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12:15 AM
@M.A.R.ಠ_ಠ thaaaaanks
Yipeee
 
12:27 AM
Welcome to the CV town Avnish!
@M.A.R.ಠ_ಠ :P I realized I probably wouldn't be able to identify with a diborane. If I log into my account, I would want to see myself. So, yeah, I decided not to change names :-)
 
1:17 AM
Tobe honest, this
0
Q: Reduction half-reaction for the reduction of elemental oxygen

John D Write the reduction half-reaction for the reduction of elemental oxygen in the presence of water, producing hydroxide ions This does not make sense to me - a half reaction (from what I understand) is when you have an "element + some number of electrons -> element charged" or "charged element...

Doesn't seem like it deserved a downvote :(
Another fair question
-2
Q: Ideal gas Law best describes the properties of which of the following gases at 0 degrees Celsius and 1 atm?

user63266a. $\ce{PH3}$ b. $\ce{HBr}$ c. $\ce{SO2}$ d. $\ce{N2}$ I believe that it is $\ce{N2}$, but I'm not too sure, since technically all of them would act the same at STP.

 
"drive-by downvotes", sad. ;-)
(i.e. I agree with you)
1
Q: Questions on DNA structural motifs

uhohIn the recent Nature Chemistry paper I-motif DNA structures are formed in the nuclei of human cells (open access link in LATimes) figure 1a shows "Schematic of i-motif and G4 structures." I'm not a biologist, nor a chemist, so please forgive if the answer to my questions seems obvious. I've ...

 
 
1 hour later…
2:31 AM
@GaurangTandon thanks
 
 
4 hours later…
6:17 AM
46
A: Why does potassium react more violently with water than lithium?

Avnish KabajFor the reaction, $$\ce{M -> M+ + e-}$$ the heat liberated is highest for lithium owing to its high negative $E^\circ$ value so one would think that the reaction must be most vigorous. The reason behind the more violent reactivity of potassium rather than lithium lies in kinetics and not i...

46 upvotes! This must be your dream answer @AvnishKabaj
-2
A: Is borazine aromatic?

MollyCooLYes, Borazine is aromatic. According to Hückel’s rules, a compound is aromatic if it satisfies three conditions: Planarity Complete delocalisation of π-electrons Presence of $(4n+2)$ electrons where $n$ can be $1, 2, 3, \dots$. Borazine is aromatic as there are 3 nitrogen atoms in the struct...

Dont know why it was downvoted. This is what is given in books like JD Lee
 
@Abcd I just got lucky
 
 
2 hours later…
8:43 AM
The first ionization energy (the minimum energy required to eject an electron out of a neutral atom in its ground state) of sodium is about 496 kJ/mol; therefore, sodium is not donating its electron voluntarily. However, it’s also not chlorine that is stealing the electron since the first electron affinity (the energy released when an additional electron is attached to a neutral atom) of chlorine is only 349 kJ/mol and thus not enough to steal the electron from sodium. It’s actually the large lattice energy of NaCl that provides the energy for its formation. — Loong ♦ 1 min ago
I guess this is one of the most wide-spread misconceptions in early school chemistry.
 
9:19 AM
@Abcd probably, but Martin has commented it below clearly, that while the result is true (borazine is aromatic), but the method to derive it is wrong (Huckel's rules only for carbon cycles). Although I'd agree with you that I didn't know of this before, and if I was in Molly's place I'd have written the same answer as he did
@Loong ah, you caught me. It is! :(
 
9:46 AM
@AvnishKabaj I fixed everything else, but can you please fix the second image here? thanks! chemistry.stackexchange.com/q/43181/5026
 
 
5 hours later…
2:32 PM
@GaurangTandon Done
 
Anonymous
3:16 PM
 
Anonymous
@AvnishKabaj Doesn't look like :P
 
Anonymous
Also, can someone please tell me how to fix image sizes?
 
Anonymous
Hey @s.patroller Welcome :)
 
@DivyankaChaudhari I use a phone and the image size is fine there
 
Thanks @DivyankaChaudhari :-)
 
3:19 PM
Look for some fine points of editing
In meta
 
Anonymous
Okay! Thanks @AvnishKabaj
 
Sid
Right, Someone help me as to why Hexaaqua cobalt (III) complex is a strong oxidizing agent and hexammine cobalt (III) complex is stable in Aqueous solution.
 
30
A: Hidden points of editing you probably didn't know

Geoff HutchisonSizing for images If you post to Imgur (the default host for StackExchange) you can use URL suffix codes to change the size of the image in your answer or question: $$ \small \begin{array}{clcc} \hline \text{Thumbnail Suffix} & \text{Thumbnail Name} & \text{Thumbnail Size} & \text{Keeps Image P...

2
 
Sid
I remember it has something to do with one of them being strong-field ligand and some sort thing but maybe you guys can provide me with an elaborate answer
 
Dunz
Nobody answers stuff over here
2
You'd have better luck at the main site @Sid
 
3:48 PM
@GaurangTandon But Huckel's rule just works for many inorganic compounds... there are more examples I have seen (cc: @Martin)
 
@Abcd well, mart is a computational organic chemist. If he says it doesn't work, then it doesn't work. I take that as a citation :-)
@AvnishKabaj thanks dude
 
@GaurangTandon KK, nevertheless its a good JEE trick ;)
 
@Sid sorry sid, I'm in 12th pass and haven't heard of this in our jee prep notes. You'll probably want to ask this on main, seems a good enough question :-)
 
class?
not pass?
 
I just gave 12th final exams, but results aren't out yet. So I'm in no man's land atm @JavaScriptCoder
 
3:54 PM
@GaurangTandon I wonder why JD Lee uses Huckel's rule. Even he is a renowned inorganic chemist...
 
@Abcd ha yeah
 
@GaurangTandon when r ISC results
 
@Abcd somewhere about mid may
@Abcd no clue :/
 
@GaurangTandon how much did you get in ICSE, how much are you expecting now?
 
@GaurangTandon that must suck :P
 
4:05 PM
@Abcd confidential
@JavaScriptCoder haha unless you get a decided college, it does :P
 
He errybody
Hi*
 
Hi
 
back in the lab!!
 
great
 
time to find out if silica pad workups are ruining my product >:- (
 
4:53 PM
@Sid I can answer this, but I would much prefer the space of the answer box. Chat isn't enough.
 
Sid
@orthocresol So, it's a decent enough question for the main site?
 
Yes, I think so
 
@Sid post it up!
we're always happy with non-obvious chemistry
questions
 
Sid
Posted the question.
I could probably have written something better but exams. >.<
 
5:08 PM
You know it might just get close voted
 
5:32 PM
@Abcd Hückel's rules for inorganic compounds? That doesn't sound right...
 
6:00 PM
Can anyone help me out ?
Regarding Kp and Kc ...
 
Zhe
@NehalSamee What do you need?
 
@Zhe ...In dissociation of PCl5 , if initial mole is $a$, initial concentration is $C$ and degree of dissociation is $\alpha$ , then what would be final mole no and concentration for PCl5 ?
In equilibrium ...
@Zhe ... ... ?
 
Zhe
6:21 PM
@NehalSamee What are you dissociating into?
PCl3 and Cl2?
 
 
1 hour later…
7:29 PM
@Zhe ... Yes ...
 
Zhe
8:27 PM
@NehalSamee Once you have the balanced equation, you can just write the table of initial concentrations, deltas, and final concentrations
so, C, 0, 0
-x, +x, +x
$x^{2}/(C-x) = \alpha$
 

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