Mathematics - 2017-12-05 (page 5 of 5)

11:00 PM

Perhaps :P Both are fairly common in Greece.

11:26 PM

@AkivaWeinberger Yo, broh :) Do you have time and are willing to check "my" proof above?

11:36 PM

@nbro Remember how $h$ was defined

or, the relation between $g$ and $h$

if anyone is familar with relation algebra, please check: math.stackexchange.com/questions/2552936/… and help if you can

stuck on it for hours

@AkivaWeinberger Yes, one is a shifted and scaled version of the other...

Write me a formula

@AkivaWeinberger $\langle x,y \rangle = \dfrac14 (\|x+y\|^2-\|x-y\|^2)$

@AkivaWeinberger I wrote already the relation between $g$ and $h$ in the first part of my solution...

But I am unsure how to conclude what I have to conclude

Because $c_n$ is a constant

So, more specifically, we have $g(\frac{N}{2\pi}(y + \pi)) = h(y)$ or $g(x) = h(\frac{2\pi}{N}x -\pi)$.

11:53 PM

any discrete number theorists here?

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