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15:06
@Integrator The serial voting reversal script does not catch everything. Sometimes the moderators or community managers see a longer term pattern that escapes the short term patterns noticed by the script. Obviously, it would take a lot of bounties to get 10K in a day, so this is not a case where the daily script has reversed the votes.
@Committingtoachallenge you mean $3.1\%$?
@robjohn How does one evaluate this integral: $$\int_{0}^{\pi/2}\; \frac{\sin(2\theta) \sin(\tan\theta)}{5 - 4\cos(\tan\theta)}\;d\theta=\frac{\pi\,e}{2(2e-1)^2}$$
Olivier Oloa lost 10,000 overnight? LOL.
@robjohn I may be wrong but...
<sup>thanks to venus</sup>
15:22
It's just a reversal of serial upvotes.
@BalarkaSen 10000 ? are you out of your mind?
@Integrator I'm not. Have a look at here
@Integrator No, but the upvoter is out of his mind.
@WillHunting I bet he lost in Vegas :D
What is serial upvoting
15:26
@user130018 A user voting up someones question/answers regardless of content
@Committingtoachallenge serially!
Anonymous
@Committingtoachallenge I am creating a blog
@Venus Something to try would be
$$
\begin{align}
\int_0^{\pi/2}\frac{\sin(2\theta)\sin(\tan(\theta))}{5-4\cos(\tan(\theta))}\,\mathrm{d}\theta
&=\int_0^{\pi/2}\frac{2\tan(\theta)\cos^4(\theta)\sin(\tan(\theta))}{5-4\cos(\tan(\theta))}\,\mathrm{d}\tan(\theta)\\
&=\int_0^{\pi/2}\frac{2\tan(\theta)\sin(\tan(\theta))}{(5-4\cos(\tan(\theta)))(1+\tan^2(\theta))^2}\,\mathrm{d}\tan(\theta)\\
\end{align}
$$
@Ashwin Awesome, will you keep statistics ;)?
@user130018 It means X keeps upvoting Y a lot, either on the same day or over a long period of time. The former may be detected by the automatic script, but the latter can only be detected by a community manager.
Anonymous
15:26
@Committingtoachallenge yes sir
Anonymous
@Committingtoachallenge Oh I don't think I will keep the statistics,but I will write what I study each day
How did they find out this user got people to vote on their answers for 10,000 rep regardless of the content?
@WillHunting I'd like to see who was the upvoter!
@Ashwin What shall you call it?
@Integrator Only the community managers will know. It is top secret.
15:28
@Integrator It was probably multiple accounts
Anonymous
@Committingtoachallenge Statistics without numbers :D
@WillHunting The game is afoot!
@Ashwin So graphs with no labels :)
@Committingtoachallenge Script can't detect multiple account serial upvotes, AFAIK
@BalarkaSen It can, I will find a user in a sec
Anonymous
15:29
@Committingtoachallenge Details but no graph :)
@BalarkaSen But a wise programmer can write wise scripts!
@robjohn OK. I'll try.
Anonymous
@Committingtoachallenge Actually,I will give the data but won't plot a graph :D
@Ashwin Will you record pages a day, time spend studying?
@Committingtoachallenge Probably!
Anonymous
15:30
@Committingtoachallenge Yes I will
Greetings
Anonymous
@Committingtoachallenge Give me 5 minutes,I will be done with the blog thing
@Chris'ssis Greetings!
@Integrator Hi
$$\int_{0}^{\pi/2}\; \frac{\sin(2\theta) \sin(\tan\theta)}{5 - 4\cos(\tan\theta)}\;d\theta=\frac{\pi\,e}{2(2e-1)^2}$$ ?
@Venus it seems elementary to me.
Anonymous
15:31
@Chris'ssis Were you playing with integrals in your cradle?
He had series upvotes and downvotes of two accounts deleted simultaneously
@Chris'ssis This method works almost all the time!
@Committingtoachallenge But that is you identifying the upvoter/downvoter, not the scipt ;)
@BalarkaSen No the script did, it deleted xNova and another
Time to walk an anxious dog... BBL
15:32
I called him out on him losing -225 and -225
@Chris'ssis It seems difficult to me.
@Committingtoachallenge ah! i didn't know it could do that.
+ a one week ban
script can even ban/delete users?
@Chris'ssis I was suggesting $x=\tan(\theta)$
15:33
@BalarkaSen If it can't than it was an admin, but it happened within less than a minute of him starting to mass downvote
Script can even create users
Anonymous
@Committingtoachallenge I am done and I cannot post today's statistics because I never looked at my book :D
weird @Committing.
@Ashwin Haha what time is it there?
Anonymous
@Committingtoachallenge 9 PM
15:35
Would almost be time for me to wakeup if I was there(apparently :P)
@Venus make use of the elementary series, namely $$\sum_{n=1}^{\infty}\frac{\sin(n x)}{2^n}=\frac{2\sin(x)}{5-4\cos(x)}$$ that you combine with variable change $\tan(x) \mapsto x$ and then you're done in one line.
Anonymous
@Committingtoachallenge I will let you know the link,but not here.You know where to see :D
@robjohn Yeah, that is a good step.
@Ashwin Okay haha
@Ashwin Here it's 9:07 :P
Anonymous
15:37
@Integrator ?
@Ashwin ?
@Chris'ssis OK
@Ashwin You are not fully an autodidact, since you are doing Mech eng
Anonymous
@Committingtoachallenge But does that matter?
15:41
@BalarkaSen Yes they do. The map sending all circles but one to the basepoint and the identity map on that last circle is continuous (this is just by the definition of the wedge product!), and is a retract by definition.
@Ashwin What do you mean? I'm sick now, I don't play with anything (unfortunately).
Anonymous
@Chris'ssis It's obvious.You are good at what you are doing.
@Chris'ssis He means were you as a baby in your cradle, toying with integrals
@MikeMiller Hrm. I was confusing with homotopies. Hrm.
You're on the right track, @Balarka. You've got part of the right argument written down, but more needs to be done.
15:43
@Committingtoachallenge @Ashwin hehe, not really. This stuff is not hard at all. I only succeed because it's easy.
Well I am going to have a 1:45am coffee and get to work
Anonymous
@Chris'ssis You make me feel I am dumb.By the way,are you enrolled in a university course or something?
She is a 25 year old accountant with no Math uni
@Ashwin No, wait, you don't need to feel like that. I have no background in math, I'm self-educated, especially by personal research.
Anonymous
15:46
@Chris'ssis How old are you now then?
@Ashwin 30 $\pm$ something.
hi @Committingtoachallenge @Chris'ssis @Mike
@TedShifrin Hi
meh. @Ted's still ignoring me.
After retiring will you still come by here @Ted?
Anonymous
15:47
@Chris'ssis How good are you at other ares of Mathematics?
LOL, we'll have to see, @Committing
Hi @Ted
@TedShifrin You'll miss us ;)
Uh huh, like my students'll miss me.
Got my TA assignment... lower-division linear algebra
15:48
I thought you told me it was upper-level, @Mike
@Ashwin In the last period of time I didn't focus on other math areas, but I strongly believe I have the potential to do well in many areas.
They probably will, I miss some of my lecturers, even some I seldom talked to.
Anonymous
@Chris'ssis I am $100 \pm something$
@MiieMiller some kind of division algebra? I'm in!
@TedShifrin I was expecting that, but I didn't have the assignment yet.
15:48
@Ashwin I'm $18\pm\sqrt{2}$
@Ashwin OK
Anonymous
@Chris'ssis You cannot say you have the potential in something unless you try it
(I asked the professor to request me as the TA for linear algebra. It turns out they were teaching both upper and lower division... and requested me for lower division. Oops!)
I'll be back later ($2hr \pm 1hr$)
No complaints; it's at 1PM.
Anonymous
15:49
$ \pm OK$
Ah ... guess you screwed that up. They probably want you to get more teaching experience first, anyhow.
Probably.
@Ashwin So far I succeeded in all areas I wanted to succeed. But, yeah, you might be right.
Anonymous
@Chris'ssis So you should try other areas
Well, @Mike, my probability class is remarkably consistent :( Average was 68 (one good student still to take the test on Monday). Previous averages 65, 68.
15:50
@Ashwin I'm only attracted to integrals, series and limits now. When you combine the extremely hard work with the crazy passion then you may excel in everything. This is my belief.
Have fun, @Committing
@TedShifrin Yeesh...
Anonymous
@Chris'ssis I remember Terry saying this when he was asked whether the math was invented or discovered:"Mathematics is discovered but the tools that we use to explore it are very much invented
One really smart guy who's had mental problems has bailed (sigh) ... so an A student will get an F. Current thinking is 6 Ds and Fs out of 33, but several of the Fs have punted.
@TedShifrin What do you mean by bailed?
Anonymous
15:52
@Chris'ssis I strongly believe that you are lurking very much in the inventing side
Oh, I lied, it's out of 29, and 3 of those are basically no-shows.
He just quit coming to class, doing work. I kept checking on him for the first half of the semester, but then he just disappeared. There's only so much I can do :(
@Ashwin yeah, I like to create things very much, to discover tools! I'm about to publish some articles on this side. Some might be already published, but I need to check that.
@TedShifrin Well, mental problems can get very bad. =( Just look at John Nash, and that Jasper Loy.
@Will Names starting with a J
Anonymous
@Chris'ssis That's a great news
15:55
Yeah, I am not unfamiliar with this phenomenon. I have another student in my other class who's also just quit/given up, even though it was supposed to be a straightforward class for him.
I'm sorry to hear that.
Basically, math is not a good major/career choice for people battling depression. Math is just too mentally taxing in the best of circumstances. I know @Jasper doesn't want to hear this ... but ...
@TedShifrin When I was in undergrad, I took MC on 2 exam days because I felt so bad.
what's MC ?
@TedShifrin I will get completely well in a year from now.
15:57
We all hope so, @Jasper.
@TedShifrin Medical Certificate.
well, @Chris'ssis, I am familiar with that phenomenon, too, but you were not in a totally dysfunctional depression, then.
@TedShifrin True, it depends on the level of the depression.
@TedShifrin Next year besides solving my mental problems and studying math, I will also email my prime minister to ask for some laws to be changed. I hope I don't get into trouble talking about controversial issues.
I'm not sure email is the best way to do that. I think a typed letter would be better.
Anonymous
15:59
@TedShifrin Even I was in a depression state yesterday,due to which @WillHunting isn't speaking to me
@WillHunting Do you wanna change laws? Then you should be part of your government stuff. :-)
I'm sorry to hear that, @Ashwin.
@TedShifrin I might make an appointment to see them in person too.
I never had depressions.
Anonymous
Lil' Kid lol
15:59
When you say your prime minister, you mean a local politician, or the prime minister of the whole country?
@Chris'ssis Yes. Even though I intend to leave this country, I want to do something for the people before leaving.
@TedShifrin The whole country. But I might see another minister for that. I have not decided.
@WillHunting Do those people want you to do something for them?
@Chris'ssis I do not know. But it is my moral responsibility to try.
You should start small, @Jasper. Contact your local representation. The prime minister will not see you.
@Ashwin Well depression is not quite a good thing to be proud about.
Anonymous
16:02
@BalarkaSen I don't think I am
So why lol at being a kid and having no depressions? :P
Anonymous
@BalarkaSen (I am depressed about the fact that (I am depressed about the fact that(I am depressed about the fact that I am depressed!)))
@WillHunting You should make an appointment with his father first before meeting his son. I hear he is the most powerful person in Singapore
Anonymous
@BalarkaSen And I won't be depressed again
@Ted Good morning! I think I'm starting to get the hang of Taylor series :)
16:06
@teadawg1337 Do you know how to reverse them too?
heya @Teadawg ... cool ... they're quite fun once you get the hang
They're fun stuff @teadawg1337
I hope people don't go around saying they have depression or OCD when they are just a little upset or a little obsessed and have not even gotten formally diagnosed.
Anonymous
He is speaking about me here
@Mats Is that where you take a Taylor series and swap $(x-a)$ with $a$ and vice versa?
16:10
@teadawg1337 Could be, I don't know how to do it the conventional way.
So what did you mean by your comment, @Mats?
Hello!!!

Let $E \subset \mathbb{R}^d$ Lebesgue measurable and $\phi (t)=m \left ( \Pi_{i=1}^{d} (-\infty , t_i ) \cap E \right )$. To show that $\phi$ is Lipscitz, can we do it as followed??

Let $x>y$.

$$|\phi(x) - \phi(y)|=|m \left ( \Pi_{i=1}^{d} (-\infty , x_i ) \cap E \right )-m \left ( \Pi_{i=1}^{d} (-\infty , y_i ) \cap E \right )|=|m \left [ \left ( \Pi_{i=1}^{d} (-\infty , x_i ) \cap E \right ) \setminus \left ( (-\infty , y_i ) \cap E \right ) \right ]| \leq m \left ( \Pi_{i=1}^{d} [y_{i}, x_{i} ] \right )=\Pi_{i=1}^{d} [y_{i}, x_{i}]$$
I think I see what's happening in there @Mike. The fundamental group $\pi_1(\mathfrak{H})$ is $\prod \Bbb Z$, which is uncountable (direct product not direct sum) while the fundamental group of the countable boquet is the free group on countably many generators, in turn countable.
Now then I guess I have to verify why it's a direct product instead of a direct sum.
http://math.stackexchange.com/questions/584866/algorithm-for-reversion-of-power-series

...
@TedShifrin Lagrange Burmann inversion I presume.
Duh. I forgot that I was on ignore.
16:14
No, @Balarka, that's not the fundamental group of the Hawaiian earring. The fundamental group of the Hawaiian earring is complicated.
I mean what injects into it @Mike
I still don't know what reverse function means, @Mats. It doesn't appear to be either the inverse function or the multiplicative inverse.
Not only $\bigoplus \Bbb Z$ but also $\prod \Bbb Z$ injects onto it, that's what I have to prove.
@Balarka To clarify, you mean injects as a set? Because I highly doubt there is a group injection.
@Mats: The fact that no one has addressed your question indicates you should define your terms in the question :P
16:15
As set, yes.
@TedShifrin I mean functional inverse, not the reciprocal of the function.
Oh, you do mean inverse function.
Actually I think there is a group injection though @Mike
I really doubt it.
And I don't. I am pretty sure about it.
OK, want to bet?
$\prod \Bbb Z$ sits inside $\pi_1(\mathfrak{H})$ as a group.
@MikeMiller Sure. 5$.
@Venus This version might be interesting too $$\int_1^{\infty}\left(\frac{\{x\}-\frac{1}{2}}{x}\right)^2\ \mathrm dx$$
So you want to solve recursively for $b_n$ so that composing $g(z)=\sum b_nz^n$ with $f(z)=\sum a_nz^n$ we get $g(f(z)) = z$.
LAGRANGE BURMANN
Hell he can't hear me.
16:18
@Mike: You're corrupting minors with bets.
You can't get money to me. I was rather going for, if you're wrong, I ignore you for a week. If you're right, I plead with Ted to unignore you until he does (or until he ignores me too.)
gets ready to ignore @Mike
LOL
@MikeMiller OK. I'm in.
@Ted Yes, I love to ignore minors. Anyway, he's wrong, so no need to ignore me. :)
@Balarka OK.
I thought it was only cofactors you ignored, @Mike :)
16:22
My phone corrected that from corrupt... but I do both.
@MikeMiller Well consider the natural retractions $r_n : \mathfrak{H} \to \Gamma_n$ for all $n$s. Then consider the map $f : \pi_1(\mathfrak{H}) \to \prod \Bbb Z$ as $[\gamma] \mapsto (\pi_1(r_1)([\gamma]), \pi_1(r_2)([\gamma]), \cdots)$. This is clearly a homomorphism, as the maps $\pi_1(r_n)$ are.
hey professor!
heya @beginner
So proving surjection also gives us a surjective homomorphism @MikeMiller which proves embedding.
@TedShifrin i learnt dim today and now my brother has sent me a list of exercises to do
16:26
What dim, @beginner?
Very good, @beginner. It's a powerful notion. You can find lots of exercises in books :P
Is your brother a math student?
Dimensions as vector spaces?
@TedShifrin yeah this one is doing university mathematics, another is done chem and another is just working
"...which proves embedding." As sets, yes.
@MikeMiller but surjective homomorphisms!
16:28
What?
the homomorphisms are clear.
@BalarkaSen yeah for finite dimensional vector spaces i learnt heaps of stuff, but i dont know much about infinite dimensional, i think i learn that in functional analysis later
Does anyone know hat $f \circ g$ means if $f$ and $g$ are functions? ;-;
it means g(f(x))
yuck functional analysis.
16:28
if you have $(f \circ g)(x)$
You know very well that just because $A \to B$ is a surjective homomorphism of groups does not imply that $B$ injects into $A$.
No need to fuss with infinite-dimensional yet, @beginner. Not with your name.
You have that backwards, @beginner.
@MikeMiller eh? aw hell. you're right.
sorry i mean $(f\circ g)(x)=f(g(x))$
It means $f(g(x))$.
16:29
yeah well obviously i was wrong
Hmm, @Mike, it would seem your're safe for the moment from being ignored.
@Balarka You also need to show that the map is surjective, and I need to prove that your guess is actually wrong.
@TedShifrin hehe woops i read a book that did xfg and it confused me. yeah i will learn functional analysis stuff after i finish linear algebra i think
I would suggest you save functional analysis until after you've done a good job of learning calculus and finite-dimensional analysis :)
@TedShifrin oh okay hehe, woops, balarka says i am over enthusiastic
16:31
Crazy algebra loony-birds sometimes like to write functions backwards, @beginner. You should avoid them like the plague :P
@MikeMiller Don't. I will take it as an exercise to fund the fundamental group of H.
If Balarka calls you over-enthusiastic, it's the pot calling the kettle. So you should actually calm down :)
@Ted He's 11, to put Balarka's comment in perspective.
I know, @Mike, I know.
@Balarka It wasn't found until 1986
16:32
Heya @robjohn
@TedShifrin but which is backwards? the normal one g(f(x)) you do right to left which is weird, and the 'weird' one xfg does left to right
@TedShifrin How is Saturday treating you?
Writing functions on the right of $x$ is hardly ever seen, @beginner. There's an abstract algebra book that was revered decades ago that did that.
ok, i'll avoid it like the plague :)
Finished grading my probability exams, @robjohn. Now I have letters of recommendation for 10 students for grad school and two finals to write. :) How're you?
16:33
@MikeMiller Who's 11?
Beginner.
Oh, @robjohn, and I've already finished writing 3 other letters, submitted them electronically all over the place.
@TedShifrin Pretty good. I have to go to a board meeting and then come back to a cleaning of the house after that.
@all thanks so much!
Board meeting on Saturday, @robjohn?
Sorry if we confused you, @Conor :) Be well.
16:34
@Ted thanks! You, too!
I dunno @Mike. It's a continuum, so I feel it has a near relationship with my solenoid. :P
I hope that's a joke. Anyway, I trust you'll let me know if you made any progress when I see you in a week.
C'mon Mike.
Just before you ignore me @Mike. Can I ask you something?
@robjohn my comment was deleted from some post, is it indication that my account might get suspended?
16:39
I don't get why they're defining a whole bunch of abstract simplicial complexes to study the Cech fundamental group. I have a different idea in mind, not sure if it works.
Take a connected space $X$.
$\mathcal{O}$ be the chosen open cover of $X$, replacing the base point by the choice of the cover.
balarka gets ignored alot
LOL @beginner
I don't know anything about the Cech fundamental group. But go on.
@BalarkaSen what is a prat?
This time it's because you lost a bet, @Balarka :P
16:41
I figured you were from Britain, @beginner, and I thought "prat" was British slang. So I'm confuzled.
@Integrator No. Comments get deleted all the time. If it was flagged by enough people, something might happen. Was the comment offensive or spam?
i can't say where i am from, but i have not heard prat before
@MikeMiller Now call $\{\mathcal{O}_1, \mathcal{O}_2, \cdots, \mathcal{O}_n\}$ a loop if $\mathcal{O}_i \cup \mathcal{O}_{i+1}$ is nonnull, with modulo $n$ indices.
You're not even supposed to be here in the first place, @beginner ! :D
@Chris'ssis when I see that, I think $-\frac12\mathrm{d}\log(5-4\cos(x))$
16:42
@robjohn No! Thanks!
i am 13 born on 12 may 2001
so i am allowed to be here :)
@Integrator Then you shouldn't have anything to worry about.
@robjohn Thank god!
Oh, I thought your mum had told you not to be here, @beginner :D
Actually @MikeMiller. You need a choice of basepoint too.
16:44
@TedShifrin :)
@beginner OMG!! I feel old... there are people here who have not lived in the 20th century!
ADG
ADG
hi everyone
@robjohn That was the first idea that came to mind when I saw the question (I mean in the first 5 seconds). It might be approached in more ways, but that way is an elegant way.
@robjohn: I was almost born before the midpoint of the 20th century, so hush up :D
@robjohn i wish i had that would be cool hehe
16:44
What do you mean by non-null? Not contractible?
@TedShifrin I was born when there were 49 states.
Call $\{\mathcal{O}_1, \mathcal{O}_2, \cdots, \mathcal{O}_n\}$ a loop based at $x_0$ if $x_0 \in \mathcal{O}_1$ and $\text{bd}\, \mathcal{O}_i \cup \text{bd} \,\mathcal{O}_{i+1} \neq \emptyset$
Surely it was 48 for me ... looks it up
@MikeMiller Ah typo. Good catch.
What is the boundary of an open set? Are we doing point-set topology? grumbles
16:46
Wow, @robjohn, I'd forgotten ... So you're between Jan 3 and Aug 21, 1959.
@TedShifrin Yep
@robjohn did you see this one? I posted it above. $$\int_1^{\infty}\left(\frac{\{x\}-\frac{1}{2}}{x}\right)^2\ \mathrm dx$$
That means, instead of a loop, you set up a bunch of open sets which open covers the loop.
So you're almost surely almost 6 years younger than I, @robjohn :P
@MikeMiller Yes, the boundary in point set topology.
16:47
@Chris'ssis No, but I'd attack it the same as the one without the square
@Chris'ssis That one at least converges absolutely
@robjohn I see.
@Chris'ssis That is on main (without the square)
$\text{bd} \, A$ is the set in $X$ consisting of points where each open nbhd around it intersects both $A$ and $A'$.
@robjohn @DanielF: One of my probability students made me work hard to understand why his intuition that if $X_n$ all have mean $\mu$ and $\text{Var}(X_n) \to 0$, then it needn't be the case that $P(\lim X_n = \mu) = 1$. (He thought he had an easy proof of the Law of Large Numbers.)
@robjohn Yeah, it's based upon the one on main.
16:48
@Balarka The boundary of an open set is only empty if it's closed. Your definition is wacky.
@Chris'ssis did you have a different approach?
I don't like your antecedents, @Mike.
@MikeMiller forget about the definition, i need to translate everything from my metric space language to usual topological space language. just tell me if the definition of loops work
@Ted I'm barely capable of speaking English.
Then you merit ignoring, too, @Mike :)
16:49
Do it @Ted
Let us all ignore everyone.
not me balarka
you're underaged, @beginner. not taken into considerations.
that is actually a good thing here i guess :)
@robjohn I might have some, I need to check that if it works.
@Balarka I meant that your definition of loops doesn't make sense. You're calling a sequence of open sets a loop if $\partial(O_i) \neq \varnothing$. But this is only true if your open sets are closed.
16:50
but a bad thing normally
@MikeMiller wat.
As I told you the other day, @beginner, don't squander your youth. Once it's gone, you can't have it back.
@TedShifrin was it along the lines that a sequence can be square summable, but not summable?
Sorry. This is true precisely when they're not closed.
\delta O_i \cup \delta O_{i+1} is nonnull @Mike
16:51
No, @robjohn, it wasn't :)
Non-null meaning non-empty?
@TedShifrin but what is a good use of your youth, that i dont know. some say going and climbing mountains, others say good grades, others still say to make as many friends as possible
It was a discrete probability mass function with values $-1$, $0$, $1$ :)
yeah well @Mike. boundary nonemtpy doesn't mean they're closed, but rather the contrary
@MikeMiller yes
how about good grades with a group of nerdy friends while climbing mountains
16:52
get used to my stupid terminologies
@TedShifrin what was the approach? I'm curious.
My example, you mean?
@Balarka My point is that your definition automatically makes everything into a loop.
@Chris'ssis $$\bbox[8pt,border:3px #FF69B4 solid]{\color{red}{\large\ln\left(\,2 \pi\,\right)-\frac{7}{4}}}\tag{$\color{red}{❤}$}$$
ok. i don't see how @Mike.
16:53
@TedShifrin just don't lose it... I keep a tight hold on mine :-)
If I'm not mistaken @Chris'ssis
His intuition, of course, was that variance going to $0$ means that the distribution concentrates at the mean. But my example was $p_n(\pm 1) = 1/(2n)$, $p_n(0) = 1-1/n$. Then $X_n\to 0$ weakly but not strongly. :)
take $X$ and two totally far away open sets $O_1$ and $O_2$ inside open cover $O$. $\{O_1, O_2\}$ isn't a loop @Mike
@Venus I didn't compute it, I just asked it. Nice answer! :-) (I mean I can compute it easily, but I didn't work on it)
"far away" being "boundaries are disjoint"
16:54
My initial instinct, @robjohn, was that he was in essence thinking weak law, not strong law, so he was in his head interchanging $P$ and $\lim$.
You're going on ignore in five minutes, @BalarkaSen, so I don't need to get used to your terminology. OK, now I see the problem. You kept writing $\cup$ instead of $\cap$. :P
@TedShifrin That works, too. :-)
@beginner: I'm not criticizing, nor am I telling you how to live your life. Just don't feel compelled to be a college student before you're 16 :)
so the definition works @Mike?
16:56
oh i wont @ashwin showed me a post on arxviv(or whatever lol) that says that i would not realise what i miss in my other classes and it would hold me back one day
and my parents agree
i presume we can define some homotopy group outta this
@BalarkaSen It won't turn into a group; how could it?
@Chris'ssis If I can you must be too, but not vice-versa
I still take great pride in having been well-rounded as a high school and college student, @beginner.
@MikeMiller Well, you have da loop and you have da group. you loop de loop and group de loop to have da homotopy group!
16:57
I guess you need some notion of homotopy between your loops.
@Venus I think you overestimate me ... (that's it)
Some might argue that I'm an ill-rounded human being, but one can't be perfect :P
@MikeMiller Right, a sense of equivalence classes
@TedShifrin thats the plan, i really wanna hurry up and see if i like chemistry, biology and physics so i know where i want to go. but for now math is all i can do :)
But there's no obvious one. Anyway, good luck with your silly fundamental groups.
16:57
Well I'll think about it
See ya.
Don't forget language and literature, history, etc., @beginner. It's important, too.
hey it ain't silly @Mike
@TedShifrin oh yeah i forget those ones hehe
Well, @Mike, you should take advantage of your week of silence and ignore all of us and get work done.
Speaking of which, I have to have lunch, go shopping, and work on finals/letters.
16:58
@Chris'ssis Nah, comparing to my ability right now, maybe 5-6 years I can level you
cya later @Ted
Get to work on those letters... deadlines are coming up
see ya, @beginner.
ah well i have to go too
Some deadlines have already come and gone, @Mike.
16:59
I can't tell you how much it drove me crazy when one of my writers submitted the daybefore the deadline...
cya @balarka
Yeesh!
Well, when people don't ask me until a week before the deadline, I'm quite annoyed, @Mike. Students need to realize how busy some of us are ... and this is the greatest number of letters I've ever had to write in my entire career. ...

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