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cuonglm
cuonglm
14:43
Does anyone face this problem in zsh
0
Q: Why zsh precommand modifiers stop accepting arguments if quoted?

cuonglmzsh has precommand modifiers, which precede a command to alter how command is interpreted. Some of them are command and exec. $ zsh -c 'exec -a foo zsh -c "print -- \$0"' foo $ zsh -c 'command -v ls' /bin/ls But they stopped accepting arguments if quoted: $ zsh -c '\exec -a foo zsh -c "print ...

zsh
lgeorget
lgeorget
zsh -c '\exec -a foo zsh -c "print -- \$0"' gives me the same error as yours
however \exec -a foo zsh -c "print -- \$0" in a zsh shell works (and closes the shell immediately)
don't know what to think about it to be honest
cuonglm
cuonglm
exec replace the shell with the new command zsh -c
zsh -c finish and quit immediately
lgeorget
lgeorget
14:59
yes, I understand that part
but I don't understand why the first command does not do the same thing as the second one
cuonglm
cuonglm
because it wraps in another zsh -c
lgeorget
lgeorget
Ah, got it. So actually, the second command probably gives the same error as the first one, we just don't get to see it because the shell closes right away

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