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23:01
What?
Oh right. I forgot about there are direct formulae to compute the Fourier series. Now the hilbert-space and linear-algebra tags look quite silly.
J.M. should rejoin very soon, I'd think.
23:17
@AsafKaragila cstheory is research level, and I am not sure if this question is a research level question. It might be.
@Srivatsan I think it's fine. It's linear algebra and hilbert space techniques anyway.
I need to buy a heating.
@Srivatsan I think you can phrase it in research level.
He's looking for a useful algorithm, one can ask it in a clever way.
@tb Not sure.
Much like asking about a specific function can be cleverly and nicely asked about a general family of functions instead.
23:19
@AsafKaragila I don't understand what graphs though. Could be the Hamming graph (connect two sets if their symmetric difference is a singleton set). But that doesn't fit too well either.
@Srivatsan Yeah, and set theory... this question is all about forcing without choice in modal logic, under large cardinal assumptions.
Yes, it has the word "set", it must be [set-theory]. Not even elementary set theory.
@JonasTeuwen I guess it's just a reiteration of your comment. But note that $f(x)$ is a common abus de notation for the function $x \mapsto f(x)$.
Yes, but it is very ugly.
@AsafKaragila Why did MSE settle on set theory and elementary set theory, rather than advanced set theory and set theory?
Or advanced set theory and elementary set theory?
@Srivatsan I don't know. It was brought on meta several times, though. I do agree with the current status, [set-theory] is what you do when you actually deal with the axioms; the other stuff... equivalence relations and whatnot is all elementary stuff.
Much like [elementary-number-theory] vs. [number-theory]
23:26
Maybe this is dumb, but isn't that a variant of the Knapsack problem?
Neat, I got 175 points today. I have 34 minutes to get 25 more :-D
@AsafKaragila Yes, the current policy is clear. And this question wouldn't fall under set theory, whether or not [elementary-set-theory] fits.
@Srivatsan Quite.
@tb Variant, yes. But we are now looking at the least k subsets of the original set. Presumbly these near-minimum sets could have greater structure (that is to say, this problem might not be NP-complete).
(where subsets are ordered according to the sum of the elements)
@Srivatsan I see. Meanwhile J.M. has posted an answer/comment.
23:34
My impression is that this problem is quite different from knapsack. Whether it is a standard problem, I have no idea.
@tb With all due respect to JM, that's quite a non-answer. =)
[Of course, I am sure JM intended to post it as a comment; just saying.]
Well, I'm sure y'all can resolve that without my participation :)
Ok, I'm off for dinner. Bye!
bye
@Jonas: I have some bad news.
@robjohn Oh?
@robjohn Oh. Thanks 8-).
23:47
I don't think it's bounded under the conditions given.
Tick tock, will I break the 200 limit today or not?
@robjohn And it doesn't help if $t \lesssim \min(1, |y|^{-1})$ right? 8-)?
No it doesn't because that is the same as $t \in (0, T]$.
@robjohn Thanks. I'll adapt my argument then.
I could bound the one part, but when I went to bound the second part, the counter-example was pretty clear.
I needed to bound $\left|e^{-t^2}x-y\right|^2$ below, but I couldn't in the second case.
@tb How far are you from Epic?
@AsafKaragila No idea
23:53
@AsafKaragila I'm lucky to get 50 today :-)
@robjohn Two more votes and I hit 200, four more and I hit the cap.
@robjohn that's more than me :) 36 unless some answers happen to be deleted
@AsafKaragila :-p
@tb Nice. If I hit the cap today, we can get an Epic badge together... it'll be my 14th ;-)
@AsafKaragila oh, that's the amount of rep today :)
23:55
@robjohn I'm standing in front of the ruins of my world image.
@JonasTeuwen Why is that?
Hah. I see. :-P
@robjohn Because my inequality fails!
@JonasTeuwen Is it that critical?
I don't think so. I have the condition $t \min(|x|, |y|) \leqslant C$. I think I only need the part with the $|x|$ in there. I just wanted to state the result in a more general form which might be useful in the future.
why distinguish
I am saying that if in the next two minutes I will get two more upvotes then I will be one day closer to an Epic badge :-P
@tb I'm not making a real distinction, the /reputation page does.

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