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Jasper Loy
Jasper Loy
23:16
Wow @mike did you see the comment on my answer?
Since when does trivial case analysis count as "incredibly hard to solve"? It may not be the most elegant solution and may take some work, but it's definitely not hard. — user2345215 9 mins ago
This totally pisses me off.
And then I got a downvote there, lol.
Geezis, it's time to delete account.
Mike
Mike
The guy's a dick.
But remember what skull said earlier.
Jasper Loy
Jasper Loy
He should try to solve it.
Then he will realise how hard it is.
But he probably won't.
Because he will give the short flawed proof.
@pedro Careful he will flag your comment.
Pedro Tamaroff
Pedro Tamaroff
I know the mods. =)
Jasper Loy
Jasper Loy
Anyway it is at most a suspension. =)
OK, time to sleep, lol.
Pedro Tamaroff
Pedro Tamaroff
23:51
@AlexanderGruber Aaaaaaaaaalex.
Alexander Gruber
Alexander Gruber
@Pedro
Pedro Tamaroff
Pedro Tamaroff
How's a going?
Alexander Gruber
Alexander Gruber
@PedroTamaroff not bad. just had a massage.
Pedro Tamaroff
Pedro Tamaroff
@AlexanderGruber i take it you didn't pay? =D
Alexander Gruber
Alexander Gruber
@PedroTamaroff haha naw
Pedro Tamaroff
Pedro Tamaroff
23:53
@AlexanderGruber I'm still group theorin.
I don't see how it will earn me a massage, though.
Hmm....
Alexander Gruber
Alexander Gruber
person who hit me last october's gonna be payin' for all that. (well, her insurance.)
Pedro Tamaroff
Pedro Tamaroff
@AlexanderGruber Did she tell you what caused the crash?
Alexander Gruber
Alexander Gruber
@PedroTamaroff no, i've never spoken to her actually, she just said "sorry" at the accident before we ran off to the ER
Pedro Tamaroff
Pedro Tamaroff
@AlexanderGruber smooth as fuck
Alexander Gruber
Alexander Gruber
my doctors talk to my lawyers talk to the insurance guys
i think she was texting maybe, she didn't seem drunk
Pedro Tamaroff
Pedro Tamaroff
23:55
shaaaaaaaaait.
no bad sequels, right?
Alexander Gruber
Alexander Gruber
nope :) been smooth sailing since then
Pedro Tamaroff
Pedro Tamaroff
good good
so, I have a problem
Suppose $M$ is a maximal subgroup of a finite (yay!) soluble group $G$. Then it has prime power index.
Now, I have proven that if $G$ is soluble and $H$ is a minimal normal subgroup, it is elementary abelian.
Alexander Gruber
Alexander Gruber
good!
Pedro Tamaroff
Pedro Tamaroff
Then take such a subgroup. If $H\leqslant M$, $M/H$ is maximal in $G/H$ and by inductive hypothesis we're done.
Thus, suppose $H\not{\!\!\leqslant }M$.
ugh that code sucks
Alexander Gruber
Alexander Gruber
$\not{\!\!\leqslant}$
there you go
Pedro Tamaroff
Pedro Tamaroff
23:59
Then $H\cap M$ is a proper normal subgroup of $H$, and since $H$ is minimal normal, $H\cap M=1$.
Then I can set up a cool iso, right?
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