in Math Mods' Office, 9 hours ago, by Martin Sleziak
lcm was created recently: http://chat.stackexchange.com/transcript/3740/2016/10/17
I have a $m$ dimensional subspace $V$ of $\mathbb{R}^n$, I know for another subspace $W$ for which $$V\oplus W=\mathbb{R}^n$$ Now basis of $V$ is given explicitly in a matrix $M$ whose $m$ collumns are linearly indipendent and play role as basis for $V$. My question is how I can find explicitly...
Suppose I have two subspaces $V$ and $W$ of $\mathbb{R}^n$ such that for another subspace $X$ we have $(V\cap W)\oplus X=(V+W)$ How can I find a basis explicitly for $X$ when I know basis for $V,W,V\cap W,V+W$ explicitly? when $V,W$ is given, $V-W$ make sense?Like we know $V+W=\{x+y:x\in V, y\...
The basis was recently created. But it's a horrible tag. There are different notions of basis in mathematics, and they are not entirely the same at all. Hamel basis Hilbert basis. Schauder basis. Topological basis. The tag is used as a free for all. And if it continues to exists, it will be u...
As commenters said, reaching 3000 reputation does not preclude you from earning Marshal badge. You can still flag spam as spam, flag Very Low Quality posts as such, flag answers that should have been a comment as Not an Answer, and flag comments when there is a reasonable case for doing so. That...
Definition. $0=\emptyset$. Definition. $S(x):=x\cup\{x\}$, $S(y):=y\cup\{y\}$. Show that for any natural numbers, if $S(x)=S(y)$ then $x=y$. We will use induction for proof but, how? Can you hint? Proof trying. Let $t\in x\cup\{x\}$. Then, $t\in y\cup\{y\}$ by the assumption. Now, we have to...
The Question confused everyone in my class If \begin{align} x^{{3a}^{bc}}={(x^b)^a}^c \end{align} and ($a,b,c$ not equal to $0$). Find 3abc-1/bc ^= to the power.
Evaluate $(b^2)^{\frac{1}{2}}$ for $b=-1$. If you substitute $b=-1$ first and then simplify you get $((-1)^2)^{\frac{1}{2}}=(1)^{\frac{1}{2}}=1$ but if you simplify first and then substitute you get $b^1=(-1)^1=-1$. What am I missing?