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8:12 AM
The tags and are gone.
It seems that the tag called conformal-map or conformal-maps was created and removed a few times in the past.
Questions where the tag was added/removed (including the editors): data.stackexchange.com/math/query/1105163/… data.stackexchange.com/math/query/1038474/…
It is this one:
Apr 5, 2017 at 4:01, by Martin Sleziak
-2
Q: Doubts on Complex Analysis

HirakI have doubts in the following two problems. One is this and the other one this For the second question letting $f=u+iv$ I found that $x=\dfrac{u-3u^2-9v}{(1-3u)^2+9v^2}$ and $y=\dfrac{v}{(1-3u)^2+9v^2}$. Now how to proceed ? And for the map in the first image to be a Mobius transformatiion w...

 
8:33 AM
Questions where the tag was added/removed (including the editors): data.stackexchange.com/math/query/1105163/… data.stackexchange.com/math/query/1038474/…
0
Q: How would conformal map from $\Bbb C\backslash\{z\in\Bbb C : Im(z)=0, Re(z)\le 0\}$ to the unit disc $\{|z|<1\}$ look like?

John CataldoHow would conformal map from $\Bbb C\backslash\{z\in\Bbb C : Im(z)=0, Re(z)\le 0\}$ to the unit disc $\{|z|<1\}$ look like? Riemann's theorem guarantees the existence of a conformal mapping $f:\Omega\mapsto D$ where $\Omega=\Bbb C\backslash\{z\in\Bbb C : Im(z)=0, Re(z)\le 0\}$ is simply connecte...

3
Q: How does a conformal mapping preserve angles in hyperbolic geometry?

ApplicationSuppose I have a sector $D = \{0 < \arg z < \alpha\}$ where $\alpha \leq 2\pi$. If I apply the function $w = \frac{\zeta - i}{\zeta + i}$ from the upper half plane to the unit disc ($\zeta = z^{\frac{\pi}{\alpha}}$), I get that the vertex of the sector goes to -1 and $z = \infty$ goes to 1. I get...

 

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