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22:00
That’s the hard part
I think Bott-Tu did the world a service with their exposition.
I feel the same about homological algebra... I only really got an intuitive feel for it by doing it for months
“Why would someone ever write down the octahedral axiom?” Because you use it every damn day
The who?
don’t worry about it
it's an axiom for triangulated categories
I wouldn't want to TeX that
22:02
@TedShifrin well, it also depends what one calls the chain rule. for better or worse, I always tend to think of it in terms of stuff like $\frac{d}{dx}=\frac{du}{dx}\frac{\partial}{\partial u}+\frac{dv }{dx}\frac{\partial}{\partial v}$
it proclaims the existence of certain maps of chain complexes, more or less
I've never encountered it, Mike.
Well, Semiclassic, getting them to do the single-variable chain rule to do Frenet calculations for non-arclength-parametrized curves usually flunked one or two students every time I taught it.
I don’t have the presentation in terms of the Jacobian matrix as a reflex
22:03
For instance if v there is an equivalence this tells you that Cone(u) = Cone(vu), a reasonably common situation in real life
Using the matrix multiplication makes life so much easier.
@Ted I have probably done more homological algebra; that’s the only reason
I still have no idea what you're talking about, Mike. It's OK.
For sure you have.
You do enough and you eventually see this picture as valuable
Beyond the usual homology/cohomology stuff, I did wander into some Ext stuff when I was exploring one of the topics Griffiths suggested I work on for a thesis. I did something else.
22:05
I am skeptical of categories but I think the triangulated category axioms are a triumph of that kind of thinking. They thought really hard about how you do homological algebra in practice and then pulled out precisely how we think about it
And then even better it allows us to focus our thinking. If those are the only axioms we use, then those are the only axioms we have to think about
you don't really need the fancy approach to homological algebra via derived categories and triangulated categories for most things, it just makes certain things more clear on an abstract level and you can do stuff like reason about derived functors when there are not necessarily enough injectives. Just throwing resolutions at everything does seem ad-hoc in comparision
I agree. When writing down this stuff I like to be very explicit, bar constructions and stuff
But when thinking about how to prove things, that’s not really the language
@TedShifrin yeah, that’s clear even just from how tedious it was for me to write out that simple example
hey yall
Mathein , do I really need to learn real analysis ( rudin ) in order to study more algebra?
In regular multi classes (with no matrices or linear algebra) I explained the general chain rule in terms of superposition of effects, @Semiclassic.
22:14
I did not finish that course due to too many courses i took ><
“Regular multi classes” seem to be a scam
No, Kasmir, but you need to learn it to be a competent mathematician.
They should know linear algebra
okay thanks :D
22:15
Mike, there's nothing wrong with engineering-style math. Rigorous proofs aren't for everyone; nor should they be.
I want to spend summer doing algbra only
@KasmirKhaan no, you don't. It's worth knowing it as part of your general mathematical knowledge, though
Well, that's good. Then I don't have to talk to you, @Kasmir :P
It is fundamentally an application of linear algebra IMO. They should know what a derivative really is, and what the chain rule really says
haha @TedShifrin
22:16
Forget rigor, but don’t forget understanding...
@MatheinBoulomenos this is my plan , read lang book linear algebra, artin and dummit for abstract algebra and do rep theory by serre
@MatheinBoulomenos is that order good ?
sounds good
Mike: That's too much baggage for the average calculus student. I can talk about "good" linear approximation without the linear algebra. I just think it's not the ideal course for a mature math student.
i also wish i can do algebraic geo
but i dont know where that fits
22:18
Preparing students to take an upper-division E&M course is a bit different threshold than for a serious differential geometry course
I think we did the chain rule in our freshman analysis course for Frechet derivatives
Mathein ! where does algebraic geometry fit in that list?
before rep theory or after? :D
If I can do those from now untill summer , i would be very very happy :D
@Semiclassic: My undergrad diff geo is meant to be naive. No need for the derivative as a linear map or the fancy chain rule, except perhaps in one place.
not untill summer , but untill september =p
it's independent of rep theory, but you need some commutative algebra beforehand (not sure how much is in D&F). I'd do it after rep theory, though as I think it's harder
22:20
The one course in physics where I think the naive equation of vector calculus and multi variable calculus is problematic is in thermodynamics
okay thanks alot :D
of course rep theory also gets as difficult as you want it to, but I meant the basics
hmm well i think ill just add commutative algebra to that list
and if you can give me a name of good book for that
iwould be super mega glad :D
I took a chemistry thermo my freshman year, Semiclassic. The math wasn't that difficult, although obviously I had less trouble than most of the chem majors.
@MatheinBoulomenos dont tell me you learn it from german book ><
22:22
the basics of representation theory can be appreciated with just linear alegebra and basic group theory, though at some point knowing some module theory over non-commutative rings becomes really handy
Ill keep that in mind =p I still have no intuition of module yet tho ><
module and tensor products
those two are a nightmare =p
representation theory is a great point of why you should care about modules and tensor products
glad Mathein is a patient algebra teacher and Ted can resign
yes yes i know :D
Mathein helped me lots with algebra and Ted with analysis :D
am glad i found ya :D
also anon helped me lots! :D
many others as well to be fair :D
including semi and alesandro
@MatheinBoulomenos obviously you should care about tensors because curvature is a tensor :P
22:25
I don't ever think of that when I think of tensors
@MatheinBoulomenos commutative algebra book ? any recommandation ? :)
@KasmirKhaan the easiest book on commutative algebra I studied from is probably Atiyah-Macdonald, but I'm not sure if that's right for you. There are not much examples and the important part of the book are really the exercises which are of varying difficulty
oh you did not forget me ><
okay thanks mathein :D
People complain about its weight/length, but I recommend David Eisenbud's book on CA.
I like his taste in mathematics.
I found Eisenbud too wordy sometimes
22:27
wordy is good ._.
i dont mind reading extra if it get the info to my head ><
I think Eisenbud fits Kasmir better than A-M.
but yeah, Atiyah-Macdonald, Eisenbud and Matsumura are the three classic references on commutative algebra
matsumura ring theory book ?
yeah, but I wouldn't recommend that for you
okay then its settled :D
22:29
at least not in the beginning
ill try eisenbud and A-M
and pick the easiar of the two :D
Pete Clark's notes are also really good
googling :D
I took a course from Matsumura’s book and learned nothing
22:30
@MikeMiller really? I quite like it actually
I see we're having a dope ass conversation here
I think that’s because our brains work in different ways
There's a wide variety in aptitudes, tastes, and intuitions in this room.
Commutative algebra is one of the most mysterious fields to me
aren't you supposed to be ununsleeping, Balarka?
22:32
Similarly representation theory
hmm by notes mathein i thought like 60 pages max
I have just given up on algebra in general. I might give up on math in general
that is more than a book ><
@TedShifrin I guess I am
If you're more geometrically inclined then Matsumura is not optimal
22:33
@Balarka Academia is a trap
Use homeomorphism to escape
hehehe
All righty :D now kasmir has a good plan to learn some algebra D
You gonna invert the sphere on the way?
I think of commutative algebra, especially when you assume that everything is Noetherian as the basic case where everything works out nicely and isn't too difficult. To me, when you globalize it as in alg geo or drop assumptions so you deal with non-Noetherian rings or non-commutative rings (or both) is when stuff gets really hard
22:36
On an orthogonal note, the proof that number of paths on an $n \times n$ grid going from $(0, 0)$ to $(n, n)$ using only Up or Right as available moves and staying above the diagonal for all time is equal to the Catalan number is so tricky.
At least the slickest proof I know
I need a framework for the whole discipline which I was never able to build. What do you care about? Why do you care? What tools do you havr for these? How do those tools affect the way you think about the objects?
Hey everyone!
For matsumura it felt like maybe that was the theory of associated primes but that sorta lost me
Then I became a topologist and stopped thinking about anything
hi Demonark
How's everything going?
22:41
I think that's unnecessarily self-deprecating, Mike.
Hi @Daminark
@MikeMiller maybe one could say that commutative algebra abstracts some structures that appear in fundamental objects of algebraic number theory, algebraic geometry, invariant theory and elsewhere. It's hard to care about, say Dedekind domains unless you've seen them in a course on algebraic number theory or you see their relation to the group law on an elliptic curve
The reasons to care is related to the applicability I think (unless you're a crazy algebraist like me who just loves to learn about rings even without any motivation). The most basic example is perhaps the structure theorem for f.g. modules over a PID which is on the border between linear algebra and commutative algebra. It allows an elegant treatment of some advanced linear algebra, classifies finite abelian groups and is used all over the place when you deal with Dedekind domains in ANT
Other examples are e.g. the Noetherian hypothesis which allows an easy treatment of primary decomposition and stuff like the Hilbert basis theorem implies geometrically that varieties are cut out by finitely many polynomials
I could go on, but I think you get the idea. Some structural insight on special classes of commutative rings gives interesting results in other fields. As for the fundamental tools, I'd say that the two fundamental tools in a modern treatment of commutative algebra are localizations and module theory (I'm no expert, this is just my personal impression)
I suppose it would be nice to see a presentation that clearly explained its fundamental tools and where they appear
But perhaps this is ignorance: I have an understanding of that in differential geometry and topology because I've done a lot
I haven't done a lot of algebra
I remember when you were gonna be an algebraic number theorist. Damn, I'm old.
22:54
I do too
And now I still care about Dedekind rings, but only because submodules of flat modules are flat
The algebraists have long since broken me
No need to assume Noetherian then, that still works for Prüfer domains
Dedekind domains are nice because fractional ideals are invertible
Basically implies line bundles over $\text{Spec} D$ have inverses under tensor product.
ie the ideal class group works
Localizations allow us to restrict our attention to certain subsets of the spectrum, so if you think of a commutative rings as a ring of functions on the affine scheme, this is like the analog of restricting functions. This allows us to do an algebraic analog of a partition of unity argument.
(An "algebraic partition of unity" is just a finite set of elements that generates the unit ideal, but if you work out what this means for thecorresponding subsets of the spectrum, it becomes clear why this is called partition of unity)
Yeah it's just (weak) Nullstellensatz
The open sets are so fucking huge that it's a dumb notion :3
(Not really, actually: the partition of unity plays the same role in proving that the structure presheaf is a sheaf)
even more important perhaps than partitions of unity are localizations at prime ideals, these are the stalks of the affine scheme, so it's a bit like a tangent space on a manifold which is the stalk of the sheaf of $C^\infty$ functions
Localization of a prime ideal is a standard argument because local rings are easier, just like linear algebra is nicer than differential geometry. (But probably not that much easier) I don't remember who wrote it, but I read somewhere that the parts of commutative algebra which are well understood are often the parts which have been succesfully reduced to local rings
23:01
Ahem.
I'd say the other fundamental tool is module theory, so instead of studying a ring directly, we study who it acts on abelian groups. So we can associate to each ring a really nicely behaved category that reflects some properties of the ring and for commutative rings even completely determines the ring (Morita-equivalent rings have isomorphic centers)
I guess this is justifies that a lot of objects that come up naturally are modules. If $R$ is a ring, then each ideal is a submodule, the quotient by the ideal is a submodule, if $f: R \to S$ is a ring homomorphism, it makes $S$ into a $R$-module and in the commutative case, you easily also get the $R$-module structure on Hom-Sets where on the modules is a $R$-module (this is more difficult for non-commutative rings)
This means that one can apply results on modules in a quite flexible way
Of course there are also examples in othe disciplines, e.g. in diff geo the sections of a vector bundle are a module over the ring of smooth functions (even a module sheaf over the ringed space.) Or representations are modules over group algebras, but that's mostly noncommutative, so yeah.
but the idea behind studying modules over a ring to understand the ring itself is the same idea why you would study group actions or linear representations to understand a group, you pick a nice category and study how your object can act on that category
@MikeMiller Does that make commutative algebra a bit less mysterious?
It was definitely a nice explanation and I very much appreciate it, but I think I'd heard most of that before. I think I need to get my hands dirty at some point to really understand this
sure, nothing can replace that
Mike Miller, you share the name of an NBA sharpshooter. Are you aware of this?
Then the question is finding time
I am
23:12
Yay :)
There are in fact a great many Mike Millers, at least three on the StackExchange network
Surely more, and I've only encountered 3
At my undergrad people frequently emailed Mike Miller, the head of IT, instead of me; my email was smmiller and his was mmiller
Guys, I got a 48/50 on my representation theory homework! He took of two points because I assumed the result that if a vector space is irreducible, then its dual V* is also irreducible :(
Thats a funny anecdote :)
You got 96%? That's great!
Im very pleased! Do you know how to prove the result I did not prove?
23:14
Remember that mistakes are an important part of learning; if you never made mistakes I bet you would not learn as well
But of course you should then strive to use those mistakes as an educational tool
That is a very good philosophy
@NicholasRoberts are you working over $\Bbb C$? If you do, then character theory is probably the easiest
is $V$ finite dimensional?
Hm, indeed we are over C.
makes a "run of the Miller" joke
23:16
Yes V finite dimensional irreducible representation over complex numbers. We wish to show V* is irreducible
It's much easier to prove that if $V$ is reducible then $V^*$ is reducible, and then use the fact that there is a natural isomorphism $V \to V^{**}$
(which respects the group action)
Will V and V** be isomorphic as reps? I know they are as vector spaces
Yes. Try to prove this yourself
(The map you know is an isomorphism will respect the group action, you just need to show that)
23:18
So, we need to show that the image of an element under the isomorphisms satisfies the group action axioms?
Im confused by when you say "with respect to the group action"
I'm saying "respects the group action", aka "is a homomorphism of representations", aka $f(gx) = gf(x)$
Ah, intertwining operator
By definition two representations are isomorphic if there is a vector space isomorphism $f: V \to V'$ so that $f(gx) = g f(x)$ for all $g$
Terrible name! But I will relent; it's surely a name liked by history
Ah now I see. So we take the canonical isom. into the double dual and show this property that you just stated holds.
Seems fine to me. And once we establish this, we get that V** is reducible
Now what?
We showed earlier that V** is reducible; we're proving something about V and V** here (what are we proving, precisely)?
23:24
you mean V*
I do not. I think I have been unclear about the strategy, though I also think I should stop giving details soon so that you can do it yourself ;)
I am suggesting a proof by contrapositive: suppose $V^*$ is reducible, and prove that $V$ is reducible as a result.
Lol, im trying to quote your message but cannot
You know that the dual of a reducible representation is reducible, so $V^{**}$ is reducible
23:26
Ok I see now
The rest is all you buddy
23:56
@MikeMiller what are some applications of homological algebra?
hi chat

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