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20:00
Sure it is, google will tell you to just use google instead - fixed.
@Studentmath Not without tools :/
Or do you want me to open my computer with my teeth ?
@Studentmath Workaround $\neq$ fix.
Don't you have some tools at home?
I'm not at home
I'm in internship
Some of us are better at breaking than at fixing ...
20:01
@Daniel point taken
@Ted enough analysis for today. And for the linear algebra question, primary decomposition kills it
I wanted an elementary argument !
@Ted in French education, the theory of eigenvalues/diagonalizability stands on primary decomposition (it's the very first thing we learn !)
Using just partial fraction decomposition :)
Well, fine then ... :D
@G.T.R Uh ?
20:04
@Hippalectryon ?
@G.T.R it's the very first thing we learn ! c'est en Spé ?
oui
Scared to even try another test.. and the exam is in a week
20:24
@Studentmath How old are you, and what's the drinking age in Israel?
18, 18
I bet you a beer you'll do great
what is the gambling age?
this is internet gambling, perfectly legal
20:28
18 as well!
Heck, I will bet - at least I get something eitherway, that way
I will mail you an Israeli beer if all goes well
And the same to you
I am the witness.
:16236603
If you don't pay up, skullpatrol will be knockin' @ your door
A friend of mine makes this bet every time he has a hard test... he ends up out a lot of beer, but he doesn't seem to mind
20:35
It is somewhat calming
@Hippalectryon what's your solution to the functional inequation ?
@G.T.R You don't expect me to give you the answer do you ;) - But i/@balk can help you :D
I never give out answers to the problems i like
And i expect people to do the same
What have you found so far ? @G.T.R
(I was stuck a long long long time on it btw, but @balk solved it in like 15 minutes :/ i felt bad)
I dislike his solution
@PedroTamaroff I guess you need some content to make it work.
@G.T.R whose solution?
@robjohn Ah?
20:43
@G.T.R :O you looked at it ?
cheaturz
@PedroTamaroff _
@DanielFischer Hello!
@PedroTamaroff your comment to Mike Miller that failed
@PedroTamaroff Buen dia.
@Hippalectryon unless it's something without Lebesgue integral ?
20:45
@G.T.R I haven't even seen Lebesgue's integrals yet
@balk's answer is from like a week ago
@Hippa Every time you put the @ there it pings him
by balk you don't mean Balarkasen ?
If you don't want to get his attention you shouldn't @, it can be annoying
But i'm too lazy to go get his full username :P
20:50
hi there
do I need to change my name back? Will someone get upset?
I haven't seen Tom Cruise in here complaining ;-)
hehe, ok, well if Tom Cruise joins this site I will change it
why is the site not loading now
@TomCruise Ah, I feared it was only me.
Ping says: PING math.stackexchange.com (198.252.206.140) 56(84) bytes of data.
From 88.79.26.197 icmp_seq=1 Destination Net Unreachable
guess I needed a break anyway...
@Hippalectryon his solution is flawed
20:55
@G.T.R I knew it :D
@G.T.R I told him something was missing
But i couldn't see what
I believe you can't get to the solution without using the fact that's it's strictly increasing, which he didn't do
@Hippalectryon What problem?
that's irrelevant... he assumed continuity at some point
oh so that problem is still unsolved?
@G.T.R xD
@TomCruise Nope
It was solve long ago
Actually i solved it
Then i posted it on MSE to get a shorter answer
I got a one line solution now :D
@G.T.R Then find the right way to do it ;-)
Could we assume the function was differentiable, or no?
20:58
@DanielFischer find all $f:\mathbb{R}\rightarrow\mathbb{R}$ such that $\forall (x,y)\in\mathbb{R}^2,\ f(x+y^2)-f(x)\geq y$
we are talking about the fixed point problem, right?
@DanielFischer find all $f:\mathbb{R}\rightarrow\mathbb{R}$ such as $\forall (x,y)\in\mathbb{R}^2,\ f(x+y^2)-f(x)\geq y$ @TomCruise
Ah
@Hippalectryon
@G.T.R was quicker
Oh I thought we were talking about something different
21:00
@DanielFischer what do/did you do for a living ? Not that I want to meddle in your privacy, but I can't take any guess (you said you're not a programmer)
I wanted to watch the new $300$ movie, but I preferred to create a new problem ...
Contract killer.
3
@Chris'ssis watch the Budapest hotel thing instead, it's worth it
@G.T.R what is that ?
| language = EnglishFrenchGerman | budget = $31 million | gross = $161,867,037 }} The Grand Budapest Hotel is a 2014 comedy film written and directed by Wes Anderson and inspired by the writings of Stefan Zweig. It stars Ralph Fiennes as a concierge who teams up with one of his employees to prove his innocence after he is framed for murder. The film is a British-German co-production financed by German financial companies and film funding organizations, and was filmed entirely on location in Germany. Plot In the present, a teenage girl approaches a monument to...
21:03
They should make a film where an infinite number of cars filled with infinitely many annoying french people come into a totally full hotel with infinitely many rooms, and how they manage to find a room for everyone :D
@DanielFischer How much per contract?
@skullpatrol Depends. There'll be a discount for my first contract, so if you're quick, it may not be too expensive.
@Chris'ssis Do both :D
this is what awaits you,Daniel, if you go that way
@Hippalectryon :D
21:07
@G.T.R Nah, I take Natalie Portman, like Jean Reno.
This is for fun (mainly) $$\int_0^1 \sum_{n=1}^{\infty}\log\left(\frac{1}{\sin^2(\pi x)}\right)\cos(2 n^2 \pi x) \ dx$$
@G.T.R I like that video
I like the song better but the vid is OK
The vid is funny
I've got a better one tho :c let me find it
The girl looks a lot like Vanessa Paradis, but I can't tell for sure
21:18
TO MUCH VIOLENCE HERE
@G.T.R what do you think about the question above? May I swap the integration and summation? I see no Ted around to ask him the same question.
bye
@r9m I see you hidden under some mist on the right panel (I barely see you) :-)))
@G.T.R aah that's the one
OK, it's time to see the first 15 minutes from $300$ (I cannot watch more in a single day or?).
21:23
chat was down for 10 minutes for you as well ?
so I see the site is down ... again ...
Maybe it was overheating :D
has @Hippa burnt to a crisp yet?
oh, apparently not
@TedShifrin Don't worry i have some lives left
I hope so, @Hippa.
r9m
r9m
21:26
@Chris'ssis :D .. Hi super sis I'm cooking something and watching Bra-Cmr match :)
I'd hate to have to go to your funeral before I'd even met you !
@r9m xD auto-tab much ?
@TedShifrin Don't worry you probably won't be notified if it happens :P
r9m
r9m
@Hippalectryon ?
@r9m Hi there :-) What's your favourite team? :-)
I think @GTR would notify me, @Hippa ... :D
21:27
@r9m you had writte @Hippa instead of @Chris'ssis :D
@TedShifrin True, he could know by asking my prep school... though i doubt he would do that :P
r9m
r9m
@Chris'ssis I'm an Arg/Ned Supporter .. but if they meet in a match I'll be supporting Ned :P
C'est vrai, @Hippa. On s'en fout de toi, évidemment.
@r9m I see ...
Je star ou je flag ? :D
r9m
r9m
@Hippalectryon :P .. sorry .. wrong button :P
21:29
LOL ... ni l'un ni l'autre
woohoo
site running
@TomCruise Where to ? :D
got laid
3
^_^
wow, ok
did you use to be com truise?
21:32
The chat bugged out because I was out for a bit. All I saw was @TedShifrin : got laid
now wait a minute, @Alizter ...
I might have impregnated her, not sure yet
@Alizter i thinkso , at least it was weird for me i couldn't connect
heya @Charlie
@TedShifrin hello theodore
21:33
@EnjoysMath her ?
@TedShifrin how are you?
Her name is Lorianne. Pretty sure it's safe to say that here, right?
I'm doing pretty well, @Charlie ... my summer is half gone ... how are you?
21:35
@EnjoysMath I mean, who are you even talking about ?
I just saw a 'her'
Idk the context
@TedShifrin fine, just lot nervous
@Hippa: It was his own her.
@Hippalectryon just never mind
21:36
why, @Charlie?
Err ......
maybe the chat filter took out my message
@TedShifrin I have an exam
did you use to be com truise? - I might have impregnated her, not sure yet
^ ??
21:36
scroll up
@Charlie: Be confident. You'll do much better that way.
Salut @GTR
Two unrelated statements, Idk who com truise is
@TedShifrin D:
OOOOoooh ok
@EnjoysMath are you ready for child support and STDs ?
@Ted bonsoir
21:37
thanks for killing the romance
@EnjoysMath I didn't see any romance
r9m
r9m
sigh
@EnjoysMath So why tell us?
21:39
because she doesn't want me to tell anyone so I figure you guys are far enough away that it's ok
Was she conscious and over the age of consent?
I want to propose a very interesting double integral ...
She was 33, I'm 28
i believe you should have kept it for yourself @enjoys
ooooh, a different sort of proposition
21:40
is it some no-strings attached relationship ? @EnjoysMath
@Chris'ssis DO IT
@skull
r9m
r9m
@Chris'ssis where ? :D
My computer is going to die soon. I tried generating $S_7$
@Chris'ssis Make sure to add 300 in it
21:41
She is 33, but she will be turning 34
@Alizter: It can join @Hippa's on the trash heap.
@Charlie
@Alizter Mine is already dying
@skullpatrol how is it going?
Eh 16 gb of ram shouldnt be in the trash
21:42
@Charlie Fine thanks, how are you?
yes I changed my name again, some are not happy with it, but I dont care :)
@skullpatrol fine i think, thanks
Since I have no idea who you are, @TomCruise, I have no opinion.
heya @skull
@TedShifrin Hello Professor
This is newly created. Find the closed form of $$\int_0^1 \int_0^1 \left \{\operatorname{arccot}\left(\frac{x}{y}\right)\right \}\left \{\operatorname{arccot}\left(\frac{y}{x}\right)\right \} \ dx \ dy$$
where $\{x \}$ - the fractional part of $x$
21:43
For all you know Tom Cruise likes to browse MSE
@Chris'ssis: $=$
and likes to refer to himself in the 3rd person
@Chris'ssis That's mad as always
:D
So 'twould seem @TomCruise.
21:45
@TedShifrin What that symbol means? ": ="
@Chris'ssis: When you define $\{x\}$, it should be $ = $ whatever ...
@Balarka: You're gone, remember? Another 7 days.
@TedShifrin I think it is defined just putting into context?
i am gone, but i am going to do this prank here time to time, @TedShifrin
byes.
one defines by the word "is" or the symbol "$=$" :P
No, @Balarka. You're banished.
@Ted I'm reading some about Lie groups. It's neat. The Lie algebra feels impossibly successful and powerful.
21:47
what's new @skull ?
"impossibly successful and powerful"??
@TedShifrin you're right.
@Charlie chillin' ... how 'bout you?
I was being picky, @Chris'ssis ... But I know you take pride in what you write.
does that look non-trivial to someone else ? math.stackexchange.com/questions/845124/…
21:48
@TedShifrin :D
@skullpatrol dunno kinda weird
Yes, @GTR, seems quite nontrivial. I have no earthly idea.
@Charlie too much world cup hype?
@skullpatrol nono, it's not that
21:51
I'll also consider $$\int_0^1 \int_0^1 \int_0^1 \left \{\operatorname{arccot}\left(\frac{x}{y}\right)\right \}\left \{\operatorname{arccot}\left(\frac{y}{z }\right)\right \} \left \{\operatorname{arccot}\left(\frac{z}{x}\right)\right \} \ dx \ dy \ dz$$
@Ted It works too well! It does too much!
@skullpatrol hehehe
I have now switched to non graphical rendering of cayley tables so that they are generated and saved. You can view them when they are done. It is especially useful for groups of order $7!$ cough $S_7$
@TedShifrin yeah, typing things fast ... :-)
Well, groups are rather special beasts, @Mike. Structure constants of the Lie algebra are all-knowing :D
21:52
An algebraic (combinatorial) construct like that shouldn't be able to keep track of all the geometry you lost...
@Alizter Why is it so heavy ?
"lost"
I don't know why you say combinatorial, @Mike, unless you're doing weights for representation theory.
@Charlie kinda surprised that OldJohn doesn't come here anymore :(
@skullpatrol no one comes here anymore
21:55
@Ted I tend to think of discrete things (with finitely many possibilities) as combinatorial. Probably that's bad terminology. Oops.
r9m
r9m
@G.T.R I don't think so :-)
Scratch "with finitely many possibilities".
@GTR: I put what I believe is a non-stupid comment.
r9m
r9m
I would get more motivated in answering questions ... only if I knew which are the hot users :P lol
@Ted maybe he should do as you suggest and then try expanding $f$ as a power series and find some relation between coefficients
21:59
Well, we need to look at the differential equation we get and see if it has ordinary singular points, etc. But, yes, @GTR, that would be a plausible suggestion.
@r9m: That definitely would depend on the eye of the beholder.
@skullpatrol :'(

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