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Jonah
Jonah
00:52
@mitchelljohnstone probably missing something, but not seeing a way to trim the two args down to equal size without them being being "enclosed" at the end, unless I use mix. eg, this works for the basic calculation, but only with the mix, otherwise it returns the answer enclosed: ↑⍤(≤⌿⌊⍥≢↑¨,⍥⊂)
 
3 hours later…
Adám
Adám
04:19
@Jonah Maybe again a case for a dfn? {(+/,+/⍤~)+/⍺≤⍥((⍺⌊⍥≢⍵)∘↑)⍵} use the already computed length: {l(⊢,-)+/⍺≤⍥((l←⍺⌊⍥≢⍵)∘↑)⍵}
Jonah
Jonah
@Adám You don't prefer (⊃(≤⌿⌊⍥≢↑¨,⍥⊂)) to {⍺≤⍥((⍺⌊⍥≢⍵)∘↑)⍵}?
Adám
Adám
Either is fine, but there are other clever approaches, like +/1 0∘.=1 1⍉∘.≤
Jonah
Jonah
@Adám Isn't that only for processing after you've got them the same length?
Adám
Adám
No, that's the whole thing. Uses an outer product, so original lengths can be anything, then takes the diagonal which trunkates to shortest.
Jonah
Jonah
@Adám I'm getting rank error pasting that as is
Adám
Adám
04:28
      6 6 2 1 (+/1 0∘.=1 1⍉∘.≤) 6 5 5
2 1
Jonah
Jonah
@Adám maybe bc I have 0 indexing set
Adám
Adám
Yes, that'd do it. If so, then change 1 1 to 0 0
Jonah
Jonah
yeah that was it. ok that solution is quite nice, ty
 
3 hours later…
Jonah
Jonah
07:02
does apl have non-overlapping n-wise reduce. ie, the equivalent of _2]\] in J? Link
I noticed the specifying a negative reverse the results in apl, rather making the window non-overlapping, but thought there might be another way to achieve it.
Adám
Adám
@Jonah ⌺ Stencil.
 
11 hours later…
Jonah
Jonah
17:54
@Adám My solution to the key value problem, using stencil: ' =' (⊢⌺(⍪2 2) ~⍤∊⍨ ⊆ ⊢) 'lang=APL dial=Dyalog'. tryapl link. Suggestions?
mitchell johnstone
mitchell johnstone
18:09
@Jonah That's exactly what I had ∘.○
 
2 hours later…
Jonah
Jonah
19:55
@mitchelljohnstone Nice, I was wondering if there was a shortcut for the (⍪2 2) part, since there is in J. Neither language afaik allows a wildcard for one position in shape, which I think would be a nice feature.

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