@DanielSank Oh, yeah, it could...
 
@Kaumudi It's good to consider the cases qualitatively. Good job. However, note that if you simply solve the dynamics of the problem, the correct case reveals itself automatically.
 
user228700
8:28 AM
@DanielSank Huh. I didn't even think about the fact that they won't move together 'cause of the spring in b/w...to me it seemed like they could? :/
 
user228700
@DanielSank What do u mean by solve the dynamics?
 
@Kaumudi Suppose I toss a coin. It could land heads up, and it could land heads down, but if you know the initial velocity and orientation, you can just compute exactly how it lands.
 
user228700
Hm...
 
user228700
So, in this case, I should've placed myself in the frame of reference of the COM and then...what?
 
@Kaumudi I'd go with conservation of energy.
 
user228700
8:33 AM
Hang on, they can't move together 'cause of the spring...how so?
 
Uh, well what do you mean by "together"?
I'm imagining the blocks are touching, which means the spring is compressed and therefore pushing the blocks apart.
 
user228700
Right...
 
user228700
OK, then it definitely doesn't make any sense to say that they move together.
 
@0celo7 "it is pshysics question and it got stuff"
 
user228700
Damn, I have some serious problems when it comes to conservation of momentum. I wonder if it's just 'cause I'm super dumb or if my brain is complicating otherwise simple concepts...
 
8:37 AM
@Kaumudi I have some idea of why you're confused, but perhaps it's best if you keep explaining and I'll just pipe up when you need help.
 
user228700
Thank you :-) I'm gonna go check out some problems on YouTube to make sure my brain is doing the reasoning correctly...
 
user116211
8:58 AM
I just saw the comment @yuggib. I've figured the problem out myself; nevertheless, thanks for showing interest :)
 
user116211
9:22 AM
0
Q: Two Cases Of Harmonic Motion Caused By Gravity

StokeI'm a highschool student and we learned not so long ago Simple Harmonic Motion, and I'm trying to analyse "similar" cases which I thought of. Here we have a body (with mass $m$) being affected by the gravity of a body whose mass is $M$, yet it doesn't collide with it (it just goes through its ...

 
user116211
Homework?
 
9:58 AM
Yo y'all, is there some specific reason why there's a meta tag and also ?
shouldn't the latter be a synonym of the former?
 
@EmilioPisanty not that I can think of
 
@DavidZ I suggested the synonym but without some mod magic it'll just linger in limbo for all eternity
 
user228700
10:56 AM
Does anyone here listen to "Dear Hank & John", the podcast?
 
11:17 AM
@Kaumudi Never really bothered, I don't quite grok podcasts as a format
but I do follow vlogbrothers pretty closely
at least since (roughly) the time that crash course astronomy came out
 
Hello
 
user228700
11:46 AM
@EmilioPisanty Ah, OK. I must mention though, that the podcast is hilarious and I never fail to learn something new from it :-)
 
user228700
@EmilioPisanty Nice! :-D Have u been to any nerdfighter meetings/any of their shows?
 
user228700
@EmilioPisanty Ah, I too was introduced to them via Crash Course (Chemistry, in my case). Been a hardcore nerdfighter since April of 2014 :-)
 
$$\text{Whole} > \sum \text{parts}$$
 
@Secret, that reminds me of a poster I once saw...
"be $\geq$ you ever imagined"
 
Complex system is all about the above equation (and also the $\leq$ version). We have to be always ready for surprises when we mix A with B
 
user228700
11:59 AM
@heather: Hi :-)
 
@Kaumudi, hello! =)
Working on anything especially exciting?
 
@DanielSank oh my god
How is that real?
 
@0celo7, hello! Another day of school on the horizon.
 
0
Q: Is there any guarantee that there will be only one point on the isotherm curve of a system that has a certain Y coord?

AHBWhen reading this part of the "heat and thermodynamics" book of Zemansky, is there any guarantee that there will be only ONE intersection of the $Y=Y_1$ and the isotherm line? There must be. Because otherwise the concept of temperature would be self-disproving.

Is it even possible to exist a substance whose isotherm is not monotonic?
A Thermometer is a device that measures temperature or a temperature gradient. A thermometer has two important elements: (1) a temperature sensor (e.g. the bulb of a mercury-in-glass thermometer) in which some physical change occurs with temperature, and (2) some means of converting this physical change into a numerical value (e.g. the visible scale that is marked on a mercury-in-glass thermometer). Thermometers are widely used in industry to control and regulate processes, in the study of weather, in medicine, and in scientific research. There are various principles by which different thermometers...
fine...water...
 
user228700
12:21 PM
@heather Hang on, how old do u think I am..? :-P
 
25?
Probably doing a PhD in chemistry
 
user228700
@0celo7 Wait, how old are you?
 
18
19
 
user228700
Have u seen this:
 
user228700
 
user228700
12:36 PM
Yeah, I'm 17.
 
So?
 
user228700
But, but. U just said...oh, never mind. U tend to forget things very soon?
 
What?
Dunno what you're talking about
 
@Kaumudi oh, yeah, I thought that avatar looked familiar
 
I fell asleep at 7:30
crashed
Yet I'm still so tired...
 
user228700
12:49 PM
@0celo7 U just asked if I'm 25. Never mind.
 
user228700
@EmilioPisanty :-) "Pizza. The answer is always pizza".
 
user116211
@Secret WTH is that?
 
@Kaumudi ok so you're 17
Doing a PhD at 17, wow
 
1:42 PM
@MAFIA36790 whole is more than the sum of its parts
 
Jim
@Secret This is why $1>0.5+0.5$
 
Hello
 
user228700
@0celo7 Very funny -_-
 
user228700
@Ramanujan: Dude, do they teach u linear programming too? Not for school, for the exam.
 
user228700
Who the heck starred this: (:-P)
 
user228700
1:56 PM
1 hour ago, by Kaumudi
But, but. U just said...oh, never mind. U tend to forget things very soon?
 
user228700
@Ramanujan: Holy eff, do they teach u all this:
 
user228700
 
@Kaumudi nope
 
user228700
Actually, no, never mind. Most of that is in the syllabus.
 
user228700
@Ramanujan Hey, but damn, I forgot, u wouldn't know, right? LP is in 12th.
 
2:04 PM
Yep,everything over mind
 
user228700
"Everything over mind"?
 
user228700
What do u mean?
 
user228700
I thought u said only 11th is over.
 
(pura sar ke upper se gaya) what you send picture
Yep,only 11th is over
 
user228700
:-P Lol, I see. Sar ke upar se gaya, kyunki abhi tak aap logo ko sikhvaya nahi, ya tumhe pata nahi?
 
user218912
2:09 PM
guys this is an english chat.
 
user228700
(Excuse my Hindi, folks.)
 
user228700
@bl00 No fair! Besides, I feel that it's sometimes better to speak with Ramanujan in Hindi. Hey, people share stuff here in other languages that we don't get all the time. But OK :-( If u say so, no more Hindi.
 
user228700
@Ramanujan: Is it possible for u to find out if LP is taught to ur seniors for the exam? (NOT for school)
 
@Kaumudi I don't talk anything to senior till now,not possible
 
user228700
@Ramanujan Not possible? Wow, OK.
 
user228700
2:14 PM
Alright, thanks anyway. I'm gonna risk it and study LP.
 
Btw,why are studying something which is not for jee? @Kaumudi
 
user228700
It IS in the syllabus.
 
user228700
BTW, "pura sar ke upar se gaya"="It went over my head"
 
user228700
Not mind :-)
 
Can you answer this?chat.stackexchange.com/transcript/message/33053200#33053200 don't answer now,DHMO is trying for me @Kaumudi
Same, langue is used to understand,not to correct it,i will keep in mind
 
user228700
2:23 PM
@Ramanujan That's not true. The purpose of language is to make sure that the person whom u are speaking with is able to understand you as clearly as possible. I didn't understand when u used the word mind in place of the word head, so I brought this to ur attention for ur own benefit. I can be a little pedantic at times, but it's something I'm trying to grow out of. Bura mana, to I'm sorry, but yes, to help u was my only intention :-)
 
@Ramanujan India!
So confusing
 
user228700
@0celo7 Dude, I explained this to you! (The deal w/ all the exams ie.)
 
user228700
@Ramanujan At first glance, I dunno how to do it. I will think about it later and let u know, since I need to finish LP now. (I'm sorry! I hope DHMO helps u)
 
2:47 PM
@Ramanujan The answer is (4). You don't need to do any clever maths to see that. Just take $n=1$ in which case the expression becomes atan(1/3) = 0.3218 and (4) is the only equation that gives this value.
 
I think all Math is clever.
 
I've always considered myself to be possessed of low cunning rather than cleverness :-)
 
@JohnRennie that will surely help only when I know what's value of atan(1/3)
Teachers used to solve most of problems by same method, but as I want to study in deep,i don't want to do in that way
 
@Ramanujan aren't you allowed to use a calculator? If not then I agree that calculating arctangents by hand is probably a non-starter :-)
 
@JohnRennie calculators are not allowed
@JohnRennie one quick math problem?
 
2:59 PM
@Ramanujan OK in that case I guess you have to do the proof properly and I don't know how to do that. It's the sort of thing you could ask on the Math SE.
@Ramanujan my maths isn't very good, but I'll help if I can.
 

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