@M.A.R.ಠ_ಠ :P I realized I probably wouldn't be able to identify with a diborane. If I log into my account, I would want to see myself. So, yeah, I decided not to change names :-)
Write the reduction half-reaction for the reduction of elemental oxygen in the presence of water, producing hydroxide ions
This does not make sense to me - a half reaction (from what I understand) is when you have an "element + some number of electrons -> element charged" or "charged element...
a. $\ce{PH3}$
b. $\ce{HBr}$
c. $\ce{SO2}$
d. $\ce{N2}$
I believe that it is $\ce{N2}$, but I'm not too sure, since technically all of them would act the same at STP.
In the recent Nature Chemistry paper I-motif DNA structures are formed in the nuclei of human cells (open access link in LATimes) figure 1a shows "Schematic of i-motif and G4 structures."
I'm not a biologist, nor a chemist, so please forgive if the answer to my questions seems obvious. I've ...
For the reaction,
$$\ce{M -> M+ + e-}$$
the heat liberated is highest for lithium owing to its high negative $E^\circ$ value so one would think that the reaction must be most vigorous.
The reason behind the more violent reactivity of potassium rather than lithium lies in kinetics and not i...
46 upvotes! This must be your dream answer @AvnishKabaj
Yes, Borazine is aromatic.
According to Hückel’s rules, a compound is aromatic if it satisfies three conditions:
Planarity
Complete delocalisation of π-electrons
Presence of $(4n+2)$ electrons where $n$ can be $1, 2, 3, \dots$.
Borazine is aromatic as there are 3 nitrogen atoms in the struct...
Dont know why it was downvoted. This is what is given in books like JD Lee
The first ionization energy (the minimum energy required to eject an electron out of a neutral atom in its ground state) of sodium is about 496 kJ/mol; therefore, sodium is not donating its electron voluntarily. However, it’s also not chlorine that is stealing the electron since the first electron affinity (the energy released when an additional electron is attached to a neutral atom) of chlorine is only 349 kJ/mol and thus not enough to steal the electron from sodium. It’s actually the large lattice energy of NaCl that provides the energy for its formation. — Loong ♦1 min ago
I guess this is one of the most wide-spread misconceptions in early school chemistry.
@Abcd probably, but Martin has commented it below clearly, that while the result is true (borazine is aromatic), but the method to derive it is wrong (Huckel's rules only for carbon cycles). Although I'd agree with you that I didn't know of this before, and if I was in Molly's place I'd have written the same answer as he did
Right, Someone help me as to why Hexaaqua cobalt (III) complex is a strong oxidizing agent and hexammine cobalt (III) complex is stable in Aqueous solution.
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I remember it has something to do with one of them being strong-field ligand and some sort thing but maybe you guys can provide me with an elaborate answer
@Sid sorry sid, I'm in 12th pass and haven't heard of this in our jee prep notes. You'll probably want to ask this on main, seems a good enough question :-)
@Zhe ...In dissociation of PCl5 , if initial mole is $a$, initial concentration is $C$ and degree of dissociation is $\alpha$ , then what would be final mole no and concentration for PCl5 ?