I have a set of ordered pairs, { (a, 1), (b, 12), (c, 8) }. Is it too difficult to define a (partial) function that gets me the ordered pair with the second element being the greatest (in this case, (b, 12))?
@tohecz Yep. :) I don't want to say here's a function max(...) that magically does stuff. :) And in a second thought, it doesn't seem to be partial at all. :P
@percusse well, that returns $(x,y)$ basically, and anyways it's good to define it. People don't like "too much notation assumptions". I get comments in reviews that I should "say what \lfloor x\rfloor is when I use it".
and that's the problem: It's not a standard notation ;)
I mean, if you prepare slides: fine. If you write down an article: fine, but with a comment on how do you mean it ;) For me, \argmax is something that can't be seperated, and the space in between is there because these are two words.
@egreg In optimization and other problems, we usually don't know what the global optimizer anyways. But we need to say something about it. So the function invertibility is naturally not assumed
Hmm, maybe I should embarrass myself to you: Here is my understanding.
Let `f:X\times Y \to R` such that `f(x,y) = y` where `X` and `Y` are Banach also let `t = \max_{(x,y)\in X\times Y}`. Then assume `S\times T` be a subset of `X\times Y` such that for every element `(x*,y*)` in `S\times T`, `\max f(x*,y*) = t`. For that we say `\arg\max_{(x,y)\in X\times Y} = S\times T` ?
@egreg It's a set of ordered pairs. The second element of the pair is a natural number. I would like to return the first element of the pair which has the largest number.
@PauloCereda Don't use the pair then. Imagine you are plotting a function which means you have pairs of points (x,f(x)). But you still can say the argument of \max f(x)
@PauloCereda Your domain is probably a set of sets of ordered pairs. For each of those sets, call it A, you want to consider the set of second elements in A, compute its maximum, and select a first element corresponding to it.
@PauloCereda whatever set of ordered pairs is a relation. Every relation is an incomplete multi-function (to each left argument it assigns zero, one or more right arguments).
@egreg let's call a "set of ordered pairs" a "relation" and it'll be simpler:)
@egreg ok, I didn't know that. However, "boheme", besides refering to my home, refers to a certain approach to life as well (but I suppose that it is so in many languages)
This person seems to be seriously disgruntled, doesn't he?
@egreg: I see too many people using LaTeX too, when they shouldn't. This formula would be much easier to render in MS Word, so why don't you just go ahead and tell me to use a different tool altogether? — Mehrdad1 hour ago
I did not find bold word in the manual.
My tex is:
\documentclass{article}
\usepackage[framemethod=tikz]{mdframed}
\newtheorem{question}{Question}
\mdfdefinestyle{que}{
linecolor=cyan,
backgroundcolor=cyan!20,
}
\surroundwithmdframed[style=que]{question}
\begin{document}
\begin{question}
Lor...
I try
\newtheorem{question}{Question}
\mdfdefinestyle{que}{
font = \normalfont, % not working
linecolor=cyan,
backgroundcolor=cyan!20,
}
\surroundwithmdframed[style=que]{question}
but without success.
The font is in italics at the moment.
How can you have normal font in such a environme...
@PauloCereda yep, I have those you have to tie yourself :) I'm thinking about getting a tartan vestcoast and a matching bowtie shipped from Scotland :)
@egreg I wear them sometimes to the church when I play the organ
