The QCD quark Lagrangian in the chiral limit is $$ L_q = i \bar{q}{\not D} q $$ which possesses a global $SU(3)_L \times SU(3)_R$ symmetry. I've read many places that this is symmetry is spontaneously broken to $SU(3)_V$ by $\langle \bar{q} q \rangle \neq 0$. Question: How does this qualify...