@r9m in your general formula the powers in your second bracket goes as n-1 , n-2 , n-3 after each term.....but look at how you did to z^6-1 , the power goes as 4,2, which is n-2 , n-4
on page 13 of the paper here there is a proof in theorem 4 that all eigenvalues of this tridiagonal matrix, which has strictly positive entries down the subdiagonals, are simple. Unfortunately, I don't get the argument. Apparently, it is almost immediate to the editor that $ker(J-\lambda I)$ must...
I can't find any question about coupon's collector problem
but without replacement.
Or perhaps I'm over complicating and I just need to use the hypergeometric distribution? My problem is something like: There are N balls. K of them are white. I draw until all white are drawn. What's the expected number of draws?
Experimentally I discovered the limit below that says that
$$\lim_{n\to\infty} \int_0^{\pi/2} \frac{1}{\displaystyle \cos\left(\frac{x}{2}\right)\left(\cos\left(\frac{x}{2}\right)-\cos\left(\frac{x}{2^2}\right)\right)\cdots \left(\cos\left(\frac{x}{2}\right)-\cos\left(\frac{x}{2^{2n+1}}\right)\r...
Guys, by the previous question of mine, the penultimate one, we've possibly found another amazing way of computing $$\lim_{n\to \infty} \frac{1}{(4n+1)^{2n}}\prod_{k=0}^{n-1}\frac{(4k+3)^{4k+3}}{(4k+1)^{4k+1}}=e^{2 K/\pi-1/2}$$ Isn't really this amazing?
@Sawarnik heck, had I started programming at 13 (like you started math on here) instead of 17 I would be much better than I am now xD be glad you have a good start
@Chris'ssis the $\log \log$ integral (one which felixmarin and robjohn answered) seems to be related to Randemacher's formula :O .. I'm trying to find an online reference :-)
@Chris'ssis no no no closed form .. the series seems to be related to it (can also be derived from) .. wait I'm looking for an online reference (if I don't find one .. I'll type out the whole thing .. I read it from Apostol's ANT book)
@UserX ask Adamchik .. he seems to be at the root of this conspiracy :P
@MarcGato interesting question there :) .. how would you find the radius of the circle circumscribing a regular n-gon in terms of the incircle (circle inscribed in the n-gon) ?
ah .. someone already answered the :P fast guns all around ! :D
what is the solution of this integral:$$\int^1_0 \frac{-2(t+a)+(1-a)}{((t+a)^2+(1-a)^2)^2} dt$$
canyou help me? that is a part solultion of a question which I should to solve it!
There is a very interesting puzzle for fibonacci sequence
You are climbing a stair case. It takes n steps to reach to the top. Each time you can either climb 1 or 2 steps. In how many distinct ways can you climb to the top?
The answer is fibonacci sequence: F(n) = F(n-1) + F(n-2). The explanat...
By the way, did you guys read a LaTeX book somewhere or something to type answers? I just read that brief guide and watched other people's codes, should I do something more for my typesetting?
Experimentally I discovered the limit below that says that
$$\lim_{n\to\infty} \int_0^{\pi/2} \frac{1}{\displaystyle \cos\left(\frac{x}{2}\right)\left(\cos\left(\frac{x}{2}\right)-\cos\left(\frac{x}{2^2}\right)\right)\cdots \left(\cos\left(\frac{x}{2}\right)-\cos\left(\frac{x}{2^{2n+1}}\right)\r...
@robjohn I think I found some (some additional work is required). The problem is that now I try to take an English lesson, I wanna improve my English, so I'll postpone the work on it for some minutes.
@Chris'ssis Other than what I posted above and writing the difference of cosines as the product of sines, I have not come up with anything else promising.
the quote just emphasizes the fact that it's harder and more time-taking to writing up what you want to tell concisely than writing it up the way you find natural
@Semiclassical The problem with the literature is that you never know what the author had in mind when he wrote what he wrote. I almost always quarreled with my professor about that. Who knows what the author had really in mind?
@MikeMiller yes. actually my prof (you can google him up, name's mahan mitra, now a monk =P) is a big fan of gromov. i never actually asked him whether he actually ever met that guy but i should now that i mention it.
in fact he is sold on hyperbolic geometry actually.