I found this theorem after a search:
"Let L be the linear transformation
L(v) = Av
then A is diagonalizable with n linearly independent eigenvectors S = {v1, ... ,vn} if and only if the matrix of L with respect to S is diagonal."
Do you know if it is true the other way around?
What I mean is, if A is diagonalizable with n linearly independent eigenvectors S = {v1, ... ,vn} then the matrix of L is diagonal.
Is that true?