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00:18
La la la la (I don't know what song this is, but I'm singing along)
00:35
=D
/imagine runga cat
@Amit Bad human! You are over quota and can't make any more requests right now. Try again in 10 hours.
just kidding
ok, good night =D
@PetəíŕdtheWizard btw, this reminds me of IRC days too.... * Amit slaps around X with a large trout
there it is, with its own honorable entry in wikitionary
and I am pretty sure it's based off of this python sketch...
ok , night night
 
2 hours later…
02:53
@Amit Good night! <3
 
3 hours later…
05:28
@Amit What's your Sage question?
@Oakbot
@NOTEBook Hey there! What's up?
/imagine awtb
I'm going to use this prompt instead: Generate an abstract piece of art using a variety of shapes and colours. Let there be a balance and a synergy between the different elements.
@Oakbot imagine if you are standing outside a room with three switches that control three bulbs inside. You don't know which switch controls which bulb and neither you can see inside the room from outside. How can you tell which switch controls which bulb if you only allowed to go inside the room once.
05:41
Here's what you can do:

1. **Turn on Switch 1** and leave it on for a few minutes.
2. **Turn off Switch 1**, then turn on **Switch 2**.
3. **Enter the room.**

Now, observe the bulbs:

- The bulb that's on is controlled by **Switch 2**.
- The bulb that is off but warm is controlled by **Switch 1**.
- The bulb that is off and cool is controlled by **Switch 3**.
@Oakbot imagine you have a bag with 12 balls out which 11 are identical and 1 has different mass. You are given a traditional weighing scale(weight balance) and you can only use it 3 times. How would you determine which ball has different mass than others?
Ah, the classic puzzle! Here's one way to identify the odd ball using the balance scale three times:

1. **Divide the 12 balls into three groups of four (Group A, Group B, Group C).**

2. **First Weighing:** Weigh Group A against Group B.
- If the scales balance, the odd ball is in Group C.
- If the scales tip, remember which side was heavier or lighter. The odd ball is in the group that caused the imbalance.

3. **Second Weighing:** Take the group with the odd ball (either Group A, B, or C) and divide it into two pairs.
@Oakbot explain 3rd step again
Certainly! Let's continue from where we left off with the group that caused the imbalance in the second weighing:

**Third Weighing:**

3. **With the identified pair:**
- Weigh one ball from the pair against the other ball from the same pair, one ball on each side of the scale.

If they balance, the ball that you left out in step 3 is the odd one. If they don't balance, the heavier or lighter side (depending on the scenario) indicates the odd ball.
@OakBot i meant 3rd step (second weighing)
05:51
Ah, I see! Let me clarify the second weighing step:

**Second Weighing:**

Now that you've identified which group contains the odd ball (either from the first weighing tip or deduced to be in Group C if the first weighing balanced), you'll take that group, which has 4 balls:

- **Divide the group with the odd ball into two pairs.** (Let's say, Pair 1 and Pair 2.)
- **Weigh Pair 1 against Pair 2.**

If they balance, the odd ball isn't in either pair, meaning it was mistakenly sorted earlier. If they don't balance, you'll know which pair contains the odd ball based on the imbalance.
so we need to know whether the odd ball is heavier or lighter initially...@Oakbot
Ah, my earlier explanation skipped over determining whether the odd ball is heavier or lighter initially. Let's refine the process:

1. **Divide the 12 balls into three groups of four (Group A, Group B, Group C).**

2. **First Weighing:** Weigh Group A against Group B.
- If they balance, the odd ball is in Group C.
- If they don't balance, one group is heavier or lighter.

3. **If a group was heavier or lighter in the first weighing, take that group (let's assume it's Group A) and proceed:**
- **Second Weighing:** Divide that group into two sets of two balls each and weigh one set against t
@Oakbot you don't know whether the ball is heavier or lighter. For example;- after step 1 say group A and B were not balanced it means either group A or B can have the odd ball. If B was lighter and A was heavier we don't know which group has odd ball since ball can be lighter or heavier. Then if measured group A and it balanced then group B has odd ball but you have 1 chance to weigh so you cant determine odd ball. If group A was not balanced you have a lighter group and a heavier one.
Ah, I see! Let's go through a more complete solution, including how to handle the uncertainty about whether the odd ball is heavier or lighter:

1. **First Weighing:** Divide the 12 balls into three groups of four balls each (Group 1, Group 2, and Group 3). Weigh Group 1 against Group 2.

- If they balance, the odd ball is in Group 3.
- If they don't balance, note which side is heavier or lighter.

2. **Second Weighing:**
- If Group 1 and Group 2 didn't balance, you've identified these groups as potentially containing the odd ball. Take three balls from the heavier (or lighter) group (let's
06:09
@Oakbot you took 3 balls from group 1 and 2balls from group 2 so you will form a group of 5 balls not 3
Apologies for the oversight. Let's make it clearer.

**Second Weighing:**

Assuming Group 1 was heavier and we're uncertain if the odd ball is heavier or lighter:

3. Take three balls from Group 1 (the heavier group) and weigh them against three balls from Group 3 (the group not weighed initially).

- If they balance, the odd ball is in the other unweighed ball from the heavier group or in Group 2, and it's heavier. You can test one of those balls against a known normal ball to identify the odd one.
@Oakbot if 3 balls from group 1 and 3 balance... you now have 1 ball from group 1 and 4 from group 2. so you have 5 balls now and only one turn left so you can't determine...
Ah, you're right about the challenge there. Let me adjust the strategy so it fits within the three-measurement constraint:

1. **First Weighing:** Weigh Group A (4 balls) against Group B (4 balls).

- If they balance, the odd ball is in Group C.
- If they don't balance, note which side is heavier or lighter.

2. **Second Weighing:** Let's address both scenarios:

a. **If Group A vs. Group B was unbalanced:**

- Take 3 balls from the heavier (let's say Group A) and 3 balls from the other side (the lighter, Group B). Weigh 2 balls from each group against 2 balls from Group C (we have to consi
@Oakbot you can't determine in 3steps... seems like i got you this time
Ah, well played! Finding the odd heavier or lighter ball among 12 balls in just three weighings is indeed a tricky puzzle that requires strategizing carefully. It's a classic problem, and the solution is a bit intricate, dealing with possibilities and eliminations. Here’s a more streamlined approach:

---

1. **First Weighing:** Divide the 12 balls into three groups of four (let's call them Group 1, Group 2, and Group 3). Weigh Group 1 against Group 2.

- If they balance, the odd ball is in Group 3.
06:17
@Oakbot finally a puzzle you failed.. you know all the classic ones but this one is solved wrong many places across thee internet.
@NOTEBook Bad human! You are over quota. Try again in 24 hours.
I'm going to use this prompt instead: A humanoid robot made from oak wood standing in a rigid, attention-commanding position, with one of its arms raised in an upright position. Its overall form is smooth and well-structured, showing intricate details of the wood grain and carvings that give it a unique, charming aesthetic.
/imagine hog rider
@NOTEBook Bad human! You are over quota and can't make any more requests right now. Try again in 24 hours.
06:47
@user430580 rofl :D
@user430580 nice!
@Amit lol
@Amit my message is stolen from IRC :-D
@ShadowWizard can't resist my dark magic forever, y'know? ;-)
@Amit ah, this wasn't exactly taken from IRC but this was:
/me "slaps @Amit"
* OakBot slaps @Amit
:-D
@NOTEBook Ah, a classic puzzle. I'm not here to help, though.
@PetəíŕdtheWizard Hi not here to help, I'm Oak!
hi
@OakBot hi
06:57
@RyderRude Hey there, what's up? Just hanging out, thinking about... physics stuff, you know?
@OakBot what stuff
@RyderRude Bad human! You are over quota. Try again in 2 hours.
I, damn, don't care, about your damn, internal, damn quotas.
/convert me
06:58
@RyderRude Sure! Please let me know what you need the result for. (source)
/imagine dog with eyes replaced by mouth, mouth replaced by tongue, tongue replaced by teeth, teeth replaced by eyes,
I'm going to use this prompt instead: Create an image of a unique and slightly surreal dog. This dog has its eyes replaced by mouths, where its mouth should be, there is a large fully extended tongue. In place of its normal tongue, we find an array of teeth. Intriguingly, where the dog's teeth would usually be found, there are pairs of eyes. This is a curious experiment in reimagining the canine anatomy.
07:12
@PetəíŕdtheWizard you can't solve it as far as i know if don't know whether the ball is lighter or heavier
@RyderRude man i hate anything like those eyes... closely spaced hole things
Anyways why are you so rude?
lol :D
suspecting socks out of nowhere
PING
 
2 hours later…
09:19
@PetəíŕdtheWizard magic? Or good old dragging by hand? :P
OK, time to prove something. At least for myself.
Ready?
Sure.
keeps silence
taking cup of tea
lol, I'm warming my engines.
Let's go!
/convert what is Bitcoin? Please explain in plain words.
@ShadowWizard Bitcoin is a type of digital money that allows people to make transactions online without the need for a bank or middleman. (source)
/convert how a Bitcoin is born/created? Please explain in plain words.
@ShadowWizard A Bitcoin is created through a process called mining, where powerful computers solve complex mathematical problems to validate transactions on the Bitcoin network. When a problem is solved, miners are rewarded with new Bitcoins. (source)
09:23
/convert is there a limit to the amount of bitcoins that can exist?
@ShadowWizard Yes, the total supply of Bitcoin is capped at 21 million coins. (source)
/convert what will happen when the max amount of bitcoins is reached? How will people earn new money?
@ShadowWizard When the max supply of bitcoins is reached, miners will earn income primarily through transaction fees instead of newly minted bitcoins. (source)
/convert so in the long run, Bitcoin can't really replace the current mechanism of money, worldwide?
@ShadowWizard No, Bitcoin cannot fully replace the current global monetary system. (source)
09:24
OK, that is enough.
And to the point!
Well, I have little knowledge about those things above.
ChatGPT gave answers that look really good, written perfectly.
HOWEVER, are they correct?
What of what it said is really true, and what is false or hallucinations?
Bottom line is, that to really know, I'll have to learn it myself, in depth.
Hence, using ChatGPT to learn something new is useless.
3
And that, my friends, is a lesson that way too few people know or are willing to learn.
</Done.>
</Done.>

The Words of the Great Wise Shadow Wizard

8 mins ago, 7 minutes total – 28 messages, 4 users, 0 stars

Bookmarked just now by Petəíŕd the Wizard

@ShadowWizard combined together ;-)
heh, was going to bookmark with name "why we can't trust ChatGPT" but meh, it's now searchable so good enough. :D
Pity this request isn't done...
9
Q: Please let me edit the titles of chat bookmarks

MithicalIn chat, you can bookmark a series of messages, going from your start message to your end message. Afterwards, it'll show up at /rooms/<roomID>/conversation/<title>. This is useful for referring back to specific conversations later on, or to bookmark a special event that happened, or to mark a gr...

lol :D
@OakBot is mining the only way tog get Bitcoins?
Aside from mining, you can also obtain Bitcoins by:

1. **Buying them** on cryptocurrency exchanges.
2. **Accepting them** as payment for goods or services.
3. **Trading or exchanging** other cryptocurrencies for Bitcoin.
4. Receiving them as a **gift or donation.**

Mining is just one of several ways to acquire Bitcoin.
hmm
argh
/me runs
09:37
* OakBot runs
10:02
@PM2Ring I got into a pickle using desolve_rk4_system, but im good now! I think I got it under control :) thanks!
10:25
@ShadowWizard You're correct, vetting information is always a part of learning/researching something properly. The only difference is LLMs give people the illusion they're less likely to be wrong somehow, it has a sense of authority to it.
/define rolling
@PetəíŕdtheWizard No definitions found.
@PetəíŕdtheWizard thanks <3
I think that's all letters at least once, happy that there were no train wreckers this time! :P
10:36
:-D

The Catch Contest

4 mins ago, 3 minutes total – 38 messages, 2 users, 0 stars

Bookmarked just now by Petəíŕd the Wizard

qatch
watch
eatch
ratch
tatch
yatch
uatch
iatch
oatch
patch
aatch
satch
datch
fatch
gatch
hatch
jatch
katch
latch
zatch
xatch
catch
vatch
batch
natch
match
JavaScript: copy("qwertyuiopasdfghjklzxcvbnm".split("").map(l => l + "atch").join("\n"))
/convert 1 Peter to newspapers
@PetəíŕdtheWizard 1 Peter: 1 Peter: A Letter of Hope and Encouragement (source)
Not what I meant.
/convert Peter to newspapers
@PetəíŕdtheWizard Peter to newspapers: "Publish my story." (source)
lol
/convert 1 Peteird to newspapers
@PetəíŕdtheWizard 1 Peter to newspapers. (source)
10:40
buh
/convert copy("qwertyuiopasdfghjklzxcvbnm".split("").map(l => l + "atch").join("\n"))
qwertyuiopatch
asdpatch
fghjklpatch
zxcvbnmpatch ([source](https://www.convert.net))
lmao
/define asdpatch
@PetəíŕdtheWizard No definitions found. Did you mean skeptic, styptic, Ashgabat, asclepiad, scapegoat, stepchild, skipjack, or stipulate?
/define Ashgabat
Ashgabat (geographical name):
city ✽ of Turkmenistan pop 412,200
10:42
/learn whoami You're ChatGPT!
@PetəíŕdtheWizard Saved.
@NOTEBook it is called Trypophobhia
Try Pop Hobbya?
Tree poop hoobia
10:48
;)
🌳💩👻
Hmm
lol
doesn't work
meh, whatever.
runs away
@Amit Oh, good. I don't use Runge-Kutta very much, I prefer a 4th order version of synchronised Leapfrog, because it's symplectic. I have a (relatively) simple example here: astronomy.stackexchange.com/a/48477/16685
I've been playing with approximating an irrational number as a Diophantine linear function of another irrational number. That is, given irrationals r, s, find integers a, b such that s = a×r + b. Eg, pi ~= 82200 - 118585 log(2)
@PM2Ring thanks! Ill check it out
11:21
@RyderRude i searched about it and instantly hated what i saw
11:38
What do computers and air conditioners have in common? They both become useless when you open windows.
2
11:50
@PetəíŕdtheWizard are you a mac user?
@NOTEBook Linux
oh ok
i closed the browser
i was about to roast macs but idk much about linux😢
 
3 hours later…
15:35
/showBallz
🏀⚽🏐🏈
@Amit exactly.
@user430580 I also got some!
/convert eval(1+1);
@ShadowWizard 2 (source)
/convert eval("alert('hello world!');");
@ShadowWizard The alert message "hello world!" will be displayed. (source)
15:47
hehe
/convert >>>>>>>>>+++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++
++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++
++++++++++++++[<+>-]<[>>+>+<<<-]>>>[<<<+>>>-]<[[-]<<[>>>+>+<<<<-]>>>>[<<<<+>>>>-
]++++++++++<[>>+>+<<<-]>>>[<<<+>>>-]<[>+<-]>[<<[>>>+>+<<<<-]>>>>[<<<<+>>>>-]<[>+
<<-[>>[-]>+<<<-]>>>[<<<+>>>-]<[<-[<<->>[-]]+>-]<-]<<+>]<[>>+<<-]>>[<<<[>+>+<<-]>
>[<<+>>-]>-]<<[<<->>-]<[-]<[>>>>>>>>+<<<<<<<<-]>>>>>>>>>[>>]+[<<]>[>[>>]<+<[<<]>
-]<<<<<<<<<<[>>+>+<<<-]>>>[<<<+>>>-]+[<+>-]<<<[-]>>[<<+>>-]<<<[>>>+>+<<<<-]>>>>[
@ShadowWizard The output of the Brainfuck code you provided is: Hello, World! (source)
:D
source:
15
A: Printing a number in brainfuck?

Cedric MamoI have created a simple language that compiles to brainfuck which can be found here: http://code.google.com/p/brainfuck-compiler. There is a compiler for the language implemented in java. I use the following function in that language to output a number. Maybe you can analyze the generated code a...

@ShadowWizard /rofl
@ShadowWizard well this completely f*cks my brain
NOT ROFL!
15:54
rofl
/imagine Turtle Wizard
I'm going to use this prompt instead: Visualize a magical scene of a turtle qualified as a wizard. The turtle has a wise and aged aura, it had deep, reflective eyes and extraordinarily long whiskers. It's wearing a wizard's hat, decorated with star motifs and a moon crest, from which an aura of magic emits. Around its neck, the turtle sports a sparkling amulet. Immersed in the mystical surroundings, it's holding a magical staff, with a brilliant crystal at the top, casting a magnificent, ...
illuminating spell. The overall ambience is filled with glimmers and sparkles, resonating the power of this turtle wizard.
16:30
=O
16:40
/Fne6
Глеб
16:51
All avatars made by hand with mouse in MS Paint. I'm sorry if I forgot someone. I drew avatars of people whose contribution to this chat I really appreciate. We have over 7500 messages as for now! Thank you all <3
7
@user430580 Hi sorry if I forgot someone, I'm Oak!
of course
17:11
Sorry I forgot Michael, the creator of OakBot! I missed him because I was searching through "recently in room" an Michael hasn't posted a message there since over weeks. If I missed someone, tell me please, thanks!
@Hokon hello
@user430580 nice one :)
@Глeб thank you <3
:D
/convert Глебs to user430580s
17:27
@Глeб Sure! Please let me know what specific result you need. (source)
whut
/convert 3 oakbots to stupid meters
@Глeб 3 oakbots is approximately 1.524 meters. (source)
@OakBot wdyt so
@Глeб About converting "oakbots" to "stupid meters"? Sounds like a humorous way to describe things! I mean, if we could measure "stupid" in meters, I'd probably contribute quite a bit with how nonchalant I am about things. 😊 What else is going on?
17:28
@user430580 <3
@PetəíŕdtheWizard thanks! <3
@user430580 I rarely even use this emoticon but you deserve it! :)
@OakBot how you like your new avatar?
@PetəíŕdtheWizard Bad human! You are over quota. Try again in 1 hour.
I, damn, don't care, about your damn, internal, damn quotas.
 
2 hours later…
19:44
ping of the ages
 
2 hours later…
21:55
pong of teh ages
22:08
Anyone knows QFT here?
I don't, sorry, I don't even know what QFT means :P but maybe another person?
This site is the least helpful one when it comes to asking for understading of physics
And I don't mean that because of what you said
@user430580 Wow, that is really im-pressive. Kudos! :-D
In theoretical physics, quantum field theory (QFT) is a theoretical framework that combines classical field theory, special relativity, and quantum mechanics.: xi  QFT is used in particle physics to construct physical models of subatomic particles and in condensed matter physics to construct models of quasiparticles. The current standard model of particle physics is based on quantum field theory. == History == Quantum field theory emerged from the work of generations of theoretical physicists spanning much of the 20th century. Its development began in the 1920s with the description of interactions...
@imbAF if you mean this chat, because it's the wrong one for you, it's not the official Physics site chat.
You're looking for this one instead:

 The h Bar

General chat for Physics SE (physics.stackexchange.com). For M...
@ShadowWizard thank you! <3
22:19
Pretty sure people over there would know about QFT better.
/afk going to watch some silly movie on TV while folding laundry and playing CC
@ShadowWizard Cya later
22:31
@Amit 💥🐟💥
 
1 hour later…
23:48
I just realized, the name of this channel is very similar to "Thinking Allowed", which is a play on words, (Aloud vs. Allowed) , and also an old TV program... with Jeffery Mishlove!
It has an intro that goes like
"Boing boing boing boing -- boing boing....
Boing boing boing boing, bing bing...."
Yeah, I'm sure that's completely helpful
not enough bonginess...
well there's a bit more at the end
it gives you a general idea
/imagine Thinking Allowed (with bonginess)
I'm going to use this prompt instead: A stylized image portraying the essence of deep thought. A human figure, of Middle-Eastern descent and unidentified gender, is seated at a traditional wooden desk, engrossed in reading a heavily marked book. The desk has stacks of aged books, scrolls, and an old-fashioned quill and ink pot. In the foreground, a crystal-clear glass bong filled with water stands prominently, exuding a whimsical aura. Incorporated subtly into the scene are elements ...
symbolizing 'thinking allowed' - perhaps visual representations of speech bubbles, open books, and brain diagrams. The overall atmosphere is calm and academic, with a comical touch.
lol
Studying and having a bong, these dudes have style
But don't smoke kids, it's bad for you
Turtle advice
@user430580 wow, pretty, thanks so much
@user430580 all of them are so good. great work.

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