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8:42 AM
in MathOverflow, 1 min ago, by Martin Sleziak
I will add a more readable link: For which Banach spaces is the self composition operator Lipschitz? And also a one-boxed version:
in MathOverflow, 55 secs ago, by cfp
Thanks! (For future reference, how do you do that?)
in MathOverflow, 7 secs ago, by Martin Sleziak
:57928706 I would suggest to take this into another chatroom - so that your question does not get lost among the discussion which is mainly about formatting messages in chat.
First, I'll mention that you can easily check source of any message in chat - to see how somebody wrote something: How to view/copy source of a message in chat?
 
cfp
Thanks Martin. Actually I found it in the help. (I hadn't noticed it buried under info)
 
cfp
Sorry for wasting your time. Thanks again.
 
In case somebody else stumbles upon this I'll add that I the syntax is [text](url) (the same as on the main site). In this case [For which Banach spaces is the self composition operator Lipschitz?](https://mathoverflow.net/q/392231) produces: For which Banach spaces is the self composition operator Lipschitz?
To be able to create such link quickly, I use the bookmarklet called Link from here: web.archive.org/web/20180705103212/https://… msleziak.com/various/bookmarklets.html
 
cfp
Thanks!
 
8:48 AM
And if you include a message which contains only the link to a post (and nothing else), then a bit of preview is displayed. This is called oneboxiing and works for various other things. (Comments, YouTube, Wikipedia, ...)
0
Q: For which Banach spaces is the self composition operator Lipschitz?

cfpLet $X\subseteq \{f|f:D\rightarrow \mathbb{R}^n\}$ be a Banach space, with $C^\infty(D,\mathbb{R}^n)\subseteq X$, where $D\subseteq \mathbb{R}^n$ is open and bounded. Let $U\subseteq X\cap \{f|f:D\rightarrow D\}$ be open, and define the operator $\Phi:U\rightarrow U$ by $\Phi(f)=f\circ f$ for all...

 
If $x \in \mathbb{C}^{m}$ and $A$ is a $m \times n$ matrix, prove the following inequalities:
(a) $\|x\|_{\infty} \leq\|x\|_{2}$.
(b) $\|x\|_{2} \leq \sqrt{m}\|x\|_{\infty}$.
(c) $\mid A\left\|_{\infty} \leq \sqrt{n}\right\| A \|_{2}$.
(d) $\|A\|_{2} \leq \sqrt{m}\|A\|_{\infty}$.
How to do this last 2 inequalities I know some how I need to use (a) and (b) and use operator norm but vector product is not defined for this case
 
I see that you have already asked in the main chatroom:
in Mathematics, 5 mins ago, by maths student
If $x \in \mathbb{C}^{m}$ and $A$ is a $m \times n$ matrix, prove the following inequalities:
(a) $\|x\|_{\infty} \leq\|x\|_{2}$.
(b) $\|x\|_{2} \leq \sqrt{m}\|x\|_{\infty}$.
(c) $\mid A\left\|_{\infty} \leq \sqrt{n}\right\| A \|_{2}$.
(d) $\|A\|_{2} \leq \sqrt{m}\|A\|_{\infty}$.
How to do this last 2 inequalities I know some how I need to use (a) and (b) and use operator norm but vector product is not defined for this case
Let's hope you'll get an answer there.
This would be on-topic also in Linear & Abstract algebra - since it is about matrices.
This is what SearchOnMath return for (c) and for (d).
IIRC Approach0 will be available again after May 12.
 

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