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4:22 PM
Sigh... Continuous over-unity power generation, or it doesn't matter.
 
JRE
@W5VO It has to be over unity energy production. Unfortunately, the over unity crowd doesn't know volts from amps from watts from joules.
 
Yes, I suppose that's true.
I don't hang around those circles enough to know the games they play to make it look like they've accomplished something significant
 
JRE
@W5VO Where did it pop up to come to your attention?
 
But if you did have an over-unity energy production system, then you have accomplished what half a century of research with the world's top minds in particle physics have failed to accomplish. Not impossible, but highly improbable
@JRE just dropping in briefly
I've seen home-shop fusion reactors before, but the goal was "merely" to achieve fusion, not necessarily to make a power plant
 
JRE
@W5VO Ah. OK. Now I know where you're coming from. There's a whole sub-culture out there doing all kinds of perpetual motion machine type stuff, and hollering "over unity" every time they turn around. Then there's a particular fusion reactor project over on the physics chat.
 
4:43 PM
@JRE It's the eye-rolling over "I'm going to hide my blueprints for 5 years - no pics either" for a fusion reactor that doesn't have any real use besides being able to say you made fusion.
 
JRE
I haven't been following it very closely. I know it's there, but that's about all.
 
5:11 PM
How does one find Vout of a schematic like this?
 
Make some assumptions about what kind of load is present on Vout, and then algebra
 
Or, since I'm not a native English speaker - what do I google to find more details on a divider like this?
 
I'd probably go with Kirchhoff's Current Law, that will let you come up with a generic solution
Alternatively, you might convert your voltage sources into current sources with a Thevenin equivalent circuit
 
5:27 PM
hmm
 
 
1 hour later…
6:30 PM
Hi, You can use Nodal Analysis for this. I did so and solved for Vout
Here are the results from symbolab.com (example values like R1 = 10, V1 = 10V, ...), but be careful - I have chosen different names for resistor for my convenience.
Here are the results from a CircuitJS simulation:
I'm sorry, it's not called Nodal Analysis, it's Mesh Analysis. (I am learning in Poland, so I had no idea what was the English name for this)
Also, I have a question: Why does AM radio use a carrier wave? Why can't we just send audio without modulating it? What about the power transmitted?
(Let's forget about different radio stations, just one)
 
JRE
6:49 PM
@KamilWitek Even if you have just one transmitter, a carrier wave is better than blasting out kilowatts of power at audio frequencies. Audio covers several octaves, so it is difficult to get even transmit power over the whole range. It is also easier to pick a weak signal out of the RF noise that is always present.
An effective antenna at audio frequencies would also need to be enormous. At 20 kHz (audio, but above what most folks can hear,) the wavelength would be just about 15km. A 1/4 wave antenna would have to be nearly 4 km long.
You can use wire loop antennas instead of a dipole, of course. Still, it takes a lot of antenna at such low frequencies.
 
OK, now I get the idea, but let's assume that we have an ideal transmitter, infinite bandwidth, the place for this enormous antenna and so on... Now what about the power? Is it the same for higher frequency modulated signal as in lower frequencies, unmodulated signal? (Is it easier to transmit higher frequencies? I guess it is...)
 
JRE
7:22 PM
@KamilWitek You have to spread the power over the whole bandwidth. The wider the bandwidth, the more power you have to transmit. Bandwidth in this case as compared to the transmit frequency.
 
Another problem (amongst several) is that you would have only one person/station that could transmit at one time
 
JRE
The real problem is really just picking it out of the noise. You can't effectively filter out the noise in the RF spectrum. With the carrier wave, you can use a narrow bandwidth filter (compared to the frequency of the carrier wave) to reject noise.
Since you can't do that if there's no carrier, you will have to transmit more power to get the same signal to noise ratio that you can get with a carrier just by using a better filter.
 
7:40 PM
OK, I think that I understand it now, Thanks.
 
@W5VO I understand what you're meaning. And I understand that everyone has doubts. And I won't tell you other wise. Because I actually want you to doubt. I don't believe in free energy. Free energy is a hoax and technically can never be achieved. Just as we may never be able to achieve time travel. Because it's impossible. We may get close to traveling at very fast speeds. But not even close enough to slow down time to a stop.
 

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