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00:02
The truth is that I'm very attached to my work, and I might be often misinterpreted because of that (while defending it).
My work is like a living being to me.
Anyway.
I'm out.
00:22
BigM seems to be throwing a tantrum and is now spite downvoting my answers.
Moderators, to my knowledge, can't see votes and can't undo them. There's an automatic script that checks for serial voting every day (it should run in about three hours today); if he's downvoted more than one or two it should catch it and reverse the downvotes.
It's just one. So far, anyway.
Unfortuantely, there's probably nothing that can be done then.
00:37
@MikeMiller Look at this.
First he pretends he can solve the exercise by giving "overgenerous hints" and when I press him for an answer he admits he can't do it either.
I should go.
01:16
Morning, @AlexWertheim.
Hello, @Mike. How goes it? :)
Pretty good. A bit tired.
Long day?
Mm, just didn't get a good night's sleep last night. The day was no longer than usual.
@RudytheReindeer Ugh, don't engage with users in silly fights.
01:19
Ah, I see. I didn't sleep so well myself after the Duke-UNC game. Good fun.
@PedroTamaroff It's not silly! I am trying to help the OP. BigM posted a whole load of rubbish. How is OP, presumably an undergrad, supposed to know that the answer is misleading?
And then BigM converted his upvote to a downvote.
@RudytheReindeer It has three downvotes already.
@PedroTamaroff Yes, now.
01:23
Still. Don't engage negatively.
You can point out the mistake.
But the point was: he spite downvoted the question and I left a comment pointing it out.
That is not negative, it is stating a fact.
@RudytheReindeer Don't do that.
You don't know as a fact he did that.
I guess I can't prove it. Ok.
But it was pretty clear. Someone has to do something about people like this.
I caught him in the act.
01:25
No you didn't.
Again: you don't know who downvoted.
So don't accuse users through comments.
That usually creates discussion, as you see.
Right, I know.
And it is not useful.
If you want, you can flag.
No, flagging wrong answers is discouraged and will be dismissed. I tried before.
Whatever. He's got -3 now. That's enough for today.
I meant flagging if you know as a fact the user is being abusive.
I am going now. Byes.
01:28
Goodbye.
01:53
Good afternoon.
02:38
When a plane contains the line $\overrightarrow{v}_1=\overrightarrow{a}+t\overrightarrow{u}$, does this mean that the vector $\overrightarrow{u}$ is parallel to the plane??
I might be mistaken, but I don't think there exists the notion of "a vector parallel to a plane", you could say the vector is embedded in the plane, yes; as well as the line.
I'm incorrect, the vector could be outside of the plane and, in that case, it would be parallel to it. It's just not as common as the notion or usefulness of perpendicular vectors in relation to planes.
03:04
Gu
Hi!
0
Q: How do I make two rectangles not touching if they touch?

BarakadosI want to keep this as specific as possible while keeping the idea open to interpretation to different languages. Assume the class rectangle has the following items. object Rectangle{ number x; (The center of the rectangle on the x axis.) number y; (The center of the rectangle on the x axi...

03:19
$\displaystyle\left(\dfrac1{x+1}-\dfrac1{x+3}+\dfrac1{x+5}-\dfrac1{x+7}+ \dotsb \right)\sim \dfrac1{2x+4}$
Hi, anyone knows an free step by step computational engine similar to the wolfram alpha pro?
What I wrote probably isn't true, actually
 
2 hours later…
05:51
@Victor If you practice enough, that's your brain you want.
06:01
Hi everyone!
I have discovered a new and elementary proof of FLT. Can anyone tell me where can I publish it?
06:20
@anon Gotta love the anon.
@IshanSingh You can try viXra.
morning, @anon, @Emrakul
06:35
blegh
@anon What happened?
night time
Don't you like nighttime?
It's quiet.
And people don't interrupt you.
true
but I am too le tiered to enjoy
@anon How the Langlands programme going?
06:42
not. been thinking about peter-weyl.
What's that?
I'd call it a fundamental theorem of representation theory
for finite groups it's $\Bbb C[G]\cong\bigoplus_V{\rm End}_{\Bbb C}(V)$ as $V$ runs over irreducible representations. for compact the story is more complicated, and more complicated still for locally compact.
it wows me that it's got a version for loc. comp.
06:44
@anon This semester Mariano is giving a course on rep. thry of algebras.
yeah, only being locally compact allows a kind of wideness to the group
I'll tell you if I survive it.
cool
(if we're talking lie groups) it still forces the group to be finite dimensional, so it's not tooooo shocking. as far as i know there's nothing like it for infinite dimensional stuff.
 
1 hour later…
07:48
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I think MSE shoud say "Thank you" for the contribution of the people, and ask their permissions for any rights.
Anyway, I don't wanna read such texts anymore because they annoy me far too much.
Some delete their accounts, but look ...
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08:40
@SayanChattopadhyay No one is asking anything to be continued till infinity.
If you assume an hypothesis, and contradict it, you can apply induction.
This is why I am asking you to study set theory carefully first. Induction is a very basic mathematical tool.
hmm
harrumph
09:24
What is tho correct adjective or noun to represent someone who is more expressive in writing than in speaking?
09:39
"expressive" could mean lots of things
i don't know, maybe a writer?
you should take this question here
@stalkingisn'ttolerated G-man's right, why the hell are you asking this in a chat for people interested in mathematics?
Does anyone know how to tell if a given curve is a parabola or a hyperbola?
In the sense that you have in front of you a drawing of the curve
on a piece of paper
a good criterion might be: hyperbolas approach a pair of lines as you go out to infinity while parabolas don't
@G-man check the eccentricity
09:51
let me clarify things further: i was in an interview and the interviewers presented me with a print out of a conic section and some basic geometric tools, and asked me to conclusively find out what it was. it could be anything except a circle
so @DavidWheeler how do propose to do so?
well if there's no numerical references, no equation, and only a section of the curve displayed, then i would look at how "bendy" the curve is-hyperbolas are "bendier"
hm, it could also be a small arc of an ellipse
@KarlKronenfeld exactly.
@DavidWheeler remember "conclusively"
i could see one vertex and an arc
"vertex"?
methinks it should be fairly easy if you're using standard terminology here
local maximum in curvature, i suspect is what he means
09:56
@david yeah
Hello @Committingtoachallenge.
you could i suppose guess at a focus, draw a directrix, and check distances-if it's a parabola, they would stay equal, if the drawing was at a scale where you could tell something-something you can also do to roughly guage the eccentricity
Anonymous
Hello!
you'd know if you had the focus and directrix approximately right, because the two distances would stay at a constant ratio
it's how they used to draw conics before descartes and his windowpane view of the plane
Anonymous
@KajHansen How you doing?
10:20
hey, i just thought of something: first i would construct the axis(that's easy), and then i would make two incident rays parallel to it. if they meet at a point on the axis, it's a parabola. isn't that right?
Hello, there ... I just want a clarification to this idea posted years before... math.stackexchange.com/questions/36912/p-vs-np-and-gödel
I am studying the same thing and intuitively... the statement used in Gödel's incompleteness theorem "This statement cannot be proved." Is an example of a statement that is verifiable yet unprovable. Now, if proof is equivalent to an algorithm (a supposition I am unsure of) then isn't this an instance of some language in NP but not in P?
10:41
Hi jasper @ABeautifulMind
who is jasper? i don't see him in the chat room.
@BalarkaSen I can do anything in induction I have read it thoroughly
Why did I ping @ABeautifulMind @G-man
ok.
so anyone have any ideas on my problem?
Parabola or hyperbola
@sayan what?
10:55
Parabola is a curve in which the difference distance of the set of points on the curve from two fixed points is constant@G-man
It is the hyperbola @G-man not parabola
@Sayan do you even know what my problem is? and FYI I am well-versed on the knowledge of conic sections.
What's ur question.....then
I might have misread it
given just a small piece of curve, tell what kind of conic it is
why don't you just scroll up a bit and read it
meh, i'm too lazy
11:04
Ya so take two points and find the difference between the set of points on the hyperbola with the two points and see that if the distance is constant@G-man
@David I was saying that to Sayan. And BTW I figured out a way to identify parabolas
I got it @G-man
@G-man I kno, I was just messin' wit' ya
@Sayan think clearly, that won't work
11:07
Search your feelings, and you will know it to be true
11:45
@ABeautifulMind Hey Jasper, Sorry I have been busy, how are you doing?
@Chris'ssis I can't see why you have posted this big text wall, what was the purpose?
I think I detect a concern with intellectual property rights. Just sayin'
@DavidWheeler Oh, I don't know what worry she would have. This stuff is just to cover their arses.
@Mike I was led to believe Euler was pronounced 'oiler' by a lecturer.
today's tabloid headline: stackexchange stole my nobel-prize-winning idea!
@Committingtoachallenge lol, that was in response to a snarky remark I made concerning the Euler characteristic. Mike smacked me for it :P
12:05
What was? Him saying it is 'you-ler'? Was that a joke? Is it 'oiler'?
I said: "I dimly remember something about some guy named Oiler..."
which prompted his comment (after he smacked me).
someone had posed (just before) a query on proving the number of passes (saddle points) in relation to hills and valleys on a spherical planet. I dryly commented: "oh yeah, spheres have the two-number-thingie".
@Committingtoachallenge Not too good. Every day, I try to conquer my negative thoughts with positive ones. But it's hard to make progress. Even when progress is made, you can retrogress.
12:20
@ABeautifulMind Did you used to have a different user name?
@Committingtoachallenge Well, sometimes people pronounce it a certain way because they heard from others, but it is not necessarily correct. So just pronounce it any way you want.
@DavidWheeler Yes, I am Jasper, the guy who keeps deleting accounts.
@DavidWheeler I usually have a blue square as my picture, so people recognise me, but there are also imposters, so beware.
I remember you, Jasper
Yes, I am still struggling with mental illness. I have not been working for so long. It is very sad.
I hope to get well by the end of next year. Pray for me.
I struggled with bipolar disorder for a long time. I think I'm better, but there's no guarantee.
I have MDD, OCD and PTSD.
12:23
here's to hoping happiness finds you.
I have been thinking about my entire past and my entire possible future lately. I am trying to be positive instead of negative about things. I need to believe that something extraordinary is possible.
I wrote a song once which has this line:
If you wake up early in the morning, take a look at the rising sun-and try to forget about, all of the things you've done. There's another long night behind you, and another day's just begun. Let your eyes open wide, lay down all your fear. Give your heart to the sky, and all your sorrow will disappear.
@DavidWheeler Thanks, I am going to take a nap.
@ABeautifulMind Yes this is definitely a concern, but thinking about it won't help
@ABeautifulMind Enjoy any progress my friend
@ABeautifulMind Enjoy your nap
12:39
@Committingtoachallenge Why? Because I wanted to post it. Do you think that I care to give you any explanation about what I do, say?
@Committingtoachallenge Next time you wanna address to me say first "Hello" or something like that, and then "May I disturb you?".
This is if you wanna see me answering back to you.
Both you and @TedShifrin should learn to respect me if you wanna engage in a conversation with me.
If you wanna just make remarks, then OK, I'm going to make remarks too.
I don't quarrel with you, no, not at all, just tell you to be nice.
12:56
@Chris'ssis Wow very large overreaction, maybe take your aggressive tendencies elsewhere
@Chris'ssis I'll just block you to save you the trouble
13:09
hi @teadawg1337
Hello @G-man
Have we met before?
yeah, earlier i used the name yashg
Ah, hello there! You should have mentioned that first :P
So, how goes it @G-man ?
it goes fine for the most part
13:26
The past few days have been rather uneventful for me, lol
yeah i remember
nothing of note happening in tennesse these past days
14:07
Simplest way to handle $\int \frac{x^2}{2\sqrt{1-x^2}}\,\mathrm{d}x$?
Did you try making trig substitutions?
@N3buchadnezzar I think $x=\sin(\theta)$ would be of great use here
@teadawg1337 Meh, takes too long :p
Ends up with $\int = \frac{1}{2}\cos \theta \sin \theta - \frac{1}{2}\theta$
@N3buchadnezzar I'm ending up with something different
@teadawg1337 You end up with $\int \sin^2 \theta \,\mathrm{d}\theta$ right?
$\frac12\int\sin^2{\theta}\,d\theta$
@N3buchadnezzar There's a 2 in the parent integral's denominator
14:26
@teadawg1337 right
$\sin^2(\theta)=?$
22 mins ago, by N3buchadnezzar
Ends up with $\int = \frac{1}{2}\cos \theta \sin \theta - \frac{1}{2}\theta$
just divide by two
I know, but that's not the end result that I get, either
You multiplied by a factor of $-1$ somewhere
15:20
@DavidWheeler Hey! Nice to see you here again.
15:49
Hi @BalarkaSen
Hullo.
You finally figured out how to prove that $|\Bbb R| = \infty$, then?
How is life going then......especially algebraic topology
Actually.........Nope :(
fine.
@SayanChattopadhyay well, if you have a set $A$ and for any finite subset $B \subset A$, $A - B$ is nonzero, what does it mean?
How do u go about it....I understood that n and n+1 and all about that but after that it would be something like this no....
$n,n+1,n+1+1........../infinity$
look at my last message.
15:58
$A-B$ means elements which are in A but not in B
yes. haven't you studied Hammack yet?
Why I did answer it right
i didn't ask for the definition of $A - B$.
[i should've said nonempty instead of nonzero]
Morning, @Huy.
But B is a subset of A.....
16:02
yes. so?
So does that mean A-B will contain only the null set
it doesn't. study Hammack.
a bit thoroughly and slowly this time, please.
hello, i have an interval $[a,b]$ how to obtain a sequence of interval [a_n,b_n] with (a_n) is an increasing sequence and (b_n) is decreasing ?
Its a proper subset right@BalarkaSen
it is.
there are a whole bunch of examples of sets A and subsets B of A such that A - B is nonempty.
16:05
@robjohn did you manage to finish the question we talked about yesterday? The one with log sine.
if that isn't obvious to you, you need to restudy set theory.
But if it is a subset then all the elements of B have to be elements of A
sure
by no means that implies A - B is empty. :P
And then A-B will be nonempty because there will be elements of A in it
Ok.....I was a bit late in deductions....
@SayanChattopadhyay right.
16:07
Fine @BalarkaSen
you should study sets carefully, @Sayan. these kind of deductions should come naturally and quickly.
I have studied set theory just takes a little bit of time to deduce them......
that means you have only skimmed through set theory, not studied it carefully. :P Trust me, i have been there.
anyway, answer my original question.
Ok fine can I ask u a question....@BalarkaSen
go on.
16:10
Anyways thanks for directing me towards high order mathematics @BalarkaSen
Well I kept on studying differentiability and continuity yesterday but I don't get the difference between them......actually I had skipped the differentiability questions
If the right hand limit is equal to the left hand limit equal to the value of the function at a point a then it is a continuous function right @BalarkaSen
@robjohn @DanielFischer Hello!!! We have the function
$$y(t)=\left\{\begin{matrix}
0 &, 0 \leq t \leq \frac{1}{2} \\
\frac{(t-\frac{1}{2})^2}{4} &, \frac{1}{2} \leq t \leq 1
\end{matrix}\right.$$


Do we find its derivative as follows?

$$\lim_{t \to \frac{1}{2}^-} \frac{f(t)-f(\frac{1}{2})}{t-\frac{1}{2}}=\lim_{t \to \frac{1}{2}^-} \frac{0-0}{t-\frac{1}{2}}=0$$

$$\lim_{t \to \frac{1}{2}^+} \frac{f(t)-f(\frac{1}{2})}{t-\frac{1}{2}}=\frac{\frac{(t-\frac{1}{2})^2}{4}}{t-\frac{1}{2}}=\lim_{t \to \frac{1}{2}^-} \frac{t-\frac{1}{2}}{4}=0$$
@Sayan It only implies that the function is continuous at the point $a$, not that it's continuous everywhere
Do you mean to say you don't know of a function that's continuous but not differentiable?
Otherwise, if you mean difference in definitions, that one is pretty obvious :P
And differentiability is like its derivative is present everywhere right @BalarkaSen and @teadawg1337
16:14
Yes, @Sayan.
@evinda That's one way to do it.
It's been at least two years since I've studied basic calculus, I won't be of much help with definitions lol
I know a function which is continuous but not differentiable...
so what is your question then?
anyone know some good references on complex manifolds? i'd like to understand how the notion of a riemann surface generalizes to more than two complex variables, but my formal background isn't great
16:16
My question is how do I find that a function is not differentiable
@SayanChattopadhyay: do you mean, how do you find such a function, or how do you demonstrate that it's not differentiable
Demonstrate and even find....
@SayanChattopadhyay ah. well just see if $\lim_{h \to 0^+} (f(x + h) - f(x))/h = \lim_{h \to 0^-} (f(x + h) - f(x))/h$ or not.
I seem to recall a set of rules that define non-differentiability
Huybrechts is a standard good reference for complex geometry, @Semiclassical. I assume you want to know more than the definition.
16:19
@BalarkaSen's on the money there---just check the RH and LH limits and see if the first derivative can be made continuous
At a point x=0,let's say right
Oh ya I remember a doubt again @BalarkaSen
@MikeMiller @Huy everywhere.
:P
Huygens, Huybrechts, ...
@MikeMiller: right now, i'm interested in the concepts and some of the terminology (mostly to be able to recognize the difference between terms like Kahler manifolds, K3 surfaces, etc.)
sure, Huybrechts should work fine.
my lack of formal training in riemannian geometry will probably come back to haunt me
16:21
If there is a function which is converging when I keep on finding its derivatives like the first,second,......does that mean I can say the infinite derivative exist @BalarkaSen
not really. only when you're talking about Kahler manifolds.
complex manifolds don't come equipped with a Riemannian structure in general
@evinda looks good.
@SayanChattopadhyay there is nothing called infinity derivative, technically speaking. $\lim_{n \to \infty} f^{(n)}(x)$ can be a weird beast.
thing is, i'll probably be most interested in being able to integrate on such surfaces
16:22
that sounds more like differential forms?
which is a smooth manifolds thing, no complex geometry involved
but maybe there are techniques for doing so special to complex surfaces, I dunno
16:23
the reason i have the complex case in mind is b/c in the Riemann surface context one is able to talk about Picard-Fuchs equations (which in that context i understand in terms of the cohomology of the surface)
presumably it's more general than that, but it's not something i know well
the stuff you're talking about is lost on me, so i doubt i can say much
Why @BalarkaSen will it be a weird beast
i'm not sure what i'm saying is actually sensible, heh. might not be
hence why i wanted some good references :P
huybrechts is just a standard complex geometry text. take a look to see if it's what you want/need.
16:26
googling what you just mentioned it sounds like you're thinking about mirror symmetry or something? which is wizardry
i've gone to three different talks on mirror symmetry and understood nothing of any of them
same here. i know mirror symmetry is in that direction, but i'm trying to aim for more pedestrian things
(which is to say, i'm not doing string theory :P)
picard-fuchs equations just naturally brings up an early paper on mirror symmetry
yeah. i know it's relevant in that context
@Chris'ssis I looked at it a bit, but didn't finish it.
it's an example of what's known as a Gauss-Manin connection
16:29
@robjohn I just answered it on main
3
A: Evaluate $\int_0^{\pi/2}\frac{x^2\log^2{(\sin{x})}}{\sin^2x}dx$

Chris's sisLet's start out with the auxiliary result \begin{equation*} \int_0^{\pi/2}\frac{x^2\log{(\sin(x))}}{\sin^2(x)}dx=\pi\ln{(2)}-\frac{\pi}{2}\ln^2(2)-\frac{\pi^3}{12}. \end{equation*} By the integration by parts all reduces to $$\int_0^{\pi/2} \cot(x) (x^2 \cot(x)+2 x\log(\sin(x))) \ dx=\int_0^{\p...

which i'll confess is something i more know in terms of its name than in terms of the concept
two very different names :)
seems like a remarkably rich field of study I've never heard of before
16:30
@Chris'ssis I won't look until I get some time to finish.
@robjohn Nice!!!
@DanielFischer How else could we do it?
@evinda what's nice?
Daniel said that this is one way to do it
@evinda if you used the arrows, I'd know what you are referring to.
@MikeMiller mostly i'm just trying to figure out how one takes the story i know in two complex variables (e.g. elliptic curves + picard-fuchs) and extends it to more complex variables
it's definitely known, i just don't know it :)
16:33
@robjohn Nice!!!
@evinda Compute the derivative for $x < 1/2$ and for $x > 1/2$, note that they have the same limit at $1/2$, and use a theorem that says if $f$ is continuous on $(a,b)$, differentiable on $(a,b)\setminus \{c\}$ and $\lim\limits_{x\to c} f'(x)$ exists, then $f$ is also differentiable at $c$, and $f'(c)$ is that limit.
well, elliptic curves are one complex variable, hence the name...
oh I see
Picard Fuchs is done on something whose fibers are elliptic curves
@evinda Ah, okay. I was surprised by the !! for simply saying it looks okay.
sorry 🌝
@MikeMiller my computer doesn't render that character
16:36
@robjohn whoops... iPhone smilie
@robjohn aha. I knew how to do it in the first 10 min I saw it.
hello my peeps
@MikeMiller full moon with face according to the unicode table
right. and i suspect the new context would still have the fibers be algebraic varieties, but no longer something in 2 variables like $y^2=x(x-1)(x-\lambda)$
Hello @EnjoysMath
16:38
so yeah, i'm reaching around for a handhold into that realm
@DanielFischer A ok.. In this case can we take the closed intervals $[0,1]$ and $[0,1] \setminus{\frac{1}{2}}$ ?
A finite union of open sets $V_i$ is such that $\overline{\cup_i V_i} \subset \cup_i \bar{V_i}$ or are they
equal
Hello @Chris'ssis.
@ABeautifulMind Hello. How are you doing?
@Chris'ssis Thanks for your videos. I am still struggling. I hope I find the way soon.
16:40
@evinda Yes, we're only interested in an interior point, so whether the interval is open, closed or half-open doesn't matter.
Hello @ABeautifulMind yesterday I was a bit busy with math yesterday.....sorry I was not able to talk to u
@SayanChattopadhyay Hi. BUsy with math? Don't forget the girls too.
What??? I didn't understand
Girls what girls @ABeautifulMind
@robjohn Did work some more on the triple integral I said evaluated to $0$?
@Semiclassical Did you continue the work on the triple integral (the one in the first octant)? :-)
i'm waiting for the weekend right now
16:44
@Semiclassical Nice! :-)
@DanielFischer I see.. Thank you!!! :)
stuck right now thinking about how to dig out a nice approximation for a certain kind of contour integral
@DanielFischer (see above)
@Chris'ssis The one with $x,y,$ and $z$?
@Chris'ssis just to check---the triple integral case has four sinc functions, right (in the same way that the double integral had just three)
16:49
@Semiclassical I think that's the one
@robjohn Yes.
@Semiclassical Yes.
@EnjoysMath Open or not doesn't matter, for a finite union, you always have $$\overline{\bigcup A_i} = \bigcup \overline{A_i}.$$ A finite union of closed sets is closed, hence you have $\subset$, and each set on the right is a subset of the one on the left, hence $\supset$.
right. i still think that the same strategy that worked before is sensible, i.e. represent the sinc functions as fourier transforms and hope the integrals in $x,y,z$ are then simpler
@Semiclassical $$\int_0^{\infty} \int_0^{\infty} \int_0^{\infty} \frac{\sin(x)\sin(y) \sin(z) \sin(x+y+z)}{xy z(x+y+z)} \ dx \ dy \ dz $$
16:53
@Semiclassical You can't use the Fourier Transform trick since these are not full sinc functions
one can't use the convolution theorem, no
but one can still write each sinc function as an integral over some frequency $\nu_i$
A question....
which field of mathematics are modular forms?
and then try to evaluate the integrals over $x,y,z$. in the original case, those just simplify to delta functions, so you end up with a product of identical rectangle functions (if my quick mental review is right)
@SayanChattopadhyay It looks like complex analysis
that won't be true anymore, but one can still hope for something nice with the integrals
16:56
@SayanChattopadhyay if you had to call it part of something else, I'd say number theory. it also intersects with complex analysis and riemann surfaces. the more narrow topic of moonshine connects it with representation theory of sporadic simple groups too.
@SayanChattopadhyay number theory!
ah, anon beat me to it.
hi @anon.
hello balarka
any mods. in here?
robjohn is a mod
speaking of modular forms, i've heard people say modular forms can be visualized by looking at line bundles over modular surfaces. i've been dying to know what those are ever since i heard that.
16:59
that's also something I wanted to learn later
partially because i've never understood modular forms. huge formulas, ugh.
they're bundles of infinite sticks mon
morning, @anon
@robjohn: could i ask you a quick mod. related question regarding deletion of comments?

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