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9:00 PM
Link to your books?
 
I don't much care that the definitions are wishy-washy. It's just poorly organized and poorly written, and far too focused on computation.
I bet one can teach a calculus course that's not computation-based without it being proof-based. Somewhere in the middle.
 
I challenge you to teach that course, @Mike.
 
My high school "calculus" had barely no proofs @Mike
 
I don't think you have any idea of what you'd actually do.
 
My high-school math had barely no proofs, @Sab
 
9:01 PM
@Sab: You can find my books on Amazon (overpriced, totally).
 
A-levels they call it xD
 
@MikeMiller was that the gamble bet?
 
No.
 
@Ted I'm sure I'll find them in the library :D
 
@TedShifrin I have no idea what I'd actually do. I think it would combust.
I think a better person than me could do it.
 
9:02 PM
If I don't I will tell them to order it and I'll borrow it xD That;s what I did with Apostol second edition. When I'm going to uni next semester they will have it by them and I'll borrow it since noone does xD
 
Chern's book will be here next Friday.
 
I've taught medium courses (where I don't expect students to write much in the way of proofs), @Mike. But there was still emphasis on computation/applications ... more interesting, challenging ones. I also like Simmons' Calculus (and diff eq) books.
AH, cool, @Mike.
Good planning, @Sab. I like your style.
 
I totally don't get the concept of teaching maths without proofs.
 
prove it
 
I have had some nice books on my shelf for months
Naive Set Theory by Halmos
I loved that book
 
9:04 PM
@robjohn are you around?
 
Wanted to keep it lol
 
For teachers who don't want to invest a lot of time with their students, it's the way to go, @DanielF. In Europe, students aren't as whiney (or at least they didn't used to be) and parents don't butt in the way they do in the US.
It takes hard work on the teacher's part to be demanding. Just reciting proofs in dull fashion doesn't get anyone much of anywhere.
 
@Ted I;m not really sure why the first page of google is showing a site with your book on it for like Free to View
 
LOL ... some people here mentioned that, @Sab. There are illegal copies all over the web, apparently.
I'm not sure if the Multivariable Mathematics book can be found that way. I know the Linear Algebra one can.
 
Did you think of taking any action? Like a DMCA complaint?
 
9:06 PM
True, @Ted, just reciting isn't anything good. That's why you let the students prove stuff in exercises.
 
which one is it, @Sab?
 
I just googled "Linear Algebra by Ted Shifrin"
 
But then you have to spend hours coaxing them in office hours, @DanielF, and most faculty don't want to do that. They get promoted/raises for publishing research, not raising students' levels.
Right, @Sab, I reported that one to the publisher, and they're supposed to be working on it. THat's not the book I was talking about. Look for Multivariable Mathematics.
 
Books should not be typed on a computer. They should be done on a typing machine.
 
Ugh, NO ...
 
9:08 PM
And I thought teaching was an important part of a Professor's job.
 
Silly you @DanielF ...
 
I'm an old-fashioned guy.
 
@TedShifrin What do you think about the theory that says that some students excel when they learn on their own?
 
Most go through the motions, but unless we actually base promotions and raises on serious quality of teaching (not just being easy to get high evaluations from students), it won't happen at most universities. Small colleges, yes.
Some students, for sure, @Chris'ssis. But I think very, very few.
 
This one is really famous @Ted :D
 
9:09 PM
In the classes I teach, with the best students at our university, I might have one a year who would excel that way. No more.
 
At least there is nothing like a pirate version on the first 3 pages on google(I don't go past page 1 normally lol)
 
haa!! suppose $K$ is not closed, and $\alpha$ is a limit of $K$ while not being in $K$. Then $f:K \to \mathbb R$, $f(x)=\frac{1}{|x-\alpha |}$ is not bounded! so indeed, if every continuous real valued function is bounded, then $K$ is compact. — Oria Gruber 1 min ago
:D
 
@TedShifrin 1/1000
 
My denominator is small, @skull, but I'm talking about the top .5% of the students.
 
@Chris'ssis I know someone who excelled like that.
 
9:11 PM
Well, @DanielF, $K$ has to be closed. 50% done.
 
@Sabಠ_ಠ I'm sure of it. :-)
 
Guy never came to maths lectures he aced it with 100% on the first test.
He self-learned it all.
 
@Sabಠ_ಠ like me :-)
 
@TedShifrin That part was in the question, $K$ bounded but not closed was the missing part.
 
@r9m Vladimir posted your proof :/
 
9:12 PM
@Chris'ssis like me in high school xD But uni is different. I took it lightly lol
 
So @r9m lost his rep points by being stubborn and lazy :D
 
r9m
@G.T.R great :D !! .. I'll hit it with something else then .. =P (I think I have another ace up me sleeves :P )
 
@TedShifrin Don't understand me wrongly, I'm sure the professors may teach you a lot of things, but some are built to learn alone, especially those with social phobia. It's hard to imagine what difficult is for those students with social phobia to stay focused on things. It's a hell!
 
@TedShifrin to be an independent researcher you must be in that .5%
 
r9m
@TedShifrin XD .. happens a lot :)
 
9:17 PM
@TedShifrin That's what I meant. E.g., asking calc students not to write a proof, but still to explain why something's true. (A proof in disguise.) Do computations, but don't spend the course doing them.
I told you someone better than me could pull it off!
 
I just think that doing proofs that are formal and give little insight (what I call "mathematical masturbation") does little good in a standard course. I'm not talking about a theory course or one for majors. And I do do proofs when they impart understanding/insight.
 
Right. I agree.
 
So I insist on a proof of the Fundamental Theorems of Calculus, for example. And for why conservative force fields have potential functions, etc.
 
Right.
 
even physics courses require proofs
 
9:22 PM
they call them derivations, not proofs :)
 
r9m
Now I'm onto disturbing/annoying Vladimir with the doubts/questions I faced while proving it ... =P
 
You enjoy being a pest, @r9m? :D
Oh, wait, you're here. Of course, you do.
 
lol
 
r9m
@TedShifrin pestering is my second nature :P .. especially when I think I have a chance to learn sth :D
 
What's your first?
 
9:25 PM
boo
 
learning is the first
 
Heya @Ilan :)
 
I like Vladimir's witty comment "How to guess this proof? It is easy enough: $\frac13$ can only come from $\int t^2 dt$ in this context, so we need to estimate $f$ somehow via the integral of $tf'(t)$.". Good insight
 
Yes, I love it when people give insight. (See above.)
 
r9m
@G.T.R I envy your questions :P ... they get a lot of attention :-)
 
9:28 PM
I don't recall paying attention to any of @GTR's questions!
 
r9m
I mean they always have a decent number of upvotes and views :)
 
@TedShifrin You know, I wish I would invest more time in studying. Sometimes, I feel kinda wasting my time. Although I do study atleast 3 hours a day. But I always think it's not enough and I can push myself more and more and thus I can study more and understand more. But I don't know when I studied enough to succeed in the test - it's not high-school anymore which I studied like 2hours before the exam and got 100 mark..
 
@r9m I've been posting a streak of non-trivial questions (mostly oral exams) but go back earlier in time, they're less numerous
 
Well, @Ilan, you're right. It's not high school any more. But give yourself a break. It's impossible to work a full-time job and be a serious college student. Being in the full-time military is even more onerous!
Maybe I should post an occasional question on main for you, @GTR :D
 
9:32 PM
Surely you have things you'd like to know, @Ted?
 
@TedShifrin Well, I'm not going to give up anyways. I'm just not that kind of a person to give up. and I hate being defeated (Like: getting a bad mark after I sweat alot for the exam). Do you have an insight to make me less misreable than I am now?
 
@Ilan: I would tell you to do the best you can do and stop beating yourself up.
I also would comment that I've taught plenty of students who, with 3 hours a week of my lectures and numerous office hours, probably aren't understanding things as well as you do. So you should appreciate that you're learning a lot.
 
I'll second that advice
 
Part of what I do as a teacher is act like a cheerleader. (I recognize that that is not the European model.) You have no cheerleader other than yourself, @Ilan.
 
why the big difference?
 
9:35 PM
There's now a business model of education in the US, @skull. After all, the students and their parents are the consumers. We have to please them. ... But I felt like I had to cheerlead and encourage students to work hard/learn even before that.
 
@TedShifrin I see, well, then I need to keep working on my discipline, because sometimes I decide something and I don't eventually do it. For e.g., planning to study for 3hours, but I scroll facebook sometimes, answer to unimportant calls, chatting, etc.
 
Not to mention spending time talking to worthless people like us, @Ilan :D
 
Exactly. although sometimes I find you useful ;)
haha. @TedShifrin
 
Illusory.
We're just cute and charming :D
 
I asked you to not mention that :D
 
r9m
9:38 PM
@Ted would you mind if the pestering me follows you to fb ? :D xD
 
Well, I'm off to bed now. Going to manage my time more efficiently now for studying. Need to get off the things the distract me while studying.
 
LOL @r9m
Glad to help, @Ilan :) Good night.
 
You got fb Ted? :O
 
r9m
@TedShifrin I'll take that as an affirmative :D
 
Some of you people may not like what you find on FB ... :D
 
9:40 PM
gimme! :)
 
@Ted ah, I have another non-trivial question. Find all $n\times n$ square matrices such that $\exp(M)=I_n\$.
 
What field, @GTR?
 
$\mathbb R$
 
Ah, ok. Well, I still have some answers.
We just need the "realified" Jordan form.
 
NO!
 
9:43 PM
Don't yell at me.
 
please not Jordan :P
 
Well, I need to use that to prove I've got everything.
 
@G.T.R You don't need to prove it, just to use it. That's nice, actually.
 
@Ilan: You're welcome to submit a friend request if you so desire.
runs fast and hides from @hippa
 
@TedShifrin :D
@TedShifrin I created a new meme :P
not showing it tho
Lol
 
9:45 PM
Oy vey.
 
It's not for you don't worry
 
You may send it to me privately, @Hippa. :D
Oh, good.
 
Some friend of mine just made a http gui generator
 
For whom is it?
oh lord
 
And i needed an image to test it
:D
 
9:46 PM
@DanielFischer Daaaaaaaaaaaaaniel.
 
not saying hello to @Pedro
 
@PedroTamaroff Yeeeeeeeeeeeeeeeeeeeeeeeeeeeees?
 
What do you mean, it's not for me, @Hippa? Oy.
 
9:47 PM
@DanielFischer Do you know the name "Carothers"?
 
@Daniel: Did she figure out your hint?
 
@TedShifrin I mean, even though you're in it, it's not because it's you
 
@TedShifrin Not yet, it seems.
 
It's because it was what i had right when I did it
 
frappe @Hippa très fort
 
9:47 PM
ewwww that hurts
 
@PedroTamaroff I know the name, yes. But hardly more. What is it about?
 
@DanielF: Perhaps the next hint would be: does $f$ have a primitive?
 
@DanielFischer I am reading a book written by him, but his name has a certain ring, like he's famous or something.
 
so, @GTR, are you asking this question to test me, or do you not know the answer?
 
It's a cool surname.
 
9:49 PM
much cooler sounding than us Russian types, @Pedro.
 
@TedShifrin No way!
 
LOL
 
Kolmogorov is the mathiest surname ever.
Chevoratev.
 
So you don't like the British school?
 
Shilov.
Tychonov.
All sound cool.
@TedShifrin What's the British school?
 
9:50 PM
Шифрин и Таморов
 
r9m
@Chris'ssis Is there no end to this tail ? ;)
 
@Ted no I do not :(
 
Carothers sounds English or Irish ...
 
@TedShifrin Yes, Tamarov would be a nice addition. Hehe.
@TedShifrin The book is by the CUP.
 
Naptime.
 
9:51 PM
@r9m It's a surprise! :-) I'll create a lot of questions of this type, maybe some hundreds (I wanna explore each type of family as much as I can).
 
oh fine, @Pedro ... you like you but scorn me ...
no, @Mike, dinnertime.
So, @GTR, what do you surmise is the answer?
 
@TedShifrin WAT.
Ted please.
 
LOL ... I put both our names in Cyrillic
 
Oh, I only recognized mine I don't know Cyrillic.
 
ah :)
 
9:53 PM
Trivia. Huey rejected an offer to compose for the Ghostbusters movie.
 
r9m
@Chris'ssis Yessss !!! put them in a book .. all the charts and details of your exploration .. Marco Polo :D !
 
$0$, but unsure @Ted
 
@G.T.R :O trouvé :D :D :D prntscr.com/3v6702
 
Think about $2\times 2$ rotations, @GTR.
 
@chris'ssis I am at lunch. I hate the mobile interface. I will be back in a while.
 
9:54 PM
@robjohn I wanted to send you something privately (in case you have an e-mail for that you use on MSE).
@robjohn OK
 
lunch at 3 PM? Oy ...
 
@DanielFischer Do you recall the proof of the open mapping theorem off the top of your head?
 
In complex analysis or in functional analysis, @Pedro?
 
Functional analysis.
I didn't know there was one for CA.
 
I'm out ... :P
 
9:56 PM
@PedroTamaroff Not all details, but I could reconstruct them, given a little time.
 
Yup, all complex differentiable maps are open maps (except for constants).
 
r9m
@Chris'ssis why so secretive ? :D
 
@PedroTamaroff Though, if you're asking about the version for webbed spaces, reconstructing that would take more than a little time ;)
 
WTF are webbed spaces?
 
What on earth is a webbed space?
 
9:58 PM
ROFL
 
I heard about barreled spaces once.
 
me too
@GTR: Tu es toujours là?
 
@TedShifrin Spider webbed space ? :D
 
Do you guys want me to look up what a webbed space was? I forgot the details, I have to admit.
 
@Ted yes
 
10:01 PM
So think about what you exponentiate (in $2\times 2$ matrices) to get a rotation through angle $\theta$ @GTR
 
@Ted are you referring to the identification with complex numbers ?
 
Wow, they even got their wikipedia page
 
sure, @GTR, but you still need the exponential.
 
@DanielFischer Weesh.
 
Well, @DanielF, I've lived a long time without knowing about these things. I reckon I can survive longer ...
Spider webs in mathematics ... We had sheaf theory with all the agronomical vocabulary :P
 
10:05 PM
@r9m Well, it's nothing secretive there (or it is a bit?) ... :D
 
@PedroTamaroff Well, unless you're going in really deep, you won't need to go beyond LF spaces, I guess. Probably not even beyond Fréchet spaces.
Okay, @Pedro, so what was the question?
 
I was assuming @Pedro meant Banach spaces.
 
r9m
@Chris'ssis I just wanted to sound like 'Why so serious ?' there ! .. :P
 
@DanielFischer That was my question. =P
I am a bit surprised that Carothers' book doesn't prove any of the major theorems though.
 
Why reprove stuff that's in tons of textbooks?
 
10:09 PM
@PedroTamaroff What major theorems?
 
@DanielFischer Open mapping, closed graph, uniform boundedness.
 
So what is Carothers's book?
 
@r9m Do you know there is a soundtrack with this name? 'Why so serious?' -> youtube.com/watch?v=t6wrZ6P6-wU :-))))))
 
@PedroTamaroff And is it supposed to be a textbook on Functional Analysis?
 
"A short course on Banach Space Theory"
 
10:10 PM
Erm, that should prove such things, IMO.
 
Sorry $\uparrow$
 
Well. So after a glimpse of what it doesn't contain, what does it contain?
 
r9m
@Chris'ssis (y) this sound track (Joker's theme) sounds awesome with HD surround sounds !! :)
 
What do you put when you have no idea what tag to write ? :/
 
Give me a hint, @Hippa.
 
10:13 PM
It's about a weird think i remarked when applying $\ln$ to the pascal triangle
 
Oh, that is weird. Do you have it typed in, @Hippa?
 
@TedShifrin Yep
 
10:14 PM
@r9m Yes, I know. :-) Don't miss this one -> youtube.com/watch?v=tZXBvJnPx3A
 
Yeah @DanielF: I gave her an upvote on that comment.
 
Link me, @Hippa.
 
@TedShifrin It's written, but not asked yet
 
So, what does he say in his introduction, @Pedro?
 
10:15 PM
@TedShifrin i need to enter a tag
 
r9m
@Chris'ssis YA .. :D .. I have 'em all in lossless audio :)
 
combinatorics, precalculus [I got censored for removing a precalculus tag and putting combinatorics a week ago] ... I have to see @Hippa
 
0
Q: What is that curve that appears when i use $\ln$ on Pascal's triangle?

HippalectryonI made a little program that generates pascal triangle as images : I first tried it associating to each pixel a color which's intensity was proportional to the number in the pascal triangle The colors being 0-255, i used the following function to convert value to colors: $$f(x)=\frac{x-m}{M-m}2...

 
@PedroTamaroff The section headers in chapter 6 are a little, how shall I say. But looks not bad. Presumably, it presupposes the basics like OMT, CGT etc.
 
Yes, that's what Carothers says.
@DanielFischer A little what...? =P
Ah, yes. They strike me as funny.
 
10:19 PM
@Hippa: Maybe something like $(\log x)/x$? I'm not truly understanding the relevance of Pascal here. What's on the $x$-axis?
 
@r9m Good! :-)
 
@TedShifrin i'm basically drawing the pscal triangle
 
I don't get it yet. How does $\binom nk$ enter in here?
 
Someone please help on this one math.stackexchange.com/questions/843018/…
 
10:20 PM
I know what Pascal's triangle is, @Hippa. :) How is it related — precisely — to your curve?
@Swadhin: You do know that you can find all the solutions to Putnam problems on the web?
 
@TedShifrin The web solution seems beyond my understanding, so I am asking here.
 
@TedShifrin You see how the pictures are pascal's triangles ?
 
@DanielF: Kudos to you on the restraint and guidance of that OP. :)
Well, @Swadhin: I would recommend that you say what precisely you do not understand in the web solution as part of your question.
 
@TedShifrin And moreover, they are using too much of intuition and assumption.
 
Hmm. If I am looking at a configuration with a ring length 4, there is a lobe outside and a lobe inside. I look at the subgraph induced by the lobe outside together with the ring itself, call it O, and I define a proper 4 colouring of it $f:O\to [1,2,3,4]$ so that, if $R=\{v_1,v_2,v_3,v_4\}$, $f(v_i)=i$ for $i=1,2,3,4$. Why is it so that either $v_2,v_4$ are at different components of the subgraph of O induced by the colours 2,4.
Or that $v_1,v_3$ are at different components of the subgraph of O induced by the colours 1,3 - but both isn't possible?
 
10:23 PM
@TedShifrin Kudos to claire for looking over her notes.
 
@TedShifrin and I cannot find the intuition in that, is the solution only possible by intuition?
 
Well, I'm just applauding your patience and guidance, @DanielF.
 
Well, thanks.
 
@DanielFischer Did you like the contents, tough?
It has lots of references, for one.
 
@Swadhin: I have not worked that problem or looked at the solution. But undoubtedly people will tell you to read it. So you should say explicitly what you follow and what you don't in that solution.
@Hippa: No, I really don't.
 
10:24 PM
@PedroTamaroff I said: "But looks not bad".
 
@TedShifrin Higher intensity => higher number
 
@DanielFischer Does not bad = good?
 
So, if the commenter is correct, you should look at Stirling's formula and see if it fits (more or less what I said just guessing). Do you know Stirling? @Hippa
@Pedro: No, "not bad" = "not bad" :D
 
@TedShifrin I think so
 
$\log(n!) \sim n\log n - n$ @Hippa
 
10:26 PM
@TedShifrin $\binom{n,k}$'s equivalent right ?
 
So what is the estimate on $\log\left(\binom yx\right)$?
 
@TedShifrin I have seen one solution, where they say, it seems that $-1,0$ are crucial points, so one can assume $F(x)=a|x+1|+b|x|+cx+d$ , now, there are quite a few things I do not understand here, why should the sum need to be linear, second, why should we consider this?
 
bows @DanielF
@Swadhin: I'm not going to think about the problem. I suggest you incorporate all of these comments into your question.
 
@TedShifrin Ok, I asked for help here anyway.
 
10:28 PM
@DanielFischer OH HO HO!
 
The more specific and focused you make your question, the more likely you'll get helpful answers, @Swadhin. Just sayin'.
 
@TedShifrin $\ln\binom{y}{x}\sim y\ln(y)-x\ln(x)-(y-x)\ln(y-x)$
 
heya @Kaj
 
Hello everyone
 
10:29 PM
@TedShifrin ok, thanks.
 
OK, @Hippa ... I suggest you graph level curves of that, as that commenter suggested. :)
is that for @DanielF, @Pedro?
 
@TedShifrin Ok done :) i added something at the end
 
@TedShifrin Hehe, yes.
 
@TedShifrin Btw is the english correct at the beginning ? I'm not sure
 
no, @Hippa, "which's" should be "whose"
The least I can do for your reteaching me French :D :)
 
10:31 PM
Thanks
:)
 
@TedShifrin, according to the little tracker, my rep in the diff geo section is no longer 0 as of today :P
 
Can anyone please explain: if $r(x)$ and $s(x)$ are any two functions, then $\max\{r,x\}=\dfrac{r+s+|r-s|}{2}$?
 
LOL @Kaj ... You mean you deserved to pass the class? :D
@Hippa: Based on mathematica, these are not level sets of that function. I'm not quite sure.
 
llollllllllll, I just cracked another tough series!!! :-))))
3
 
@TedShifrin Well maybe if I tried with huge numbers i wouldn't have that anymore, but i can't do it on my computer
@Chris'ssis :D Congrats
 
10:36 PM
@Hippalectryon Thanks! I have so fun here now! :-))))))
 
Well, perhaps I wouldn't go that far @Ted. Just trying to even out a little bit, ya know? Total score of 145 under the abstract algebra tag, and the next highest subject is elementary number theory with a total score of 41, LOL
 
ugh ... @Kaj: Robert Lewis with his damn fiat lux ... has to always publish complete solutions when I'm trying to get the student to figure something out. I abhor him.
 
@Chris'ssis Write down a correction of one of the monster integrals once a month and send it to me :D
 
You don't need huge numbers, @Hippa. That conjecture is just wrong. I don't think it's level curves at all. I think it's the graph of the function.
 
@TedShifrin But
hehe i did 'but' him
 
10:38 PM
@TedShifrin, I've been trying to work on that because I've been bad about that in the past. It's surprisingly difficult to give just enough so that someone is no longer stuck, but avoiding giving too much at the same time.
 
@Hippalectryon It is possible you may find it soon in one of the American monthly magazines ... :-)
 
@Chris'ssis I live in France :/
 
Well, @Kaj, keep trying. We have to win this battle. :)
Maybe I've rubbed off on you :D
 
@TedShifrin Why is the pattern still the same for 50*50 and 150*150 ?
 
@Hippa, what I said doesn't make sense either. Agh.
 
10:39 PM
@TedShifrin Don't worry i didn't even see it xD
 
Ask @Kaj to look at it :P
 
I can't believe this question is getting so many upvotes :/
 
It's interesting, @Hippa. I just don't quite understand it yet.
 
haha, what are you looking at @Hippa?
 
10
Q: What is that curve that appears when i use $\ln$ on Pascal's triangle?

HippalectryonI made a little program that generates pascal triangles as images : I first tried it associating to each pixel a color whose intensity was proportional to the number in the pascal triangle The colors being 0-255, i used the following function to convert value to colors: $$f(x)=\frac{x-m}{M-m}25...

 
10:41 PM
That's pretty interesting @Hippa. +1 as well, because it's refreshing to see questions with originality and effort from the OP from time to time.
 
@Kaj: You'll find most of the young'uns who hang out in this chatroom are seriously vested in mathematics. :)
I still say the graph looks like $y=(\log x)/x^k$ for some $k$.
Well, translated ... $y=(\log (x-c))/x^k$ for some $c,k$.
 
You know what bugs me about SE is not that people will post asking about their homework, even if that question may have been asked before. No. It's those users who will post either a list of problems, or will post 10 questions in a single night that are obviously coming from problem sets (and invariably end up with downvotes on each one).
 
Not to mention take-home exam questions which then 100+K rep users obligingly post solutions to, even when asked NOT to. I'm so pissed off, @Kaj.
 
r9m
@Chris'ssis Awesome !! but how will I know that it is you (or is it that you are planning to publish under the name Chris'ssis -_-) ? :D
 
If people would stop answering these questions, the 1-100 rep users would desist. But all these guys have to show off how great they are.
LOL @r9m
 
10:44 PM
Well i should thank @Alister, he gave me the diea with his dihedral groups :D
 
@Hippa: I feel like we should be able to figure this out. I'm just being too dumb.
Please don't meme that.
 
I won't :)
 
@r9m Is it a bad idea to use the name Chris'ssis? :-)))
 
@TedShifrin, I remember seeing someone posting about a question that was apparently on their in-class midterm as they were taking the exam! Flagged/voted to close as soon as I saw it. Nevertheless, SE has a lot to offer when it's used correctly.
 
I agree, @Kaj. So these guys in here are on the good side :)
 
10:47 PM
@r9m btw, this is such a great day to me, a blessed day! Really! :-)
 
Congrats @Chris'ssis.
 
@DanielFischer OK, now I do have a question.
 
r9m
@Chris'ssis Great :D
 
@TedShifrin Thanks Ted! :-)
 
@Hippa: So I'm still confuzled. I'm muddled by what the axes are and what the intensity is. What are we looking at?
$y$ and $x$ are what? Intensity is what?
We are looking at level curves of intensity. I grant that.
So intensity is something like $\binom y{\log x}$?
 
10:50 PM
Also, what does the color "0" look like, and likewise for 255?
 
@DanielFischer Nevermind got it.
 
@PedroTamaroff Got what, out of curiosity?
 
LOL @Pedro @DanielF
 
r9m
@Chris'ssis Who is Chris and his sis ? :{ any idea for a meme @Hippa ? :P
 
Oh, you answer my questions at the very beginning. $x$ is the entry of the triangle, $M$ is the max, so we're rescaling (since $m=1$ which is basically $0$) to $y=\log (x/M)$. But where do the various rows come in, @Hippa? I'm still confuzled.
 
10:54 PM
@KajHansen 0 is black, 255 is white
 
@r9m That wording sounded like Bonnie and Clyde :-)))
 
@TedShifrin $x,y$ (left->right and up->down) are the rows, columns of the pascal triangle
 
Wait, that's not what you wrote.
 
?
Uuuh mea
horizontal is the colums
vertical is rows
That's still unclear-_-
@TedShifrin It's exactly as in i.stack.imgur.com/HQ7wX.gif
 
You put $x$ is the entry. So you mean Intensity at $(x,y)$ is the ratio of the $y$th entry of the $x$ row to the max in the whole thing.
 
r9m
10:57 PM
@Chris'ssis you mean the 1967 movie ? I haven't seen it yet :-)
 
Or vice-versa. What does the top line represent (with slope approximately $-1$)?
 
@TedShifrin It's the line of 1s (cf i.stack.imgur.com/HQ7wX.gif)
 
@DanielFischer Suppose that $B_1(0)\subseteq \overline{M \varphi(B_1(0))}$ for some map $\varphi:X\to Y$. Then for any $y\in Y$ we can find $x\in X$ so that $\lVert x\rVert < M\lVert y\rVert$ and $\lVert y-\varphi x\rVert <\varepsilon$.
 
r9m
@Chris'ssis no ! :]
 
@r9m OK :-)
 
10:59 PM
OK, so the intensity is the ratio at $(x,y)$, where $x$ is the column and $x-y$ is the row.
 

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