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00:01
@TedShifrin Done =p
Kasmir: Sorry for the delay. I broke a glass in the kitchen and had to clean it up. Now I need an extra cocktail!
@Kasmir also look at Lang... chuckle
@TedShifrin Omg I hate when that happens ><
@Daminark dont get what you mean ? =p
It was a joke, don't look at Lang
what is Lang ?
not story has been told before this
Is it something famous?
Now I know why Ted calls you denimork -.-
or daminork or something like that
00:10
DEMONark.
Yes that :D
That was angelic as far as jokes go!
@mick No, but he has a degree in Finance and is the Information Services Director for Clay County, Minnesota.
Why do you ask?
@TedShifrin Thanks Ted Ill start reading now :D
I'm sure it'll be just perfect, Kasmir :P
00:20
:D
00:34
@Ted okay so Atiyah did some confusing functorial stuff to define all the vector bundle operations
Well, unconfuzle yourself!
Can I ask about the... "idea" behind the stuff?
Like, say if we take the direct sum of vector bundles
Vaguely, is it that you're doing things pointwise and retopologizing so that you still have a vector bundle?
Or hmm
Number of solutions of the equation $$\sin(x)+\cos(x)= x^2-2x+\sqrt35$$ is:______

The answer that I got was zero (which is correct). My method was:

Maximum value of $$\sin(x)+\cos(x)= \sqrt2$$

and minimum value of the LHS function = $$\sqrt35 -1 \approx 5$$
Thus, it is impossible for the two graphs to intersect and there will be no solution.


I just want to know whether my approach was right or not coz reaching the answer isn't important but the solution is important.

Please ignore if the question wastes your time or is unnecessary busy work for you.
If you're locally trivial maybe you can just say okay, near a point you have two neighborhoods on which you're the product bundle, so on the intersection it's still a product bundle where you've now got the direct sum of the stuff?
@Daminark Yeah so the non-functorial, transition-functions perspective, is the following
Suppose $E/B$ is a vector bundle
00:46
But what if I don't wanna suppose that?
Lol jk move on :P
taco
🌮
Now, take two arbitrary trivializing neighborhods $U$ and $V$ on the base $B$; that means $E$ is a product over them.
Demonark: You don't need to retopologize, really. You're just locally (on open sets) the direct sum of the two vector spaces.
Oh, never mind, Balarka is still awake.
Heya Faust :)
Jenna must be our local illustrator :)
00:48
Yo @Faust and @Jenna!
You have trivializations $\rho_U : p^{-1}(U) \to U \times \Bbb R^n$ and $\rho_V : p^{-1}(V) \to V \times \Bbb R^n$. Suppose $U$ and $V$ intersect nontrivially; then these gives two different trivializations $p^{-1}(U \cap V) \to (U \cap V) \times \Bbb R^n$ of $B$ over $U \cap V$.
Hey @Daminark and @TedShifrin
@Daminark 'sup
Looks perfect to me, @Abcd.
@TedShifrin Thank a lot for verifying Ted :)
00:49
I have a hw question that ask's to prove the following. sup(S ∪ T) = max{sup S,sup T} and inf(S ∪ T) = min{inf S, inf T}.
Sure @Faust.
now in about a page i proved rather easily that
sup(S ∪ T) = max{sup S,sup T}
by showing enclosure in both ways
It shouldn't be a page.
I would use up all the ink in the world like that :P
You mean inequalities both ways.
$\le$ is easy.
i have dysgraphia its not many words but i have to space them alot so people can read it and i showed both ways
But $\ge$ takes a bit.
00:51
@Daminark Look at $\rho_{UV} = \rho_U \circ \rho_V^{-1} : (U \cap V) \times \Bbb R^n \to (U \cap V) \times \Bbb R^n$. This represents the "transition" from one trivialization to another, right?
OK, Faust. I'm not trying to pick on you.
So what's your question?
Looks like it @Balarka
thinks to self: I thought Balarka never transitioned
3
anyway my question is can i use sup(S ∪ T) = max{sup S,sup T} and a logic argument on its truth value to prove that inf(S ∪ T) = min{inf S, inf T} has the same truth value and so is always true or false whenever sup(S ∪ T) = max{sup S,sup T} is true or false ?
basically i dont want to have to re-write everything out to prove it
@JennaSloan chuckles at incoming glorious pun 'inf
00:53
Ah. Here's the question, @Faust. Can you write $\inf S$ directly in terms of sup of something?
@Daminark Notice $\rho_{UV}(x, v) = (x, \varphi_{UV}(x, v))$ where $\varphi_{UV}(x, -) : \Bbb R^n \to \Bbb R^n$ is an isomorphism, because nothing happens to the first factor.
@TedShifrin its obviously the sup (-S)
but i dont know if that is a fact or something im assuming to be true
It's just transition from one local trivialization to other by some self-isomorphism of the fibers over each point.
Almost.
The self-isomorphisms vary point-to-point.
00:55
Demonark, shouldn't that have been inf'?
really?
hmm\
Draw pictures or try an example, Faust.
Say the set is $(-2,3)$.
ponders for a sec
ah so ic ant do it that way
Maybe...
00:56
Yes, yes, @Faust. You can. Just fix it!
I was pondering Ted's thing, I'm still with you @Balarka
-sup (S) ?
$-\sup(-S)$.
brain melting
Pictures help.
00:58
whats that even mean in words/
@Daminark Gotcha. Then I can associate to any pair of (nontrivially intersecting) trivializing open sets $U, V$ on the base $B$ a transition function $\varphi_{UV} : U \cap V \to \text{GL}_n(\Bbb R)$, agreed?
You turn it upside-down, but then you need to turn it upside-down again at the end.
Try my example.
@Faust please don't let your brain melt, it gets all over the floor and someone's gotta clean that up
At least stand on a towel
Demonark: Stop humo(u)ring and pay detention to Balarka.
Agreed @Balarka
00:59
I am on detention with Daminark though
well the negative of the sup S is -3 and sup -S is 2 and the -sup -S is the correct inf of -2
True enough, Balarka.
Its correct even though it makes my head hurt
Well, it's the conjugation thing that shows up all over mathematics (change of basis, groups, etc.), Faust.
If you're going to change coordinates (flipping), you need to change back at the end.
$-\sup [-(S ∪ T)] = \inf (S \cup T) $
01:01
\sup
\inf
but, yes.
I'd probably put another set of parentheses.
i still need to neagte the other side
No.
You have it right.
@Daminark So, you can reconstruct the vector bundle $E/B$ just from a given chart on $B$ and the transition functions $\varphi_{UV}$ corresponding to each pair of open sets $U, V$ in the chart; just look at $\bigsqcup U \times \Bbb R^n/\sim$ where $\sim$ puts $(x, v)$ and $(y, v)$ in a equivalence class if they are related by a transition functions.
dont i need to show that inf(S ∪ T) = min{inf S, inf T}
That should follow from this negation stuff.
01:03
Having the data of a vector bundle over a base is the exact same thing as having a trivializing chart and the data of the transition functions.
Remember what happens to a max when you negate the set.
mm but it doesnt seem that coherient
Why do we need the intersections to be non-trivial btw? If they only intersect at a point, that point is open so presumably if the trivializataion only occurs there we're still chill, right?
Be patient, Faust.
Points aren't open. We're Hausdorff, Demonark.
I mean, unless you have isolated points.
@Daminark They can't intersect at a point; they have to intersect at an open set.
01:04
Nontrivial means nonempty, anyhow.
Right.
Sorry for interjecting, Balarka.
I mean technically even if they intersect trivially you can define the transition functions in a dumb way.
Oh we're Hausdorff, alright
Sup chat
01:04
@Ted No worries, I was about to say what you wrote :)
Eric!! Hi :)
What's goin down
And I guess I was thinking of, okay we choose a point and two trivializing neighborhoods of it. But sure I gotchu now
I had visitors for the weekend and taught my class, so now I'm having martinis :P
You doing OK, Eric? The people I know in FL who are posting on FB are doing fine.
@Eric I'm listening to a post-rock album and Daminark and I are goofing with vector bundles
how's it on your end
01:06
−sup[−(S∪T)]=inf(S∪T) = Negation of [min {inf S, inf T }]
Slow down, Faust.
@Ted my parents hunkered down in a safe place and now it's just riding it out but looks like everything is ok
Let's work on the negative of $\sup(-(S\cup T))$.
@Balarka what album
I'm so glad for you and them, Eric.
whew
01:07
Yeah I'm really relieved, just hope the house ends up being ok
ok
@Eric it's a fairly recent one, "In Silence We Yearn" by Oh Hiroshima
try this if you want to have a hear: youtube.com/watch?v=ZnvF5k4StzI
Also what's the functorial point of view on vector bundles
prob my favorite out of the album
im confused i thought we already did that bit?
01:08
I'll have a listen
So we're taking the negative of $\max(\sup(-S),\sup(-T))$, right, @Faust? Did you write that?
no ah i see
@Balarka this is p chill
Actually we need $-(S\cup T) = (-S) \cup (-T)$. Is that clear?
Let's say $T$ is a functor on vector spaces, you say it's continuous if $T:Hom(V,W)\to Hom(T(V),T(W))$ is
01:10
@TedShifrin why isnt it just $ S \cap T $
So if $E$ is a vector bundle, define $T(E) = \bigcup_{x\in B} T(E_x)$
Whoa. Where did that come from?
@Daminark anyway so, really, if you specify the transition functions (they have to satisfy $\varphi_{UU}(x) = I$ and $\varphi_{UV}(x)\varphi_{VW}(x) \varphi_{WU}(x) = I$ to consistently define a vector bundle - called the cocycle conditions) for a given open cover by charts on the base, that's the same thing as having a vector bundle.
We're not doing set complement. We're flipping across the origin in $\Bbb R$.
ah
baka
01:11
@EricSilva i quite like it
ah i agree
I always liked the vibe of post-rock
Good stuff for doing work to
Not for me ... whatever the **** you're talking about :P
$-(S \cup T) = (-S) \cup (-T)$
i had to say it in words for it to make sense
You can argue that that's correct, @Faust? Then proceed.
01:13
its almost a dead genre now though; good that this swedish band is coming up with new stuff
Think about mirror images on $\Bbb R$.
@Balarka so if you take the transition functions perhaps you can define vector bundle operations?
@TedShifrin you're a classical music person :P
Well, I like folk from the 60's and 70's, too. :P
Ah me too
01:14
IDT I dislike any particular kinds of music besides country music
runs in horror
@Eric but yeah so given $\phi:E\to F$ ($F$ is another vector bundle), you define $T(\phi)$ by $T(\phi_x) : T(E_x)\to T(F_x)$.
although there's a newbie who made it as a "gay country singer" (and I contributed to his album) and I don't find him particularly country at all.
the negation of max{sup -S,sup -T}
Now you want to give $T(E)$ and $T(F)$ topologies so that $T(\phi)$ is continuous
01:16
@Daminark Aha, exactly. Say $E/B$ and $E'/B$ are two vector bundles (say rank $n$ and $m$) and suppose their corresponding transition functions are $\varphi_{UV}$ and $\psi_{UV}$. The direct sum $E \oplus E'$ is defined out of the transition functions $\varphi_{UV} \oplus \psi_{UV}$ which sends each point $x \in U \cap V$ to the $(n+m) \times (n+m)$ matrix with two big diagonal blocks corresponding to $\varphi_{UV}(x)$ and $\psi_{UV}(x)$ and zero diagonal blocks off-diagonal
i need the negation of max { -sup (-S), -sup (-T) } dont i?
No, you need $-\max(\sup(-S),\sup(-T))$, don't you?
Oh that's slick @Balarka
I just think countty is really boring
(Notice that $\varphi_{UV}(x)$ is an $n \times n$ matrix and $\psi_{UV}(x)$ is an $m \times m$ matrix)
01:17
I'll be back in a few minutes
I don't like the whining sound, Eric. But sometimes things are called country that I don't think are country.
@Daminark Cool, right?
Does bluegrass count as country
It's just taking the isomorphisms $\Bbb R^n \to \Bbb R^n$ and $\Bbb R^m \to \Bbb R^m$ fiberwise and taking the "direct sum isomorphism" $\Bbb R^n \oplus \Bbb R^m \to \Bbb R^n \oplus \Bbb R^m$
I am trying to negate this statement? sup[−(S∪T)] = max {sup (-S), sup (-T)
01:18
I don't think I like this functorial nonsense considering how concrete these objects really are
sorry im totally lost
@BalarkaSen I meant "zero matrix blocks"
@Eric Is this to Daminark?
You're not negating a statement, @Faust. Just a real number.
Yes @Balarka
Eric, you and I are on one side, and they're on the other :P
01:20
@TedShifrin i dont understand that statement =P
Atiyah's construction unifies the construction of all the various vector bundles (direct sum/tensor product/hom/dual/etc etc etc)
useful for exposition, not sure if for pedagogy :P
i want to use that fact that sup[(S∪T)] = max {sup (S), sup (T) to prove the inf case
I guess you don't really use this construction unless you already know what's happening
I found it pretty. I don't think I would tell it to anyone
@Eric yeah
why can't i just negate the statement sup[(S∪T)] = max {sup (S), sup (T)}
01:22
Right, @Faust. So we need to take $-\max\{\sup(-S),\sup(-T)\}$. But we know $-\sup(-S) = \inf(S)$.
Don't say negate statement.
I just think the concrete stuff with local trivialization a and transition maps is like... Really easy to visualize and not even a hassle to deal with
That's a matter of logic.
Geometers like transition functions more than topologists, @EricSilva.
I guess I make enough local computations that I want that picture
I like transition functions
Good, @Balarka. You'll find them all through Riemann surfaces and line bundles.
01:24
Then we know that $-\sup[−(S∪T)] = \inf [(S) \cup (T)] $
no minuses on the right, Faust (I think).
oh
@Balarka solid no
01:25
your right
Lol but I love bowie
Ron Davies was a country singer though
that's the guy who wrote the song
I mean it just doesn't sound like country tho
Not twangy or whiny enough? :D
so i know need to write out what -max{sup (-S), sup (-T)} is
01:26
bc Bowie doesn't have a country sound
Right, @Faust. What's $\max(-a,-b)$?
-b
sorry
01:28
LOL
is that an interval?
No, no, max of two numbers.
You used set brackets. My bad.
Similarly I think all along the watchtower performed by Hendrix vs Dylan are completely different genres
What's $\max\{-a,-b\}$?
01:29
Cause their sounds are suuuuuper different
right, I agree
@Balarka this is definitely countrt
@Balarka this is definitely country
1000% country music
It did the thing again where an edit turns into a new message
So weird
Technology is appallingly unperfect.
01:32
If bluegrass counts as country though then there's some country I can enjoy
@TedShifrin sorry i dont understand unless i know what they are i cant compare them as the result changes if one or both or none are negative?
But it's weird bc I associate contry with certain styles of vocals but bluegrass doesn't have it
Eh, the functors don't help pictorially but I think if you get used to them they're convenient if nothing else. Plus I'm in the void between being more pictorial than not and basically not being able to make any sense out of pictures so seeing both is useful
That doesn't matter, @Faust. You should engage the min.
but the min a,b doesnt make sense
01:33
thinks Demonark belongs in a deep void
Of course it does, @Faust. What do you mean?
let a=2 b=3
But in one sweep everything you do to vector spaces can be done to bundles which is pretty nifty as far as things go
then the max is -2
but the min of a,b is 2
What's $\max\{-2, 1\}$ and what's $\min\{2,-1\}$?
Well, there's a minus sign, isn't there? The same minus sign we had :)
ones 1 the other negative 1
01:35
Nope. Try again.
@TedShifrin I have done nothing to deserve this!
OK, fine.
:p
So ... $\max\{-a,-b\} = -\min\{a,b\}$. Isn't that convenient?
I think math has a principle of conservation of difficulty, so you often pay the price for being too sleek
01:36
slick? :D
yeah now i have all the pieces
Although I love to be sleek, Eric :P
Yes, @Faust. You do. You'll get it all now.
but how do i write it out to get marks?
Yeah slick that's the word
like what do i say that im doing?
01:37
State carefully all the facts you're using. If something is non-obvious, prove it.
I don't know what your prof expects for level.
k ima write it out
Although I think if sleek connotatively means everything is "pretty and shiny" and elegant then it still works
Have fun. You'll do fine.
Thank you so much =)
@Eric what kind of music do you usually listen to
01:37
I like being pretty and shiny, Eric :P
hip hop? rock? violent death metal?
@BalarkaSen I don't listen to death metal lol
hits Balarka over the head and throws him in bed
I listen to a lot of hip hop, rock, jazz, classical, Brazilian music, whatever
01:39
i see
Can anyone tell me if i finally got this negation correct?
https://math.stackexchange.com/questions/2424279/negation-of-logical-statement-in-graph-theory
I don't think my tastes are really narrow
so you're not in the metal game at all
I was when I was like 15
Bye all :)
01:39
Bye Ted
See you, @Ted
Bye @Ted!
I have found myself slowly drifting towards metal
I am pretty into the Chicago hip hop scene lately @Balarka so there's that I guess
@BalarkaSen i didnt know you were a magnet!?
01:41
I've been listening to a lot of chance, towkio, noname, Vic Mensa, bj the Chicago kid donnie trumpet etc lately
@Eric ah cool
tbh idt hip hop is my thing
But that's just lately, I guess I listen to samba just as often because it's the kind of music I enjoy playing
I think hip hop is wide enough that finding some you enjoy is more a matter of finding the right ppl than unilaterally disliking the genre
well there's death grips loooool
Although the same can be said for a lot of genres
Do you like them unironically
true
just their first mixtape
01:44
I actually don't think they're bad
But I'm more into chill stuff I guess
they occasionally do come up with interesting sonics, true
I also adore Kendrick
i have tried to listen to some of his things
good kid mAAd city eg
I can appreciate it, but I can't really say it's my thing
I think to pimp a butterfly is one of my favorite albums of all time easily
Not a huge fan of DAMN. Tho
01:47
Tbf I grew up listening to a lot of Compton rappers so kdot is like, very much also a nostalgia trip for me in terms of sounds
yeah i can see why actually growing up listening to rap would create an appreciation for that
being from a rock slash folk background it's kinda hard for me
I guess I also like the underground far more than the mainstream for completely non musical reasons lol
I mean underground stuff comes in all genres, I listen to a lot of underground stuff
i agree
I play a lot of folk (being a mandolinist) so I love that kind of stuff
i have been recommended dalek recently
01:55
I mostly do game soundtracks lmao
@Eric cool!
I listen to those too @Daminark lol
@Daminark undertale soundtracks are amazing
I agree with that^^
Right? That and FTL are my favorite
01:56
That shit is dope af
but yeah it's funny that my underground tastes has led me down to bizarre, bizarre shit
That's kind of what you expect tho
I date a percussionist so I'm familiar with bizarre ass music lol
I have been listening a lot of the experimental Scott Walker albums recently
Tilt and Drift are my absolute favorite
I went to a concert recently that was 3 hours of people tapping on desks
It was actually like super dope

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