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10:00 AM
I am sea turtles :)
 
which one
there's a shit ton
 
how do I specify which one?
 
well there's a lot of people with that username
@anon I added you
 
@anon, how (x^(ab)-1)/(x-1) is divisible by (x^a-1)/(x-1)?
 
when you divide the first by the second, you get an integer
 
10:06 AM
Hello everyone.
 
hi
 
Just a small formatting question (I tried a few things but couldn't get it)
 
@anon, many many thanks sir, got everything clear.
 
How to represent 10C4 ?
 
in LaTeX?
 
10:07 AM
I tried $10\choose4$
yes I suppose
 
$\binom{10}{4}$
 
Ok thanks @Sush
 
${}_{10}C_4$, although higher up we use $\binom{10}{4}$
${10\choose4}$ actually works just as well
 
A troop 5 meters long starts marching. A soldier at the end of the file steps out and starts marching forward at a higher speed. On reaching the head of the column, he immediately turns around and marches back at the same speed. As soon as he reaches the end of the file, the troop stops marching, and it is found that the troop has moved by exactly 5 meters. What distance has the soldier travelled?
 
Thanks @anon I am not using the curly braces properly
 
10:17 AM
@AshishNitinPatil, will you answer me please?
 
Sorry @Sush was busy for a bit
Looking into your question
 
@AshishNitinPatil, thnx.
 
Let's say the troop has a speed x metres per hour.
And let's say soldier moves with x+y speed.
Total Time taken = 5m/x (troops speed)
Gimme some time :P
 
Calc iv is making me sad
 
10:32 AM
I see
 
http://assets.openstudy.com/updates/attachments/52981fbbe4b04e12f8221eb3-usukidoll-1385715305230-scan1310240004.jpg
#14 is making me mad
 
the length is given :/
 
my lame attempt seen here
http://openstudy.com/study#/updates/52985c22e4b04e12f8222aa1
 
@AshishNitinPatil, don't we get a numeric answer?
 
@Sush Lets keep T & S for speeds of Troops & Soldier respectively
Thus, 5 x T is total time taken
 
10:35 AM
what is happening
 
While going in same direction, soldier takes (T - S) x 5 time
While in the opposite direction (T + S) x 5
Thus, 5T = (T-S)*5 + (T+S)*5
I am sorry
5T = (S-T)*5 + (S+T)*5
I goofed it up again.
 
@AshishNitinPatil, Oh don't worry. if i ask this on main site without my any effort, will I get answer? What is your advice?
 
Ok answering in a bit
@Sush link to the question please
 
@AshishNitinPatil, pardon my ignorance. which link do you want?
 
anyone good at automata / formal languages?
 
10:42 AM
I'm a fuzzball in calculus iv
 
@Sush Oh, you haven't actually asked, that's ok, give me a bit
of time
 
@usukidoll have you tried the Khan Academy?
 
T_T I can't help it if my prof wants this assignment ASAP and his lectures are so slow and some other stuff just pops up I just...feel...overwhelmed
 
@Sush I feel like there is a cute, nonalgebraic way to solve this.
 
@KarlKronenfeld, will you mention it for me please?
 
10:46 AM
I would love that too... currently I am messing up simple speed-distance-time arithmetic :/
 
@Sush I don't see it yet.
 
Soooooo, what should I do? shall i ask it on main math.se without any effort?
 
I'm just working on it for my own enjoyment. Do what ever you would like.
 
@Sush you should ask on the main site than relying on me.
 
@KarlKronenfeld, I am waiting. I think the answer should not be "information is lacking"
 
10:49 AM
I do think so @Sush
But, that's a maybe
 
@Sush I think there is enough information, i.e. I could do it algebraically, I think. I just want to exploit a symmetry that I noticed to see if there is a nicer solution.
 
iv?
 
@AshishNitinPatil, thanks. It is the question from "TEST OF MATHEMATICS AT 10+2 LEVEL" book and have tried for it a lot.
 
brb afk (Gotta go & check my exam paper)
 
I give up T_T
cries
 
10:55 AM
nvm :(
 
I need a shoulder to cry on T_T
 
don't you have shoulders?
 
Cries
 
Where did all these new people come from
 
Let the speed of the troop be x mps and the speed of the soldier be
y mps. Then, (5/x+y) + (5/x–y) = 5/y
OR 2x/(x^2 – y^2) = 1/y
OR x^2 – y^2 – 2xy = 0

OR x/y = (1 +- 2^1/2)/1 Since, distance is directly proportionate to speed. Hence when the troops travels 5 metres the man travels 5(1 +- 2^1/2)/1 m. Distance cannot be negative. So, the distance traveled by the soldier = 5(1 + 2^1/2) m.
 
11:02 AM
This chat has LaTeX support
 
hey
Anyone know how to use write reports in latex here?
I am having some problems with my bibliography
 
I think you're probably the most knowledgeable person here on the topic
lol
 
 
1 hour later…
12:30 PM
Hello
I have a question
 
What's that, carpe?
 
I am considering the following series of functions: \sum \frac{1}{1+n^2 x}
I showed that this series converges point wise on ]0;+\infty [
And am considering at this point the normal convergence
 
Are you sure there's no typo?
 
the sequence of functions is clearly bounded
Sorry yes
edited
 
Ah ...
 
12:33 PM
So I was wondering what is ||\frac{1}{n^2 x}||_{\infty} equal to ?
 
Right.
 
is it \frac{1}{n} or \frac{1}{n^2}
 
Do the calculus exercise. Where is its maximum?
 
ok thank you
It is very strange. The derivative is always negative on ]0;+\infty [
Therefore the function is always decreasing
@TedShifrin
 
is there a type of matrix or easy way to find if the eigenvector*eigenvalue of A'A are of equal length
okay ignore that ive misinterpreted the question
need to find when the eigenvector of A'A=eigenvector of a
 
1:03 PM
Greetings
I remember that some time ago I wondered if there is a brilliant elementary way to test the convergence of $$\sum_{k=1}^{\infty}\sum_{n=1}^{\infty}\sum_{p=1}^{\infty}\frac{1}{(k+n)(k+p)(n‌​+p)}$$
(after I created it - - of course)
 
@Chris'ssis My first guess is that it diverges, but I would have to check to be sure.
 
@robjohn True.
 
1:19 PM
Note that there are six regions: $k\gt n\gt p$, etc...
 
@robjohn. Can I ask you to verify something after you've finished helping Chris's sis ?
 
@Chris'ssis It should converge if you let the summation index start from 2. I think.
 
@MatsGranvik Apparently it seems it converges, but no. It's a deceiving question.
@robjohn Right.
@robjohn For instance, one may extend that 3-series to a 12-series. Perhaps some inequalities help there too.
(or extended to n-series, say n is large)
 
@robjohn, or someone else please! I asked here that "A troop 5 meters long starts marching. A soldier at the end of the file steps out and starts marching forward at a higher speed. On reaching the head of the column, he immediately turns around and marches back at the same speed. As soon as he reaches the end of the file, the troop stops marching, and it is found that the troop has moved by exactly 5 meters. What distance has the soldier travelled?
" and got badass' answer http://chat.stackexchange.com/transcript/message/12399036?noredirect=1#12399036 I can't understand it . Will you pleas
 
@robjohn I am considering the series of functions $\sum \frac{1}{1+n^2 x}$
I showed simple convergence and am now considering normal convergence
It is clearly bounded but I am trying to determine $|| ||_{\infty}$
I now that the limit in $0^+$ of the sequence of functions is n
 
1:31 PM
$$
\begin{align}
\sum_{k=1}^\infty\sum_{n=1}^k\sum_{p=1}^n\frac{1}{(k+n)(k+p)(n+p)}
&\gt\sum_{k=1}^\infty\sum_{n=1}^k\sum_{p=1}^n\frac1{8k^3}\\
&=\sum_{k=1}^\infty\sum_{n=1}^k\frac{n}{8k^3}\\
&=\sum_{k=1}^\infty\frac{k^2+k}{16k^3}\\
&=\infty
\end{align}
$$
@Carpediem summing over $n$, I assume?
 
yes but I found the answer, it's easy
The sequence of functions is decreasing
 
@Carpediem Are you sure it is bounded? as $x\to0$, I don't think it is.
 
@robjohn Yes, it works.
 
Therefore the sup is reached in 0
 
@robjohn, please help me too!
 
1:34 PM
And f_n(0)=1
 
@Carpediem at $x=0$, the series diverges.
@Carpediem Monotone Convergence says that the function has to be unbounded as $x\to0$
@Sush with what?
 
@robjohn, I asked here that "A troop 5 meters long starts marching. A soldier at the end of the file steps out and starts marching forward at a higher speed. On reaching the head of the column, he immediately turns around and marches back at the same speed. As soon as he reaches the end of the file, the troop stops marching, and it is found that the troop has moved by exactly 5 meters. What distance has the soldier travelled?
" and got badass' answer http://chat.stackexchange.com/transcript/message/12399036?noredirect=1#12399036 I can't understand it . Will you please help me?
 
@Sush Try striking out all the words that are not nouns. Then draw some arrows and lines and you can almost see the equations behind the text.
Verbs can be rewritten as processes between nouns.
 
Carpe, you're right, so what do you conclude ?
 
@MatsGranvik, why and how did we get $\frac{5}{x+y}+\frac{5}{x-y}=\frac{5}{y}$?
 
1:46 PM
@TedShifrin It does not converge normally on ]0, +infty[
but if we consider an element x \in ]0,+\infty[ , it converges normally on [x,+\infty[
@robjohn
 
Good. I would use a different letter than $x$ in the last sentence, though.
 
Let's take $a$ then
Just want to make sure regarding something
the max is 1 ?
 
Yup.
 
@Carpediem Yes. Away from $0$ it is nice
 
The max occurs at $a$. :)
 
1:49 PM
Ah ok because of the divergence
at 0
 
@Sush $(\sqrt2+1)5$ meters
 
@Sush This question that I asked did not get any upvotes but the notation technique should be able to analyze your problem: math.stackexchange.com/questions/396267/…
 
@Sush Ah, I see that I agree with badass.
 
@robjohn, will you please help me understand what he says?
 
@Sush I took the length of the troop to be 1 unit and their velocity to be 1. I then took the speed of the lone soldier to be $v$ and the time it takes him to overtake the troop to be $t$.
@Sush that gives $vt-t=1$ since that is the distance difference of the troop and the soldier
 
1:56 PM
@robjohn, still I can't understand at all!
 
@Sush let me draw a picture...
 
2:07 PM
@TedShifrin Can I ask you another question ? Is the series continuous wherever the series converges ?
 
Oh, man, I love Arthur Fischer's spam-replacement edits :D
 
@Sush So we get $\frac{2t-1}{t}=\frac1{1+t}\implies t=\frac1{\sqrt2}\implies v=1+\sqrt2$
Make more sense?
 
2:32 PM
Carpe, what do you think?
 
Is $1/4$ the maximum of $x^2+y^2-xy$ when $0\leqslant x,\,y\leqslant 1/2$?
 
2:45 PM
@IanMateus Yes, it is.
 
@DanielFischer thanks, how did you do it?
 
@IanMateus Looking for critical points in the interior (none), tracing along the boundary.
 
@DanielFischer I'm sorry, but how exactly "tracing along the boundary"?
 
@IanMateus By symmetry, only the parts $\{ 0 \leqslant x \leqslant \frac12, y = 0\}$ and $\{ x = \frac12, 0 \leqslant y \leqslant \frac12\}$ need to be considered. On the first, you have $x^2$, which evidently attains the maximum for $x = \frac12$. On the second, $\frac14 + y^2 - \frac12y = (y - \frac14)^2 + \frac{3}{16}$.
 
3:00 PM
@DanielFischer I got it now, thanks!
 
@IanMateus maybe it also help to look at x^2-xy+y^2 as a simple quadratic equation in variable $x$.
 
3:21 PM
@Chris'ssis thanks, how is your mathematics going today?
 
@IanMateus Thanks. It works pretty good. I play with some beautiful questions. :-)
 
@Chris'ssis More questions from your students?
 
@IanMateus I have one very nice! Happily I did it yesterday.
 
@Chris'ssis mine is certainly not excellent today... It never has been, but I'm working it out. Hehe
@Chris'ssis show it!
 
OK.
 
3:23 PM
$(\partial u/\partial x)^2+(\partial u/\partial y)^2=1$
 
@PabloRotondo Yes, but they aren't my students since I'm not a professor.
 
How can we show that the $u$ could be expressed locally as a sum of a distance function to a curve and some constant?
 
@Chris'ssis Haha, last time we chatted here I understood that they were your friends/students
 
@IanMateus this is the nice question. Compute $$\sum_{n=1}^{\infty} (\text{arccot}(n)-1/n)$$
@PabloRotondo Indeed! :-)
 
@Chris'ssis oh, I've seen robjohn's solution yesterday, awesome! It doesn't even seem to converge at first glance
 
3:28 PM
@IanMateus This one has a nice closed-form. It's a different one!
 
@Chris'ssis really? I thought they were the same
 
@IanMateus No, they are different. Moreover, i wonder if there is a straightforward way to compute this one.
(let's say we don't want to employ @robjohn's solution-way)
 
@Chris'ssis hi, Chrissy Chris! :)
 
@Charlie The great Cat!!!!!!!!! Helllooooo! :-)
 
@Chris'ssis what is your way? I have to go to the park with my dog, but I will look when I get back.
@Chris'ssis Oh, this is different. I should try this one.
 
3:32 PM
@Chris'ssis :))))))))) how are you?
 
@Charlie Hi :D
 
@robjohn Riemann zeta function. I don't have the solution in latex yet. Later I'll type it.
 
@IanMateus hi :)
 
@Charlie Have you seen this?
 
@IanMateus yup
 
3:47 PM
@Charlie Attending some problems! How about you? :D
 
4:03 PM
@Chris'ssis I'm melting
 
@Charlie Poor cat :-(
 
@PedroTamaroff We endow $X\times \mathbb{R}$ with the metric $\delta((x,s),(y,t) = d(x,y) + \lvert s-t\rvert$. That induces the product topology and makes it a complete metric space. $f\colon X\times\mathbb{R}\to\mathbb{R};\;f(x,t) = t\cdot d(x,U^c)$ is continuous. Consider the closed subspace $\tilde{U} = f^{-1}(1)$. Complete, obviously, $x \mapsto \left(x,\frac{1}{d(x,U^c)}\right)$ is a homeomorphism $(U,d)\to\tilde{U}$, and an isometry for $d'$. Done.
 
Hal
4:19 PM
Hello. Could anyone tell me how to write, in notation, "there is some difference between set A and set B" (I don't deserve to be in this chat room)
 
@Hal $A \neq B$?
 
@Chris'ssis :(
 
@Hal try Chris Langans syndiffeonesis.
 
@Hal why you don't deserve? :)
@Chris'ssis any nice problem?
 
4:40 PM
@Charlie A really nice one?
 
@Chris'ssis a really nice one
 
@Charlie Got it. Try this one! :-) $$\sum_{n=1}^{\infty} \arctan\left(\frac{1}{F_{2n-1}}\right)$$
 
@Chris'ssis Oh no!
 
@Charlie Fibonacci numbers ... :D
 
hahah $F$ Fisher snedecor distribution :P
 
4:42 PM
@Charlie I sent it to one of my former professor ... no hope ...
 
@Chris'ssis :///
 
@Charlie Well, I did it on my own. (no help needed)
 
@Chris'ssis because you're very good
 
@Charlie If I were good I'd be a professor ...
 
@Chris'ssis you just need to teach
 
4:46 PM
@Charlie I don't think I have the necessary skills for doing that.
 
@Chris'ssis to teach?
 
Hal
@Charlie thank you.
I said I didn't deserve to be here because it was such a simple question.
 
@Charlie to teach at a certain level.
 
@Hal so what? :)
@Chris'ssis teach what you know, learn more, then teach what you learned
 
Hal
Ha, I was expecting to be flamed out of here.
 
4:48 PM
@Hal of course not
 
Hal
The thing I'm starting to notice about math-people - is how interested they are in other people getting to know math
 
yes
I like when people have curiosity in learning math
 
Hal
I've never bumped into the attitude that conveys "buzz off kid, you don't know enough to be in our club"
 
@Hal that's rude
 
Hal
It's usually the opposite - like you just said
I agree. It's just such a strong and consistent contrast, it makes me wonder if there's some underlying construct (as the social scientists might say)
Anyway, whatever it is - it's encouraging in more than one way.
 
4:53 PM
DAMN
@Hal some people like being pedant
make others feel they are dumbs so he/she will seem to know more
 
@Charlie are you trying to tell me something about Gaussian distribution?
 
@Chris'ssis yup :) I like it, it's cute
normal distribution
it's fascinating
@Chris'ssis do you like it?
 
Hal
$A \neq B$? <- is this actually written with the letters neq and dollar signs, or is that markup for something?
neq is for the not equals sign?
 
@Hal it's rendered using mathjax, so wjen you install it on this chat you see the symbols
 
Hal
Okay.
 
4:58 PM
@Hal yes, \neq is different
 
Hal
Does that appear as equals with the slash? I'm trying to avoid the equals sign. I'm using this for a philosophy paper, and the problem I'm addressing, I believe, has to do with abuse of the = symbol.
So I'm trying to avoid using it.
 

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