If $b_1,\dots,b_n\in V$ form basis of vector space $V$, does that mean that there is no linearly independent vector $v\in V$ of $b_1,\dots,b_n$, right?
@Sush because pivot columns have only that term in 1 equation (say you have four equations) so there is no way of expressing other variables in terms of a tat variable
@Chris'ssis greetings to the awesome one who asks questions on math stack, and when people answer using paragraphs and paragraphs of working....at the end the one who answers it using the least amount of steps and space :p
@TheArtist Have you seen this one? springer.com/mathematics/analysis/book/978-1-4614-6761-8 Try to get that and study it in small details again and again. Besides that, on MSE there are lots of qurstions from where you can learn a lot of very precious things.
@TheArtist Anyway, I gotta leave to eat and go attend an optics and a math tutoring class, so if you have any "eureka" moments or hints, tag me and I'll see them later.
@Chris'ssis I will get the first book first ;) must not get more than one at one time :p I tend to then check both books at curiosity and not finish none :/
@Chris'ssis soemtimes it's hard to believe in yourself :p
@Chris'ssis thanks for the advice :)
@Chris'ssis and for the book ;) :)
@Committingtoachallenge you know I stalked some profiles today of top users, there was this guy on the top list...he has put that he will deactivate it :p is there anyway to get hold of his account? :p why deelete wen you can give off to others :/
@TheArtist, I think I couldn't understand! $$ \begin{matrix} 0 & 0 & 1 \\ 1 & 0 & 1 \\ 0 & 1 & 1 \\ 0 & 0 & 0\\ \end{matrix} $$ is echelon matrix and third column has no pivot, but it is not linear dependent on first two columns!
@Committingtoachallenge nono I don't want to steal.. If they have collected 70k reputation, why just delete it. Give it off to someone else who wants :p
@Sush the first two columns are dependant on the third , the third column contains free variables
@Sush if you think I didn't get your question properly :) please rephrase it :) because im not 100% sure what you mean either
@Committingtoachallenge but he's finding a way to deactivate it :p , if one can contact him and tell okay give me the password we will deactivate and then change the pro pic and name :p
I'm sure you guys can briefly get the result by some methods of complex analysis, but now
I'm only interested in real analysis methods of proving the result. What would you propose
for that?
$$\int_0^{\pi/2} \frac{x^5}{2-\cos^2(x)}\ dx$$$$=\frac{\pi^6 \sqrt{2}}{768}+\frac{5 \sqrt{2}\pi^4}{64}\op...
@Chris'ssis can you suggest any book which you have or read or consider good for the types of integration you posted just before or for the related topic
i have no idea about Li, Ei, and other special functions, which I am interested in
@TheArtist If you click on the arrow on one of those lines, it will make your comment in response to that one... it will put an arrow to the left of your comment which can be used to find out to which comment yours refers. Furthermore, you don't need to type the user's name; it is put there for you.
@TheArtist It is a special function, which means that your integral cannot be written with the usual functions $$\mathrm{Li}_{\color{#C00000}{2}}(x) =\sum_{k=1}^\infty\frac{x^k}{k^{\color{#C00000}{2}}}$$
@TheArtist I guess so, but are you using them to test your knowledge, or are you talking about the grades from a course reflecting general math ability?
@robjohn I know its good for a teacher to check if students know the material....but using it as a measurement of your knowledge and intelligence and math ability is wrong right?
@Hippalectryon Often (just the part with dreaming integrals). However, there is something interesting in my dreams, there I'm like a super human, the way I talk, the way I move, the way I solve questions, my creativity is beyond measure, but then I wake up ... (and I lose all)
@Chris'ssis I don't like questions where the answer has a bunch of special functions in it. $\mathrm{Li}_n$ is not as bad as some, but it still leaves a bad taste.
@Chris'ssis I spent what time I had before I left in trying to write out what you were asking. There are only a few ways I know to approach things like that complicated sum of quotients.
@robjohn Trust me, it's not as bad as it seems to be. My research shows that the most terrible things seems to be a piece of cake when approaching them properly.
@UserX open up the books and read the theory. understand them thoroughly. read the theorems, memorize them but not as facts but as problems. exercises. then sleep on them. you'll figure why they are true.
I have found a closed form for the following new series involving non-linear harmonic numbers.
Proposition. $$\sum_{n=1}^{\infty} \dfrac{H_n^2-(\gamma + \ln n)^2}{n} = \dfrac{5}{3}\zeta(3)-\dfrac{2}{3}\gamma^3-2\gamma \gamma_{1}-\gamma_{2} $$ where \begin{align} & H_{n}: =\sum_{k=1}...