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hey
02:44
@MadhuchhandaMandal are you not confirm
2 hours later…
Madhuchhanda Mandal
05:01
I am confirm... But there is a twist in the problem
hey
05:37
@MadhuchhandaMandal what twist
4 hours later…
Madhuchhanda Mandal
09:16
Try solving it and say the answer.. I will then crack the twist
3 hours later…
hey
12:39
do we have to remember that or is there any method to find it
@YashasSamaga @Mystic
@MadhuchhandaMandal $2sin^{-1}x$
Madhuchhanda Mandal
13:27
But the twist is that it could be $2cos^{-1}x$ as well !!!
You had substituted x=sin theta... You could substitute it as x=cos theta as well !!!
hey
13:49
@MadhuchhandaMandal oh yes , so whats the actual answer
is both answers are correct
Madhuchhanda Mandal
14:34
No both the answers are not correct simultaneously... When : -1/root(2) <= x <= 1/root(2) , your answer is correct but not cos^{-1}x$.... But when 1/root(2) <= x <= 1 , cos^{-1}x$ is correct but not sin^{-1}x$
hey
15:15
ohk
Madhuchhanda Mandal
15:48
Isn't it good?
1 hour later…
hey
17:14
It is
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