« first day (668 days earlier)      last day (4649 days later) » 

00:00
@DylanMoreland With two or three people you're way better off than me...
@tb Right! That's the thing.
Maybe I don't understand well enough the responsibilities that come with actually being good at research, but the lack of participation seems crazy to me.
Ah well. That's my rant.
@DylanMoreland there's a discussion on this on meta MO
The comments here are hilarious.
-2
A: Origins of the modern definition of topology

Mathemagician1234Frechet is credited with the definition of a metric space in his 1906 paper and Hausdorff came up with the prototype of the standard axioms in his 1914 treatise on set theory.It was created as a direct abstraction of the metric space concept and it is not quite the modern definition. For example,...

@BillDubuque I think surfing you answers to [number-theory] will let me learn a lot.
Although I suppose a lot of people have dropped out of MO too.
00:06
@DylanMoreland But let's be honest. Is the situation on MO that different?
That MIT open courseware lecture is surprisingly good, I figured they would have not reviewed anything and assumed you would know it all. I guess I just have bad math teachers
@DylanMoreland there's also a discussion on that on meta MO
@MarkDominus tl;dr?
@PeterTamaroff Summary: Adam Smith and AndrewL really do not get along.
@Jordan Yay! Sad but true: crappy teachers are all over the place.
00:10
lol, "who asked you?" --> "you asked"
User A posts an answer full of errors. It is downvoted. User A complains in the comments and demands to who downvoted and why. User B says 'I did and here is why' and posts a scathing but fair critique of the answer. User A becomes defensive and says "Who asked you?" User B says "You asked."
Yes.
There are other delights in that thread, but that was the chief one.
Yes, but after the tenth iteration of this game, it becomes boring...
On the bright side, I just downloaded that paper that @tb referred to and I am eagerly looking forward to reading it.
There are numerous such exchanges between the two.
@MarkDominus The paper is really really great. Enjoy!
@tb Yeah. It just started to seem mean-spirited at some point.
00:13
who are adam smith and andrewL?
i'm assuming andrewL is mathemagian?
magician, yes
@DylanMoreland i like coming here to ask questions instead of MO
but you're right it's mostly Professor Emerton who answers.
@DylanMoreland Maybe, but as much as I disliked the attacks, I'm still siding with the mathematician among the two.
@PeterTamaroff for a moment i confused your and symbol with the wedge operator and i was incredibly confused.
@Eugene Oh, I use $\wedge$ for "and". Is it wrong?
00:17
No, that is quite common.
@Eugene I find that sort of writing unintelligible at first glance, but you won't win over Peter :)
@PeterTamaroff Semantically I think \land ("logical and", I think) might be better.
@DylanMoreland What does that last thing mean? ¬¬
@PeterTamaroff absolutely not. i've just been seeing it used as the grassmanian for too often lately
@DylanMoreland True. $\land$
Wait.
@BillDubuque Ooh! I know I can use Bezout for that!
00:18
The really look the same.
!
They are the same glyph, I think.
But the code reads better.
I didn't even know about \land. I've always written \wedge.
@DylanMoreland yeah it's not on peter. it's on me
And I feel funny about it every time.
It's all about the semantics, they say...
00:20
@DylanMoreland But you shouldn't be reading the code!
I sometimes consider signing my name $D\ominus$.
@PeterTamaroff I just mean that you are possessed by the ghost of Landau and that's probably a hard thing to get rid of.
bill's answer is great
@BenjaminLim what's up?
00:20
@DylanMoreland LOL right.
+1 @DylanMoreland
@tb Please see the picture
@Eugene But his symbology is rather odd. Marvis translated but even the translation is ambyguous.
@BenjaminLim Oh, I saw that in the transcript. Did the talk go well?
00:21
It went pretty good!!!
@PeterTamaroff i love it though!
First talk in my life
simple and effective
@BenjaminLim Very nice to hear!
@Benjamin Congratulations! Did you have fun?
00:22
@Eugene When I understand the symbol I will love it too. I usually love his answers.
@BenjaminLim Good action shot for the website.
@PeterTamaroff the way to think about it though is $a$ and $b$ share no prime divisors
@tb Yeah I was quite stoked, some people said it gave a not so scary impression of commutative algebra
@MarkDominus Indeed I did though my handling of the slate boards was a bit chaotic
@DylanMoreland hahahahahahahah
@DylanMoreland aren't you staggered by how tall @BenjaminLim is though?
@BenjaminLim Learning to manage the blackboard space effectively takes practice.
00:23
@BenjaminLim But... Did you give your talk in Liliput?
maybe it's just cause i've been short my whole life
@Eugene Actually, yes. And I don't know why you'd ever have a board that low.
@tb No but I am "tall" in the sense of 6ft 2
@tb looks like i'm not the only one!!
@MarkDominus Thanks for all the advice on the main page
@DylanMoreland May I ask how tall are you since @Eugene started this trend?
00:25
@BenjaminLim Oh, sure. I hope some of it was of some use.
6 ft 1 in. A relative insect.
@MarkDominus It was indeed, I made sure to be calm. Once my entire stack of notes fell off the table and I calmly picked all of it up without saying a word.
@DylanMoreland Wow you're pretty tall too....
@DylanMoreland 6' 1" is really tall. my 6' 1" friend towers over me
@DylanMoreland i guess i'm a relative microbe.
My 7yo has a book of puzzles and just asked me "Who is bigger: Mr. Bigger, Mrs. Bigger, or the baby?"
But she cannot fool me, because I have heard all these already.
@tb Shit how did you reach up there??
00:28
@tb Jesus!! are you giving your talk in gulliver's house?
exactly...
@Eugene Wow that was a pro comment!!!!
@tb Friendly smile dude!
@tb What's your height? And lol what a face!!
@tb how are there even words on the top board??
00:30
@Eugene I have some relatives in malaysia. When I go there they always seem to obsessed with my height......
@BenjaminLim around 5ft 8
@BenjaminLim because you are really tall
you'd probably stand two heads above me
i'm not looking forward to the lousy grading i have to do this weekend
@Eugene Dude, I was just given back my ifirst analysis midterm: only 20% passed (you pass with 4/10) and most of the fails were with 0 or 1
@tb Not bad.
@PeterTamaroff i passed? wow! i didn't even take it. i must be getting quite good at analysis.
00:39
@Eugene ¬¬
@PeterTamaroff = D
@Eugene ;) I'll go grab something to eat.
ok see ya!
@PeterTamaroff you'll crush it next time
@Eugene crush what?
@PeterTamaroff the exam
@PeterTamaroff also a 20% pass rate for a first analysis midterm is quite common in my experience.
00:49
@Eugene What do you mean by crush? Pass?
@PeterTamaroff as in 10/10
Dominate. Tell it who's boss.
@Eugene Oh but I did crush it!
@PeterTamaroff wow! awesome then!
@anon Like a bawzz
00:50
@PeterTamaroff your classmates must not be liking you so much
@PeterTamaroff i only got a 7.5/10 for my first midterm
@Eugene Well, I pressume not. But I tend to help them and explain so if they don't give some love, they won't get any.
@PeterTamaroff haha.
@PeterTamaroff i crushed my last two exams in my analysis class though
@Eugene I guess its a more advanced analysis course right?
Than mine
@PeterTamaroff i don't know. maybe you could take a look and tell me
@Eugene Oh, well not that much harder,
But I assume it is more rigorous.
00:57
@PeterTamaroff i doubt it
It is great you have this two:
Elements of set theory
Some topological properties of R^n, metric spaces
Do you know any Spanish?
@PeterTamaroff i know "que" and "piso mojado"
@PeterTamaroff oh! and "donde esta la biblioteca?"
I think donde es el bano is more important than la biblioteca...
@anon that didn't make it on community though
heh
01:00
@anon ¿Dónde está el baño?
I am lazy. And also barely remember any Spanish from 5 years ago :P
I'm totes familiar with lonely island.
@anon and i bet you la biblioteca has el bano
I bet you finding a library is an inefficient overall plan to find a bathroom :P
Unless you happen to be very near a library and know it...
01:04
fair enough
Then again I guess you can get both a library and a bathroom knowing only la biblioteca.
which is good if i have need for bathroom reading material
not necessarily good for others desirous of bathroom usage :)
@Eugene LOL
@Eugene When I went to the US I met a Japanese girl that spoke spanish quite well.
01:12
@PeterTamaroff i have a malaysian friend who speaks fluent spanish
unfortunately i was never gifted with learning languages
i've always wanted to learn german though
@Eugene I'd ilke to know German to read old maths
but they've told me it is written in dialect
so there is no sense in bothering to learn modern german
@PeterTamaroff mine is more of a desire to learn the language for itself
french is what i NEED to learn
@Eugene True. I want to learn that too to read French math
should be easier for you though. you know spanish already
@Eugene Is French really related to spanish?
01:23
yes.
I'm working on $(a,b)=1\Rightarrow (a+b,a^2-ab+b^2)= 1\text{ or } 2$ now.$
Seems though.
should be ok
still in chapter 1 then?
did you mean $a^2 - ab + b^2$ or $a^2 - 2ab + b^2$?
the first
and it should be 1 or 3
not 1 or 2
cool
should be ok
@PeterTamaroff how's it coming along?
01:45
@Eugene Still thinking.
@PeterTamaroff ok. let me know if you want to ask anything
(actually I was reading 9gag)
I'll get back to it now.
@PeterTamaroff haha.
fair enough. don't let me get in your way
I liked the proof of (a,b)=1 then (a+b,a-b)=1 or2 that showed that if d was a divisor of a+b and a-b then d | 2b and d |2a thus d |(2a,2d) =2 (a,b)
this is similar
01:48
@Eugene i presume so
no surprise right?
but the $^2$ are f**cking me up
Aha!
What if I multiply (a+b)(a^2-ab+b^2)=d
Then if D is a common divisor D |d
well try it and see
Guys I need a quick word about this please, What do you think I should do?
@anon : Hi (hope i didn't wake you up from maff)
Hi @Peter
@RajeshD Hello
01:54
@Peter : take a look at the above and give me some suggestion
@RajeshD I can't help you.
ok
Hi @Dylan
@RajeshD: If you publish your experimentation, speculation, theories and work etc. on, say, a blogging platform, it will have more exposure and you are somewhat more likely to get help. There is little chance someone could successfully "steal" your idea - as your idea being yours would be documented on the internet anyway.
That's just to assuage any paranoia you may have. Not sure if it will garner much help for you.
the journal of experimental math seems to want more than just some computational evidence and a conjecture
@PeterTamaroff solved it yet?
@Eugene Nah. Stop it, you'll jinx me! =)
02:01
@PeterTamaroff sorry =P
My hint is to figure out how to get a 3 into the mix :)
@anon great hint!
@anon What are you talking about¿
Your problem ends with gcd=1,3. Surely you're wondering where a "3" enters into the discussion / derivation / mix?
@PeterTamaroff let me know if you need another hint
02:09
I got number theoretical here
i can't freaking read the question. i hate people who don't tex
Really I think the best answer would be both answers put together.
two in a row...
i can't read the question so i can't say how useful the answers are
@anon : sounds good
while bob dylan can't sing i can't help but like his music
02:18
@Eugene I went to a recital some weeks ago. It make me sad how his voice f****ed up the great music the other guys were doing.
@PeterTamaroff bob dylan??
@Eugene Yes. He came here to Argentina.
@PeterTamaroff holy crap! i think he's amazing though!!
@Eugene Sure he is!
But he sounded like a Wookie with a flu.
@Eugene EUREKA!
@PeterTamaroff haha
@PeterTamaroff got it?
02:20
I think so.
cool
Let $d$ be a common divisor of $a+b$ and $a^2-ba+b^2$
Then $d$ divides $a^2-ba+b^2-(a+b)(a+b)$
@PeterTamaroff yup that's it
Thus $d$ divides $-3ab$
It is clear it can't divide neither $a$ nor $b$, so it has to divide $3$, right?
@PeterTamaroff about 30 minutes
02:22
@Eugene Sorry?
@PeterTamaroff well that's not clear
but it can be made so
anyway
@Eugene 30 minutes what?
i said it took about 30 minutes to solve
not bad
@Eugene Oh!
Well, minus 9gag and eating :P
haha
anyway
$d$ divides $a + b$ and $-3ab$
so $d$ divides $3b^2$ and $3a^2$.
so since $gcd(a,b) = 1$
by question 3
$gcd(a^2, b^2) = 1$
so $gcd(a+b, -3ab) = 3$ if and only if $3 \mid a+b$
02:25
Wait.
@Eugene Does this follow trivially or do we need a similar manipulation as to get to $d |3ab$?
?
does what follow trivially?
You say that $d$ divides $3b^2$ and $3a^2$
yup
$d$ divides $a+b$ and $-3ab$
so $d$ divides $3a(a+b) - 3ab$
similarly $d$ divides $3b(a+b) - 3ab$
02:28
Right.
haha
this is still elementary number theory
long way more until analytic number theory
@Eugene I know. I'll get there!
@PeterTamaroff i'm actually taking my first class in analytic number theory
so we'll probably get there together
@Eugene When?
this semester
as in right now
02:30
@Eugene Cool. Maybe it takes longer for me, since I'll be autolearning...
today we finished the mangoldt function
@Eugene Cool. So I assume you already studied $\varphi$ and $\mu$
@PeterTamaroff feel free to take a look if you want
@PeterTamaroff i studied that in elementary number theory
@Eugene Hey I have a quick number theory question
@BenjaminLim no guarantees that i'll be able to answer it but i'll try
02:32
Why is it if $p \equiv 1 \mod 4$ then $-1$ is a square mod p
I can do concrete calculations to show why this holds
but not a proof
do you know gauss' criterion?
ah ok
let me see
there's also a group theoretic proof i believe but that one is long
02:33
not really
um
In number theory Euler's criterion is a formula for determining whether an integer is a quadratic residue modulo a prime. Precisely, Let p be an odd prime and a an integer coprime to p. Then : a^{\tfrac{p-1}{2}} \equiv \begin{cases} \;\;\,1\pmod{p}& \text{ if there is an integer }x \text{ such that }a\equiv x^2 \pmod{p}\\ -1\pmod{p}& \text{ if there is no such integer.} \end{cases} Euler's criterion can be concisely reformulated using the Legendre symbol: : \left(\frac{a}{p}\right) \equiv a^{(p-1)/2} \pmod p. The criterion first appeared in a 1748 paper by Euler. Proof The pro...
oh
it's euler's
is it that one?
sorry
hahaha
yup
so basically
@Eugene It is interesting how your proffesor grades.
02:35
$-1$ is a square in $\Bbb{Z}/(p)$
yup
actually a square of a non-quadratic residue
@Eugene You have already studied all from Apostol's book?
@Eugene So from Euler's Criterion we get that $-1$ will be a square of a non-quadratic residue?
Or are you currently in the course you linked¿
02:36
@BenjaminLim from euler's criterion we get that the lengendre symbol of -1 mod p is 1
so yes
@PeterTamaroff no i haven't. i read the second book before but not the first
now if $p \equiv 3 \mod 4$
so let's see
(p - 1)/2 is odd then right?
so $(-1)^{(p-1)/2} = -1$.
so it is a nonresidue
02:38
so it is not a square
how?
ah ok
i'm stupid
@Eugene I guess I'll study from the book as your professor suggests
@Eugene Because if $-1 = x^2$ then raising both sides to the power of $(p-1)/2$ shows that $1= -1 \mod p$ a contradiction
@BenjaminLim the hard part is the converse
@BenjaminLim right
@Eugene Converse to what?
02:40
@BenjaminLim as in if -1 is a square mod $p$ then $p=1 \pmod{4}$
ah ok. I don't need that result atm.
Thanks eugene
ok
no problem
Our lecturer is absolutely crazy asking us to prove quadratic reciprocity in a galois theory class
I have to use machinery from commutative algebra and number theory to solve the damn thing
@PeterTamaroff that's good. it's a bit outdated though
proof is like 4 pages
02:41
@Eugene When did you take that course?
@BenjaminLim if you had some alg number theory you could just use the ramfication of the prime ideals
@PeterTamaroff i'm taking it now
@Eugene Unfortunately I don't know algebraic number theory.
But even our tutor can't solve the problem. Also according to the tutor the lecturer's solution uses algebraic number theory in disguise
@BenjaminLim sorry i didn't try proving QR using galois theory
it's messed up the proof
so long and so many lemmae
@BenjaminLim haha
it really is a beautiful subject though
02:43
I know. But I am saying it was not fair of the lecturer to ask us to do this. I went to see him and even he admitted it was too hard and out of the scope of the course.
@Eugene Why do you say its outdated?
fair enough. it does seem like the machinery is not there yet.
@PeterTamaroff well a lot has been done since it was written no?
@Eugene Oh well, right. Then let me know what updates your prof introduces!
@PeterTamaroff i will!
@PeterTamaroff he's a geometer though so i doubt he'll know
@Eugene Why would he give a course on ANT?
02:46
@PeterTamaroff i guess the university assigned him to it?
@PeterTamaroff it's not uncommon
@PeterTamaroff anyway i have to go do something now. bbl
bye
@Eugene BBL?
be back later
@Eugene I figured it out in the mean time =P
ok then. bye!
If you take too long I'll be gone
Since its 15 to 12 here.
02:52
I don't think you can expect a book like that to take you up to recent developments. Number theory is too big.
@DylanMoreland Where should one study from then?
That's not what I meant! It seems like a fine text.
On that note, I've been looking in Iwaniec-Kowalski for my analytic number theory needs recently. It seems alright. It's certainly recent.
lol it took me 30 secs, tops
@DylanMoreland I assume you're a number theorist.
Or want to be one.

« first day (668 days earlier)      last day (4649 days later) »