The Nineteenth Byte

Yay!

(You do get overtime pay, right?)

Anonymous

I'm salaried, so no

I'm planning on doing some work this weekend too. Got a project I want/need to have done by Monday and this whole SE drama ate up half my time at work. >_<

Also salaried.

Why does salaried mean no overtime pay?

3:12 PM

I get paid X dollars per year regardless of how much (or little) I work.

Naturally, if I stop working or slack off a lot, then I get fired.

Basically all my company cares about is "did you get your work done in a reasonable amount of time". I can go to doctor's appointments or whatever in the middle of the day and no one cares.

But who assigns you work?

What if they give you too much?

At my company in particular, my bosses are great, so YMMV for other companies. People generally have a pretty decent estimate of how long it'll take to fix a bug or do a project, and there's frequent communication regarding progress so there usually aren't any surprises.

Actually, come to think of it, when I was assigned this project I'm working on now, there was literally no time limit or expectation, due to the magnitude of its scope and uncertainties about what gotchas might be uncovered. So far it's been two months (I think) and we're about to ship the first iteration.

So, you're working at the weekend because you feel an ethical obligation to be fair to your employer?

That's not the worst reason I've ever heard, by a long way.

@wizzwizz4 Not really, no. I just wanna get this thing done!

Oh. That's much better than silly old ethics.

Actually enjoying what you do.

3:26 PM

Aye, I do love my job.

I actually had to consciously develop a work/home separation because my work was so close to what I had previously been doing as a hobby (to put it lightly).

@El'endiaStarman I'm also really enjoying the project I'm currently working on

I'm writing code that draws shapes and/or waves on a screen

I find it amusing that that statement is both very simple and hints at something really interesting.

Like, if you were just a newbie programmer, I'd be like "Oh cool!" and supportive of you learning stuff. But I know you're an experienced coder, so instead I'm like "...what are you really working on?" :P

Hehe

Anonymous

@wizzwizz4 The main reason I'm working today is because I missed a day last week, and I'm almost out of PTO/sick days (both PTO and sick days deplete a single allotment of days off at my company), so I made a deal with my boss to work today and get that day off sick.

Anonymous

I'm drawing small shapes on small screens that do things when you poke them

3:34 PM

Man, I'm missing out on the drawing shapes fun. My code just gets things from a place and other things related to those.

@Mego A pocket radio software.

@El'endiaStarman So if you drew x = cos(θ), y = sin(θ) on a canvas, obviously you'll get a circle. If the angles increase at different rates you get some really interesting shapes, so we use x = cos(a * θ), y = sin(b * θ). For a=1, b=2, you'll get kind of an infinity shape.

Anonymous

@wizzwizz4 Close

Anonymous

The device goes in your pocket and uses radio waves for communication

Anonymous

But most people would call it a mobile phone or a cell phone

3:38 PM

But that's not its primary function!

Now if a=1.5, b=1, then having θ in [0°, 360°) it creates a shape that looks like it's cut off in the middle. So it's better to do two full revolutions

So one problem I'm running into, is "given an arbitrary a and b, how do I know an appropriate number of revolutions to do?"

Anonymous

@DJMcMayhem 7

If you do too many, you'll end up with a mess because they start overlapping and not being distinct lines anymore

Anonymous

Surely that problem has been solved - they're Lissajous curves

@Mego Oh wow thanks I didn't know the name for that

That's really helpful actually

Anonymous

3:41 PM

Glad I could help

Anonymous

And also glad I remembered something from pre-calc

So basically I'm making a graphical Lissajous editor

You should just be able to write a and b as fractions with the same denominator, and take the denominator.

Although the waves don't necessarily have to be sinusoids. You could use triangle or buzzsaw waves

@DJMcMayhem heh, i once made something like that for when we had them in a physics lesson

Anonymous

3:43 PM

Well, technically they're special cases of Lissajous curves with A = B = 1, δ = π/2

@Mego well sure the ones I described are. But I think I'll eventually let the user specify all of those too

I just haven't gotten around to that yet

"X/Y multiplier"

You can also rotate the entire shape around the origin

Anonymous

@wizzwizz4 That will only work if a/b is rational

@Mego And if it's not, there's no way to make a closed loop.

Anonymous

Correct

But all floats are rational.

Anonymous

3:46 PM

So if a/b isn't rational, the problem can't be solved, and you have to decide on an arbitrary "good enough" point

Anonymous

@wizzwizz4 Who said anything about floats? Maybe symbolic input is allowed

I've been doing too much IEEE lately.

@Mego Can use continued fractions to help derive a good rational approximation.

@wizzwizz4 I did try rounding to the hundredths place. It "works" but like I said, if you do too many revolutions the lines and up really close together and looks terrible

Like one big blob

@DJMcMayhem Is this designed for looking nice?

3:48 PM

Not necessarily but it would be preferred

@DJMcMayhem could creating the infinite fraction of x÷y & cutting off at some point work?

(whether "some point" is taking first N items or until the item is over some constant, or some mix of the two, i have no idea, all i know is that infinite fractions are a fun way to round fractions)

Or just iterate through all the values of i in the allowable range and find the one with the minimum difference between the ends of the line.

@dzaima Isn't that basically the same? Just taking a certain number of decimal points

Although this conversation does help me realize that the exact values of a and b don't matter nearly as much as a/b

@DJMcMayhem that doesn't refer to "decimal" though, and allows for funky ratios (e.g. x=1/7 & y=1) very clearly

I think right now if you made a or b high enough, it'll draw across the circle rather than around it (if that makes any sense)

4:18 PM

here's quick apl "rounding" a given float (with a hard-coded max "complexity" of 100, whatever that means)

4:59 PM

here's a damn 1+ quine. seriously, though, that was surprisingly fun. that should also be _very_ golfable
https://tio.run/##7VxJc9pIFL7zK56lAy2QBSI5YTjYqUrKExdFeZLDRMiUkJqgGm3TEl4qzG9nXksswhhmDqkMywOs6uXr7639WtLByUs2iaPWfK5eNKapaIz8qMGjR0jy8YoKZh38KOMiERyv2Ib@cqrvCDd4gS/OMw@gAb9xwUPZjXRoNc33iLjzXR65HPwUPnyAmz8uf7@G90YTwR@v78A03mHrU@8rfOrfPb6r@GESiwzSl7QyFnEIbhwE3M38OEphMefxv6a8Ukl1SD3oFl2m6fDj70rF42OII54E05SliO1CD7tauwL48ccQxcgtsqK/GAt4xFCe4YjvjxpcdKG1npafRKDxoHxNne@8DQrUYYm2mjb2FLDGfsAhi2HEgT9zd5pxz1Y2SOQS/uxnzNTWsqMEFYyTknzLtHWoiuoaJJwnBCHUENzx2MZqww3ilC/GeJCiegUcTczH8ssk1OFeh1Ga6XCjQw/nL…

size/2:
https://tio.run/##7VpJc9pIFL7zK56lAy2QJURywnAwqUrKExdFeZJDImRKSE1QjbZpNV4qzG8nryUWYQwz8bDZAFjVy9ff258Q5fiRD6KwOh7LZ/owYXrPC3Ua3kGcrhdkMMrghZyymFG84hja0622zRz/Eb7YD9QHHf6gjAZiGqpQrRjvEXHtOTR0KHgJfPgAzW/nf17Ce62C4I@X12Bo73D0qfUVPrWv794VvCCOGIfkMSn0WRSAE/k@dbgXhQlM9lz695AWCokKiQuNbEoUFX7@Uyi4tA9RSGN/mJAEsQ1o4VSpFQBfXh/CCLkZz@aTNZ@GBOVpNvtxp8BZA6rzbfGKGRoP0tfE/kFrIEEZpmizYuFMArPv@RR4BD0K9IE6Q05dS1ogEUfog8eJocxlhzEqGMU5@aZhqVBkxTmI2fcIQqjGqO2ShdOa40cJnaxRP0H1MjiamK6ll0Ggwo0KvYSr0FShhfumJdylzn1XwU8K7kcMHBFhJFrwkgONBhRJcdE3TSg3wFhYQjmaHaNRLmkpywzKEsP5U4YbU3DEUUwUS0RwYROJmlCHyiJLLk5XQc/2bcw…

Neat.

ungolfed
https://tio.run/##7VZLc9pIEL7rV7TFgRHIAtk5YXOwU5WU1xTl8iaHjZCpQRqCKkKjnRn5sSG/ne2WeAhjSA572EN4qGZaX3/9mJ6eyV/MTGZny2XjpFNo1ZkkWUdkj5CXcqsBfhuSzAiVK4FPHMPd@tUdV1H6Ap/4s0ihA38IJeY0zVw46/rvEDFIIpFFAhIN79/D9V@nf17BO6@L4A9XA/C9cxx9HH6Gj3eDx3MrmedSGdAv2poqOYdIpqmITCIzDat3sfi7EJalXdAx9Kspc1z4/sOyYjEFmYk8LTTTiO3DEKdOzwL8JFPIJHIrU81XslRkDO15XH19dOCkD2fb1/TJFQYP9mfNv4oe2NCGNTrohjizIZgmqQAjYSJAPIuoMCIO7R0SUhHPiWG@s7Wd5eigzGv2Az90oamaW5DiTwhCqKcEj9mOthelUouVTKQa3avgGGIpKx@zuQv3Lky0ceHahSG@D0JKl7vNXRd/JXgqFUS0wki0k6UI@n1osuZubq6h3Qd/R4R2PJ5jUDEbOvsMzh7D6WuG@4A4cpkzJ6QV3HmJRNdwCd1dlto63cwnPOVYcT…

@dzaima is zero is just 1< ಠ_ಠ

@dzaima no, that's "is less than 2" ಠ___ಠ

5:26 PM

@dzaima Zero is 11+1<.

@wizzwizz4 that's for checking if zero is the top element of stack

1+1< works though

at which point inlining is way better (it probably was before too but whatever)

caird coinheringaahing

Any more feedback on this? Planning on posting soon

full program with that
https://tio.run/##7VlLc9pIEL7zK9rSgRGSBSI5YTiYVCW1GxdFeZPDRsiUkIagWr12NPhR8f52tkdCIIwhay8PE0CgmsfXX3dP9/RIdvzAR1FYn0zks@o4YdWBF1ZpeAtxOl6SwVDBCzllMaN4xzZ086muzRz/Ab7Y99SHKvxOGQ1EN9SgXjPeI@LKc2joUPAS@PAB2n@e/3EJ7/Uagj9eXoGhv8PWp85X@NS9un1X8oI4YhySh6Q0ZFEATuT71OFeFCYwnXPp32NaKiUaJC60si5RNPjxT6nk0iFEIY39cUISxLagg12lUQL8eEMII@RmPOtPx3waEtSn2@z7rQJnLajPp8UnZug8SF8T@zttgAQq5GizZmFPAnPo@RR4BAMK9J46Y05dS1ogESL03uPEUOa6wxgNjOKCftOwNCiz8hzE7DsEIVRn1HbJgrTu@FFCp2PUT9C8DI4upmPpbRRocK3BIOEatDXo4LxpieXS5mtXw28KHkYMHBFhJFpYJQdaLSiT8uLatEFtgbEwhHp0O0anXNJRlhmUJYbzpwzXpuCIo5golojgwiQS…

A: Sandbox for Proposed Challenges

6:18 PM

even shorter
https://tio.run/##7VhLc9pIEL7zK9rSgRGSBUNywnAwqUpqtyiK8iaHjVAoIQ1BtXrtaPCj4v3tbI@EQBhDnCwQkgUZah5ff/2Y7pbk5EFM46g5n6sX9VnK62M/qrPoFpJsvaIC1cGPBOMJZ/iLYxgUWwOHu8EDvHfuWQB1@J1xFsppZECzQV8joue7LHIZ@Cm8eQPdPy//uIbXZgPBb697QM1XOHrX/wDvBr3bVxU/TGIuIH1IKxMeh@DGQcBc4cdRCos9j/09Y5VKakDqQSefEs2AL/9UKh6bQByxJJilJEVsB/o41VoVwI8/gShGbi7y@WItYBFBfabDP99qcNGB5mpbfhKOzoPyIXU@sxYooEOBtho2zhSwJn7AQMQwZsDumTsTzLOVNRIpwu59Qai20h0laGCclPRb1DagyqsrEHfuEIRQkzPHI2vSphvEKVussSBF83I4upitZT/T0IAbA8apMKBrQB/3LVuGy1jFroF/GXgSc3DlCSPRWpRc6HSgSqrrsemC3gG6toR6TCdBpzzS1zYZtA2Gy6cMN5bkSOKEaLY8wbVNJOpCGxrrLKVz@i…

New Sandboxed Posts

6:35 PM

0

Golf a new OEIS sequence. This is a code-golf challenge. The goal of this challenge is to create an integer sequence that is not in the OEIS using the fewest possible number of bytes. Your program can either output an infinite list, or it can be a function from the natural numbers to the intege...

New Sandboxed Posts

7:55 PM

0

A: Sandbox for Proposed Challenges

Draw a CE mark graphical-output Your input is the scaling factor n. You must output an image of width 82n and height 48n (if you are generating a vector image, it should have that as its default size). The image will be either transparent or white, with the following regions in black: The segm...

flawr

8:40 PM

@DJMcMayhem are you familiar with Mr. Lissajous?:)

oh ninja'd

@wizzwizz4 what about -0 :D

@flawr Eyyyy lmao!

(Powers of two, I reckon.)