Yes, isomorphic vector spaces have isomorphic complexifications.
If you're asking how to "implement $\mathbf{R}^{+} \otimes \mathbf{C}$" without unwrapping the isomorphism with the usual vector space structure on $\mathbf{R}$, I don't see a way to do this offhand. At first glance it's tempting to think of the complexification as $\mathbf{C}^{\times}$ with complex multiplication as "addition", and exponentiation as "scalar multiplication". The fatal problem is, the complex exponential mapping is not injective (unlike the real exponential mapping), so to make sense of the operations you end …