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01:01
Hey guys, anyone knows if this is an identity? $\sum_{k=0}^{n} \left( \begin{array}{c} 4n \\ 4k\end{array} \right) = 2^{4n-2} + (-1)^n \cdot 2^{2n-1}$
 
2 hours later…
02:49
@TedShifrin I might be overstepping here, but do you happen to have a suggested exercise list for the chapters of your text? I'd like to do all the questions for every chapter, but as we all know that isn't possible.
@dc3rd I actually did assign this problem. You can find my problem sets online (I can give you the link), but the computational stuff was WeBWork, online, so the problem sets are more theoretical. I don't know your background or goals.
@TedShifrin Would you like to see what I have so far?
I've completed some, and some I've been stuck on for a while. Some wording is unclear as well
03:12
@TedShifrin Yes I wouldn't mind that link at all.

Background: Did Spivak last year along with Insel's Linear Algebra, doing the second half of this concurrently with your book. Going to be in my 4th year of University in the fall. Took a year and half off because my math foundations have not been satisfactory for what I want to do.

Goals: In the end statistical modelling, but I would like to get a masters as well and who knows perhaps a PhD because I do enjoy the theoretical components of everything.
Ah, a future data scientist/statistician :)
I'm glad you're putting forth the effort to improve your math foundations. The majority of students I've seen wanting to go into stats/DS have no interest in doing that
@TedShifrin

My study track in more detail would be:

Spivak, Insel (Linear Algebra), Rice (Math Stats) [done it already] ----> Shifrin (then Munkres), Insel, Differential Eqns, Num Theory, Stats courses (regressions, etc) --> Topology, Groups, Rudin (or something similar was also thinking Royden) ---> Upper Year Stats courses that are built off of everything above
Stats/DS does not use differential equations at all. If you intend on going into high-performance computing, you'll find numerical analysis useful, but otherwise, you won't use it.
@Clarinetist Yes. For whatever reason I'm extremely particular and want to make sure I know WHY I may be able to apply such and such a technique. I'm not into just depending on the formula and chugging along. What if I want to alter the expressions and things of that nature.
@Clarinetist well I always had the view that whatever modelling I am going to be doing isn't going to be static and as such Diff Eqns might be handy for those scenarios
After you get through Insel's and Ted's text, I would suggest diving more deeply into statistical theory combining linear algebra and probability, something like Foundations of Linear and Generalized Linear Models by Agresti.
03:23
There's some other things I probably forgot to inlude, but that's the skeleton more or less
@Clarinetist I have Agresti's book here actually, but I know I'm not ready for it yet. You don't think maybe I should do the measure theory from Rudin or Royden first before I approach these higher level Stats books?
Stochastic modeling requires some background in stochastic processes - so you'd probably need something like Royden's text, a more probability-focused measure theory text, and then probably Stochastic Differential Equations by Oskendal
You DEFINITELY don't need measure theory before Agresti
If you want an alternative text, another one is Plane Answers to Complex Questions by Christiansen
Ok...well I'm also working through Kutner's Linear Regressions book at the moment. Definitely is a gem compared to the book I had to use for a past linear regressions course
(but be sure to start at the appendices before you start on Ch. 1)
Kutner is a classic, but avoids linear algebra for the most part (as far as I recall; I don't own that text but have skimmed it)
You're probably slightly confused by what I'm suggesting. I'll give you the spiel I told a Math PhD student recently
Stats does not build on itself like math does.
You do not need to take pre-calculus based stats, for example, before taking calculus-based stats. In fact, you could do measure-theoretic stats without knowing any calculus-based stats.
There are essentially three "levels" of stats. None of them build on each other, but are entirely dependent on your math background. Talk to any decent stats department with a graduate program: they will care more about your math background than any stats classes you have taken.
But there would be large gaps in what I'm missing from the big picture right? So for example I sat in on a grad level math stats course and the discussion of a sample space was far different from my 2nd year course
You summed it up in your last statement
My personal opinion: I didn't really understand stats until my master's level courses (i.e., Agresti, Casella & Berger). Undergrad-level stats is too watered down for practical use.
Everything you thought you knew about sample spaces you will throw out when you hit PhD-level probability.
03:32
I see. Well now I have something to concern me because I in essence have scorched earth with respects to my math stream of things and was really banking on my performance from my higher level stats courses to compensate for the earlier poor math showing (I took math courses before I was mathematically mature enough and suffered the consequences)
hence why we have a "year and a half" break from school....lol
My alma mater, for example, strongly emphasized good performance in real analysis coming in.

Also, there is no shame in doing a MS before you pursue a PhD. That's essentially the route I went, because I was (and have) been working full-time on top of my education.
Oh I don't even see an issue of getting an MS before any PhD. I look at it as good preparation should you want to take that next step.
Anyway, my two cents. Hope that helps. I had to learn the hard way when it came to understanding how to structure my stats curricula to prepare me for industry work. No one really guides you through this stuff.
Yes thank you for the insight. I have been struggling on asking myself the right way to structure things.
If you're intending on entering industry with a MS, Agresti and Casella & Berger will be the foundations of your work. I use Agresti's Categorical Data Analysis nearly every day (a higher-level text than the previous Agresti).
03:39
Yes industry is the intention. Academia doesn't call me in that way
I'm going to check out the Casella & Berger text
FYI I absolutely hate C&B, but it's better than the alternatives. You already know the material from Rice, so you have a decent foundation coming in already.
I have heard good things about Hogg and Tanis' text, but I've not obtained a copy nor read it.
If you want an absolute headache, see Bickel and Doksum's Mathematical Statistics, Vol. I
Looking at the moment, I have the Hogg text: Introduction to Math Statistics?
Yeah, I believe that's the one. I've not read it, but people seem to recommend that one as a substitute for C&B
Sorry, wrong one
It is Probability and Statistical Inference
Ok. Well I look for that one along with C&B.
Once you get through the Agresti + C&B core, you can essentially dive into any master's-level text in stats
Could be survey sampling, nonparametric estimation, time series, experimental design, categorical data analysis, etc.
03:46
Well in that case, the next phase of the operation is planned out. Thanks for the input.
04:14
@dc3rd For stat grad work you definitely need some analysis strength, but you don't need Munkres topology. That is clearly overkill. I'm not sure you need more linear algebra than what's in my book (@Clarinet Do statisticians care about Jordan canonical form?). You definitely want some measure theory to do serious graduate probability, so Royden would be more useful than Rudin.
You need a bit of facility with fiddling with unions and intersections of sets, but you definitely do need a whole lot of point set topology.
vzn
vzn
@Semiclassical some dramatic new developments in QM foundations + QC experiments! think you would find it of (high?) interest... wonder about your take on it... chat.stackexchange.com/transcript/message/56826061#56826061
@TedShifrin Regarding Jordan Canonical Form, no, it's not important at all. The eigendecomposition, Cholesky decomposition, and singular value decomposition are much more important.
@TedShifrin you say I do need a lot of point set topology, but isn't the first half of Munkres Topology all point set?
At the master's level, you need almost zero topology (just know what an open set is). Different story at the PhD level, but it's primarily point-set.
04:19
What is it that topology at the PhD level brings to the picture? (if it can be answered easily)
vzn
vzn
@Clarinetist stats/ DS is making major inroads to physics and yes it is starting to be used on differential equation type systems, its a new area, but already strong results in it. deepmind protein folding is a top example, and ML is being used on quantum computing problems increasingly, etc
Any measure theory book or class will assume you know some topology coming in is basically what it is.
If you want more specifics, you can Google the "Borel $\sigma$-algebra"
Actually before I took the decision to take this year off and thought I could rapidly plug my gaps I was reading and "attempting" Athreya's Measure Theory and Probability and encountered Borel sets, so it was from there I assumed that topology would be important even at the master's level
Remember how I said that when you hit PhD-level probability, you're going to throw out any understanding you had of sample spaces? That's the main reason.
vzn
vzn
anyway also on that topic, DiffEq is used heavily in engr ofc, and DS+ML increasingly being used in engr areas etc. so yeah, think DiffEq is one of the top math courses to take esp if one has any applied interests. and heck even if you dont theres a lot of deep theory in DiffEq etc
04:25
Athreya was a professor at my alma mater. It is used only for the PhD stats classes there.
So I wasn't even attempting to walk before I could crawl but was all out sprinting....
Right. And as much as I love Athreya's text... I've actually bought about 20 other books on that topic since I enrolled in that program about 5-6 years ago (just graduated last year)... I've not found a single book on that topic at that level that was suitable for self-study
I'm going through the second semester right now through a similar text, but I refer to Athreya all of the time as a reference.
Is your self study just towards the ambition of absolute mastery and as a result apply the skills and thnking how you see fit?
That's the dream.
I've also had an interest in measure-theoretic probability since my actuarial science days.
So you want to be able to truly try and bring everything together and understand how they complement each other.
04:33
@dc3rd Sorry, that was a typo. I meant do NOT need.
Basically. It also helps me do my job better.
I could see that being the case
For SVD, etc., Strang is way better than a theoretical lin alg book.
Dr. Shifrin?
Oh oh, polite is here.
04:36
I did write this:
@TedShifrin I would agree with that. You may want to also consider, in addition to the intro book by Strang, Linear Algebra and Learning from Data by Strang, better suited as a second text
Oh, sorry if I missed stuff.
SVD?
What have you got?
04:38
@dc3rd Singular Value Decomposition
So this is for chapter 3, #16
We are given that $\forall x,y, f(x+y) = f(x) + f(y).$

a) We claim that $\forall i \in \mathbb{Z}_{\ge2}, \forall x_i \in \mathbb{R}, f(x_1 + \dots + x_n) = f(x_1) + \dots + f(x_n).$

Let $x_1,x_2,\dots,x_n \in \mathbb{R}.$ Using our given, let $x_1 = x$ and $x_2 = y$. Then $f(x_1 + x_2) = f(x_1) + f(x_2).$ Assume that it holds for some positive integer $k \ge 2$. Then $f(x_1 + \dots + x_k) = f(x_1) + \dots + f(x_k)$. We now note that $x_1,x_2,\dots,x_n$ are just real numbers, so define $z = x_1 + x_2 + \dots + x_k$ Then using our given, $f(z + x_{k+1}) = f(z) + f(x_{k+1}) = f(x_1 + \dots
b) For the longest time, the wording confused me. I thought there was one universal $c$ which worked for all $x$, in other words asking me to prove the claim that $\exists c \in \mathbb{R}, \forall x \in \mathbb{Q}, f(x) = cx.$ Either way...
So after that wording confusion, I was unsure of what to do. So then I just continued onto #17:
We are given that $\forall x, y \in \mathbb{R}, f(x + y) = f(x) + f(y)$ and $\forall x, y\in \mathbb{R}, f(x\cdot y) = f(x) \cdot f(y),$ and $\exists x \in \mathbb{R}, f(x) \neq 0.$

a) We claim that $f(1) = 1.$ Since $f(x+y) = f(x) + f(y),$ notice that $f(1 + 0) = f(1) + f(0) = f(1) \Rightarrow f(1) = f(1) + f(0) \Rightarrow f(0) = 0.$ Then, using the other property, $f(1 \cdot 1) = f(1) \cdot f(1) \Rightarrow f(1) = f(1)^2 \Rightarrow f(1)(f(1) - 1)) = 0.$ Thus, $f(1) = 0$ or $f(1) - 1 = 0$. If $f(1) = 0$, then $f$ is the map $x \mapsto 0,$ since using definition two $f(x \cdot 1) = f(x)
It is saying that. One $c$.
I'll let you read that before continuing to paste, otherwise there will be a massive wall of text.
Right, that's good.
For problem 12 in the derivatives chapter, I have this:
a) $a'(t) = L(a(t))$ I assume one might mistake and write $L(t)$, but $t$ is time and $L$ maps distance to speed limit, not time spent on road to speed limit.

b) We are given that $a'(t) = L(a(t)),$ and $b(t) = a(t-1).$ We wish to show that $b'(t) = L(b(t)).$ Taking the derivative of $b(t) = a(t-1),$ we have $b'(t) = a'(t - 1) = L(a(t - 1)) = L(b(t)).$

c) We are told that $a(t) = b(t) + c,$ where $c \ge 0$ is some distance. Since $a'(t) = L(a(t))$, we see that $a'(t) = b'(t) = L(a(t)) = L(b(t) + c).$ $B$ will always travel at the speed limit if $c = 0.$
04:44
That's not the intent. What when $c>0$?
Sorry, for some reason stackexchange didn't scroll down
I didn't know you wrote a message
Well, if $c > 0$ then $b'(t) = L(b(t) + c)$
And we want to find under what conditions $b'(t) = L(b(t))$
I don't see how $c > 0$?
Right.
You want a condition on the function $L$.
Oh. lol
$L$ is constant then?
But we have that $L(b(t)) = L(b(t) + c)$
04:54
Yes.
So either $L$ is constant or $b(t) = b(t) + c$
Think about the graph of $L$.
Most likely the answer is quite simple
But I don't see how it could not be constant or that c is nonzero in that case
It just has to be
If I imagine L, I imagine it to be a kind of step function
05:00
Think about some common functions.
I guess that L is periodic, maybe?
There you go!
OK, cool.
Okay, well, cool.
Here is my work on question 8 in the limits chapter:

a) It can exist. Define $f(x) = 0$ if $x < 0$ and $f(x) = 1$ if $x \ge 0$. Define $g(x) = 1$ if $x < 0$ and $g(x) = 0$ if $x \ge 0$. We see that $\lim_{x \to 0+} f(x) = 1, \lim_{x \to 0^-} f(x) = 0$, so $\lim_{x \to 0} f(x)$ does not exist. Similarly, $\lim_{x \to 0^+} g(x) = 0, \lim_{x \to 0^-} g(x) = 1.$ Therefore, $\lim_{x \to 0} g(x)$ does not exist either. However, notice that $\forall x \in \mathbb{R}, f(x) + g(x) = 1.$ Thus, $\lim_{x \to 0} (f(x) + g(x)) = 1,$. Using the same definitions for $f,g$, notice that $\forall x \in \math
05:03
Ugh, I don’t have the book with me, so I'll have to look at this later.
I can upload the exercise
One moment
8. (a) If $\lim _{x \rightarrow a} f(x)$ and $\lim _{x \rightarrow a} g(x)$ do not exist, can $\lim _{x \rightarrow a}[f(x)+g(x)]$ exist? Can
$\lim _{x \rightarrow a} f(x) g(x)$ exist?
(b) If $\lim _{x \rightarrow a} f(x)$ exists and $\lim _{x \rightarrow a}[f(x)+g(x)]$ exists, must $\lim _{x \rightarrow a} g(x)$ exist?
(c) If $\lim _{x \rightarrow a} f(x)$ exists and $\lim _{x \rightarrow a} g(x)$ does not exist, $\operatorname{can} \lim _{x \rightarrow a}[f(x)+g(x)]$ exist?
(d) If $\lim _{x \rightarrow a} f(x)$ exists and $\lim _{x \rightarrow a} f(x) g(x)$ exists, does it follow that $\l
I tried hard to look for a counter example to b), but I couldn't find one.
OK, a is right. For b try to give a proof. B and c are related. D is right. What would make it be true?
So c is true?
Hmm
Your answer to c is right. Proof?
Oh so it's right
Is b right?
05:11
Yes.
Okay! Great. I thought you meant that what would make c true
I asked that for d. But I want proofs for b and c.
Well, for b) we have that $\forall \epsilon > 0, \exists \delta_1 > 0, 0 < |x - a| < \delta_1 \Rightarrow |f(x) - L_1| < \epsilon,$ and $0 < |y - a| < \delta_2 \Rightarrow |f(y) + g(y) - L_2| < \epsilon$
So this is tricky. Using triangle inequality, we have that $|f(y) + g(y) - L_2| \le |f(y) + g(y)| + |L_2| $
I'm going to chime in with a hint: what would you suspect is the limit for $g$, assuming it exists?
Oh I might have an idea actually
Well, I would want $g(y) - L_2 = -L_1,$ maybe?
05:15
You're allowed to use known theorems.
Oh, another tip
You needn't prove everything from scratch once you have theorems.
Am I? In that case... We know that if $\lim_{x \to a} f(x) = L_1$ and $\lim_{x\to a} g(x) = L_2$, then $\lim_{x \to a} (f(x) + g(x)) = L_1 + L_2$, then
Right.
Whenever you're proving that a certain limit exists assuming other limits exist, rarely do you want to use the raw "$\epsilon$" in cases for which you know the limit exists.
See, e.g.,
4
Q: Letting $\epsilon = \frac{\epsilon}{2}$

user_hello1I know this is minor, but how is it that you justify this formally? $$ \begin{equation} \begin{split} | x - a | < \delta &\Rightarrow |f(x) - l| < \epsilon \\ &\Rightarrow |f(x) - l| < \frac{\epsilon}{2} \end{split} \end{equation} $$ To better illustrate what I mean, consider as a counter-exam...

05:18
Since we know that $[...] = L_1 + L_2$, we have that $|f(y) + g(y) - (L_1 + L_2)|,$ so then
$|f(y) - L_1 + g(y) - L_2| \le |f(y) - L_1| + |g(y) - L_2|$
The main point is this: since that inequality is true for EVERY $\epsilon > 0$, it is also true for any reasonable transformation of $\epsilon$ that also results in a positive number.
Ted is pointing you in the right direction, assuming you have that theorem available.
Don't muddle things, Clarinet.
Polite, focus on applying your theorem, nothing else.
So then since the sum limit exists, we have that $\forall \epsilon > 0, \exists \delta_c > 0, 0 < |y - a| < \delta_c \Rightarrow |f(y) - L_1| + |g(y) - L_2| < \epsilon$
Ignore everything I said (I'm heading to bed soon, anyway); Ted is right: apply that theorem cleverly, and you'll be done in one step.
And notice that since the limit of $f$ exists, $\forall \epsilon > 0, \exists \delta_f > 0, 0 < |x - a| > \delta_f \Rightarrow |f(x) - L_1| < \epsilon/2$
05:22
I want no deltas, no epsilons..
Subtracting the consequent from the line above, we have that $0<|y - a| < \delta_c \Rightarrow |g(y) - L_2| < \epsilon/2$
Okay :(
Okay, going back to that theorem
Well, we have a theorem of $P \land Q \implies R$. P is true, and R is true, so Q must be true? lol
Since Q cannot be false, otherwise we'd have true and false implying true, and the implication is true, which makes no sense
Wrong logic.
False premise implies anything.
You're right
05:27
Heading to bed soon, but will chime in anyway: there is nothing deep to think about here (i.e., don't complicate this). What do you have available as the assumptions in part (b)?
Well, the contrapositive is that if $\lim_{x\to a} (f(x) + g(x))$ does not exist, then at least one of the individual limits do not exist
But actually that doesn't help that much I suppose
Okay, so let $\lim_{x\to a} f(x) + g(x) = L_3$ and $\lim_{x\to a} f(x) = L_1$
We know both of those are true
Big hint: what tool do you have other than logic?
Oh my god
I just realized
We don't know the first thing. What you do know is that it's just a value.
Hahahahahaahahahahahaah
So then, since both of those limits exist, we can do the following trick:
05:30
Yes, Clarinet makes a crucial point.
$\lim_{x \to a} (f(x) + g(x) - f(x)) = L_3 - L_1 = \lim_{x \to a} g(x)$
Right. $g=(f+g)-f$.
Yes, indeed
OK, good.
I should have stopped trying to do an $\epsilon-\delta$ proof
Jesus
05:32
What about c?
the speed of light?
Well, if the sum does exist, then we just showed that $g(x)$ does exist.
So that can't be the case if the sum does exist.
Which means that it's not possible for the limit for f to exist and the limit for g to not exist
And the sum of the addition to exist
Now this part is logic.
OK, enough for tonight.
Okay. Define $P$ to be the limit of f exists, $Q$ to be limit of g does exist, R to be the lim of the sum to exist. Our theorem states that $P \land Q \implies R$. As you wrote, $F \implies R$ is always true, so maybe?
@TedShifrin Okay! Thanks for the help tonight!
what is the meaning of d/d₩overline{z} in 'f is analytic if and only if d/d₩overline{z} f =0?' derivative w.r.t ₩overline{z}?
d z/d overline{z}=0?
 
5 hours later…
10:52
$\left\{x \mid x \in \mathbb{N}\right.$ and $x^{2}=a^{2}+b^{2}$ for some $\left.a, b \in \mathbb{N}\right\}$
Does this set have upper bound ?
I think no beacuse x can take any value between $-\infty to \infty$
@mathsstudent close, but $x \in \mathbb{N}$ so not $-\infty$. Can you explain why $x$ can be any such value?
So it is (0,\infty)
No, you can not write any square as the sum of two other squares
For example $2^2 = 4$ is not the sum of $a^2 + b^2$ for some $a, b \in \mathbb{N}$
so x are those pythagorean tuples hypotenuse kind of thing ?
It will cover all natural numbers
@Krijn
@mathsstudent Yes, indeed
@mathsstudent Hmmm, no? Why? I just showed that 4 is not covered
11:01
Right got it
The thing is you need to show that the set of those ' pythagorean tuples hypotenuse kind of thing' are unbounded. It's not too difficult, there's a one-line argument.
can you help me I do not get that argument ?
@Krijn
Do you know a 'pythagorean tuples hypotenuse kind of thing'?
Just a number $x$ in that set basically?
Intutively I got but not able to write it mathematically @kri
@Krijn
Can you name one pythagorean triplet
11:10
(3,4,5)
Right
Now what happens when you multiply that by say, $2$. Every number in that tuple.
right got it thanks @Krijn
12:03
Hi all
Consider the paths of length 1. They should be (9*8)/2 - 8 (straight lines which are composed by 2 segments)=28. However, the solution is 40. Why?
What am I missing?
12:19
if $f : X \rightarrow \mathbb{R}$ is measurable, why is $g : X \times \mathbb{R} \rightarrow \mathbb{R}$ defined by $g(x,t) = \chi_{f^{-1}(t, +\infty)}(x)$ measurable?
More specifically, I want to know why the proof of this theorem goes through:
Let $\phi(t) = v[0,t)$ where $v$ is a borel measure on $\mathbb{R}_{+}$. Then for a random variable $f : (\Omega,\Sigma) \rightarrow (\mathbb{R}_{+} , \mathcal{B})$ we have $\int_{\Omega} \phi(f) d \mu = \int_{0}^{\infty} \mu(\{x : f(x) > t \}) v(dt)$.
The proof starts with $\int_{0}^{\infty} \mu(\{x : f(x) > t \}) v(dt) = \int_{0}^{\infty} \int_{\Omega} \chi_{f^{-1}(t,+\infty)}(x) d \mu(x) dv(t)$. Now we apply tonelli. At the very least to apply tonelli we should have that $\chi_{f^{-1}(t, + \infty)}(x) = g(x,t) : \Omega \times \mathbb{R}_{+} \rightarrow \mathbb{R}_{+}$ is measurable, but I can't seem to prove this, even just manually checking the definiton
I also supose we require $v$ to be a $\sigma$-finite borel measure ?
12:55
@Curio They have direction, so going from [1,1] to [1,2] is a different path then [1,2] to [1,1]. But I'm not sure what paths they allow. do they allow [1,1] to [2,3]? (i.e. top left to bottom middle?) do they allow [1,1] to [3,3] (skipping [2,2])?
I'm assuming not, paths can only go from [i, j] to [i ± 1, j ± 1] because then I do get 40
@dc3rd often, you need a minimum of topological structure on the space to prove existence of the (conditional) measures that you want to use
And to prove measurability of certain maps
Ted is right though, the necessary topology will mostly be supplemented by your lecturers/books. And the point-set topology that topologists care about is not the same as the point-set topology that probabilists/statisticians care about
@porridgemathematics I have no clue what that proof is trying to do, but this should be straightforward. It's only necessary to check that $\{(x,t):f(x)>t\}$ is measurable and this is the preimage of $(0,\infty)$ under the measurable function $(x,t)\mapsto f(x)-t$
the proof is actually a bit slick, once you apply tonelli you get $\int_{0}^{\infty} \int_{\Omega} \chi_{f^{-1}(t,+\infty)}(x) d \mu(x) dv(t) = \int_{\Omega} \int_{0}^{\infty} \chi_{f^{-1}(t,+\infty)(x) dv(t) d\mu(x) = \int_{\Omega} \int_{[0,f(y))} 1 dv(t) d\mu(x) = \int_{\Omega} v[0,f(y)) d\mu(x) = \int_{\Omega} \phi(f) d \mu$
test
hahahahahah
the typewriter is back
rekt
return of the typewriter
13:10
$\int_{0}^{\infty} \int_{\Omega} \chi_{f^{-1}(t,+\infty)}(x) d \mu(x) dv(t) = \int_{\Omega} \int_{0}^{\infty} \chi_{f^{-1}(t,+\infty)}(x) dv(t) d\mu(x) = \int_{\Omega} \int_{[0,f(y))} 1 dv(t) d\mu(x)$ $= \int_{\Omega} v[0,f(y)) d\mu(x) = \int_{\Omega} \phi(f) d \mu $
the only thing that is troubling me is why we can swap the order of integration in the first equality
@porridgemathematics isn't the thing that you need to prove that the function is measurable in x?
ah, for the frist integral
yeah
but the proof swaps the order, which needs measurability on $\Omega \times [0,+\infty)$
yeah right for fubini-tonelli it doesn't suffice that one order of integrals works out
even just for tonelli, I think
needs the $X \times Y$ measurability first
13:13
and we need sigma finiteness of product measure, so I think $v$ needs to be sigma finite
@porridgemathematics which should be the only thing needed since it's nonnegative
@porridgemathematics that's too much to worry about :D
anyway @Thorgott answered my question, it comes down to the measurability of that function, since $\chi_{f^{-1}(t,+\infty)}(x) = 1$ if and only if $f(x) -t > 0$ if and only if $(x,t) \in h^{-1}(0,+\infty)$ where $h(x,t) = f(x) - t$ which is measurable as he explains
so the function is really $\chi_{h^{-1}(0,+\infty)}(x,t)$
thanks :)
13:31
hey guys, can someone help me on this one? I've got a hint but I'm still stuck in this question. math.stackexchange.com/questions/3999951/…
I'm trying to solve by binomial theorem.
Here is the part I got stuck: $\sum_{k=0}^{4n} \left(\begin{array}{c} 4n \\ k \end{array} \right) x^k (1 + (-1)^{4n-k} + i^{4n-k} + (-i)^{4n-k})$
the hint is in the comments
13:55
@MikeMiller Hi
Here's a geometry/linear algebra question
A countable locally finite graph G is called amenable if inf{|del K|/|K| : K in G a finite subgraph} = 0, where |K| is number of vertices, and |del K| is number of edges going between points in K and points in K^c (the "boundary edges")
For example, Z^n is amenable (as are Cayley graphs of amenable groups). Groups satisfying linear isoperimetric inequality breaks amenability, so these are hyperbolic groups, for example.
Trees, easy examples of non-amenable guys.
This is literally "no isoperimetric inequality"?
"Small boundaries can bound large areas"
14:00
Yeah, but that's more like saying nonlinear isoperimetric inequalities. Z^2 satisfies quadratic isoperim ineq, like R^2
So the quotient |boundary|/|volume| becomes 0 in the limit
OK I get it.
I prefer a graph on a cigar to Z^2, easier for me to see, since the size of del K doesn't increase as you go up the cigar.
@MatheusSousa calculate the $(1^k+(-1)^k+i^k+(-i)^k)$ term
@MikeMiller That's good
in case you don't know what powers of $i$ look like, calculate those first
One is a cover of the other, but yeah.
Thats one way to say the situations are the same
14:02
To be clear my cigar is homeomorphic to the plane. The graph is $(\Bbb Z/4) \times \Bbb N$ with the bottom four vertices connected to a vertex on the mouth end of the cigar
I'm just making the circles fixed radius as you go off to infty
Yeah, so $S^1 \times \Bbb R$ with $S^1$'s all having the same radius
those are some weird cigars
That's covered by $\Bbb R^2$ so the isoperimetric constants are all same
No it's $S^1 \times [0,\infty) \sqcup_{S^1 \times 0} D^2$
An annulus is not a cigar because the mouth end is supposed to have a tip
The mouth end is not relevant for your graph right
14:04
The mouth end is where I connect the bottom four vertices
Oh, I missed that.
Anyway, this is not at all important lol
But that's only adding some small contribution (1 vertex) so it can be ignored.
So take an amenable graph G and a sequence K_n of subgraphs with |del K_n|/|K_n| going off to zero. These are called Folner sets or whatever
Here is my intuitive claim: K_n approximates G very well.
14:07
Keep going I will be back in 10 and read
Cool
One possible way to state approximation I suppose would be spectral, that is, maybe spectrum of the adjacency matrix of K_n converges to the spectrum of G
This makes sense, yeah? Take a large n >> 1. Enumerate the vertices of G such that the first |K_n| vertices are from K_n. Then the adjacency matrix of K_n gives a |K_n| x |K_n| submatrix of the adjacency matrix of G such that it is almost a block diagonal form
Not all terms off-(block)-diagonally are zero, but there are a very few nonzero terms, exactly |del K_n| many
Which, relative to the size of the block |K_n|, is as small as you like.
So the question boils down to if you have an almost-block-diagonal self-adjoint infinite matrix like this, is the spectrum of the block close to the spectrum of the big infinite matrix?
This is the linear algebra. Should be true but I have not checked
Something like this seems right except I don't know the spectrum of the bottom right bit.
The spectrum of $\begin{pmatrix} A & C \\ C^T & B \end{pmatrix}$ is very close to the spectrum of $A \oplus B$ when $C$ is small. (Straightforward computation; pay attention to what happens to kernel instead of arbitrary eigenvalue since the latter is a variation on the former)
For instance if $\lambda$ is not an eigenvalue of $A$ or $B$ and $\|C\|$ is (a factor of like 1/5 or something) smaller than $|(A-\lambda)^{-1}|$ and $|(B-\lambda)^{-1}|$ then $\lambda is not an eigenvalue of this resulting matrix.
Yeah (this is the reason you'd want to use (laplacian) = I - (adjacency matrix) and not (adjacency matrix), the latter has 0's along diag)
I agree with what you said. There has to be a quantitative statement though because A is increasing in size, dim A -> infty, and ||C||/||A|| -> 0
So it's about $|C|$ being smaller than the eigenvalue gap.
The thing that throws me off here is that $B$ does not seem to have large eigenvalues
I am more used to approximating by taking the finite dimensional approximation to be an eigenvalue truncation
$A = \Pi_{\lambda \leq c} T i_{\lambda \leq c}$
You're right, it's not clear how complement of Folner set behaves.
This is the B part
Hm
14:18
@BalarkaSen This is a tough question because every reasonable notion I have of convergence ought to fail
Eg
You are asking if $\{1, 2, \cdots, n\}$ converges to $\Bbb N$
That's right :)
Sure, yes, that seems reasonable, but what notion of convergence is that???
Probably under Hausdorff metric on $\Bbb R$.
The spectrum of everything relevant are discrete sets I believe
we're looking at spectrum of I - (adjacency matrix), the graph Laplacian, which always have discrete spectra. So maybe also convergence pointwise, eg, looking at the bottom of the spectrum, convergence there, then the next one, etc
14:35
Guys, I want to show that if $(X,\mathcal O_X)$ is an algebraic variety, then $(U,\mathcal O_X\vert_U)$ is too. I checked that $(U,\mathcal O_X\vert_U)$ is a $k$-space. Now for $x\in U$, there exists some open $V\subset X$ with $x\in V$ and closed $Y\subset\mathbb A^n$ such that $\phi\colon V\to Y$ is an isomorphism of varieties.
Iif we restrict $\phi$ to $U$, then this is still a morphism (since we have a morphism iff each component function of $\phi$ is regular, which is a local property). However, now we have $\phi\colon V\cap U\to Y$, but $\phi(V\cap U)$ isn't necessarily closed in $\mathbb A^n$, so I'm not sure how to get an iso.
@Thorgott man, I tried to calculate but it means it have no solution. the only thing that is possible to do is $(1 + (-1)^k + i^k + (-i)^k)$
tell me what the powers of $i$ are
@BalarkaSen what about $K_n=\{1,...,n\}$ in the Cayley graph of $\Bbb Z$? Folner sets don't even need to cover the whole thing
oh god why is the chat a typewriter again
im innocent this time
Nvm, I figured it out I think
14:47
@Alessandro Yeah, let's compute. The Laplacian of K_n is tridiagonal with 1's along the three diagonals, yes?
@Thorgott $i$ and $(-i)$ is raised to the k power
I don't even know what the Laplacian is in this context
I - (adjacency matrix)
Well, tridiagonal with 1's along the main diagonal and -1's along the super and sub
I'm asking you to compute those values
14:49
What is the spectrum? Surely it convergences to the spectrum of the Laplacian of Z, which is tridiagonal infty x infty with 1's along the main diagonal and -1's along the super and sub, but going both sides
Spectrum is just {1, -1} with some multiplicities, or what?
Seems like it. So it trivially converges
uhh I guess but I'm not thinking very carefully about it right now
You're right though that in general it's not clear why the spectrum of the complement of the Folner set doesn't matter
This is just not a counterexample. Maybe there is some
In any case I'd argue by Mike's statements at least one direction is clear, the limit of the spectra of the Folner sets sits inside the spectrum of the full thing
When dealing with groups if $F_n$ is a Folner sequence then $K_n=\{ab^{-1}\mid a,b\in F_n\}$ does cover the whole thing. Is it still Folner? Not sure. Can something similar be done with graphs?
Seems right. But of course, covering is not a good notion of approximation
Even easier (and works for graphs as well) if you enumerate it as $g_n$ then just $F_n\cup\{g_n\}$ is a covering Folner set
So yeah covering is easy hence not a good notion
14:58
But this is good. Maybe my claim is you can always choose some Folner sequence whose induced graph converges in spectra to the whole thing
Hello.May I ask question
Find area of surface that is generated revolving the curve y= \sqrt[3]{3x} between y=-1 and y=0 about the y-axis
Can u guys help me or give me a hint how to do it
@Thorgott for $i$ and $(-i)$ raised to the k power, we have 2 possibilities. if k is odd, $i^k + (-i)^k = 0$. if k is even, $i^k + (-i)^k = 2i^k$
the same occurs with $1^k$ and $(-1)^k$
you can be more explicit
compute some low powers of $i$, you will notice a pattern
@Krijn Ok I got it, thank you very much
@Curio np
15:12
@BalarkaSen Not Hausdorff metric, Hausdorff distance between those is infinite.
@BalarkaSen This seems plausible
Someone should tell me what convergencec means though
@MikeMiller Pointed Hausdorff, you do Hausdorff metric in a large ball
This is not an issue
OK I don't know this stuff
I'm sure it's not an issue I just didn't know how to resolve it :)
But I should do linear stuff
A sequence of closed sets $A_n$ of $\Bbb R$ converges to $B$ if for every $R > 0$, $A_n \cap [-R, R]$ converges to $B \cap [-R, R]$ in the Hausdorff metric on $[-R, R]$
This would be pointed Hausdorff, centered at $0$.
OK.
Seems good
So this is topology and not metric
Yeah
Sorry
15:17
Oh no you can make this metric. Call that $d_n$ for $[-n,n]$ and then take $\sum d_n/2^n$
Standard trick
I'm caught up now
Suppose $x_{n} \in \mathbb{N}$ for all $n$ and $\left(x_{n}\right)$ converges to $x .$ Show that there is an integer $N \in \mathbb{N}$ so that $x_{n}=x$ for all $n \geq N$
@MikeMiller Ah cool fair enough
@Thorgott for n = 1, we have: $\left( \begin{array}{c} 4 \\ 0 \end{array} \right) x^4 \cdot 1 + \left( \begin{array}{c} 4 \\ 1 \end{array} \right) x^3 \cdot 0 + \left( \begin{array}{c} 4 \\ 2 \end{array} \right) x^2 \cdot (2+2i^2) + \left( \begin{array}{c} 4 \\ 3 \end{array} \right) x^1 \cdot 0 + \left( \begin{array}{c} 4 \\ 4 \end{array} \right) x^0\cdot (2+2i^4)$
@mathsstudent What does 'converge' mean here, to you?
@MatheusSousa Forget all the other complicated junk. Thorgott wants you to tell him what happens to $i^k$ as $k$ increases, and then $(-1)^k$ as k increases, then to $(-1)^k$ as k increases.
This should make clear what these things (to the power of 4n-k) are.
(I won't be around to discuss this more, just wanted to clarify his hint)
16:01
@MikeMiller it happens that $i^k$, $(-i)^k$ and $(-1)^k$ increase absolute value when k increases, but the negative terms oscillate between negative and positive when k increases
0
Q: Duality Between Semilattices and Totally Disconnected locally Compact Hausdorff Spaces

user193319On page 18 of this paper, the author states that there is a duality (correspondence?) between semilattices (i.e., abelian semigroups of idempotents) and totally disconnected locally compact Hausdorff spaces. Given a semilattice $E$, consider the space of characters $$\widehat{E} := \{\chi : E \to...

16:17
haven't thought much about it, but looks like a closed subspace to me
and closed subspaces of LCH spaces are LCH
@MatheusSousa The thing about absolute value is totally false. These all have absolute value 1. I don't follow what you mean about negative terms but it sounds like it's on the right track.
16:36
So I haven't done calculus in enough time- if $\partial f /\partial y = 0$ for $f(x,y)$ will all the mixed partials (including higher order ones) also be zero?
the answer is no
@Thorgott is this the pattern? $\sum_{k=0}^{2n} \left( \begin{array}{c} 4n \\ 2k \end{array} \right) x^{4n-2k} 2(1+i^{2k})$
I'm sorry if I am very insistent. I'm really trying to understand this
that is correct, but you can still do better
what's stopping you from just calculating the powers of $i$ as I've been asking you to

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