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00:11
ive been sitting here all evening trying to verify the correct diagram to witness that the inversion map in a Segal groupoid is an equivalence
@SineoftheTime Want to play another chess game?
@Thorgott Tough. I hope you verify it soon.
@Almanzoris ok
00:47
@psie I doubt it
@Jakobian why wouldn't it? We are simply removing area (i.e. $\underline{A}(U,k-1)$) that is already in $\underline{A}(U,k)$, and $\underline{A}(U,k)$ is just a union of closed cubes, which we've already talked about, is closed
@psie differences of closed sets aren't usually closed
@Almanzoris I'd play other games, but it's 3 am here :(
Don't worry. Good matches!
It's 3 am here too.
01:02
Spain?
ty for the games
and goodnight
I still fail to understand why the author mentions that the closure of $\underline{A}(U,k)\setminus \underline{A}(U,k-1)$ is a (countable) union of cubes when $\underline{A}(U)$ is, among other things, a union of $\underline{A}(U,k)\setminus \underline{A}(U,k-1)$, i.e. not of the closure of $\underline{A}(U,k)\setminus \underline{A}(U,k-1)$
You're welcome, thanks for the games aswell.
Good night!
 
4 hours later…
04:42
Hi everyone. I encountered the following set of matrices with the curious property while goofing around $$P_{M}^L P_{N}^K=\delta_{N}^L \delta_{M}^K$$
Have any of you guys seen this? Does this have a name or pop up in math?
 
4 hours later…
09:04
Hi
Hi....
 
1 hour later…
10:12
hi
@NairitSahoo I don't understand the notations, what is $P_{M}^L$? I guess the deltas are Kronecker delta.
10:35
I don't understand the last line, mainly why it is isomorphic to a quotient sheaf of $\mathscr{A}^p$?
 
2 hours later…
13:00
Hi everyone. I am getting "Runtime Error" on the MSE Data Explorer, any ideas why?: data.stackexchange.com/math/query/new
Previously made queries give database error
@PM2Ring Thanks! I will post the issue there
13:25
hi
13:46
@SoumikMukherjee the sections correspond to a morphism $\mathcal{A}\vert_U^p\rightarrow\mathcal{F}\vert_U$ that is surjective by the hypothesis
is learning fun for u all, or is it exhausting
14:10
@Thorgott Thanks, got it
@RyderRude both, depending on what I am learning.
@SoumikMukherjee i find it exhausting for most things i learn
it is really hard to understand stuff
@RyderRude yes
14:29
What scientific calculator can solve functions
@Gian'sPizzeria what do you mean by "solve functions"?
@SineoftheTime Like polynomial functions
Also the graph
14:46
@Jakobian lol
@Gian'sPizzeria you did not answer my question
15:08
Hi!!
@SineoftheTime for example, I write x^2-1=0 on the calculator and the calculator gives me the solutions
Anyway
I have a test tomorrow
On differential equations
Good luck
@Gian'sPizzeria hi. use this for polynomial.roots wolframalpha.com/input?i=polynomial+roots
@Pizza hi
15:30
@Gian'sPizzeria If you're talking about finding the solution of an equation, than wolfram does the kob
@Pizza hi
In many categories, objects can be operated on in ways that resemble addition (coproducts), multiplication (products), and exponentiation. What categories have ways of operating on objects that don't resemble addition, multiplication, or exponentiation? In particular, are there categories where objects can be negated (either as in a Boolean algebra, or as in a ring)? Or where objects can be combined in yet other interesting ways?
15:54
thanks guys
@SophieSwett seems like a very broad question, are you just asking for any kind of functor?
16:14
Let $\text{Emb}(S^1, \mathcal{I})$ denote the space of all embeddings of $S^1$ into $\mathcal{I}$. Each embedding $f_\gamma: S^1 \to \mathcal{I}$ is a smooth, injective map that traces out a simple closed loop on $\mathcal{I}$. Two embeddings $f_1, f_2: S^1 \to \mathcal{I}$ are considered equivalent if they are differentiable isotopies, meaning there exists a smooth family of embeddings connecting $f_1$ to $f_2$.

Would you say that this is well-written specifically in terms of good notation and modern standards?
Is it understandable in other words
@ModularMindset there is no such concept as "embedding" without context
@Thorgott Well, not quite. I'm looking for a category C that has several interesting operations on its objects; these might be functors $C \to C$, or $C \times C \to C$, or they might not be functors at all (maybe they only act on objects, not arrows).
16:30
@Jakobian you're saying I need to specify what $\mathcal I$ is right?
@SophieSwett product is not just an object
@ModularMindset If I understand correctly, it's not "if they are differentiable isotopies" but "if they are differentiably isotopic"
And google tells me the correct way to say that is "smoothly isotopic"
Although I never actually read things from this area, so I may be wrong
@VladimirLysikov Okay thanks
16:50
@SophieSwett that's even broader
I have a basic question. Consider a rectangle in the plane (a cartesian product of compact intervals). If I remove one side from the rectangle, will the rectangle be neither open nor closed?
Like a half-open interval.
ok, thanks
@psie rectangle means the boundary only, not same as product of compact intervals
17:05
I wouldn't say so, it's common for example to consider covering by rectangles (meaning the plane shape, not the 4 segments)
All kinds of polygons are sometimes defined as just the union of segments, sometimes as the area of plane bounded by these segments
@Thorgott So it is. Let me describe my motivation.
@SoumikMukherjee ok, I meant the latter...a "filled" rectangle. All I can think about is the program Paint on Windows, where you can fill shapes with color. I meant a solid body. Not a sphere for example, but a ball. I don't know what the name is for a "filled" rectangle, i.e. the cartesian product of the compact intervals.
In the category Set, consider the empty set, any singleton, the disjoint union operator, and the cartesian product operator. These operators allow us to build new sets out of the sets we have. These operators also give rise to certain isomorphisms (for example, (A × B) × C is isomorphic to A × (B × C)). If we make a list of these isomorphisms, it so happens that there's an isomorphisms corresponding to every axiom of a commutative semiring.
I'm looking for more examples of the same concept: a category has some interesting operators, these operators give rise to isomorphisms, and the isomorphisms correspond to the axioms of a particular algebraic structure. So far, I haven't found any examples where the resulting algebraic structure is substantially different from a semiring.
17:26
@VladimirLysikov I see
@psie that's some obsession with art
@psie okay, but either way you get a set that is neither open nor closed
@Jakobian to quote an artist..."life imitates art" :)
 
2 hours later…
19:53
hello
20:06
I am new to this site
20:32
Two remarks:
1. Axioms for many algebraic structures like groups or rings can be formulated 'internally' in many categories in a diagrammatic fashion. This gives rise to notions like group objects, ring objects, etc. in a category. This can be done with any sort of algebraic structure in an appropriate universal-algebraic sense.
2. Your examples do not obey these axioms, as you note, but only obey these axioms 'up to coherent isomorphism'. So what you're really looking at is a higher-categorical version of an <algebraic structure> object (in a higher category of categories).
20:47
Yeah, that sounds about right. Algebraic structures of the usual kind, except that the operations are functors instead of functions, and the identities are (natural?) isomorphisms instead of equalities. I feel like there's probably a name for that concept, but I'm not finding anything yet. (I really don't know much category theory at all.)
Come to think of it, the prototypical example of this concept is a monoidal category: a monoidal category is a monoid, except that the "underlying set" is a category, the operations are functors, and the identities are natural isomorphisms.
By analogy, one might say that disjoint unions and coproducts make the category Set into a "semiring-al category."
21:07
It looks like nLab calls this concept "vertical categorification," or more precisely "groupoidal categorification."

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