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18:10
@MarianoSuárezAlvarez thanks for clearing that up
Algebraists, can anyone help with this one?
Ta.
Hi people!
Hello.
Could someone tell me how is called in english the "Tangent to $f(x)$ if $x = 0$"?
18:33
@unNaturhal I don't understand what you're asking.
What is what called in English?
The tangent of 0?
Mmmmh
I have a function
This function passes throw x=1
I have to calculate the tangent in that point
@Gigili Could you figure what I mean?
@unNaturhal The tangent line to $f$ in zero?
@tb Umh?
You mean $t(x) = f(0) + x f'(0)$, no?
I'd call that the tangent line to $f$ at $(0,f(0))$.
The formula is: $y = f'(x_0)(x - x_0) + y_0$
18:47
You mean $f'(x_0)$, there. I plugged in $x_0 = 0$ and $y_0 = f(x_0) = f(0)$.
@unNaturhal The tangent line passes through $x=1$ which lies on the function $f(x)$?
Hello again! Can anybody tell me what is the $\overline{\partial}$ operator?
@Nimza $\bar{\partial} f = \frac{1}{2}\left(\frac{d}{dx} + i \frac{d}{dy}\right)f$. A function is holomorphic if and only if $\bar{\partial}f = 0$.
@tb I don't thik to have undestood
@tb thank you, it is good if $\overline{\partial} = \frac{\partial}{\partial \overline{z}}$. Thank you!
18:52
@Nimza Yes, that's what it usually stands for.
@Nimza привет!
@unNaturhal You want the tangent line to pass through $(x_0,y_0) = (x_0,f(x_0))$. So I plugged in $y = f'(x_0)(x-x_0) + y_0 = f'(0)(x-0) + f(0) = f(0) + x f'(0)$. Our formulas really are the same.
Hi, Ilya
@Gigili Maybe :P However, it's not important... The important thing is that I don't know how to study the tangent on this function $\left|x^2 - x\right|e^\left|x^2 - x\right|$
@tb Yeah! Exactly :D
@tb hi, I'm away a bit, watching mr. Nobody. Didnt know it's a European movie
@unNaturhal You should first get rid of the absolute value signs, there.
18:56
@tb rid?
@unNaturhal write the formula in such a way that they disappear, by thinking about when $x^2 - x \gt 0$ and $x^2-x \lt 0$.
@Ilya have fun, see you later!
@tb I alresdy studied about all the function: Domain, Simmetry, Positivity, Derivatives (only the first), Asymptotes, and the study of the min, max, inf and sup of the function. It remains to be done this tangent, and the graphic draw...
@tb thanks. I'm a bit fascinated by Jared. Or maybe it's all because of beers
@unNaturhal Very good then. What's the derivative at $x = 0$?
@tb $1=0$ :-)
19:01
@tb In $x = 0$ I made the limit of the incremental***, and there is an angular point (because the limit is 1 for $0^+$ and -1 for $0^-$
@robjohn hullo
@Ilya howdy. How's the day treating you?
I wonder if that works into the etymology of howdy Nope, it's how do ye
It was tough, what about yours?
@Ilya so far, so good.
I'm trying to reset my mind from math and biology with beer and movies
19:04
@robjohn Isn't that short for how do you do?
(Oh, I missed your edit, sorry)
Oh no, they are doing that!!!!
Poor kids
@unNaturhal This sounds right. So you don't have a tangent line there.
@Ilya doing what? :-p
I don't know, what you're doing :)
Lost our connection somewhere in China
@tb Mmmmh.. I supposed that.. Also because for $x = 1$ the first derivative doesn't exist.. So, why in the exam exercise it ask to study the tangent to the function in $x = 1$?
19:08
Oh, his dad is strange
@unNaturhal I don't know. Maybe they want you to find out that there's none. Maybe they want you to find the one-sided tangents.
@unNaturhal I usually use $\frac{\mathrm{d}}{\mathrm{d}x}|x|=\frac{x}{|x|}$ and then apply the chain rule
that is a nice form since it carries over to the gradient
@tb Exist one sided tangents? O.o However, the tangent doesn't exist means that it is parallel to the x-axis?
@robjohn I got it
@unNaturhal okay. Just throwing in a couple of my pennies.
@unNaturhal well, don't worry about one-sided things if you never heard of it. I don't know. I don't think it makes sense to speak of tangents if there are none.
19:12
@robjohn What? :P
@tb I agree.
@tb You're right, I agree :P So, I just write down: there are no tangents in $x = 1$
@unNaturhal I was paraphrasing the idiom 'giving my two cents worth'
And halp please if you can. I can't do any thinking now otherwise I'd help him.
19:14
@MattN Called.
@Gigili Great thanks.
@robjohn Eheh, the problem is that I didn't know how to name "tangents to the function in $x = 1$", there are no possibilities for me to know the meaning of an idiom :(
@MattN done
@Ilya Thanks.
@tb @robjohn Thank you very much for the help! :) I go to eat, see ya :)
19:20
@unNaturhal bon apetit!
Maybe someone can help this guy over here.
This question is really interesting. I favorited it because of sos440 solution.
@tb But you closed it. ??
@PeterTamaroff Yes, I didn't look closely enough. Jyrki pointed out that it wasn't exactly the same.
Oh, OK.
@tb I started reading a little of Apostol's Intro to Number Theory.
I am curious about the motivation for the Möbious function. It is not zero if $n$ is squarefree right?
and if it is the product to $k$ dsictinct primes, then it is $(-1)^k$.
19:33
@PeterTamaroff I don't remember but isn't there also something with an even/odd number of prime factors that determines the sign?
@tb Right.
But the motivation for defining it interests me.
You ask the wrong guy :)
poor me. After pestering me with algebra they start with number theory of all things.
@tb Who pestered you? What do you mean?
19:36
@PeterTamaroff there's one guy who always asks me about Atiyah-MacDonald
It's not exactly my cup of tea.
@tb Oh. I heard Atiyah made great discoveries, but I never heard of Mac Donald.
@PeterTamaroff Anyway: as far as I understand the motivation simply is that the Möbius inversion formula holds.
@Gigili what does it mean?
@Ilya $\pi \rho i \phi \varepsilon \tau$ !
19:46
@Nimza приФет???
use $\beta$! :)
$\omicron \lambda\omicron \lambda\omicron$
@Ilya I think $\nu$ это н!
@Nimza $\tau$ы $\pi\rho\alpha\beta$
@PeterTamaroff Atiyah-Macdonald is a famous book on commutative algebra. Both authors are pretty famous. The first certainly more so.
$ \tau \rho \omega \lambda \omega \lambda \omega $
:)
19:48
If nothing, we could at least make a robot to hit the MathJax bookmark when needed.
@Gigili: we have skull already
and what does "tease in a mean while" mean?
@Ilya Oh? don't tell me he's going to my room to do that. I don't have enough space for both of us!
I won't
@Ilya I'll show you, cannot explain it properly.
future tense makes your statement hard to verify
19:51
We first need a Matt who is AFK for a short while.
ok
I'll be afk soon too
So that won't work. I can't tease you while you're AFK.
I have some time before December, 21st
bbl
Umm.
Seems my mind is infected with the virus, it doesn't interpret things immediately.
@Gigili If you feel the urge to eat another man's face, let us know.
28 days is usually the time it takes.
20:01
@PeterTamaroff Ekskioozmi?
@robjohn: didn't you have something on the Möbius function on your webpage? Maybe I misremember.
Anyway, Peter might be interested in that.
Hi, @leo, how are you doing?
@Ilya What's it called?
@Gigili you should remember
20:13
The first time I see Tee-Bee says hello to someone before the one says hello.
2
@Ilya Rajull?
leo
leo
@tb everything is fine. Reading about some faithful group actions. How are you?
@Gigili of course, not
@Ilya I can't think of a more annoying name for a virus. Perhaps you would drop me a hint?
@Gigili perhaps
leo
leo
by the way, I don't what term is used in spanish to "faithful action". I think must be "acción efectiva"
20:16
So, what have I missed since an hour ago?
@Gigili: Matt is here, so would you care to explain now?
You missed me.
Go AFK for a short while @MattN, I'd tease @Ilya in the mean time.
@Gigili slander!
Did I say in a mean time?
@MattN: what?
20:18
@Gigili Ok. Where did you tease him? Or do you want me to read all the transcript? Looks as if you'd been a chatty bunch : )
@Ilya What?
@MattN what did you remove?
@MattN What?
@Gigili: so...
@leo At least it's synonymous in English and it sounds good :)
leo
leo
@tb (-:
20:20
The first time I see Tee-Bee talks to someone with smile.
@leo are you from Australia, if I may ask?
@Gigili how cool. So many of new things for you today!
@Ilya Boring stuff.
leo
leo
@Ilya I'm Costa Rica :-)
The first time I see Tee-Bee.
The first time.
@Gigili Ok, going afk to pour another drink. In the meantime you tease Ilya. Ok?
20:21
Okay, I'll stop now.
@MattN what does it mean?
teases Ilya
@Ilya I don't know, just trying to play along.
@MattN I expected you more ...
Why you pretend to be male when you are female @Ilya?
@MattN you should add some eggs, sugare and meaning to this tree
20:22
@Ilya take your pick: make fun of, poke fun at, laugh at, make a monkey out of; taunt, bait, goad, pick on; deride, mock, ridicule;
@Gigili I don't pretend
@Ilya What tree?
@tb the first time I see Tee-Bee being a vocabulary ;)
Dictionary, you meant.
thesaurus.
20:24
You are all so funny : D
Either that, or it's the drink.
@tb you missed "O", TheO
@Ilya LOL
@MattN I knew you'd say that.
@MattN the latter
@Gigili you lie. I'm not a female and you didn't know Matt will say that :)
@MattN You didn't even let us enjoy the compliment for a moment.
leo
leo
20:25
@tb when we are constructing a nonmeasurable set on $\Bbb R$, we use: 1. Action of choice. 2. Density of $\Bbb Q$. 3. (Strongly) Translation invariance of the Lebesgue measure. So given a metric space $(X,d)$ with a dense subset $D$ and a borel measure which is translation invariant, we can do the same. What about other spaces? For example in $(\mathbb{N}, \mathcal{P}(\mathbb{N}), \#)$ all the sets are measurable.
Is it interesting/important to characterize all the measure spaces where we can get nonmeasurable sets?
@tb dear Diary, what does strip-tease mean then? Making a monkey out of somebody being naked in the meanwhile?
@Gigili I'm not that sort of person, ya know. : )
@Ilya At least this time it wasn't me.
@MattN: you are around
Dear Diary, they all are just my dreams, fragile as soap films...
@Ilya You're mistaken, my friend. Not about your gender, of course. But about me telling lies.
@Gigili Jasper? The-guy-who-never-lies-in-chat?
Dear Diary, today I met a woman. I also met a man. Today I went out, my dear Diary.
20:28
But this path-connected question is an exact duplicate.
Now it's been reopened.
it's going crazy now
@Ilya Oh, dear ...
@Ilya it = you? : )
How can you met both a man and a woman on a single day?
@Gigili Let me tell you a secret: I was moving
20:29
Or the man and woman?
@Jonas!
Hey! @JonasTeuwen : )
I have to leave
Byee!
20:30
and I can't leave them here, they're my dreams
Bai.
@Jonas: have dreams about this chat till I'll come - otherwise it disappears! Please
@Ilya I'll keep an eye on them while you're away.
You guys have lost me...
noooo. @MattN: you're still in the dream, don't be afraid
20:31
@leo I would probably argue that in every interesting measure space we have non-measurable sets...
@tb that's your definition of being interesting? that you cannot measure at least a part of it? otherwise you don't feel any interest? That's usual for us... I can understand you. I guess, you can't understand me
Yes, I find $(X, P(X))$ quite uninteresting.
@MattN oh; good luck then
@Ilya Thanks mate.
which subject?
20:34
Functional analysis and commutative algebra.
Which degree?
maths
Which exam?
Which virus?
Which Matt?
20:35
Which witch?
leo
leo
@MattN good luck man!
Which man? :D
@leo Thanks mate.
Thanks mate.
@MattN that was delivered to me
maybe I am leo...
20:36
For your nice edits.
Welcome! : )
@gigili: who am I
@Ilya You could be anyone.
that's wise
leo
leo
or noone
20:38
that's not :)
It's hot in here.
leo
leo
what about random?
get out of the oven
Wow it's supposed to be raining this week. Nice.
@leo: probably, yes
@MattN are you surprised about the rain in your area?
20:39
@leo It is usually hard to prove that there are non-measurable sets. For example in every uncountable complete separable metric space there are non-Borel sets that are measurable with respect to every Borel probability measure. See also universally measurable sets.
@Ilya Yes. Rain is a rare species here, especially in summer.
leo
leo
be something no deterministic
@tb thanks
Is there a picture of the void?
@tb Either that. Or you shouldn't believe everything that's on the internet. : )
20:42
I measured it myself...
@tb I'm not going to ask what...
(I didn't make this statistics)
Anyway. June isn't my least favourite month. I think the worst are August and July.
@tb And also: isn't Bern wetter than Zurich?
@MattN sheeeeeeeeeeeeeeeeeeeeeesh
@tb 73°F is the annual high? We're lucky if we stay below 103°F for our high.
20:46
@tb Hey. Did I say anything wrong? : )
@robjohn I think it's the maximal average over a day. It's rarely over 20 Celsius during the night.
@leo You usually need strong choice principles to get non-measurable sets. Translation invariance of a measure is not really the crucial ingredient.
@MattN Nothing more than where Tee-Bee lives.
I'll be there by tomorrow.
@Gigili Heh. So you fancy him that much? Can't blame you. : )
No.
@MattN I think that's the side effects of your drinks on me.
@Gigili : ) You're suggesting that Mr. Jameson can teleport?
20:51
He sure can.
Let's say "what haven't you tried" , "what will you try", "Why don't you try" instead of "what have you tried".
I'm off to bed.
Good night.
21:14
How is it going guys ? =)
21:26
@Gigili Good night!
Hm. Did I kill the conversation?
@MattN Moo.
Hi Jonas.
It's bed time here.
Good night! x
@tb I only have a proof of the basic Möbius inversion formula. However, it looks as if Peter is just starting in on the Möbius function, so it might be useful.
I will mention it next time I see him.
@MattN 'night!
@tb Was MattN leaving as well as Gigili?
@MattN Good night!
I thought he was saying goodnight to Gigili :-)
21:39
@robjohn Thanks a lot! I guess it will be in Apostol but young guys should learn to appreciate ASCII art :)
@tb I think so, too! Dying Arts should be a breadth requirement.
@robjohn I thought "It's bed time here" together with seeing the red hat jumping out of the (Gravatar) window is enough indication that Matt N.'s left for a better place.
@tb Yes, you are correct, but all I saw was him saying 'good night' to Gigili. I missed him before he left.
I wonder if I could teach Dying Arts 101 at UCLA
is there an extension of F11 that has the klein 4-group as its galois group?
@robjohn That'd be a nice course to teach. Although with such courses I'd fear of running out of good ideas after the sixth or seventh week.
21:44
artfiles.com has a lovely pron collection
I like this guy's approach to maths: non-trivial questions with the technical skills to dig through the mess and solve them.
@tb I was thinking of asking "What have you tried" in a "sire"ly manner.
To make it a little fun.
@PeterTamaroff heh :) By the way: robjohn linked to a proof of the Möbius inversion formula on his webpage.
Look at that ASCII.
hhh
hhh
22:00
I am trying to find how to determine complex fourier factors $c_n$, is that some consintent terminology?
@PeterTamaroff Pretty subtle.
@DylanMoreland We have to think of a more tortuous way of saying it.
@tb AAAA that ASCII kills me.
hhh
hhh
-
robjohn is the amster of mathJax and he uses ASCII?
Hey, my swag arrived today. Cool.
hhh
hhh
22:02
Question like this: "Suppose $f$ with $2\pi$ periodic and $f(x)=e^{-ix/2}$ when $-\pi\leq x\leq \pi$. Determine the complex fourier factors of $f$."
@anon What is it?
@hhh Fourier coefficients, maybe? I'd be the wrong person to ask.
hhh
hhh
(was about to ask the same q)
@DylanMoreland Yes that is the term.
...trying to find something in English...
What are the complex Fourier coefficients? The bloody things are always complex.
@PeterTamaroff what's wrong with it? It's like reading books in $\mathfrak{Fraktur}$ (or older texts written with typewriter and handwritten formulas). Takes a while to get used to it but after a while you can enjoy its own charm...
22:05
Hell yes, I got bubble wrap!
4
Hah, I'd love to be able to write in mathfrak. Then I'd do this on the blackboard.
hhh
hhh
en.wikipedia.org/wiki/Fourier_series#Exponential_Fourier_series <--- I can find here $c_n$, that is probably the coefficient.
In mathematics, a Fourier series decomposes periodic functions or periodic signals into the sum of a (possibly infinite) set of simple oscillating functions, namely sines and cosines (or complex exponentials). The study of Fourier series is a branch of Fourier analysis. The Fourier series is named in honour of Joseph Fourier (1768–1830), who made important contributions to the study of trigonometric series, after preliminary investigations by Leonhard Euler, Jean le Rond d'Alembert, and Daniel Bernoulli. Fourier introduced the series for the purpose of solving the heat equation in a me...
Holy cow, I do know this. But thanks.
I breathe Fourier... (and eat it too).
@hhh "coefficients" isn't English? Or am I misreading you?
@anon What else did you get? I think I'll get a shirt for the elections
hhh
hhh
22:08
That is the stuff, read them earlier -- but have to just somehow remember how to deduce the $a_n$, $b_n$ and $c_n$...not wanting remember.
It comes with shirt, pen, marker, mug, a couple stickers and a brief thank-you letter.
@PeterTamaroff see here
I don't drink coffee. Is it "normal" to drink anything in mugs or are they primarily for coffee? I guess I could make a very small root beer float.
I use mugs for everything.
Cool.
22:09
Because, in a pinch, I want to be able to use any container for coffee.
@anon You can drink tea
@tb I bought the one of $X+Y+Z=A$ from Einsten a while ago, when I went to visit Princeton.
It is my favorite one so far.
@anon Why don't you drink coffee?
I don't like it.
@PeterTamaroff the success formula?
@tb Yeah.
"Sheafification of a presheaf through the etale space" this is why math is awesome.
22:12
Yes, it is the third time I think.
Indeed.
He will eventually leave the D
only
Go figure.
@MarianoSuárezAlvarez Buenas noches =)
@hhh EULER'S FORMULA.
22:19
@anon Perhaps "did" was in response to "doit"
that would be an order of magnitude more hilarious
@anon Even more so if did answered doit. Did did doit?
@BillDubuque LOL
@hhh $c_n = \frac{1}{2\pi}\int_{-\pi}^{\pi} f(x)e^{-inx}dx$ (i think)
hhh
hhh
@JonasTeuwen Yes, I think better show my understanding with example.

$c_n=\frac{1}{2\pi}\int_{-\pi}^{\pi}f(x)e^{-inx} dx=\frac{1}{2\pi}\int_{-\pi}^{\pi} \left(e^{-ix/2}\right) e^{-inx} dx=\frac{1}{2\pi}\int_{-\pi}^{\pi} e^{-ix/2-inx} dx$

...then...

$c_n=\frac{1}{2\pi}\int_{-\pi}^{\pi} e^{-(x/2+nx)} d x$


(I wish I could find some easy way to proof-read things with Vim...)
@tb Beat me by a few secs
@hhh Emacs with preview-latex + Vim mode.
You can just integrate that sucker... What the bloody monkey is going on?
hhh
hhh
$ emacs
The program 'emacs' can be found in the following packages:
* emacs23
* emacs23-nox
* e3
* emacs23-lucid
* jove
err which one?
hhh
hhh
22:26
(I think that is a good suggestion, helps visually)
It is called AucTeX. Check it out.
@tb That was me =)
@PeterTamaroff before adopting your "sire"ly ways? :)
@tb Right.
@BillDubuque yes, I'm trying to improve on my FGITW skills here in chat. I'm a bit rusty but it's coming back...
Why are people so keen on closing this question? Doesn't look all bad to me.
hhh
hhh
22:31
@JonasTeuwen no command: M-x preview-latex, did I do it right?
@MarianoSuárezAlvarez Sorry for being a little insistent, but have you read my mail? If you're busy it's fine, but just to know if I should be expecting any feedback.
hhh
hhh
Complex integration for $\int_{-\pi}^{\pi} e^{-ix(0.5+n)} dx$?

Some noise with WA [here](http://www.wolframalpha.com/input/?i=Integrate%28e%5E%7B-ix%280.5%2Bn%29%2Cx%2C-%5Cpi%2C%5Cpi%29), some q about this?
...wait I can change it with Euler formula, thinking...
@hhh try this but you should just do it by hand.
If you can integrate $e^x$, try integrating $e^{ax}$, then plug in $a=-i(1/2+n)$ and apply the fundamental thm of calc
what anon said.
22:43
What in the world is $\risingdotseq$?
"This becomes that"?
Image of, okay.
@anon I've seen some videos where the professor used $\sim$ to denote Laplace Transformation
$$e^{at} \sim \frac{1}{s-a}$$
Ie
I arcwise connected the same as pathway connected?
@PeterTamaroff Yes, but the definitions are not the same.
The equivalence is highly nontrivial
Let me look
According to MW, not necessarily the same.
I see...
22:58
@PeterTamaroff For Hausdorff spaces the definitions are equivalent by the Hahn-Mazurkiewicz Theorem. See also here and Peano space

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