Write the smallest code that prints the lyrics for Queen's Bohemian Rhapsody.
There are quite a few means in mathematics, such as the arithmetic mean, the geometric mean, and many others...
Definitions and Task
Note that these are the definitions for two positive integers :
The root mean square is the square root of the sum of their squares halved ().
The arithmetic me...
1
I want to use a bash script to do the following things:
Monitor the data of traffic used, those data are provided by the vnstat program.
run the poweroff command if the traffic usage is large than 1 GiB.
I write a script as shown below:
#!/bin/bash
ax=`vnstat --oneline | awk -F ";" '{print $...
0
I was recently going through some posts in the Low Quality Posts, and one answer (which I won't link here) I recommended that it be deleted, and got review to leave a comment telling the user that it wasn't a proper answer, and thought that was it.
Later (just now), I happened to find the same p...
Here is the code which I want to shorten.
n=input()
while n:
s=raw_input()
x,r,g,b=(int(x) for x in s.split())
a=x/r%2
c=x/g%2
d=x/b%2
r=((a*10+c)*10)+d
if r==0:e="black"
elif r==100:e="red"
elif r==1:e="blue"
elif r==10:e="green"
elif r==101:e="magenta"
elif r==11:e="cyan"
elif r==...
When i separate the two loops at the bottom it works, but when i combine them i can't seem to make the pyramid. The height is the number of rows.
include
using namespace std;
/********** DO NOT ALTER THIS CODE **********/
void printStar(int numStars){
int i;
for (i=1; i<=numStars; i ...
I recently got an answer upvote on an answer on Programming Puzzles and Code Golf. However, I ended up checking this on chat.stackexchange (specifically this, but it appears on main chat.se too. Testing looks like favicons for multiple (at least 3) sites are not working.
Here is what it looks l...
Roots of unity via discrete Fourier transform
Given a positive integer n, the standard way to generate the n-th roots of unity is
exp(2j*pi*(0:n-1)/n)
This gives the roots starting at 1 and moving in the positive angular direction. If order doesn't matter, this can be shortened to
exp(2j*pi*...Anonymous
Anonymous
