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18:00
This obviously does not fit my taste. Is it a year-long course?
that's a cool result koro
Maybe you'll get to what I consider real analysis by the last few days.
i've never done real analysis proofs using rationals
@TedShifrin From integers we are going to rationals and then we are in dedekind cuts now...
@Franklin In an analysis class? WHY?!
18:01
How many weeks have you spent, and how many weeks are left?
Some professors should be — um — excised.
@TedShifrin the college authority decides that
@shintuku it's cool. I'll share one article here. You'll love the way they construct reals from the rationals. :-)
@TedShifrin I agree
i really think natural deduction is worthwhile knowing before real analysis
No, I'm asking. How long is the course and how far along are you?
18:02
@Koro ah that i know
using cauchy sequences
@shintuku Huh?
@shintuku iitg.ac.in/kvsrikanth/teaching/2011f/reals.pdf I think this is written very beautifully.
you don't?
@TedShifrin At this point, frankly, I am getting a grip on doing multiplications and additions using dedekind cuts
R is a completion of Q.
18:03
yes, the one requiring Cauchy sequences.
imo i find it more natural than dedekind cuts
Good grief. I would never teach Dedekind cuts in a first analysis course. It's absurd. And the students don't appreciate the subtleties. Just use the damn LUB axiom and do some actual interesting stuff.
at ted: what I couldn't understand at first was, why was i needing inequalities to prove stuff about suprema
@shintuku me too. It's difficult to grasp the idea that a number is a set.
@TedShifrin It's taught in 1st year ,2nd semester (the course I am in) and it is probably 6 months course (I mean 2nd sem will last)
18:05
Real analysis is all about inequalities and estimates.
A semester is 6 months where you are?
0=|\emptyset |
Where I taught, a semester was 15 weeks, and that is one of the longest semesters in the entire US.
@shintuku It depends on how you want to approach things. The reals are the unique ordered field (up to isomorphism). If you build the reals using Dedekind cuts, you get the least upper bound property for free. If you build it from Cauchy sequences, you get the Archimedean property for free (more or less). Or something like that---I haven't gone through the details in a long time.
right, but say, i couldn't understand why $sup(A) + sup(B) = sup(A+B)$ needed to involve inequalities. i would think: well this point here on the real line is $sup(A)$, and this point there is $sup(B)$, so clearly we have the equality, why are inequalities involved?
Most semesters are 13-14 weeks.
18:06
started to make more sense when I started thinking of real numbers as limits of sequences
@TedShifrin Our professor diagrees. He suggests to "know numbers first, why they arose, when and how?"
That is not how history works, @Franklin. Your professor is too Bourbaki. Math history would disagree with him entirely.
@Franklin This seems like the kind of person who would like to start students on category theory in the second grade.
@shintuku inequality $\le$ is just an ordering among reals.
right, but the insight was that a real number is not a point on a line. for any attempt to give a real number, there is a better attempt: that was the real insight for me
then the logic of the proofs started making sense
18:09
When one try to compare things (which is one of the central concept in mathematics) ordering is important.
@TedShifrin The book he recommends is a popular one by Terence Tao
Funny. I still think of real numbers as points on a line.
The initial chapters deal with these
Also, a book by Robert R Stoll and Abbott
Abbott is very elementary and certainly does not do Dedekind cuts. I do not know Stoll.
I would bet Terry Tao doesn't teach that initial chapter when he teaches his own course.
@TedShifrin might be...
18:11
@shintuku real number is not a point of line. But we visualize it as a point. ( it's a one dimensional vector space over R. A one dimensional vector space can be thought as line and members as a point on that line) may be a justification but won't make any justice with your initial thought.
I took analysis at MIT out of baby Rudin (early edition, which still did Dedekind cuts). The professor did all that. Never drew a picture the entire course. The worst course of my undergraduate career. Many of the students in the course were taking analysis for the third time. Many took it a fourth time.
@TedShifrin No, wait, in the preface if I remember correctly, he writes he wrote in order the way he taught in his course
Ofc, I might be mistaken
Just use either the LUB axiom or the monotone sequence lemma as an axiom and actually do some mathematics. Being pedantic to make yourself feel important is terrible, terrible teaching.
The things I am working on now, are so subtle, my head reels sometimes hehe
if that information is provided, it also arrives at a time where it's almost misleading to say that the real numbers "are" some construction. students are going to think that the model matters in ways that it doesn't.
18:14
Well, if Tao really teaches his standard analysis students that way, I don't respect his pedagogy as much. But he's a superstar and I'm not, so ...
@TedShifrin you are joking right? You are too a legendary math wizard !!!!!!!!!!!!!
@leslietownes True. I am included in these group of students you mention
Oh, I just looked at the preface to Tao's book. This was for HONORS UCLA students. That's not the general audience for the course. Similarly, Pugh's book was for HONORS Berkeley students. Abbott is much more aimed at the generic student.
This is why the general math major in the US no longer even takes a real analysis course. Pitiful, but true. There are so many different amalgamated/applied majors now.
@TedShifrin I am in Hons course as well :)))))
And the lecture notes that I see are usually more "complete" than what is covered in a course.
Well, if you're in the honors course, you should be figuring out a lot more stuff for yourself and not asking us why the proof of a converse isn't adequate to prove a theorem.
18:17
33 mins ago, by Koro
The second part is to prove that: assuming that every map $S^1\to X$ can be extended to $D^2\to X$, we must have $\pi_1(X,x_0)=0$ for every $x_0\in X$.
What to do about this one?
dedekind cuts are great for some purposes, but the definition of multiplication really sucks. even rudin can't deal with it and knows it sucks. you can sense him thinking "oh, forget this, i'm rudin, i can just say verify the cases" while giving a casewise definition of multiplication that looks an awful lot like it's assuming various field axioms (which it isn't, but haha wow it sucks)
@TedShifrin as I said, I did know it. But I was misinterpreting the language of the question badly...
Every question in Hatcher consumes so much time.
@TedShifrin I would curse the grammar skills in there
@Koro The point to understand is that an extension of a map on the circle to a map on the disk gives a homotopy to the constant map.
18:19
koro you can use the D map to write down specific homotopies between the loop based at a point and the constant loop at that point. draw a few pictures.
If you don't like polar coordinates, think of the disk as a cylinder with the bottom edge collapsed to a point.
we didn't have a lot of luck with that POV earlier. :)
Something like $F(x,t)=f(tx)$ should be easy enough. Why do people have no intuition?
@TedShifrin yeah, I have difficulty coming up with or understanding things like this.
Interestingly, I had to do this exercise in an undergraduate differential topology course long before I took algebraic topology. So then there's the need to use bump functions to smooth things out at the origin.
18:22
@Koro You are studying lots of algebraic topology nowadays . Why you think AT is interesting ?
If it is not in book, then I might not know about it until I do lot of investigation myself.
Polar coordinates. The disk is a bunch of concentric circles.
What analyst think about the subject Algebraic topology? And topologist think about analyst?
Who cares what people think about what.
IMHO, that's an inane question.
So here is how I would go about it step by step: Take $[f]\in \pi_1(X,x_0)$. f: I-->X. $I/\sim \cong S^1$ with the quotient map $q$ so there exists a unique $\tilde f: S^1\to X$ such that $\tilde f\circ q=f$. We extend $\tilde f$ to $D$ (possible by hypothesis) and still use the same notation.
18:27
I guess that analysis is about inequalities, not only real analysis.
Now, as Leslie suggests and I can feel it to some extent: somehow I am supposed to use the fact that D is convex or that D contracts to its centre.
D deformation retracts to its centre.
You should use $S^1$ and $I/(0\sim 1)$ interchangeably by now without having to talk about it, Koro.
@Yai0Phah Analysis is all about limiting process.
No, you don't need to think about deformation retraction, although I suppose you can. You want to define a map on the disk, so you want to define it circle by circle.
For that I define $g_t: D^2\to X$ as follows: $g_t(x,y)= \tilde f(tx, ty)$ (so I am just taking every point on D^2 to centre (0,0) and then composing it with $\tilde f$.
18:29
Why $g_t$ on $D^2$? I'm confused.
Oh I defined it.
Why?
What you have doesn't make sense to me. You are defining $g_t$ as maps on the circle, not on the disk.
$g_0= $ a constant map, $g_1= \tilde f$
No, you're doing the wrong thing
Using this I want to say that $\tilde f$ is nullhomotopic.
18:31
No, you want $f$ nullhomotopic, not its extension.
From that I wish to obtain $f$ is nullhomotpic.
You want to see that an extension is equivalent to a nullhomotopy.
No, you're all tangled up.
You're putting in a whole extra layer of complicatedness.
So I was thinking of going the other way round (showing extension is nh to the original function is nh).
but it gets complicated very quickly as you say.
You don't care about a homotopy of the extension. After all, every map of a contractible space is nullhomotopic, isn't it?
I don't know about this result. Is there such a result?
It would be nice if there is.
18:34
Nah, I lied. Only if the target is contractible.
See ... your complication got me unnecessarily confused.
Start with the extension to the disk and see why that gives a nullhomotopy. I've said it a bunch of different ways.
yay!! I got it.
It is not complicated. I observe the following:
So it has been proven that $\tilde f: S^1\to X$ is nullhomotopic.
Say, $\tilde f\simeq c$, where c is a constant map.
now, $\tilde f\circ q\simeq c\circ q$
LHS is just $f$.
So $f$ is null homotopic.
$[f]=0$
:-)
Now the third part: if $\pi_1(X,x_0)=0$ then every map $S^1\to X$ is nullhomotopic.
Take any map $f:S^1\to X$. Define $g=f\circ q$. g is a loop based at some point p. So $[g]=0$. Hence $f\circ q\simeq c$ for some constant map c.
hmm, how to get rid of q here?
note that the conclusion is something that needs to be shown for all maps S^1 into X, not just ones that include the basepoint x_0 in their range. i'm not sure what magic is expected to be performed by q.
And isn't $q$ going from $I$ to $S^1$? This is muddled.
But I'm giving up.
$\pi_1(X,x_0)=0$ for every $x_0\in X$ is given.
$q: I\to S^1$. $f: S^1\to X$. So $f\circ q: I\to X$.
I want to show $f\simeq $ some constant map. I have obtained above that $f\circ q\simeq c$
18:53
does someone know how much topology is used in topological data analysis?
A fair amount. It's about high-dimensional sets and recognizing them as high-dimensional manifolds.
so say a full first topology class? i'm planning my next summer for fun
or also algebraic topology?
No, graduate algebraic topology and some knowledge of manifolds, I think.
I heard that TDA is more related to algebraic topology.
noted, thanks for the comments
18:56
I think the following works:
We have a hpy F from $f\circ q$ to c with the data $F_1=c$
$\tilde f(e^{i2\pi t})= \tilde f(q(t))= F_0(t)$
hmm, no. I thought from here I would conclude that F is the desired hpy between $\tilde f$ and a constant map. But F is defined on $I\times I$.
I think I'll need quotient top. universal properties now.
F is from $I\times I$ to X. I look at the fibers of $q\times i$.
I think this works. So the hpy. $F$ induces a continuous map $\tilde F: S^1\times I\to X$ such that $\tilde F\circ q= F$
Now, $\tilde F(q(a),0)= \tilde F\circ (q\times i)((a,0))= F(a,0)= F_0(a)= \tilde f(q(a))$
$\tilde F(q(a),1)= $ constant map.
So $\tilde F$ is a hpy. between f and a constant map, hence f is nh.
Is this correct?
Hi @copper.hat !!
19:16
hi @Koro!!
i'm bored with work, just popped in for some entertainment :-)
It was raining here and since there are lot of mango trees around, there were mangoes all over the roads earlier.
They fell off the trees.
ohhh, nice!!!
the mangoes you get in California are not terribly nice
@copper.hat Depends on where you get them. WinCo often has the little ones that are so good.
WinCo?
Alphonsos, I think.
19:20
@copper.hat If you like mangoes, try mangoes from Ratnagiri. They are juicy!!
@copper.hat Big supermarket chain in SoCal.
Different state to NorCal :-)
Alphonso mangoes from Ratnagiri are very famous here.
@copper.hat Oh, but there are WinCos in NorCal, Nevada, and Arizona, too!
I'll see if I can find one locally.
19:21
AND OREGON, WASHINGTON, AND UTAH TOO?!
you may find Ratnagiri mangoes there also I think. I won't be surprised if they get exported too.
WinCo is employee owned, unionized, and (usually) rather cheap. Generally very good on bulk food. Produce can be somewhat hit or miss---on a good day, it's excellent, but on a bad day, it can be very unfortunate. The only downside is that they don't take credit cards (cash, checks, and debit cards only).
bummer, closest seems to be about 35mi away :-(
@copper.hat Where I live, that would be considered quite close.
The nearest high-quality grocery stores to my current location are at least 90 miles away.
There is a Safeway in my town, and Wal-Mart in Winslow (30 miles away), but the nearest fresh fish and produce are in Flag.
wow. i am spoiled by a Trader Joes about 1mi away
19:27
Heh. The nearest Trader Joe's is 200 miles away.
wow. the furthest apart points in Ireland are about 300ni
Oh, that's not quite right. The nearest Trader Joe's is in Prescott. Only 180 miles away.
> Trump is leaving the courthouse

Press conference from the DA is scheduled for 3:45 ET, 10 minutes from now
0
Q: Why is $\phi$ onto if $X$ is path connected in Hatcher's exercise 1.1.6?

Koro1.1.6: We can regard $π_1(X,x_0)$ as the set of basepoint-preserving homotopy classes of maps $(S_1, s_0)→(X,x_0)$. Let $[S_1,X]$ be the set of homotopy classes of maps $S_1→X$, with no conditions on basepoints. Thus there is a natural map $\phi :π_1(X,x_0)→[S_1,X]$ obtained by ignoring basepoint...

19:41
@XanderHenderson Ours is 3 miles away. There was a shooting there, with one dead, on April 1. It was not an April Fool's Joke.
Why so many shooting news from there lately?
Every now and then there is some news on shooting at some school there.
Drug traffickers are getting aggressively competitive.
What's going on?
in some sense, shootings aren't exactly "news," and nothing in particular is going on that hasn't been going on.
@user85795 but shooting at kids?
19:44
School shootings are usually psychos gone wild.
koro, in your MSE question, why would you expect g or g circ q or whatever to be based at x_0? you can certainly consider the homotopy class of any map, but why is it in pi_1(X, x_0) so that you can apply phi to it?
ahhh, I see. Thanks a lot.
@robjohn Ugh...
@robjohn Lovely. I hadn't heard that one.
We had been at the Chili's outside of which the shooting took place just 30 minutes before.
glad we didn't delay getting food
19:57
School shootings (and other mass shootings) are a hugely exaggerated problem. According to Pew, there were 45,000 firearm related deaths in the US in 2020. Even using the more liberal estimates, only around 500 of these were in mass shootings. The majority of these deaths were suicides.
Mass shootings are dramatic, but they are not the real problem in the US. :/
But they do scare people
Especially the one in Vegas.
@robjohn Indeed. They do, because they are unusual and dramatic. But your chance of being involved in such an incident---let alone being injured or killed---are close to zero.
Yes. That is why being in the same place as the one on Saturday just 30 minutes before the shooting, was jarring. Even that is pretty unlikely.
Yeah, and the one on Vegas was the biggest ever.
20:04
why not ban possession of guns?
@robjohn Indeed. I am am genuinely not trying to diminish the shock of it---a colleague of mine was shot and killed by a 12 year old in 2013 (en.wikipedia.org/wiki/2013_Sparks_Middle_School_shooting). After finishing my secondary ed credential, I worked for a bit as a substitute---Michael was one of the people whose classes I taught.
@Koro Because that would require a constitutional amendment, and there is a very powerful, vocal contingent in the US which is opposed.
ohh.
@XanderHenderson the note said 'bullying' was the cause of it.
these days it's maybe not even as clear that we can even regulate guns (short of bans) without constitutional amendment.
@leslietownes With the current composition of SCOTUS? Good luck.. :(
I'll buy a gun one day.
20:09
maybe at some point they'll decide that every one of us needs to carry a gun at all times. or that the constitution requires the government to issue guns to everybody at no charge. i don't want to give them ideas.
Come to think of it, fundamental group of a gun is not 0.
this is because of the hole that is there in the mouth of the gun from where the bullet comes out.
Hi! Is there a clever way to count this? 6 red, 5 blue and 7 yellow balls should be placed in six distinguishable boxes, such that every box contains three balls. Balls with same color are indistinguishable.
So the convexity and contractibility is lost.
What do you call a number that can't keep still? A roamin' numeral.
20:24
@CottonHeadedNinnymuggins Banned!
:(
@copper.hat lol, she gave them the finger
what's the fundamental group of the circle of a Mobius strip?
how to show that from a free product of Z with itself, there can be no injective homomorphism to Z?
koro: how does the circle 'of a mobius strip' differ from a circle? (a mobius strip regarded as a surface also retracts onto a circle, so has the same fundamental group as a circle)
koro: Z * Z is not cyclic (or even abelian)
$Z*Z$ is gross. :(
you should hear what the free product of Z with itself says about you
20:36
Oh yes, it is homeomorphic to the circle.
@leslietownes Meh. I don't really care what libel that jerk puts out into the world.
Z*Z is not Abelian??
Let's take two elements 12 and 35
(12)(35)=(1235)=(155)=11
Lol, what did I do wrong?
I think I can't combine these 'words' like this.
please don't invent notation that looks confusingly like cycle notation for elements of the free product Z * Z
(12)(35)=1235, (35)(12)=3512 so not Abelian, simple.
however, the inclusion of the boundary circle of the Möbius strip into the Möbius strip is not a homotopy equivalence even though both spaces are homotopy equivalent to $S^1$
20:41
oh no no. It was meant as a parentheses just to indicate that () was from first Z and () from the other.
@Thorgott the inclusion induces an injective homomorphism, right?
i guess how you "see" that Z * Z isn't abelian depends on how you construct or define it, but it should fall out pretty quickly. the vibe is, there's no reason for the generators of the factors to commute. there are homomorphisms of that thing into nonabelian groups that map generators of each factor to whatever elements you like
I thought Mobius strip def. retracts onto its circle.
But apparently this is false.
there are circles and there are circles
hmm, so I should use Stefan Van Kampen to find $\pi_1$ of a Mobius strip.
U= square with hole at the centre, the square has all Mobius strip identifications.
stefan van kampen, the renowned dutch electro house DJ?
2
20:48
$$\zeta(s)= \sum_{n=1}^\infty \ln\bigg( \cosh(n^{-s})+\sinh(n^{-s})\bigg) $$
V= square with a region containing the removed center.
@leslietownes Dutch?! Man, I thought he was Austro-Italian.
$U\cap V$ is path connected. $U\cup V=$ mobius strip.
leslie, Armin van Buuren
$\pi_1(V)= 0$ as it is contracitble.
$\pi_1(U)=?$
base point is bottom left point of the square
@Thorgott: any suggestions?
Ohh, Van Kampen is in next chapter so I am not supposed to use it. But who cares!
20:53
@Koro yes, multiplication by 2 in fact
I'll use it still.
the Möbius strip retracts onto the meridian circle, but not onto the boundary circle
ohh
@geocalc33 nice obfuscation
but how to complete the proof using VK?
20:54
not quite sure if meridian is the right term, but the circle in the middle
I think VK won't work like this as $\pi_1(U)$ is as difficult as finding pi_1 of Mobius strip itself.
why would you use VK, it's homotopy equivalent to a circle
which is actually notoriously not something you can compute easily using VK unless you prove the more general version of VK involving groupoids/multiple basepoints (Ronnie Brown loves this example)
This is so because U def. retracts to its bdry which is Mobius strip.
@Thorgott hmm, I don't understand why it is so.
how do you define the Möbius strip?
It does not look obvious to me, that is.
I define it a square with left, right edges identified in opposite order.
20:58
the square deformation retracts onto the horizontal line in the middle and this induces on the quotient a deformation retraction of the Möbius strip onto its center circle
you contract all the "vertical" portions and are left with a circle
what is center circle?
The thing is I find meridional , longitudinal, latitudinal terminology confusing.
anyone familiar with the Hausdorff moment problem?
@geocalc33 Yes, but I haven't thought about it since my undergraduate probability class, 20 years ago.
in this problem I read that the set of polynomials is dense in the associated Hilbert space
21:01
@Thorgott using this Torus also retracts to a circle.
And so does that bottle.
Is this correct?
@Koro No?
How are you retracting the torus to a circle?
@Thorgott I don't understand how it induces the said retraction.
@XanderHenderson I don't know. I'm trying to understand Thorgott's comment.
it looks very complicated.
@XanderHenderson but this should be true, right? We just squeeze the torus to its boundary circle.
The retraction is deformation retraction.
uh, it's definitely not complicated. i don't know why you'd want to, but you can write down the maps for everything in the square model
Ah, but then fundamental group of a torus will also be Z.
Z*Z is not isom. to Z.
so this is wrong.
@leslietownes He first did contraction in square. Then how did identifications happen? contracting a square to a line makes left and right side of the square identification in opposite order meaningless. doesn't it?
I mean the order is lost in this process.
It won't make sense to talk about joining two ends of a thread in opposite order.
to be clear, i was talking about thorgott's deformation of the moebius strip onto the 'horizontal line in the middle' i.e. if the square is IxI with left and right edges identified and the circle is the line segment y = 1/2 in this square. not the torus or klein stuff
21:13
Ohh, so the deformation retraction was onto a circle in the middle of the strip not onto the boundary circle.
Ohh I see. The confusion was because of the terminology
It makes sense and I think I don't need to look at the square also to see this.
@Koro The torus does not deformation retract to a circle.
yes, it doesn't. If it did, then torus will also have pi_1 = Z.
@Koro "Yes, it doesn't"... X(
iff no it does
I should have said: "no, it doesn't." right? (grammatically speaking)
:)
I think in American english, one says: no, it doesn't. or yes, it does.
21:17
the Möbius strip deformation retracts onto the red circle by shrinking the blue lines towards the middle
ah yes, the mobiuth trip
@Thorgott yes yes, I understood. Thank you very much. :-)
@robjohn This needs to be your new avatar!
@TedShifrin It was for a while, years ago
@robjohn Ah, a long, long while ago ... before my time.
@leslietownes Just to be clear: retraction doesn't tell you anything; for example, every space retracts to a point. You need deformation retraction.
21:23
yeah, i should have said that there. for partial credit, i think i was saying it at least some of the time
Well, I only noticed a few things when I scrolled back.
also, while i don't want to put the entire blame on the coronavirus epidemic, it certainly didn't help
and if my daughter were here, she'd say: retraction doesn't tell you anything
Well, of course, she knows all.
Yup, before my time.
I think I appeared in chat in 2013 (thanks to Peter/Pedro).
21:38
Anyone here feel confident in a recommendation of a Measure Theory book? My friend has been nagging me that something therein will help me with a few problems I've been puzzling over.
i don't know of one. measure theory tends to be treated in textbooks as an adjunct to other things because if you just study it by itself it's boring. and the other books it appears in, are not so much good books about measure theory, but good for their other topics.
but, bartle had a book called something like 'integration,' short (maybe 100 pp?), that i liked, for a lot of the basics. from the 1960s. he has some more recent book with a similar title that has more stuff, which might be an expanded version or something different.
@A016090 To what end are you / your friend studying measure theory? It is not usually treated as a topic on its own...
Briefly, what sort of topics are you wanting to learn?
My standard reference is Royden, although I learned a lot from Halmos's Measure Theory text, as well.
i would dis-recommend the rushed treatment in rudin's 'principles of mathematical analysis.' it might even be worse than PMA's multivariable calc section.
@TedShifrin Yeah, Royden is my goto for introductory stuff---he is a little "talky", but, personally, consider that a good thing.
21:42
Schilling's Measures, Integrals and Martingales has a solution manual
There is a Russian-sounding author who I kind of like...
yeah, what are you interested in? if you're interested in stochastic processes, that might be a different world from, say, someone who only wants to work on R^n or topological groups.
Bogachev, maybe?
B... something.
@XanderHenderson I haven't the foggiest. I'm handling a problem involving expected values and probabilities and I've been tackling them using converging infinite sums, he's a former mentor and professor of mine so he's fond of throwing me at things that primarily expose me to the field and secondarily, meaning by happenstance, may help me out as an alternative method.
@A016090 So if you are heading into probability, measure theory leads into integration. McDonald and Weiss has, I think, a reasonable path there.
21:44
Я этово не знаю.
@TedShifrin Жаль.
For more context, I'll give the simplest example problem I've done so far: Suppose you roll 1d6. If you roll a 6, you may roll again. Determine the expected value of the number of rolls for this situation. You'll find the solution isn't egregious, but then the problem grows in exciting ways when you try for 2d6 or 3d6, where multiple 6's each grant additional rerolls of all the d6s.
This is just counting, as in a usual elementary probability course. I don't see measure theory.
It's true that infinite sums do often show up in probability applications, if there's a possibility of arbitrarily long-lasting games.
Have you started with a good undergraduate probability book?
He says that there are principles within the field that can lead to faster computations of what I'm tackling. I'm well aware this is a discrete problem, which is also why I was curious behind his suggestion.
21:48
Well, measure theory can certainly handle discrete things, too, but this is puzzling to an outside observer.
@TedShifrin Been there, done that, got the t-shirt and teach the class on occasion. I'm just curious. I've just been abusing general sequence and series techniques to get what I wanted, and I'm sure to higher minds that just seems barbaric.
@TedShifrin Sheldon Ross' text, for example.
Perhaps one thing he is thinking of is the rôle and power of the indicator function. Most probability courses do not emphasize it enough, it seems.
When he suggested it and another professor chimed in that it was "the logical next step" for what I was doing I wondered if they were just trying to egg me into another textbook.
it's often helpful to approximate complicated or limiting cases of discrete stuff by continuous stuff, but even that tends not to need too much measure theory for things like die rolls. just normal integration on subsets of R^n would be enough.
21:51
As I recall, Ross starts with measure theory.
I taught out of Ross, but (had I not retired) would not do so again. Precisely because he underplays the indicator function.
maybe he gets a promotional kickback from some kind of referral code if you buy a book.
Huh? Ross is an undergraduate text. Nothing resembling measure.
@TedShifrin Not the intro book.
This second-guessing is silly, @A016090. Ask them directly what they're talking about.
21:52
@TedShifrin He did mention something about an indicator function, and scrawled $\intf(x)dP(x)$ or something of the sort. Admittedly on that part I was juggling students for the evening.
There is another text---something like "A second course in probability theory".
Oh, that I don't know.
whittle's "probability via expectation" is a pretty in-depth book that never does measure theory as such. some of our favorite functional analysts do similar things to indirectly construct measure spaces
@leslietownes Not likely, he often just points me in a direction or suggests a book I already have access to. This is the first time he actually didn't know of a book to recommend.
21:57
that's just so the promotion seems less like a hard sell. viral marketing.
the best measure theory salesman
@XanderHenderson Thank you kindly! My probability upbringing was through RL. Scheaffer, but this looks like it'll connect quite nicely.
I appreciate everyone's contribution to my stumbling through arbitrary recommendations.
Even Ted, who seems to tolerate my presence in measures.
another book you'll need to get is "Personal Finance the Lesliecoin Way"
@A016090 You mean to say that your presence is measured?
@leslietownes Can you buy it with lesliecoin?
22:05
no, but it's free with purchase of some lesliecoin.
I'm still waiting for all the lesliecoin you promised me.
it's all there. there's no need to spread misinformation about where it is. it is where it always was.
♫coffee coffee coffee♫
♫late in the day♫
22:29
@shintuku I buy more decaf than regular just because I find myself wanting that nice, bitter brew even in the wee hours.
i mix caffeinated stuff (usually soda but sometimes tea) with decaffeinated hydration (water or herbal 'tea') all day. i figure as long as the ratio of decaf to caf is high enough, i'm not frying my nerves too much.
Indicator functions tend to just get tossed in at the beginning of an undergrad probabillity course when talking about moving from bernoulli to a binomial count...... Here's this nice $I(x)$ that does this with value $0$ and that with value $1$........
23:03
I would like to purchase 2000 lesliecoins as a birthday gift for my friend
i know a guy who knows a guy
send me location
:D
23:48
Are these suppose to be the limits of integration to the intersecting planes we were discussing yesterday? $\int_0^1 \int_{1-z}^1 \int_{0}^{2-y-z}dxdydz$......I realized that the lengths of all the sides of the cube were supposed to be $1$ which means that the plane looking down on the cube is actually not at $1$ @TedShifrin
whenever you are back
02:00 - 18:0018:00 - 00:00

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