We are given that $\forall x,y, f(x+y) = f(x) + f(y).$
a) We claim that $\forall i \in \mathbb{Z}_{\ge2}, \forall x_i \in \mathbb{R}, f(x_1 + \dots + x_n) = f(x_1) + \dots + f(x_n).$
Let $x_1,x_2,\dots,x_n \in \mathbb{R}.$ Using our given, let $x_1 = x$ and $x_2 = y$. Then $f(x_1 + x_2) = f(x_1) + f(x_2).$ Assume that it holds for some positive integer $k \ge 2$. Then $f(x_1 + \dots + x_k) = f(x_1) + \dots + f(x_k)$. We now note that $x_1,x_2,\dots,x_n$ are just real numbers, so define $z = x_1 + x_2 + \dots + x_k$ Then using our given, $f(z + x_{k+1}) = f(z) + f(x_{k+1}) = f(x_1 + \dots…