Not a math person but thought I'd play with this problem ChatGPT gave me this morning and made an observation that might be relevant. After you select a number, stop at the first negative number that follows where the difference between that negative number and the number you had selected is the ...

Related to: Is $z=e^{\frac{1}{\log(x)}}$ a solution to a polynomial? I'd like some feedback on my purported proof. Is it correct? Assume $x,\varphi\in \overline{\Bbb Q}\ne 0,1$ where $\overline{\Bbb Q}$ are the algebraic numbers. Let $x\varphi=1$. Take $\log u \log v=1$ where $u=e^x$ and $v=e^\...