last day (15 days later) » 

Safdar
Safdar
17:08
Hey
Aniruddha Deb
Aniruddha Deb
I noticed there are 4 places for the carbocation
didn't want to crowd the comment section so shifted the discussion here.
Safdar
Safdar
Using methyl shift and hydride shift?
Aniruddha Deb
Aniruddha Deb
using multiple hydride shifts. It's not very practical but it's possible.
!image
user image
So carbocation at the bottom carbon, right -Cl, right -Me and top carbon
Safdar
Safdar
If you go towards the methyl, then it would stop there since 7 H and tertiary is attained.
@AniruddhaDeb Alright.
Aniruddha Deb
Aniruddha Deb
again not being practical here: treating it like a combinatorics question
so then you would have 8 but that is not an option... only option left is 6 in that case (3 carbocations like you said, then 2 isomers for each)
It's an ambiguous question but if it were to pop up in a paper, I would say 6. Your opinions?
Safdar
Safdar
17:15
@AniruddhaDeb Me too. However, i have some concerns not knowing anything about the reaction but that it is SN1
Aniruddha Deb
Aniruddha Deb
Again like I said its ambiguous. Lot of other factors could influence # of products as well.... Close vote with "needs details or clarity"?
Safdar
Safdar
@AniruddhaDeb You can't get anymore details though. the question is inherently vague.

last day (15 days later) »