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20:16
I have a terrible headache.
@JasperLoy Have you tried decapitation ?
I'm sure you won't feel the headache anymore
:P
@TheGame What did you eat today? =)
@JasperLoy Nothing special
I miss Sarah...
@TheGame Have you finally watched The Covenant? LOL.
@JasperLoy No, it looks awful
20:20
@TheGame I think you should try inverting my logo instead of Chris's Sis's.
Nuuu
@TheGame If you inverted my avatar it would look awful
@JasperLoy sarah was seen 3 mins ago
@Alizter So you got a copy of Hardy and Wright?
I don't like reading old-fashioned books.
20:25
@JasperLoy its a new edition
edited by andrew wiles
whole section of elliptic curves written by him
You should look at Baker's Comprehensive Course in Number Theory. He is a Fields medallist too.
Good evening (London) everyone, Random question which I felt shy to ask on meta..but what does a +1 and a "removed" message on an answer I posted a while back mean?
user image
4
@ArthurFischer has a nice comment
Silly audit
@Chinny84 I don't know what you mean.
20:26
@MarcGato You're not off.
@TheGame Must be your voice.
@TheGame I am not laughing but my ears hurt.
Nooo >:c @JasperLoy
@Alizter She posted an answer, I should log in to upvote her.
20:28
Come on guys, let's get one answer for every letter in the alphabet: math.stackexchange.com/questions/975496/sigma-notation-help
4
@JasperLoy Let's do it together :P
Lol @Arkamis
@Arkamis may we use the greek alphabet?
@IceBoy Only if we have enough accounts!
I can no longer stand living in my country. I need to try to get out asap... They have already driven me mad.
20:31
@Arkamis long time no see pal (skullpatrol here :-)
Skully!
@JasperLoy basically I only thought the rep score for answers were +10 or -2 but I had a score of +1? But not to worry I was looking for a quick answer :).
@PedroTamaroff I don't understand what you mean
@Arkamis 0-5
I know. It's rough
November's schedule is Seattle, Denver, SD, KC
@Alizter She only logged in to answer, not to come to chat, lol.
Oof.
We get to play the Jets tomorrow night :D
icic
Hi @sarah, lol.
20:35
lol @JasperLoy I emailed her
Wow, you guys could legit be 0-9 by the end of the month
Just upvoted your answer @sarah, lol.
Bored anyway at the moment.
@JasperLoy yes I saw the chat :P
@JasperLoy I wrote that on my phone. I am proud of it.
My best friend will be returning next month from Oxford, have not seen him for years.
@Sarah I dislike the idea of using the internet on phones. I am on my laptop now. I decided to move my desktop to the store room to have more space on my desk.
20:38
@Arkamis 9.5 points is a lot to cover
@JasperLoy I have moved to my laptop now. :D
Homework can wait.
Who's getting 9.5 points?
Ich needen goin. <-flawless german
bye
@Sarah OK. I think I won't log in to the site next year. I will be busy studying my 12 holy books. Then I can take the GRE in 2016 and enter grad school in 2017.
@Arkamis NYJ
20:39
@Alizter Guten tag.
@JasperLoy What do you want to study?
@Sarah You mean in grad school? Math, of course.
Well, Vegas had Broncos at -10 when they were playing NYJ in NY... and they covered
@JasperLoy I know but analysis?
@Arkamis yep, you never know
20:40
@Sarah Well, if you are talking about a thesis topic, I can't decide now. I guess I will decide on that after a year in grad school.
Ohkay
I might need to go now.
@Sarah See you, we'll email. =)
Promised my friend something. Should probably keep that promise rather than spend time here :P
@JasperLoy if I do not reply email me more.
@Arkamis Good luck tomorrow night, I gotta run...
@IceBoy Guten tag.
20:42
thanks, catch you later
Can anyone think of a function $f:A->R$ that has countably infinite essential discontinuities ? By $p \in A$ being an essential discontinuity of f, i mean that either lateral limits of f don't exist at p.
I am trying to pretend I know German, LOL.
@JasperLoy pretending is the best way to start :-)
@nerdy $\tan x$ ?
@IceBoy Bonjour, lol.
20:46
Arkamis man, straight to the pointt
thanks so much
did you think it now or you had that example already in your mind ?
@PedroTamaroff It's false?
@nerdy my first thought was to get something with countably many zeros, and shove it in the denominator
that means $\frac{1}{\sin x}$ or $\frac{1}{\cos x}$
exactly
Then, I thought that we'll need to multiply that by something periodic, which leads to $\sin x$ or $\cos x$
So then I thought $\frac{1}{\cos x} \sin x$. And I typed that
But then I realized I was a moron, as that is just $\tan x$.
@MarcGato No, it is correct.
20:49
secant x and cossent x also work right
?
cosecant*
@JasperLoy do you know of an extremely simple proof that the alternating group $A_4$ doesn't have a subgroup of order $6$ for someone who only knows group theory for a few days
@user130018 Want one?
@PedroTamaroff Great thanks.
@nerdy Yes they certainly do. It was not necessary to multiply by a periodic function (to arrive at $\tan x$) after all.
right. thanks a lot for those ideas Arkamis
:)
20:52
@Pedro yes please
@nerdy but
@user130018 Let me see if I can remember it.
$\tan x$ maps onto $\mathbb{R}$, so in that sense it's a little more interesting than $\frac{1}{\sin x}$
It is a nice proof.
Oh yeah, you are right
20:53
@Pedro I found some proofs online, but they use some concepts I can't figure out
@user130018 Let's see them.
I thought there may be some much more elementary one
@user130018 There is one where you just have to count stuff.
But let's see the one you have.
@user130018 Oh. Now I remember.
It goes as follows, @user130018
Yes, $A_4$ has order $12$.
If we had a subgroup of order $6$, it would be normal. Do you know what a normal subgroup is?
20:57
I don't understand that / symbol, the sideways triangle, homomorphisms, pi, etc.
Nevermind.
Do you know what normal means?
Or cosets
No
Well, the point is the following.
$A_4$ has some elements of the form $(abc)$.
Which have order $3$.
@PedroTamaroff I was just about to throw that same proof up there :)
That's the best proof I think.
The point is that if $H$ is such a subgroup, then $\alpha^2\in H$ for every element of $A_4$.
But if you pick the eight elements of order $3$ in $A_4$, $\alpha=\alpha^4=(\alpha^2)^2\in H$, which is impossible, @user130018
So, as I said, it all boils down to showing that if $H$ is a subgroup of a group $G$ and $|G:H|=2$, then for any $x\in G$; $x^2\in H$.
You can do so by writing $G=H\sqcup xH$.
21:04
Oh, thank you @Pedro
If you don't get this, maybe you just need to read about cosets and normal subgroups a little more.
Yeah, you're not far from encountering that material anyways
Cosets are a little strange at first, maybe.
For example how we define an order of an element in $\Bbb{Q}$?
21:47
76
Q: Is there an actual "pity" or "sympathy" upvote problem?

Jeff AtwoodThere have been a number of discussions about "pity" or "sympathy" upvotes. http://meta.stackexchange.com/search?q=pity+sympathy+upvote That is, the idea that once a post is voted down to -1, some kind-hearted user will come by and upvote the post, no matter how terrible or wrong it may be, to ...

41
Q: Do we have a problem of "pity upvotes"?

Sam SaffronI know, this may sound like it is off-topic, but hear me out. At Stack Overflow and here we get votes on posts, this is all stored in a tabular form. E.g.: post id voter id vote type datetime ------- -------- --------- -------- 10 1 2 2000...

@MarcGato order of every elt in Q is $\infty$ except $0$.
For any number theorists around : Isn't this a very wrong way to deduce a $5$-adic representation for $1/2$? math.stackexchange.com/questions/975299/…
@DanielFischer I need topology help.
@BalarkaSen Can you be a little more specific?
@DanielFischer heh, OK. Was just making sure you were around.
In this answer Tunk-Fey miss a very important thing math.stackexchange.com/questions/944065/…
This sum $$\sum^\infty_{n=1}\frac{(-1)^nH_n}{n^4}$$ can be done elementarily, no need for complex analysis. Besides that, my master formula also emphasizes the relation between $$\sum^\infty_{n=1}\frac{(-1)^nH_n}{n^4}$$
and $$\sum^\infty_{n=1}\frac{H_n}{2^4 n^4}$$ in a generalized form since this is just a particular case.
For a metric space $X$, what are the conditions on $A \subset X$ for $A' = X \setminus A$ to be open? Simmons wants me to prove this for finite $A$ and that is obvious enough by picking up a $r < d(x, A)$, $S_r(x)$ being the desired open spheres around $x$. But I am sure there can also be infinite $A$s for which $A'$ is opne, no? @DanielFischer
22:02
@BalarkaSen $X\setminus A$ is open if and only if $A$ is closed.
OK, haven't studied closed sets.
The next chapter is about them.
@DanielFischer So we have essentially proved that any finite subset of a metric space is closed?
Is that right?
Above, the last sum is $$\sum^\infty_{n=1}\frac{H_n}{2^n n^4}$$
@robjohn it's interesting to check in the next period of time what is the best proof for $$\sum^\infty_{n=1}\frac{H_n}{2^n n^3}$$ Well, I can easily finish it by using the generating functions, but I can also do it by other means. I don't think I have a very clever proof like one line proof yet.
@DanielFischer Some of the exercises in Simmons are very lame (while some are equally good). For example, the next exercise wants me to prove that every subset of a metric space $X$ is open $\iff$ singleton sets of $X$ are open.
It's trivially true : $(\Rightarrow)$ as singleton subsets are subsets and $(\Leftarrow)$ as every subset is union of singleton subsets and openness is invariant under taking unions.
22:07
@BalarkaSen That's to make sure you understand what "arbitrary unions of open sets are open" means.
@DanielFischer Hmm, OK.
I have exhausted my flags yet again
and filled up 2 review thingys
@DanielFischer One more thing : I have to prove that given a metric space $(X, d)$, $d' = d/(1+d)$ is also a metric on $X$. Walkthrough? I don't seem to be able to prove it.
$$\frac{d(x, y)}{1 + d(x, y)} \leq \frac{d(x, z)}{1 + d(x, y)} + \frac{d(z, y)}{1 + d(x, y)}$$
Then what?
@BalarkaSen Positivity and symmetry should be obvious. The only nontrivial part is the triangle inequality. Look at the function $t \mapsto \frac{t}{1+t}$ for that.
What properties of that function might be relevant?
@DanielFischer It's monotonically increasing on $\Bbb R^+$ ?
22:20
@BalarkaSen Yes. Can you see how that implies the triangle inequality?
Yes, I am seeing it.
Let me explicitly write it out and do the calculations.
Right. I am bad with names, as I have said numerous times before.
;)
ROLFROLFROFL
ROLF?
Words are bound to get jumbled up if you roll on the floor and laugh at the same time, @kuku
22:23
WHY u laugh?
@TedShifrin!
hi @Balarka
@TedShifrin Topology is so cool.
Indeed.
24.1k repurtation
what is the point of getting these reputation
22:25
@kuku You'll get a lot of bitcoins if you can make it to 10k.
no girl in this forum?
I like rep so I can get obnoxious bums banned :P
disappears in a puff of smoke
@TedShifrin I am open setting at the moment. I'm going to get to Baire category soon.
one fast old man, that guy
@TedShifrin, I found this: http://mathworld.wolfram.com/LandausFunction.html

In particular, if $g(n)$ is the maximal order of an element in $S_n$, then $\lim_{n \rightarrow \infty} \frac{log (g(n))}{\sqrt{nlog (n)}} = 1$.
Huh. It's not liking my TeX, but yeah.
Ahhh. Didn't close my {. Of course.
@KajHansen Whoa. Looks like connected to prime-counting functions.
Intriguing.
22:34
Indeed it does @BalarkaSen.
@Semiclassical Hello again.
@BalarkaSen, "$g(n)$ is constant over arbitrarily long intervals." :O
":O" Indeed.
It seems to be of number theoretic interest.
tries to pull @Kaj onto the dark side
I have no problem with NT. I just haven't taken any courses that deal with it yet.
It's better than PDEs.
I am doing topology at the moment though.
22:40
hahaha
Do you ever annoy your math teachers at school? :P
You don't want to know.
Now I'm curious! LOL
@DanielFischer Hello!4
What's up @Kaj , @Bal ?
Hey there
@PedroTamaroff Hello
22:49
See above for some mind-blowing @Pedro.
Hi @Pedro
Hi @Ted
@KajHansen OH?
Mike plays in the NBA?!
MIND = BLOWN
Regarding the maximal orders of elements in $S_n$.
Very cool, @Kaj. You taking topology and number theory this spring?
Asking me? @TedShifrin
22:50
@TedShifrin Ted!
I sat for my baby Multivariable Calculus final today.
Hi @Pedro ... Hardly see you these days.
@PedroTamaroff Mike can't keep runnin' and algebrain' at the same moment!
@BalarkaSen Lately Mike has be Lieing.
I presume you aced it, @Pedro.
@TedShifrin I was studying.
=D
22:53
Yes, I was, @Kaj.
@TedShifrin Wanna hear about the problems?
Nah. I was planning on complex and topology. And probably another 4950.
Sure ... Will you stump me? :D
Whenever you drop four digit numbers like that, it sounds badass.
I got a 1202 going on, Ted.
Let's 3402 the shit out of this.
22:54
hahah @Pedro
smacks Pedro
more hahahahs
@TedShifrin The first problem was to evaluate $(x-x_0)/\lVert x-x_0\rVert ^3\cdot\vec n$ over a closed simple regular nice beautiful surface.
Where $x_0$ is interior to the surface.
Gauss's law.
I used Gaussed theorem to reduce to the case of a ball.
Then I got $4\pi$.
22:55
Yuppers.
@TedShifrin, I can basically get advised over MSE chat, right? I'll need those precious unlocks. :P
@TedShifrin What's Gauss' law?
Some physics stuff?
Or cohomology @Pedro.
Oh?
interest
22:57
I plan to study algebraic topology after general topology. Probably that'll never happen though.
$H^2(\Bbb R^3-\{0\})\cong \Bbb Z$
@Chris'ssis Those seem to have a thicker skin than the ones without the powers of 2
@BalarkaSen In my university that's the course plan actually.
@TedShifrin O.o
I am not a university student, @Pedro
My mathematically maturity is far below you guys
meh/10
@TedShifrin OK, the other one was this.
Take $u$ some $C^2$ function. Then

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