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My score is approximately f(ω126+126,126)
where f(a,b) = f_a(b) in the fast growing hierarchy.
Ruby:
y=?.ord
z=?~.ord
def f(a,b,c,d=a+a)b<y?c<y?d:f(d,d,c-y):(y..d).each{a=f(a,b-y,c)}&&a end
f(z,z,z)
This is much much larger than Graham's number, and therefore larger than leftaroundabout's nu...
