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00:29
@Tan Yong Boon: Regarding enolization of ketones with organometallic reagents, here are two links to the problem in total syntheses. pubs.acs.org/doi/pdf/10.1021/ja00992a032; pubs.acs.org/doi/pdf/10
 
2 hours later…
02:57
@TanYongBoon ooh thanks
 
1 hour later…
04:21
@TanYongBoon: Second link is this one: pubs.acs.org/doi/abs/10.1021/ja00060a006
 
12 hours later…
16:32
@Martin-マーチン …sorry for what? Whatever, no problem. I'm wondering rather why I was unable to re-vote close (whatever option) after retracting.
@mykhal I just said sorry for summoning you to chat. I usually don't use the süperping to get messages out there; but you haven't been in here for a while. ;) I don't really know the reason, i guess there is a meta.se post about it, why you cannot add another flag on it...
a workaround would be to leave the cv pending and add a custom flag to us mods (if that is possible)... or ping us here in chat
 
6 hours later…
23:01
@mykhal There's a time limit - you can't closevote the post for maybe a month after you put "unsuccessful".
I mean re-voting is possible only after a long time.
23:41
Hi everyone, I feel a bit ashamed to ask this question but I'm starting to be crazy at the moment after days trying to model a Fischer-Tropsch multitubular reactor. I have a given intrinsic rate for CO (called rFT) in mol_CO / (m^3 . s)
Now the thing is that I feel confused by all the results I get
So just to be sure, given the reaction nCO + (2n+1)H2 --> C_n + nH2O (where C_n is an average alkane I know I will have to implement it in another way but my question for the moment is mostly about the rate of CO and H2 only) is the rate of CO, rCO, equal to - rFT? (the value is given positive) or - n * rFT ?
(sorry for the latex) because if we have $\ce{\nu_A A + \nu_B B --> \nu_C C + \nu_D D}$ then $r = \frac{1}{\nu_A}\frac{d[A]}{dt}=\frac{1}{\nu_B}\frac{d[B]}{dt}=...$ and for me my rFT correspond to the "r" although I'm not sure :/
@Hexacoordinate-C Something like ASPEN software would make this thing of yours so many times more simple...
Yes but I have to do it without ASPEn
Can't cheat? ;)
And I mean this is chemistry so... I want to be sure about my kinetics understanding
I've slept less than 5 hours for days and I'm shivering at the moment so I'd like to have some confirmation I'm not crazy
no cheating
@Hexacoordinate-C Maybe masochistic :>
23:55
Also to calculate rH2 I'd like to know if I need to take in consideration the ratio of molar weight? At first I thought it was a good idea to convert the mol_CO /( ...) into mol_H2/(...) but now I'm thinking about the ratio of stoechiometric number I've already done...
Well this is the purpose of my project to do it by hand. My professor used to do it in Fortran so I should succeed
@Hexacoordinate-C These profs with fortran :D
Never changes
If I don't use molar ratio this is what I get...
And if I do use it which seems to me a good idea although it's not written in the kinetics equations (i.e. $r = \frac{1}{\nu_A}\frac{d[A]}{dt}=\frac{1}{\nu_B}\frac{d[B]}{dt}=...$) I get

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