Mathematics - 2014-11-18 (page 1 of 4)

Rudy the Reindeer

00:00

Whenever I get a functional analysis upvote I think "Cool, soon I'll get a badge". But I already got one.

Daniel Fischer

@KarlKronenfeld Do you remember YACP? I think that's him.

Rudy the Reindeer

: (

evinda

@DanielFischer If $p(0,0) \neq 0$,it cannot be $(p^k)(0,0) = p(0,0)^k=0$. But how does this help?

Ted Shifrin

Yes, @Studentmath, we have the right answer.

skullpatrol

Hello professor @TedShifrin

Daniel Fischer

00:01

@evinda Which radical are you talking about? I assumed nilradical, $p \in \operatorname{Rad}(I) \iff \bigl(\exists n\bigr)\bigl(p^n \in I\bigr)$.

Ted Shifrin

@Hippa: Use the spectral theorem, of course.

Studentmath

:) I'm still stuck on the same thing I have been trying to prove for over a month.

Hippalectryon

@TedShifrin uh ? How ?

Ted Shifrin

Hi @skull

Karl Kronenfeld

@DanielFischer I haven't seen him do any algebraic geometry though. Turns out he has 16 answers on the subject; I am still unsure.

Studentmath

00:02

Well I managed to excel in the proof of the first part of it, got it really neat. I don't think I will ever manage the second part, though..

Mike Miller

It's even more annoying that the first thing he called wrong was actually correct and that it took him ten minutes to be right.

Daniel Fischer

@RudytheReindeer You're on your way to silver.

Hippalectryon

@TedShifrin The Spec Theorem just tells me that $A=PD^tP$

Ted Shifrin

Diagonalize, take the square root, undiagonalize.

Hippalectryon

GRR

ME STOOPID

@TedShifrin thanks :-)

Ted Shifrin

00:03

Je ne dis rien :)

Daniel Fischer

@KarlKronenfeld The username is YACP's old user id, and he referred to answers (and comments) of YACP a couple of times on meta.

Hippalectryon

Anyway I gtg to sleep a bit :) see you in your dreams

skullpatrol

Later pal

evinda

@DanielFischer I am using this definition:

$$Rad(I)=\{ a \in \mathbb{C}[x,y] | \exists n \in \mathbb{N} \text{ such that } a^n \in I \}$$

Karl Kronenfeld

@DanielFischer Ah, that makes it more convincing.

Hi @Ted

Ted Shifrin

00:05

@DanielF: I know not the drama of which you speak. Hi @Karl

evinda

@DanielFischer So, we are talking about the same definition... :)

Daniel Fischer

@evinda Okay, that's the nilradical all right. So we see that if $p\notin \langle x,y\rangle$, then $p^n \notin \langle x,y\rangle$ for all $n\in \mathbb{N}$, and hence a fortiori $p^n \notin \langle x^5,y^3\rangle$.

@TedShifrin Am I speaking of drama? Is this a dagger which I see before me?

evinda

@DanielFischer How do we see that if $p\notin \langle x,y\rangle$, then $p^n \notin \langle x,y\rangle$ for all $n\in \mathbb{N}$? :/

Studentmath

Anyhow, I am off, think I will let it be and move to regular works. G'night @Ted @Skull

skullpatrol

Bye my friend :)

Daniel Fischer

00:09

@evinda Because $q\in \langle x,y\rangle \iff q(0,0) = 0$.

user130018

Given the 9 field axioms, if it's not mentioned that for the identities $1$ and $0$ that $1 \neq 0$, is there a way to prove that $1 \neq 0$?

Ted Shifrin

night @Studentmath

Daniel Fischer

@user130018 No, $\{0\}$ satisfies everything except $1\neq 0$.

Mike Miller

So that example doesn't work, but I still don't see why the minimal primes should cover all of the zero divisors @Karl. You're claiming a reduced Noetherian ring has no embedded primes?

Karl Kronenfeld

@MikeMiller yes, the set of zero divisors is exactly the union of the minimal prime ideals for any Noetherian ring.

Mike Miller

00:15

I must have proved this before, then..

Karl Kronenfeld

So, you're having difficulty showing which inclusion?

Mike Miller

Everything's contained in a minimal one. Zorn's easily gives that every element is contained in some prime minimal with respect to containing it.

evinda

@DanielFischer So, we use the fact that: $q \notin <x,y> \text{ iff } q(0,0) \neq 0$ and we have the following:

We suppose that $p\notin \langle x,y\rangle$. Then, $p(0,0) \neq 0 \Rightarrow p^n(0,0) \neq 0 \Rightarrow p^n \notin <x,y> \Rightarrow p^n \notin <x^5,y^3> \Rightarrow p^n \notin I \Rightarrow <x,y> \notin Rad(I)$

So, we have proven that $p \notin \langle x,y\rangle \implies p \notin \operatorname{Rad}(I)$.

$\operatorname{Rad}(I) \subset \langle x,y\rangle$

Right? Or have I understood it wrong?

Daniel Fischer

@evinda In your third line, you have a nonsensical $\langle x,y\rangle \notin \operatorname{Rad}(I)$. If that is, as I suppose, just a typing slip, no problem. Everything else is right.

anon

yo @DanielFischer. I am reading about $\wp$ and you seem to have some familiarity.

Robert Cardona

00:33

Quick question about free product of groups. I am reading through some notes and came across this: $\langle a, b, c \, \vert \, a^3, b^2, c^2, aca^{-1}c^{-1} \rangle$. Is this isomorphic to this: $(\mathbb Z_3 \oplus \mathbb Z_2 ) * \mathbb Z_2$?

Mike Miller

Nevermind, @Karl.

anon

in a thread it was said $\wp$ has "order 2" meaning that the map $\wp:\Bbb C/\Lambda\to\widehat{\Bbb C}$ is $2$-to-$1$ if we count images with "multiplicity" (e.g. the value $f(a)$ has multiplicity $2$ if $f'(a)=0$, or equivalently $f(z)=(z-a)^2\times$ a function holomorphic at $a$). I have never heard "order" used this way (I've only seen it used for order of poles or roots). do you have a reference for this more general usage? @DanielFischer

also, I'd like to know why $\wp$ is order $2$, and $\wp$ is order $3$, and how to calculate this sort of thing in general (if there are any standard techniques or theorems). presumably this takes me into Riemann surface theory, so I may have to wait to learn about this.

evinda

@DanielFischer Thank you very much for your help!!!!!!!!!!!!!!!!! :)

Daniel Fischer

@anon Count the poles, that's usually the simplest way to determine the order.

Pedro Tamaroff

@anon Are you there?

anon

00:36

@DanielFischer so is there a theorem that says something along the lines of "if the number of poles is m, then it's m-to-1 everywhere counted with multiplicity"?

@PedroTamaroff no

@RobertCardona yes

Karl Kronenfeld

lol

Pedro Tamaroff

I've read this recently: if $f(z)=(z-a)^n g(z)$ with $g(a)\neq 0$, then locally (near $a$) $f(z)$ behaves like $z\to z^n$ near $0$. So each point that is not $a$ has fiber of cardinality $n$.

anon

@PedroTamaroff hmm, that's interesting. so if there is only one pole in the torus C/Lambda of order 2, then it would make sense it's 2-to-1 in a nbhd of that pole. not sure how to patch it up to the whole of the torus though.

Daniel Fischer

@anon $\mathbb{C}/\Lambda$ is a compact Riemann surface, so every non-constant meromorphic $f\colon \mathbb{C}/\Lambda \to \widehat{\mathbb{C}}$ is a (branched) covering, hence all fibres of regular values have the same cardinality, and if you count multiplicities, that also holds for the fibres of non-regular values.

anon

good, now I know what I need to go read

Mike Miller

00:40

it's a very nice riemann surface at that

my second favorite, even

2

Pedro Tamaroff

@MikeMiller DAWG

Daniel Fischer

@anon For rational functions, Ahlfors defines the order as the number of times each value is attained on page 31, for elliptic functions on page 271.

@anon Although, for elliptic functions, we have a more direct way, the argument principle. Just compute $$\frac{1}{2\pi i}\int_{\partial P}\frac{f'(z)}{f(z)-w}\,dz,$$ where $P$ is a period-parallelogram such that neither $w$ nor $\infty$ is attained on $\partial P$. Since $\frac{f'(z)}{f(z)-w}$ is elliptic, the integral is $0$.

And of course, by general theory, it's the number of times $w$ is attained in $P$ minus the number of times $\infty$ is attained in $P$.

anon

ah, the sides cancel out, yes

what's w?

Daniel Fischer

@anon Any complex value. Shows that all $w\in \mathbb{C}$ are attained the same number of times as $\infty$.

anon

ah

so number of zeros equals number of poles

Daniel Fischer

00:49

Yes. And number of zeros of $f-w$.

anon

that shows the cardinality of fibers are uniform, but how would that help us compute the # of poles (with multiplicity) if we don't already know the # of 0s?

or were we just computing the integral to do the first thing

Daniel Fischer

@anon Typically, you know the poles (if anything).

anon

ah, duh, I was mixing up zeros and poles

Daniel Fischer

The integral shows that the $n$ in "$f$ is $n$-to-one" is well-defined.

Pedro Tamaroff

@anon Or you were standing upside down.

BADUM TSS

skullpatrol

00:54

Aka on your head

Swapnil Tripathi

@anon a problem!

i need you to check a solution

actually

separability again

@PedroTamaroff ^^

field theory!

Pedro Tamaroff

@SwapnilTripathi Yes.

Swapnil Tripathi

I need to show that a separable extension of a separable extension is separable

Pedro Tamaroff

OK, where are you stuck?

Swapnil Tripathi

When the characteristic of base field is 0, i did that part.

when char = p. This is the part

where i get stuck.

anon

00:59

let's see, I remember thinking about separability over the summer

Mike Miller

sorry to hear that, @anon

anon

@SwapnilTripathi do you get to assume both are finite? I remember the infinite extension theory being daunting.

@MikeMiller heh

that joke has two meanings

Swapnil Tripathi

@anon: I don't know. That's the statement my teacher gave me. If it's that bad, i don't think we would be needing that

Mike Miller

I can't figure out the second meaning

Swapnil Tripathi

I guess I do. ;)

anon

01:04

@MikeMiller depends if you're talking about separability in math, or separating in romantic relationships

the latter being how a nonmathematician would read it

Mike Miller

ehhh

I think they'd raise an eyebrow at the word separability

but fair

Swapnil Tripathi

@anon I'll write what I've done.

wait a minute

skullpatrol

over 9,000 hours later...

Swapnil Tripathi

??

Was that for me?

skullpatrol

wait a "minute"?

Swapnil Tripathi

01:11

yes. I was writing the proof on a paper

*am

skullpatrol

icic

anon

@Swapnil try to prove a tower of simple separable extensions is separable

then see if you can use that as a lemma

Swapnil Tripathi

@anon

*Suppose, if possible, k(x) is not separable.

Jasper Loy

@Sarah I see you have not been coming to chat, no emails from you either, lol. Good luck.

@AlexanderGruber That pic looks stupid, lol.

Swapnil Tripathi

@skullpatrol 9,000 hours too soon? :P

Jasper Loy

01:21

@Alizter Not sleeping yet? I just woke up after sleeping 8 hours.

Alexander Gruber

You just don't understand my sense of humor, @Jasper. ;)

Swapnil Tripathi

hahaha. @JasperLoy

Mike Miller

I think the picture is very funny.

Jasper Loy

@AlexanderGruber I hate all things Chinese, like I said before. It's so sad to be born one this life.

Swapnil Tripathi

@anon Where art thou? I'm desperately waiting for your opinion on the proof.

skullpatrol

01:22

He's gone

Alexander Gruber

@JasperLoy Good thing I'm French :p

thanks @Mike.

Jasper Loy

OK, at least there are many Chinese math journals, lol.

Swapnil Tripathi

@skullpatrol: Does that to me all the time. :P

anon

@SwapnilTripathi just eyeballing it, what is ln f(x) in char p?

Jasper Loy

I think Chinese will become a major math language soon. It already is one of the options in some grad schools.

Alexander Gruber

01:24

I hope so

I'd never run out of letters to name things

Swapnil Tripathi

I don't know!! That's all that came to my mind when I saw f'h+fh'=0 @anon

Jasper Loy

I am not going to touch Chinese or Russian, hopefully. I only want the Latin script, lol.

Swapnil Tripathi

Haha. So it seems it is again a dead-end!

Jasper Loy

Anyone used Assimil here before to learn a language?

Alexander Gruber

@JasperLoy is that like duolingo for borgs?

Jasper Loy

01:26

@AlexanderGruber Duolingo is a computer program. Assimil is a real book with CDs, lol. I have been reading reviews of over 10 different lang programs the past few weeks, still deciding on the best for myself.

Swapnil Tripathi

@anon I think it will be all if we show the finite case. :D

Fargle

Hey, is there a good way to show that a ring is a PID in general?

anon

well, if it's noeth, show (a,b)=(c)

Mike Miller

show that it's a dimension 1 UFD?

Fargle

Not Noetherian.

Twink

01:30

Could someone please explain to me why equation (3) is true? :S

I don't understand :(

Pedro Tamaroff

@Fargle What is your ring?

Twink

D is domain and R is range

anon

@Fargle you mean you don't know a priori that it's noeth :-)

Mike Miller

anon got cutesy before me

Fargle

$\{\frac{a}{p^n}|a \in \Bbb Z\}$

p prime

Twink

01:31

Jasper Loy

@anon is actually a famous actor, lol.

Fargle

@anon And yeah, anon, you're right.

Mike Miller

localizations of PIDs are PIDs

Pedro Tamaroff

@Fargle That's a localization.

Mike Miller

NIC EJOB PEDRO

YA GOT IT

Jasper Loy

01:32

I prefer globalisation to localisation, makes the world better.

anon

if you say so...

Fargle

@PedroTamaroff Right, but I'd like to prove it directly. Do I just have to show that every ideal is principal manually, I guess?

anon

@Fargle hands-on approach: split into two cases: the ideal has elements with denominator exponent bounded, or not bounded

Swapnil Tripathi

@anon I think we could use f(x)h(x)=g(x^p) to get some contradiction!! I have that gut feeling.

anon

@Fargle yes

Mike Miller

01:34

@Fargle If you want to prove it directly, i.e. you're not willing to use any theorems... then yes, what else can you do?

Twink

:'(

skullpatrol

Hi pal

Swapnil Tripathi

@PedroTamaroff Please check my proof above and let me know if you can find a contradiction considering the statement f(x)h(x)=g(x^p) , please?

Jasper Loy

Hi @twink how is life?

Twink

hi pal

skullpatrol

01:37

:-)

Twink

@JasperLoy life sucks

Fargle

@MikeMiller Yeah. Ask a stupid question, I guess, haha.

Twink

Jasper Loy

@Twink If you wanna die, talk to me first.

Twink

Can someone please explain to me (3)?

lol I don't wanna die

I just want to know why (3) holds

skullpatrol

01:38

Have you been there @JasperLoy?

Alexander Gruber

@Twink that should be a song.

Jasper Loy

@skullpatrol I have wanted to die many times, lol.

It's sad what they did to Alan Turing.

Twink

@AlexanderGruber lol

@JasperLoy yes it's sad

Jasper Loy

@Twink Some naughty person, lol.

Swapnil Tripathi

@JasperLoy lol

Twink

01:43

I guess nobody wants to help me with my doubt :(

Jasper Loy

@SwapnilTripathi Are you from India?

Swapnil Tripathi

Yes. @JasperLoy

anon

→ 2 messages moved to Temp room

now they're (removed)

Twink

@anon can you please help me? :(

anon

dunno what D and R stand for

Twink

01:45

D is domain and R range

$\lambda \in \Bbb C$ is such that $\Im \lambda >0$

Jasper Loy

02:10

@alizter Are you sleeping?

Twink

02:40

@JasperLoy now I wanna die

:(

The Artist

02:58

@robjohn Ohhh most helpful , I see :) I changed the accepted answer to the most helpful :)

Fargle

06:00

When is a Frobenius endomorphism an automorphism? I see when it's injective, but not when it is surjective.

Hamed Gasemi

09:37

is there anyone here?

Swapnil Tripathi

@HamedGasemi yes

@DanielFischer can answer most of your doubts ;P

user2179021

10:01

hi

Partly Putrid Pile of Pus

10:32

can i just ask why this rafflearnold guy has 10000 downvotes? does anyone know?

also does he change name? i have seen other guys with 8000 downvotes and stuff that seem to disappear

Why has noone talked today, is the chat inactive?

per day 1.2k today 212

wut

Rudy the Reindeer

11:56

@DanielFischer That won't be for another while...

Unless people start asking more FA questions.

Daniel Fischer

It may take a bit, but it will happen.

Rudy the Reindeer

It seems too far in the future, I think you cannot be so sure.

I was going to comment something on the question you just answered about huge font but then I couldn't think of something appropriate so I decided not to.

sdf

Anyone who can tell me what this terminology means: G is an abelian group of type (4,2,2)? What does the "of type (4,2,2)" mean?

Daniel Fischer

If one knows how, one can scale the images a bit down so that they have more fitting size. But I don't remember how, @RudytheReindeer.

UserX

I got a chemistry problem that I'm stuck but I don't think it's chemistry.SE worth. Can someone help me here?

Studentmath

12:38

Okay. Wolfram makes no sense.

I am pretty sure wolframalpha.com/input/… goes to 0, if not to positive infinity.

The latter term is obviously smaller than the first term.

Daniel Fischer

@Studentmath Since in the latter term you have a smaller denominator, it is not obvious. Apparently, it is larger.

user2179021

12:57

hi

dorothy

hello

skullpatrol

hi

robjohn

good morning

dorothy

hi @robjohn

is now a good time to discuss by the probabilities we were talking about are not always monotonic?

robjohn

@dorothy since the conditions on which they are based are monotonic, the probabilities should be monotonic. My guess is that the variance for large numbers makes it easy for the results to become skewed.

dorothy

13:15

I am not sure I follow your reasoning... sorry. We are asking P(A_i| A_j = 0 for all j < i). So it is quite possible that if two previous A_i's are 0 then the next one is unlikely to be 0 but if three previous A_i's are zero then the next one is very likely to be zero isn't it?

and vice versa

what is the condition that you are saying is monotonic?

and when you say variance are you talking about random sampling? My results are from exhaustive enumeration

n =4 is the simplest case that shows the non-monotonicity

The Substitute

hi. I have a question regarding "almost everywhere." If it is not the case that property $P$ holds a.e., can I conclude that $P$ fails on a set of positive measure (hence a measurable set) or can I simply conclude that $P$ fails on a set with interior measure greater than $0$ (which need not be measurable)?

nullgeppetto

Hello everyone! Not supposed to spam you, but I am looking for an efficient way of computing a certain product of $3$ matrices as stated here. Thank you very much for your consideration!

robjohn

@dorothy You're asking that given the $n$ previous dot products are $0$, what is the probability that the next dot product is $0$, right?

dorothy

@robjohn yes.. but not n as that is the length of the vector

@robjohn so given the $i$ previous dot products are $0$, what is the prob that the next dot product is $0$?

robjohn

yes

dorothy

13:19

if $i=n$ then the answer is 1

robjohn

@dorothy if $i=n-1$, then the answer is $1$

dorothy

I am not sure that is right

the first dot product is with the unrotated vector

oh..oops

my mistake

you are right.. n-1

Studentmath

@Daniel ach so..

dorothy

@robjohn actually.. take n = 1011. n =4 . Now consider the inner products with 1011, 1101, 1110. Why does this imply the inner product with 0111 is zero?

@robjohn this isn't the important question in any case :)

Rafflesia arnoldii

One more T.M. Sow clone here: DV & CV, if you don't mind.

2

robjohn

13:30

@dorothy Assuming 0=-1 in the sum, the transitions are 1001, 1100, 0110. This means that the elements of the original vector must be 0101 or 1010.

Jasper Loy

@robjohn You are up early, lol.

robjohn

@dorothy so it seems that there is no vector whose inner product with all three of those is 0

dorothy

@robjohn ah yes.. my example was bad. (And 0 = -1, sorry about that)

robjohn

@dorothy no problem... I've been using binary, but I use 0=1 and 1=-1 so that xor works

I have to go afk for a bit bbl

skullpatrol

later

dorothy

13:36

@robjohn bye

robjohn

back

user2179021

hi

dorothy

hi

Swapnil Tripathi

13:54

Any one interested in a problem on perfect fields?

Jasper Loy

Nothing is perfect, except imperfection.

Swapnil Tripathi

@JasperLoy: woh! That was a bit too much philosophical.

:P

Jasper Loy

@SwapnilTripathi Well, you just need to get used to me, lol. I am in this world, but I am not of this world, lol.

Swapnil Tripathi

@JasperLoy Coming here daily would do the trick!

Link

14:19

Could someone clarify what they mean by here? 'The derivative of a 3-by-3 determinant is the sum of three 3-by-3 determinants obtained by differentiating the ﬁrst,second,and third rows,respectively.'

Swapnil Tripathi

A={a,b,c}{d,e,f}{g,h,i}. Then A'=det({a',b',c'){d,e,f}{g,h,i})+det({a,b,c){d',e',f'}{g,h,i})+det({a,b,c){d,e,f‌}{g',h',i'})

@link

Link

Ah! @SwapnilTripathi Thank you.

Swapnil Tripathi

@Link you're welcome! :)

Sawarnik

14:37

Hi @Swap !

Integrator

??

Sawarnik

?

Swapnil Tripathi

@Sawarnik Hi,

How have you been?

Sawarnik

Fine :)

@SwapnilTripathi What are you drinking in your avatar?

Swapnil Tripathi

It sure gave me wings. ;)

@Sawarnik

Sawarnik

14:39

@SwapnilTripathi Oh :D :D

Integrator

@SwapnilTripathi Try to press Shift + $\uparrow$

Swapnil Tripathi

So it went to my latest comment, i guess?

Integrator

@SwapnilTripathi So??

N3buchadnezzar

@Integrator Be ashamed math.stackexchange.com/questions/1016491/find-the-value-of-ab

Integrator

@N3buchadnezzar Is there any way to delete that post!

Sawarnik

14:42

@Integrator Ask a mod.

Integrator

@Sawarnik I tried to ask robjohn, He said you should ask OP to UN-accept it and wait!

Sawarnik

Probably you meant unaccept?

Integrator

@Sawarnik oops, Edited!

Sawarnik

Yeah, so then you must write a comment to the OP.

And sadly, wait.

Integrator

@Sawarnik I did!

Swapnil Tripathi

14:45

Bye all, off to dinner!

Integrator

@N3buchadnezzar What should I do?

@SwapnilTripathi Bye, Save me some!

N3buchadnezzar

@Integrator Dunnp

Swapnil Tripathi

And @Integrator, I don't know what happened. I edited my latest post?

Integrator

@N3buchadnezzar Dunnp??

Sawarnik

@SwapnilTripathi Bye! :)

Too early though :/

N3buchadnezzar

14:47

@Integrator Dunno

Sawarnik

Don't know.

Swapnil Tripathi

Hostel timings. Can't complaint! :D @Sawarnik

μακακας

Hey I am kinda stuck with the local truncation error, it is very trivial but I am just looking for a name for the method used

anyone familiar?

Sawarnik

@SwapnilTripathi Oh sure :P

N3buchadnezzar

@Integrator About that problem, I wrote up the log sums, but had problems evaluating them

μακακας

14:49

I have (Yk-Yk-2)/dt expanded as 2yk' etc etc

is this a taylor expansion?

Sawarnik

@μακακας Is there any way to ping you without the hard way?

μακακας

I see the chat all the time no worries

I probably should change my name in the future

@Sawarnik You are familiar with the local truncation error?

@Sawarnik I have the above term which is then expanded as a taylor polynomial but one of the coefficients makes no sense whatsoever

Sawarnik

@μακακας Not at all, sorry :(

@μακακας :D

N3buchadnezzar

@Integrator I got the following

$$ \frac{f(n)}{f(r)f(n-r)} = \exp\left( \sum_{k=r+1}^n k \log k - \sum_{k=1}^{n-r} k \log k \right) $$

Balarka Sen

15:13

@PedroTamaroff Nope. Prof's teaching basics of algebraic topology. But I don't like it.

It's full of computations.

Integrator

@N3buchadnezzar What about modulus ?

Sawarnik

Hamis.

N3buchadnezzar

@Integrator you just take the modulus of the expression abouve?

Balarka Sen

15:30

@Pedro If you are willing to restate the point-set topology problem you posed like a month ago, I am willing to try it.

UserX

@μακακας your name can be considered offensive

μακακας

@UserX not at all

UserX

I know it's a kind of chimpanzees but we both know it's a childish way to swear in Greek.

μακακας

@UserX lol nice. Mind if you help me with Numerical Analysis :)

UserX

@μακακας if I could I would.

Anyway bbl got class

skullpatrol

15:36

later pal

Balarka Sen

@UserX i read it as MAKAKAC

that's not at all offensive, no.

Integrator

@N3buchadnezzar oops, I meant Modulo

μακακας

lol I really don't care about my name I need help with numerical analysis please :/

N3buchadnezzar

$$ \int \frac{5 \cos x \ \mathrm{d}x}{\sqrt{\sin \,x} - 3 \sqrt{ \sqrt{\sin x \, } + 4\,} \,} $$

μακακας

local truncation error

N3buchadnezzar

15:40

@Integrator Yeah so ?

Integrator

@N3buchadnezzar Why did you say 'Be ashamed'?

N3buchadnezzar

:p

Integrator

@N3buchadnezzar I thought you said so, because I've posted almost almost un-implementable method to a programming related question.

N3buchadnezzar

@Integrator Yeah. I saw that when I tried to take the modulo

Integrator

@N3buchadnezzar But did you noticed OP's behaviour?

Balarka Sen

15:56

@Mike testing if I am on ignore

N3buchadnezzar

def fun( n ):
P = 1
for i in range(1,n+1):
P = P*i^i
return P

print(fun(3))

Where is my mistake ?

Transcript for

$Mathematics$ Mathematics