@Matt I dunno. From time to time, I do get a bit guilty about women not given their due and stuff. In my undergrad days, I was even contemplating adding my mother's name as a middle initial (my second name is my father's given name). :-)
I haven't acted on it because it seemed (seems) too radical...
That's one reason why I am a bit more careful than usual. Not sure if I am overdoing it.
@Srivatsan Besides complete equality would mean your date will treat you like a buddy and not like a date. Not that I couldn't live with that but I think the other way around is nicer.
@Matt Depends, I found out that it is dangerous to follow those weird courtesy rules. I once was yelled at by an acquaintance because I entered the restaurant and then later on the bus before her (as I should)...
@Matt I didn't act as she expected but according to what I was taught... The door was held open by a waiter and I entered the main hall (slightly) in front of her --- that's the rule --- after all, I made the arrangements and I should talk to the waiter who shows me to the table, etc. After that I figured out that following the courtesy rules is not always the good thing to do...
@Matt well, man enters, looks for an option, chooses one and offers it to the woman who can then accept or decline is a fairly general rule which applies here as well.
No, I'm not. It's a bit hairy in the details and I have taken some pains to answer that OP before and didn't see too much appreciation. Also, it's one of those persons who never answers a question...
(or just once a very trivial thing compared to the questions asked)
@Matt, BTW, I did not really follow the distinction between your two approaches you mentioned. But: do you have another approach for proving the Lebesgue number lemma? Why don't you add that as an alternate answer?
@Matt Well, I meant to say: I know there's at least one more proof since a comment links to them. Of course, if you have a third proof, that will totally be great.
@Matt OK. If you would like to take a shot at it, then please do. I am asking because otherwise I want to add it (just so that both proofs are there in that page).
@JM Took a bit of doing to get the rectangular candy-cane and then to merge with the old avatar, I had to figure out how to make Mathematica output transparent backgrounds.
@JM That would mess up the candy striping on the cylinders to do it that way, because the cross sections are radial instead of horizontal and vertical.
@JM I would also think that the cross sections would be slightly elliptical on the cylinders near the corners.
@JM: you probably don't have TGIFriday's restaurants there, but their logo has red and white stripes in it. My wife and I were noticing the candy-cane-like nature the other day. My avatar could almost be considered and advertisement for them.
Yes, or at least I think so. I didn't ask and I don't know their name because I'm not interested in knowing anything about them at all. As a matter of fact I already have much more than I wanted.
@HenningMakholm That seems too creepy actually, considering that Asaf could've picked pretty much any random fact: like my favorite "Lincoln was the 16th President of the US".
@brainail I didn't understand what you meant. Did you mean that you want a simple proof? Do you have any reason to believe that there's a simple proof?
@HenningMakholm Creepy that Godwin's law worked here.
@Srivatsan I think it fits the definition. This is an online discussion, and Asaf made a comparison that involved Hitler or the Nazis (namely, comparing the hot-off-the-pressness of various facts).
@HenningMakholm Yes, I agree that Godwin's law worked out to be right. I am just saying Asaf had a lot of choice (no pun intended) of random facts , and yet he managed to choose an allusion to Hitler. Which I find interesting.
Perhaps this is what happens in every online forum, I do not have much experience with that.
@Bullmoose Dimensionally it makes sense that it does not depend on the variance.
@Bullmoose After all, $\sigma$ is the only parameter (assuming zero mean), and entropy is dimensionless, so we will expect that the entropy is proportional to $\sigma^{0}$.
@Srivatsan Thanks for confirmation! By the way, if you are interested, I just saw Iyengar appearing as a donor for Wikipedia in the banner of one Wiki article. Here is his personal appeal wikimediafoundation.org/w/index.php?title=L11_1215_AI/en/…
@Tim In fact, from the name "Akshaya", I'm guessing this is a lady. And I would guess that iyengar is not a software developer although I have no evidence for this claim.
Hi, people, is the formula for finding for roots in higher degree irreducable polynomial (>5) always expressed in a very complicated way if you express it in integral?
@Victor These results are of theoretical interest mostly. If you want to (say) solve a fifth degree equation in real life, these things will be very slow (even if they give meaningful results at all). In contrast, numerical methods are usually waaay faster.
@Victor It might depend (and I am no expert on this). But my guess is that the accuracy can be tuned.
An even more interesting question is: given an accuracy, how many steps/iterations (or time if you're running it on your computer) the method takes. And there are also issues like stability of the method, and so on.